I would like to create this output in a JS while loop:
dataPoints: [
{ x: 10, y: 10 },
{ x: 20, y: 11 },
{ x: 30, y: 14 },
{ x: 40, y: 16 },
{ x: 50, y: 19 },
{ x: 60, y: 15 },
{ x: 70, y: 12 },
{ x: 80, y: 10 }
]
When I put this
sdata[i] = accumulated;
Into my loop, it adds the entries like that:
Object {
1: 1500,
2: 3005,
3: 4515.016666666666,
4: 6030.066722222222,
5: 7550.166944629629
}
What do I have to put into the loop to create the output like at the beginning?
Thanks for your help!
You're probably trying to push (x, y) points in an array. This is is how it should be done.
var sdata = []; // an array;
assuming that accumulated is a point it should have a structure like below
accumulated = { x: 10, y: 20};
Next is just create the points and push it to the array.
while(/*loop-condition-*/) {
var accumulated = {
x: xCurrent,
y: yCurrent
};
sdata.push(accmulated);
}
//that's it.
sdata now has the output as desired
Related
I need to access an object and it's property and check if the the value of the property smaller than 100 is.
My code would look like following:
let myArr = [{
id: 1,
x: 120,
y: 150,
}, {
id: 2,
x: 170,
y: 420,
}, {
id: 3,
x: 160,
y: 220,
}, {
id: 4,
x: 140,
y: 170,
}];
if(nearestEnemy.x - /*go throught all of my "x"-properties*/ && nearestEnemy.y - /*go throught all of my "y"-properties*/ < 100){
}
You don't need to matter about the other code, just look at my comments.
I want to check if the x axis and the y axis is almost the same as of one of my properties from my object in my array.
I guess you'd need something like a loop for this but I can't think of anything!
I don't know if you can understand me because I cant really explain what I mean.
Thanks for you help anyway.
You can achieve this by filtering out the objects by using Array.filter() method.
let myArr = [{
id: 1,
x: 120,
y: 150
}, {
id: 2,
x: 170,
y: 420
}, {
id: 3,
x: 160,
y: 220
}, {
id: 4,
x: 140,
y: 170
}];
function difference(a, b) {
return Math.abs(a - b);
}
const filtered = myArr.filter(({x, y}) => difference(x, y) < 100);
console.log(filtered);
It sounds to me like you have an array of points and want to find an element which is the nearest to the given point. If this is the case, you can proceed like this:
write a function that computes distance (https://en.wikipedia.org/wiki/Euclidean_distance) between two points
write a loop that minimizes distance
Example:
let myArr = [
{
id: 1,
x: 120,
y: 150,
}, {
id: 2,
x: 170,
y: 420,
}, {
id: 3,
x: 160,
y: 220,
}, {
id: 4,
x: 140,
y: 170,
}];
function distance(p1, p2) {
return Math.sqrt(
(p1.x - p2.x) ** 2 + (p1.y - p2.y) ** 2,
)
}
function nearestPoint(points, somePoint) {
let min = +Infinity,
minPt = null;
for (let p of points) {
let d = distance(p, somePoint);
if (d < min) {
min = d;
minPt = p;
}
}
return minPt;
}
console.log(nearestPoint(myArr, {x: 190, y: 130}))
This is not very efficient, but should be fine for < 10,000 points. If you have more, you'll need some kind of spatial indexing.
I have 2 array's with objects of coordinates. For example:
const coordinates = [
{ x: 2, y: 6 },
{ x: 14, y: 10 },
{ x: 7, y: 10 },
{ x: 11, y: 6 },
];
const coordinates2 = [
{ x: 8, y: 9 },
{ x: 25, y: 11 },
{ x: 2, y: 11 },
{ x: 7, y: 8 },
];
I want to make an sort function which will return which are closest to each other.
I tried multiple things but can not figure it out.
Any solution is accepted. Maybe sort 1 to the other or sort both at the same time.
This is wat I want to achive:
result array 1[
{ x: 2, y: 6 },
{ x: 14, y: 10 },
{ x: 7, y: 10 },
{ x: 11, y: 6 },
];
result array 2 = [
{ x: 2, y: 11 }, // beceause it is closest to {x: 2,y: 6}
{ x: 25, y: 11 }, // beceayse it is closest to {x: 14,y: 10},
{ x: 7, y: 8 }, // beceause it is closest to { x: 7, y: 10 }
{ x: 8, y: 9 }, // beceause it is closest to {x: 11,y: 6} after x: 7, y:10 but x:7, y:8 is even closer
];
^ the result can be different. But I want the most efficient distance between them.
The formula to see the distance of coordination a and coordination b is the following:
distance=√((x1-x2)²+(y1-y2)²).
If anyone has an idea or an tip please let me know !
You could map the first array by getting the closest coordinate from the second array.
const
getClosest = ({ x, y }, data) => data.reduce((a, b) => Math.hypot(x - a.x, y - a.y) < Math.hypot(x - b.x, y - b.y) ? a : b),
coordinates = [{ x: 2, y: 6 }, { x: 14, y: 10 }, { x: 7, y: 10 }, { x: 11, y: 6 }, { x: 6, y: 2 }],
coordinates2 = [{ x: 8, y: 9 }, { x: 25, y: 11 }, { x: 2, y: 11 }, { x: 18, y: 21 }, { x: 7, y: 8 }],
pairs = coordinates.map(o => [o, getClosest(o, coordinates2)]);
console.log(pairs);
.as-console-wrapper { max-height: 100% !important; top: 0; }
I have coordinates (x, y) of place where I am currently and array of objects with coordinates of destinations.
Coordinates x and y are just representing of fields in map like this:
and it is up to 100x100.
myPosition is array: [ 13, 11 ] where 13 is x and 11 is y (demonstratively marked it as red in above jpg).
destinations is array of object:
[ { x: 22, y: 13 },
{ x: 16, y: 25 },
{ x: 20, y: 11 },
{ x: 76, y: 49 },
{ x: 65, y: 47 },
{ x: 82, y: 33 },
{ x: 86, y: 35 },
{ x: 61, y: 59 },
{ x: 62, y: 52 },
{ x: 18, y: 52 },
{ x: 24, y: 49 },
{ x: 52, y: 55 },
{ x: 20, y: 57 },
{ x: 80, y: 11 },
{ x: 55, y: 61 },
{ x: 46, y: 59 },
{ x: 77, y: 19 },
{ x: 2, y: 22 },
{ x: 78, y: 23 },
{ x: 86, y: 51 },
{ x: 75, y: 46 },
{ x: 6, y: 8 },
{ x: 25, y: 12 },
{ x: 81, y: 21 },
{ x: 53, y: 58 } ]
I need some tips or algorithm which will sort destination array of object in order from closest to my position.
What you got is called the nearest neighbor problem.
Two solutions, depening on where you need to take your problem:
You could simply do a brute force distance search with the usual optimization of skipping the square-root:
Some code:
function DistSquared(pt1, pt2) {
var diffX = pt1.x - pt2.x;
var diffY = pt1.y - pt2.y;
return (diffX*diffX+diffY*diffY);
}
closest = destinations[0];
shortestDistance = DistSquared(myPosition, destinations[0]);
for (i = 0; i < destinations.length; i++) {
var d = DistSquared(myPosition, destinations[i]);
if (d < shortestDistance) {
closest = destinations[i];
shortestDistance = d;
}
}
If you are going to make repeated nearest neighbor queries on the same destinations array, you can use an algorithm known as a k-d tree. This where you build a binary tree representation of your grid of points by partitioning it in half many times along a different axis.
I have more than one array, I want to add them to Kendo chart, I did the search could not get the solution, it will be helpful if you help me.
see the example here
Suppose I want to add one more array like this
[{
x: 33, y: 50,
}, {
x: 15, y: 26
} ]
to the xyData object, How can I do? I have applied directly like
var xyData = [[{
x: 10, y: 20,
}, {
x: 100, y: 200
} ], [{
x: 33, y: 50,
}, {
x: 15, y: 26
} ]];
this but it did not work, How to do? please help me.
You can use Array.concat() to create one new array:
var xyData = [{
x: 10, y: 20,
}, {
x: 100, y: 200
} ];
var xyData2 = [{
x: 33, y: 50,
}, {
x: 15, y: 26
} ];
var xyTotal = xyData.concat(xyData2);
DEMO
I'm trying to build a colors structure that has 3 data per item. For example, red has x and y, blue has x and y, etc. So the 3 pieces of data are color, x, y
What structure do I need to make it easy to read the x and y based on the color. I usually do push(color, x, y) but that wouldn't work here, because I need to search quickly by the color without needing to loop. What structure do I need here, and how do I set it and get it.
What about a simple object (hash) ?
// Initial creation
var colors = {
blue: { x: 897, y: 98 },
red: { x: 43, y: 1334 },
yellow: { y: 12 }
}
// Adding new element to existing object
colors['green'] = { x: 19 };
// Accessing them
console.log(colors.blue.x);
console.log(colors.yellow.y);
// Accessing them with name in var
var needed = 'green';
console.log(colors[needed].x);
console.log(colors[needed]['x']);
Or did I understand you wrong?
Are you looking for something like a dictionary?!?
var colorArray = {};
colorArray["red"] = {
x: 100,
y: 200
};
colorArray["blue"] = {
x: 222,
y: 200
};
alert(colorArray["red"].x);
var colors = {
red : { x : 42, y : 7 },
blue : { x : .., y : .. },
...
};
alert(colors.red.x);
Or if you need the color also in the array
var colors = {
blue: { color:"blue", x: 100, y: 200 },
red: { color:"red", x: 50, y: 300 },
yellow: { color:"yellow", x: 30 y: 700 }
}
You also could use string "constants":
var RED = "red";
var colors = {};
colors[RED] = { color: RED, x: 100, y: 200 };
...
var colors = [
{color: 'blue', x: 897, y: 98 },
{color: 'red', x: 25, y: 1334 },
{color: 'yellow', x: 50, y: 12 }
]
for(var i in colors) {
console.log(colors[i].color);
console.log(colors[i].x);
console.log(colors[i].y);
}
// To insert into colors
colors.push({color: 'pink', x: 150, y: 200});
or if you have structure like this
var colors = [
['red', 837, 98],
['blue', 25, 144],
['yellow', 50, 12]
];
then
for(var i in colors) {
console.log(colors[i][0]); // output: red, yellow ...
console.log(colors[i][1]); // output: 837, 25 ..
console.log(colors[i][2]); // output: 98, 144 ..
}
and to insert into colors for this structure
colors.push(['pink', 150, 200])
or
var colors = {
blue: { x: 58, y: 100 },
red: { x: 43, y: 1334 },
yellow: {x: 254, y: 12 }
}
then
for(var i in colors) {
console.log(colors[i].blue.x);
console.log(colors[i].blue.y);
// or
console.log(colors[i]['blue'].x);
// or like
console.log(colors[i]['blue']['x']);
}
// and to insert for this sturcture
colors.pink= {x: 150, y: 200};