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I can run my project in xampp (localhost) but I cannot run when am trying run in another computer even after configuring

<?php
session_start();
define("HOST","localhost");
define("USER","root");
define("PASS","");
define("DB","project_inv");
define("DOMAIN","http://localhost/
inv_project/public_html/dont");
?>
Database:
<?php
class Database
{
private $con;
public function connect(){
include_once("constants.php");
$this->con = new Mysqli(HOST,USER,PASS,DB);
if ($this->con) {
return $this->con;
}
return "DATABASE_CONNECTION_FAIL";
}
}
//$db = new Database();
//$db->connect();
?>
JavaScript Validation Part: It comes here and keeps on loading when am trying to take from ip, e.g. http://xx.xx.xx.xx/inv_project/public_html/dont/
//For Login Part
$("#form_login").on("submit",function(){
var email = $("#log_email");
var pass = $("#log_password");
var status = false;
if (email.val() == "") {
email.addClass("border-danger");
$("#e_error").html("<span class='text-danger'>Please Enter Email Address</span>");
status = false;
}else{
email.removeClass("border-danger");
$("#e_error").html("");
status = true;
}
if (pass.val() == "") {
pass.addClass("border-danger");
$("#p_error").html("<span class='text-danger'>Please Enter Password</span>");
status = false;
}else{
pass.removeClass("border-danger");
$("#p_error").html("");
status = true;
}
if (status) {
$(".overlay").show();
$.ajax({
url : DOMAIN+"/includes/process.php",
method : "POST",
data : $("#form_login").serialize(),
success : function(data){
if (data == "NOT_REGISTERD") {
$(".overlay").hide();
email.addClass("border-danger");
$("#e_error").html("<span class='text-danger'>It seems like you are not registered</span>");
}else if(data == "PASSWORD_NOT_MATCHED"){
$(".overlay").hide();
pass.addClass("border-danger");
$("#p_error").html("<span class='text-danger'>Please Enter Correct Password</span>");
status = false;
}else{
$(".overlay").hide();
console.log(data);
window.location.href = DOMAIN+"/dashboard.php";
}
}
})
}
})
While am trying to run from other computer it displays the design and content of the page but it is not validating but when am trying locally it works fine.

Don't define DOMAIN as "localhost". This will cause errors, while calling the page from other computers.
Localhost means always the computer the script is running on. Using this in a JavaScript the reference to the server is lost and it tries to connect/forward to the client-computer - with no success. This works on the first computer, because this might be the server.

Form submited two times (ajax with jquery)

i have a simple form: when i submit it without javascript/jquery, it works fine, i have only one insertion in my data base, everything works fine.
I wrote some jquery to have result in ajax above the input button, red message if there was an error, green if the insertion was done successfully. I also display a small gif loader.
I don't understand why when i use this jquery, two loaders appear at the same time and two insertions are done in my database.
I reapeat that when i comment the javascript, it works fine, i'm totally sure that my php is ok.
$('#addCtg').submit(function () {
var action = $(this).attr('action');
var name = $('#name').val() ;
$('.messages').slideUp('800', function() {
$('#addCtg input[type="submit"]').hide().after('<img src="spin.gif" class="loader">');
$.post(action, {
name: name
}, function (data) {
$('.messages').html(data);
$('.messages').slideDown('slow');
$('.loader').fadeOut();
$('#addCtg input[type="submit"]').fadeIn();
});
});
return false;
});
I really don't understand why it doesn't work, because i use the 'return false' to change the basic behaviour of the submit button
Basic php just in case:
<?php
require_once('Category.class.php');
if (isset($_POST['name'])) {
$name = $_POST['name'] ;
if ($name == "") {
echo '<div class="error">You have to find a name for your category !</div>' ;
exit();
} else {
Category::addCategory($name) ;
echo '<div class="succes">Succes :) !</div>' ;
exit();
}
} else {
echo '<div class="error">An error has occur: name not set !</div>';
exit();
}
And finnaly my function in php to add in the database, basic stuff
public static function addCategory($name) {
$request = myPDO::getInstance()->prepare(<<<SQL
INSERT INTO category (idCtg, name)
VALUES (NULL, :name)
SQL
);
$r = $request->execute(array(':name' => $name));
if ($r) {
return true ;
} else {
return false ;
}
}
I rarely ask for help, but this time i'm really stuck, Thank you in advance

You're calling: $('.messages') - I bet you have 2 elements with the class messages. Then they will both post to your server.

One possible reason could be because you are using button or submit to post ajax request.
Try this,
$('#addCtg').submit(function (e) {
e.preventDefault();
var action = $(this).attr('action');
var name = $('#name').val() ;
$('.messages').slideUp('800', function() {
$('#addCtg input[type="submit"]').hide().after('<img src="spin.gif" class="loader">');
$.post(action, {
name: name
}, function (data) {
$('.messages').html(data);
$('.messages').slideDown('slow');
$('.loader').fadeOut();
$('#addCtg input[type="submit"]').fadeIn();
});
});
return false;
});

ajax responseText contains php source code

I am trying to make a ajax call and validate a input html field. But, instead of getting simple echo message. I am getting complete source code in responseText.
JavaScript
function checkUsername() {
document.getElementById("username").className = "thinking";
usernameRequest = createRequest();
if (usernameRequest == null)
alert("Unable to create request");
else {
var theName = document.getElementById("username").value;
var username = escape(theName);
var url= "checkName.php?username=" + username;
usernameRequest.onreadystatechange = showUsernameStatus;
usernameRequest.open("GET", url, true);
usernameRequest.send(null);
}
}
function showUsernameStatus() {
alert(usernameRequest.responseText);
if (usernameRequest.readyState == 4)
{
if (usernameRequest.status == 200) {
if (usernameRequest.responseText == "okay") {
document.getElementById("username").className = "approved";
document.getElementById("register").disabled = false;
}
else {
document.getElementById("username").className = "denied";
document.getElementById("username").focus();
document.getElementById("username").select();
document.getElementById("register").disabled = true;
}
}
}
}
checkName.php
<?php
$takenUsernames = array('bill', 'ted');
sleep(2);
if (!in_array($_REQUEST['username'],$takenUsernames )) {
echo 'okay';
} else {
echo 'denied';
?>
Previously, I tried to integrate PHP into tomcat, but I was advice it was not a good practice. TRIAL TO INTEGRATE PHP
What I can make out of this situation is that Tomcat is not parsing PHP file and instead it is returning the source code. I believe there should be a means for me to let tomcat parse php files and send the right response.
I have also tried with simple php code, with one statment <?php echo 'HELLO'; ?> and I still get the source code.
Thanks in advance.
NOTE : I do not know php, I am working an example from HEAD FIRST AJAX

you need to install PHP for Tomcat & set its path to compile it.see the below link for php configuration settings.
http://php-java-bridge.sourceforge.net/doc/tomcat6.php
http://www.studytrails.com/blog/php-on-a-java-app-server-apache-tomcat-using-quercus/

Jquery - fill input if user exist

I'm trying to fill a form if I find that the name and the firstname input by the user already exist in my database.
For the moment, I would like to check if the name and the firstname already exist in the database but my javascript program doesn't work. It's seems that the part..." "$.post("../modules/verifier_staff.php",{ nom: ..." is not correct.
Then I would like to fill my form with the data that my database give (array).
Can somenone help me to find my mistakes and to tell me how I can use the data i receive from database to fill my form?
$(document).ready(function(){
var form_nom = $("#staff_nom");
var form_prenom = $("#staff_prenom");
$(form_nom).change(function() {
checkvariable();
});
$(form_prenom).change(function() {
checkvariable();
});
function checkvariable(){
if((form_nom.val().length >0)&&(form_prenom.val().length>0)){
prenom_staff = form_prenom.val();
nom_staff = form_nom.val();
//alert(nom_staff);
$.post("../modules/verifier_staff.php",{ nom: nom_staff, prenom: prenom_staff},
function(data){
if(data)
{
alert('ok');
}
else alert('nok');
});
}
}
});

var form_nom = $("#staff_nom");
var form_prenom = $("#staff_prenom");
$(form_nom).change(function() {
checkvariable(form_nom,form_prenom); //pass arguments into the function
});
$(form_prenom).change(function() {
checkvariable(form_nom,form_prenom);
});
function checkvariable(form_nom,form_prenom){ //innclude argument in function definition
//......
}

thank for your help. Yes I'm sure that the path is correct.
Here is my code from ../modules/verifier_staff.php
<?php
include('../inc/settings.php');
include('../inc/includes.php');
//$_POST['nom']='Doe';
//$_POST['prenom']='John';
$nom=$_POST['nom'];
$prenom=$_POST['prenom'];
$Dbcon = new Db;
$personne_manager = new PersonneManager($Dbcon->dbh);
$personne = $personne_manager->get(array('conditions'=> array('nom' => strtolower($nom),'prenom' => strtolower($prenom))));
if($personne)
{
$result = true;
}
else
{
$result = false;
}
return $result;
?>
this part works well (I tested it) so I think the problem come from my javascript code. I'm a newbie in javascript/jquery.

How can I use the results of various ajax requests in another function?

I have been programming a registration form with ajax validation. The way I have it set up is in my js file, I have listeners that fire when the content of the field is changed. They send the data to the server, and the server makes sure it's valid and sends back its response in the form of a JSON object. I then read the values of the JSON object to output potential error messages.
I won't copy and paste the entire files, just one example:
$(document).ready(function() {
// USERNAME VALIDATION LISTENER
$("#regUsername").change(checkName);
}
and then the checkName function looks like this, it sends my ajax request:
function checkName() {
$.ajax({
type: "POST",
url: "./ajax_register.php",
data: {
request: "nameAvail",
username: $("#regUsername").val()
},
success: function(data) { // execute on success
var json = jQuery.parseJSON(data);
if (json.success) { // if usernames do match
$("#usernameAvailiability").removeClass().addClass('match');
$("#usernameAvailiability").text(json.msg);
} else { // if the user has failed to match names
$("#usernameAvailiability").removeClass().addClass('nomatch');
$("#usernameAvailiability").text(json.msg);
}
}
});
}
And depending on the response, it updates a span that tells the user if the input they wrote is valid or not.
The server validates with this part of the php file:
if(!isset($_POST['request'])) { // do nothing if no request was provided
print("no request provided");
} else { //ELSE request has been provided
if ($_POST['request'] == "nameAvail") { // if the request is to check if the username is valid
$response = array("success" => false, "msg" => " ", "request" => "nameAvail");
// CHECK USER NAME AVAILIABILITY CODE
if (!isset($_POST['username']) || empty($_POST['username'])) { // if no username is entered
$response['success'] = false;
$response['msg'] = "No username provided";
} else { // if a username has been entered
$username = $dbConn->real_escape_string($_POST['username']);
if (!ctype_alnum($username)) { // Make sure it's alpha/numeric
$response['success'] = false;
$response['msg'] = "username may only contain alpha numeric characters";
} elseif (strlen($username) < 4) { // make sure it's greater than 3 characters
$response['success'] = false;
$response['msg'] = "username must be at least 4 characters long.";
} elseif (strlen($username) > 20) { // make sure it's less than 26 characters
$response['success'] = false;
$response['msg'] = "username can be up to 20 characters long.";
} else { // make sure it's not already in use
$query = $dbConn->query("SELECT `id`, `username` FROM `users` WHERE `username` = '"
. $username . "' LIMIT 1");
if ($query->num_rows) { // if the query returned a row, the username is taken
$response['success'] = false;
$response['msg'] = "That username is already taken.";
} else { // No one has that username!
$response['success'] = true;
$response['msg'] = "That username is availiable!";
}
}
}
print(json_encode($response));
}
What I'd like to do now is create a function in my javascript for the register button. But I need to make sure all the forms are validated first.
I'm not sure what my options are. What I'd LIKE to do is somehow be able to recycle the code I've already written in my PHP file. I don't want to write out an entirely new if($_POST['request'] == "register") clause and then copy and paste all the validation code to make sure the input is valid before I insert the registrant's data into the database. It seems really repetitive!
I know I could check to see if all the spans on the page were set to 'match', but that could easily be tampered with and blank forms could be submitted.
so far, my register button function looks like this:
function register() {
if ( NEED SOME KIND OF CLAUSE HERE TO CHECK IF ALL THE FIELDS ARE VALID) {
$.ajax({
type: "POST",
url: "./ajax_register.php",
data: {
request: "register",
username: $("#regUsername").val(),
password: $("#regPassword").val(),
email: $("#email").val(),
dob: $("#dob").val(),
sQuest: $("#securityQuestion").val(),
sAns: $("#securityAnswer").val(),
ref: $("#referred").val()
}, success: function(data) {
var json = jQuery.parseJSON(data);
console.log(json);
$("#regValid").removeClass();
$("#regValid").text("");
}
}); //AJAX req done
} else {
$("#regValid").removeClass().addClass('nomatch');
$("#regValid").text("One or more fields are not entered correctly");
}
return false;// so that it wont submit form / refresh page
}
I would really appreciate some help, I've spent the last few hours scouring StackOverflow for an answer, but I can't seem to get anything to work. Will I have to duplicate code in my PHP file or is there a more elegant way to handle this?