I have a layout where I need each child div in two columns to have a minimum height equivalent to the height of the window. To do this, I use:
$('.element').css("min-height",$(window).height());
This works for my purposes, however I wish to apply this to a number of elements, as aforementioned.
I used an array to attempt to achieve this:
var length = [$('.first'), $('.second'), $('.third'), $('.fourth'), $('.one'), $('.two'), $('.three'), $('.four')];
length.css("min-height",$(window).height());
As I am only new at javascript, I am unsure if it is even possible to select elements in this manner. Any help would be appreciated.
Here is a jsfiddle.
Instead of supplying multiple selectors, you could as well add a new class to all elements that need to be modified.
For example, add class="adjust-min-height" and then use
$('.adjust-min-height').css("min-height", $(window).height());
edit:
If you want to use an array similar to what you asked for in your question, you could do this:
var elements = ['.first', '.second', '#maybe-an-id', '.third'];
var selector = elements.join(', ');
$(selector).css('min-height', $(window).height());
You can of course put the .join(', ') after the array, I just split it up for clarity.
When supplying multiple selectors, separate them by a comma:
$('.first, .second, .third, .fourth, .one, .two, .three, .four').css("min-height", $(window).height());
However the above code completely misses the point of classes; you should put a single class on all the above elements and use one selector only - exactly as your first example does.
Related
You need to put items in a div - <div style = 'flex-direction: column;'>.
Div needs to be created after p withid = "billing_city_field"
and closes after the p withid = "apartment_field".
Tried to do it with this function:
jQuery (document) .ready (function ($) {
$ ("# billing_city_field"). after ("<div style = 'flex-direction: column;'>");
$ ("# apartment_field"). after ("</ div");
});
But the div immediately closes. What should I do?
The issue is because you cannot append start/end tags separately. The DOM works with elements as a whole, so you need to create the entire div element in a single operation.
Given the description of your goal it looks like you're trying to wrap the existing content in a new div. As such you can use nextUntil() (assuming the target elements are siblings) and then wrapAll(). Try this:
jQuery($ => {
let $contents = $("#billing_city_field").nextUntil('#apartment_field').add('#apartment_field');
$contents.wrapAll('<div class="column" />');
});
Note the use of a class attribute in the above example, instead of applying inline style rules.
Question is not super clear but from what I can tell.
I think you have small misunderstanding what .after does with jQuery. After in this case is "structural" and not "time" related. If you check jQuery docs (https://api.jquery.com/after/) for this you can see basically what you need to do.
Simplest way to do this, if these things needs to created and don't exist already on body for example.
$(function(){
var p = $("<p id='apartment_field'>Paragraph test</p>");
$("body").append("<div id='billing_city_field' style='flex-direction: column;'></div>");
$("#billing_city_field").html(p);
});
I've added Paragraph test so result is visible easier.
And one more thing, not sure if it's error with copy/paste but make sure that # and id don't have space in-between like this.
$("#billing_city_field")
$("#apartment_field")
Edit: Looking at the comments maybe something like this, if they exist already? You should clarify the question more.
$("#billing_city_field").append($("#apartment_field").detach());
I am trying to select all the elements of a page except one, inside a function:
$('#sidebutton').click(function () {
if (!$('.sidemenu').hasClass("current")) {
prevScrolPos = $(window).scrollTop();
scrollTo = 0;
} else {
scrollTo = prevScrolPos;
}
$('.hidelem').toggleClass("hidden");
$('.sidemenu').toggleClass("current");
$('html,body').scrollTop(scrollTo);
});
It works when I use a simple class selector (.hidelem), but doesn't when I use something a bit more complicated (for example, $("*:not(.sidemenu)").toggleClass("hidden"); or $("*").not(".sidemenu").toggleClass("hidden");); these just lead to a blank window.
Could you tell me what I'm missing here?
JSFiddle: https://jsfiddle.net/et978wjw/5/ (full functionality is missing but I hope you get the idea)
The problem is that you may be skipping .sideMenu with $("body *:not(.sidemenu)"), but you are not skipping its parent DIV. If you hide an ancestor, you hide all its descendants too. You also do not skip any descendants, so the children of .sidemenu are also hidden
So you need to exclude anything that is an ancestor of .sidemenu with :not:(has()), then exclude the sidemenu itself, then exclude any children of sidemenu:
$("#container :not(:has(.sidemenu)):not(.sidemenu):not('.sidemenu *')").toggleClass("hidden");
JSFiddle: https://jsfiddle.net/TrueBlueAussie/et978wjw/8/
You really should direct the hide/show at something more specific though. Perhaps a wrapper div around everything you want hidden? I added one for the demo.
Now having said all that, your selection process is quite complicated. You would be better off simply adding a class to all the things you want to toggle instead and just toggle those (you already have nodisplay on the divs, so I used that for now).
e.g. just this:
$(".nodisplay").toggleClass("hidden");
JSFiddle: https://jsfiddle.net/TrueBlueAussie/et978wjw/9/
I have a table with the odd and even rows with a different CSS style tr:nth-child(2n){...}, and when I filter them with a textbox and jQuery, I hide() all the rows except the ones that match my criteria.
The problem is that now the rows remain with the current style (as I assume they keep the position despite they can't be seen), so the new odd and even rows doesnt match the CSS pattern.
How could I fix it?
Try to follow this example:
jQuery('tr:visible').filter(':odd').css({'background-color': 'red'});
jQuery('tr:visible').filter(':even').css({'background-color': 'yellow'});
Check here:
http://jsfiddle.net/KSL7j/1/
Hope it helps
Update
You can check this other example with odd and row CSS classes.
As CAbbott suggested in this fiddle: http://jsfiddle.net/KSL7j/21/
nth-child checks for the nth-child, not for the nth visible child or th nth whatever-styled child (hide() just adds display:none and nothing more...) and will never do.
I see two possible solutions:
1.add classes even/odd after filtering, just asking for the visible ones and then use your css on those classes
untested code:
var rows = $(tr[#display=block]);
rows.each(function(){
var index = rows.index(this);
if(index%2==0){
$(this).addClass('even');
}
else{
$(this).addClass('odd');
}
}
2.really remove the rows, not just hiding them
when you use hide() it is just set the display to none.
the structure of the dom is not modify so the nth-child do not work as you expected
you need to remove the even tr to get the effect you want.
if you want reset the rows. you can hold them in a variable and restore them back
var rows = $("tr");
var even = rows.filter(":even");
$("#trigger").click(function () {
even.hide();
even.remove();
});
http://jsfiddle.net/R2gBt/
Edit: one missing piece of information - I can't use the class selector because there are more divs with the same class. I already thought of that, but I forgot to mention it. I have no idea why my post got downvoted, but it seems awfully silly considering I provided a lot of information, gave it honest effort, and tried to be verbose with code examples. People on this forum are ridiculous sometimes.
I'm trying to set the id of a div that doesn't have one and there's no way I can give it one upon generation of the page. I've tried using jquery (.each, .contains, .find, .filter, etc.) and I can't seem to get it right. I know a ton of people have asked this question, but none of the answers made sense to me.
I have the ability to set the text (html?) of the div, but nothing else. It ends up looking like this:
<div class="dhxform_note" style="width: 300px;">Remaining letters: 500</div>
I want a handle to the div object so I can show the user how many more letters they can type by updating the text.
Using this:
$("div")
returns a list of all divs on the page. I can see the target div in the list, but I can't get jquery to return a single object.
I know it can also be done with something like this:
var divs = document.getElementsByTagName("div");
for(var i = 0; i < divs.length; i++) {
if( /^Remaining letters/.test(divs[i].innerText) )
divs[i].id = "kudosMsgNote"
}
}
but I was hoping to complete this with a cleaner looking solution involving jquery. I also simply want to know how to do it with jquery, aesthetics not withstanding.
Use a class selector.
var theDivViaTheClass = $(".dhxform_note");
Class Selector (“.class”)
Description: Selects all elements with the given class.
version added: 1.0
jQuery( ".class" )
class: A class to search for. An
element can have multiple classes; only one of them must match.
For class selectors, jQuery uses JavaScript's native
getElementsByClassName() function if the browser supports it.
You seem to be targeting the <div> by its text. Try using the :contains selector:
$("div").filter(':contains("Remaining letters")').first().attr("id", "kudosMsgNote");
The .first() is to make sure you don't set the same id for multiple elements, in case multiple elements contain the text "Remaining letters".
Here's the docs for the :contains selector: http://api.jquery.com/contains-selector/
Be careful, the text you're looking for is case sensitive when using :contains!
Is that div the only one with the class dhxform_note? If so, you can use the class selector:
$('.dhxform_note').html();
With jQuery, you can specify any css selector to get at the div:
$(".dhxform_note").attr("id", "kudosMsgNote");
will get you this element as well.
Selecting on inner text can be a bit dicey, so I might recommend that if you have control over the rendering of that HTML element, you instead render it like this:
<div name="remainingLetters" class="dhxform_note" style="width: 300px">Remaining Letters: 500</div>
And get it like this:
$("[name=remainingLetters]").attr("id", "kudosMsgNote");
However, it's possible that you really need to select this based on the inner text. In that case, you'll need to do the following:
$("div").each(function() {
if ( /^Remaining letters/.test($(this).html()) ) {
$(this).attr("id", "kudosMsgNote");
}
});
If you cannot set id for whatever reason, I will assume you cannot set class either. Maybe you also don't have the exclusive list of classes there could be. If all those assumptions really apply, then you can consider down your path, otherwise please use class selector.
With that said:
$("div").filter(function() {
return /^Remaining letters/.test($(this).text())
}).attr('id', 'id of your choice');
For situations where there are multiple divs with the class dhxform_note and where you do not know the exact location of said div:
$("div.dhxform_note").each(function(){
var text = $(this).text();
if(/^Remaining letters/.test(text)){
$(this).attr("id", "kudosMsgNote");
}
});
EXAMPLE
If, however, you know that the div will always be the 2nd occurrence of dhxform_note then you can do the following:
$("div.dhxform_note").get(1).id = "kudosMsgNote";
EXAMPLE
Or do a contains search:
$("div.dhxform_note:contains('Remaining letters')").first().attr("id", "kudosMsgNote");
EXAMPLE
how can I select the following element using prototype div#page_container h1 and after selecting it change its padding-top ? Thank you
Prototype's $$() method allows you to select using CSS selectors, eg
var elmArr = $$("div#page_container h1");
and its setStyle method allows you to change style, eg
elmArr[0].setStyle({paddingTop: "4px"});
or
$$("div#page_container h1")[0].setStyle({paddingTop: "4px"});
Edit: I'm pretty sure the returned array is also extended by prototype, so if you had multiple h1 elements in page_container, you could do:
$$("div#page_container h1").each(function(elm){
elm.setStyle({paddingTop: "4px"});
});
or
$$("div#page_container h1").invoke("setStyle",{paddingTop: "4px"});
to set the paddingTop of all of them
Make sure you include these .. and it should work , from this source
Cheers