When I click on a div a popup opens, and it closes when I click anywhere outside the popup. Because of this feature even when I click on 'Back to top button' the popup close and that I don't want. I want the popup to close on outside click but on click of few elements I want the popup to remain open.
My JS for reference:
$(document).click(function (e) {
if (!$(e.target).is('#myPanel, #myPanel*')) {
$("#myPanel").hide();
$(".span10").width(600);
}
});
You are on the right way. However, you need to include all elements that should not close the popup in the comma separated selector. Also, for those that have child elements, you need to include the ID followed by a star as well but separated by a space. The space is what is missing in your code. It should be #myPanel * and not #myPanel.
$(document).click(function (e) {
//Do not close popup for these:
// - Element with ID myPanel #myPanel
// - Any descendants of element with ID myPanel #myPanel *
// - Element with ID backtotop #backtotop
if (!$(e.target).is("#myPanel, #myPanel *, #backtotop")) {
$("#myPanel").hide();
$(".span10").width(600);
}
});
JSFiddle.
Related
I have this code for toggling menus on my site. It will open a menu on click, close others open when you click another and close them all if you click outside.
The issue is, I'm now using this for my search bar to appear too, but if you click inside the search box it vanishes - woops. Would it be possible to amend the hiding code to detect if the user wasn't clicking inside a specific area of the code?
// navbar toggle menu
$(document).on('click', ".toggle-nav > a", function(event) {
event.preventDefault();
event.stopPropagation();
var $toggle = $(this).closest('.toggle-nav').children('.toggle-content');
if ($toggle.hasClass('toggle-active'))
{
$($toggle).removeClass('toggle-active');
}
else
{
$(".toggle-content").removeClass('toggle-active');
$($toggle).addClass('toggle-active');
}
});
// hide the toggle-nav if you click outside of it
$(document).on("click", function ()
{
$(".toggle-content").removeClass('toggle-active');
});
Instead of using click, this uses mouseup. If the target is, for example #search-bar, it won't remove toggle-active from toggle-content elements.
$(document).mouseup(function(e) {
if (!$(e.target).is('#search-bar')) {
$(".toggle-content").removeClass('toggle-active');
}
});
You can see it in action with this jsFiddle.
Hopefully this helps.
I have a popup window that has a form in it and to stop the popped up div clicks from closing the window I've used:
$(".popup").click(function () {
$(".popup").css("display", "none");
}).children().click(function(e) {
return false;
});
However this works perfectly except with checkboxes whereby it disables checking them.
Is there any way around this?
popup is an overlay, then popupInner holds the form.
Try replacing your code with this:
$(".popup").click(function(e) {
if (e.target == this) $(this).hide();
});
It would hide the popup only if clicked on the element with class popup and not its children, it would also keep the functionality of the children intact.
I am using JQuery to make a 'Read More' button. When someone clicks onthe button a popup appears. This popup is actually a hidden div that appears. My problem is that while I click the button I want the div to appear from the button and when I click the cross mark on the popup it sould go back to the same button where it originated from but the result that I am getting is, when I click on the button the div appears from it whereas when I click cross it goes to the 'read more' button which I clicked the first. Please help me fix this. I guess there is a small glitch in my code. I have it on fiddle http://jsfiddle.net/shivkumarganesh/qLEbD/
Check this fiddle: http://jsfiddle.net/6uLF7/
The problem was with the local scope of the variables that store the target left and top offsets.
CHANGES
Added 2 declarations at the top:
var readMoreInfoTop = 0;
var readMoreInfoLeft = 0;
Removed var keyword from the top and left assignments inside the click handler
readMoreInfoTop = readMoreOffset.top + 10;
readMoreInfoLeft = readMoreOffset.left + 10;
Each time you open a button, you are adding another listener to the close button. You could unbind the close listener before rebinding it eg. http://jsfiddle.net/qLEbD/54/
or better yet...
bind the close listener once (outside the button click function) and store the left position on button click eg.
//doc ready...
function() {
var leftPosition;
$('.button').click(function() {
//animate popup to open
leftPosition = $(this).offset.left;
});
$('#close').click(function() {
//animate popup to close using leftPosition
});
}();
I've got a child close button inside its parent, a notification box. When the parent is clicked, the notification box expands, with the notification's description and the child button becoming visible inside it.
The button, when clicked, should unexpand the notification and hide both itself and the description.
Because the button has a click event inside its parent click event, both were being called. I turned to event.stopPropagation() to have the parent notification stop re-expanding after I clicked. While this stopped the notification from expanding on a close button click, it presented a new problem that I don't understand.
In my test, I have two notifications set up, both unexpanded. When I click on a notification, it expands and shows the description and close button. When I click the close button, the notification unexpands and the button and description are hidden. But, I found that the description and close button were appearing for the other notification!
Code:
var $NotificationContainer = $("#NotificationContainer");
$NotificationContainer.append('<div class="Notification" title="'+title+'"></div>');
var $thisNotification = $NotificationContainer.children('.Notification[title='+title+']');
$thisNotification.append('<div class="NotificationTitle">'+title+'</div>');
$thisNotification.append('<div class="NotificationDescription">'+description+'</div>');
$(".NotificationDescription").hide();
// Button used to close an expanded notification
$thisNotification.append("<div class='NotificationCloseButton'></div>");
$('.NotificationCloseButton').hide();
// When the parent notification box is clicked
$thisNotification.click(function(event)
{
$thisNotification.animate({height:250}, 1000);
$thisNotification.find('.NotificationDescription').slideToggle('fast');
$thisNotification.find('.NotificationCloseButton').slideToggle('fast');
});
// When the child close button is clicked
$(".NotificationCloseButton").click(function(event)
{
event.stopPropagation();
$thisNotification.animate({height:50}, 1000);
$thisNotification.find('.NotificationDescription').slideToggle('fast');
$thisNotification.find('.NotificationCloseButton').slideToggle('fast');
});
I don't know how $thisNotification.find('element') is not catching the right notification.
Does it work if you change the event handling to
// When the parent notification box is clicked
$thisNotification.click(function(event)
{
var self = $(this);
self.animate({height:250}, 1000);
self.find('.NotificationDescription').slideToggle('fast');
self.find('.NotificationCloseButton').slideToggle('fast');
});
// When the child close button is clicked
$(".NotificationCloseButton").click(function(event)
{
var self = $(this);
event.stopPropagation();
self.animate({height:50}, 1000);
self.find('.NotificationDescription').slideToggle('fast');
self.find('.NotificationCloseButton').slideToggle('fast');
});
used this to identify the clicked element, instead of relying on the variable that was defined when you created the element (avoids cases in loops where the all elements reference the last value assigned to the variable..)
Additionally, since you are appending to the #NotificationContainer you can just select the last item instead of searching for identical titles..
var $thisNotification = $NotificationContainer.children().last();
removed the selector completely since you have just appended the last element..
I have a div which opens when I click a menu button, I am trying to close it if the user clicks anywhere after it is open. The issue I am having is that with my code the show div and the close div when a user clicks I guess are firing at the same time for some reason. The code for the click event is below. How can I make it so they do not fire at the same time and when I open the div that does not fire the click function. Thanks!
//if user clicks and menu is open then hide menu div
$(document).click(function() {
if($("menu").hasClass("menu_closed") == false ) {
//will hide the menu div
closeMenu();
}
}
I think what you want actually is to stop propagation in the other click handler, something like:
$("your_menu_selector").bind("click", function(e){
//your code to open the menu
e.stopPropagation();
return false;
})
You might want to consider adding the event handler to close the menu in the handler that opens the menu. Have it execute only once using the one method. In the handler that opens the menu, simply check to see if it is open already and do a no-op if it is.
$('.openButton').click( function() {
var $menu = $('#menu').
if ($menu.hasClass('menu_closed')) {
$menu.removeClass('menu_closed').addClass('menu_open');
$(document).one( function() {
$menu.removeClass('menu_open').addClass('menu_closed');
});
}
});