My code is working in chrome,safari but its not working in firefox.
Here is my code
<script>
$(document).ready(function () {
$("#loginform").on('submit',(function(e) {
e.preventDefault();
$('#loading').html("Loading....");
$.ajax({
url: "login.php",
type: "POST",
data: new FormData(this),
contentType:false,
cache: false,
processData:false,
async:false,
success: function(data)
{
$('#loading').hide();
$("#message").html(data);
}
});
return false;
}));
});
</script>
Can anyone solve this issue??? I have one more same script in the same page only url is different but its working fine,but this script is not working .Iam getting empty data .But in chrome,safari its working fine.
My Html Code :
<form role="form" method="post" id="loginform" action="">
<div class="form-group">
<label for="username">Username</label>
<input type="text" class="form-control" id="username" name="username" placeholder="Enter Username" required>
</div>
<div class="form-group">
<label for="password"> Password</label>
<input type="password" class="form-control" id="password" name="password" placeholder="Enter password">
</div>
<div class="checkbox">
<label><input type="checkbox" value="" name="user_rememberme" checked>Remember me</label>
</div>
<div id="loading"></div>
<div id="message"></div>
<button type="submit" name="login" class="btn btn-success pull-right">Login</button>
</form>
Never use async:false in ajax call unless you knows specifically wat you are doing.The problem is that async:false freezes the browser until ajax call is complete (either error or success).set it to true or remove it (by default it is true).Implement error block too and check if its an error from server side
success: function(data)
{
$('#loading').hide();
$("#message").html(data);
},error:function(data){
console.log(data)
}
Try this:
<script>
$(document).ready(function () {
$("#loginform").on('submit',(function(e) {
dta = $(this).serialize();
e.preventDefault();
$('#loading').html("Loading....");
$.ajax({
url: "login.php",
type: "POST",
data:dta,
success: function(data)
{
$('#loading').hide();
$("#message").html(data);
}
});
return false;
}));
});
</script>
Related
I have form which contain email input field
<form id="TypeValidation" action="" method="post" enctype='multipart/form-data'>
<div class="form-group has-label col-sm-6">
<label>
Email
</label>
<input class="form-control" name=email" type="email" required>
</div>
<div class="card-footer text-center">
<button type="submit" name="add_usr_acc" id="add_usr_acc" value="add_usr_acc" class="btn btn-primary" >Add</button>
</div>
</div>
</form>
Issue is that in script code when alert on email then come undefined. how to get value in which user type a email
<script>
$("#TypeValidation").on('submit', (function(e) {
var email = $(this).find('input[name="email"]').val();
alert(email); {
e.preventDefault();
$.ajax({
url: "fn_acc_submit.php?addUsraccID=" + addUsraccID,
type: "POST",
data: new FormData(this),
contentType: false,
cache: false,
processData: false,
dataType: "html",
beforeSend: function() {
$("#add_usr_acc").prop('disabled', 'disabled')
},
success: function(result) {
alert(result);
location.reload();
if (result == '1') {
location.replace("lst_user_account.php");
} else {
location.replace("add_user_account.php");
}
}
});
}
}));
</script>
Please fix my problem where I am doing wrong.
Problem is in your HTML code at below line:
<input class="form-control" name=email" type="email" required>
Here name=email" is not valid.
Change this to name="email"
In you input field, it should name="email". You forgot to add opening quotes.
I'm a novice coder, and i'm having trouble putting a simple form together using validator.js
Basically since trying to build in the validation the form has stopped working, my guess is the 'data: $('#send-form').serialize(),' has not got the correct path or syntax, but i could be wrong.
As soon as i add:
$.ajax({
type: "POST",
url: "process.php",
data: $('#send-form').serialize(),
}
the alerts do not fire!
<form class="contact" name="contact" id="send-form" data-toggle="validator" role="form" >
<div class="form-group">
<label class="subTitle" for="name">NAME</label><br>
<input type="text" name="name" class="form-control" placeholder="Enter your full name" data-error="Please enter your name" required>
<div class="help-block with-errors"></div><br>
</div>
<div class="form-group">
<label class="subTitle" for="email">E-MAIL</label><br>
<input type="email" name="email" pattern="[a-z0-9._%+-]+#[a-z0-9.-]+\.[a-z]{2,3}$" class="form-control" placeholder="Enter a valid email address" data-error="Invalid email address" required>
<div class="help-block with-errors"></div><br>
</div>
<div class="form-group">
<button type="submit" class="subBtn form-control">SUBMIT YOUR ENQUIRY</button>
</div>
</form>
<script>
$('#send-form').validator().on('submit', function (e) {
if (e.isDefaultPrevented()) {
alert('form is not valid');
} else {
// everything looks good!
e.preventDefault();
alert('form is valid');
// your ajax
$.ajax({
type: "POST",
url: "process.php",
data: $('#send-form').serialize(),
}
});
</script>
Should be:
$('#send-form').validator().on('submit', function (e) {
if (e.isDefaultPrevented()) {
alert('form is not valid');
} else {
// everything looks good!
e.preventDefault();
alert('form is valid');
// your ajax
$.ajax({
type: "POST",
url: "process.php",
data: $('#send-form').serialize(),
});
}
});
(untested)
I am posting a form to a php file using ajax but for some reason which I can't figure out, it is not using ajax but directly posting to php.
My form:
<form id="editform" name="editform" action="ajaxeditform.php" method="post">
<input type="hidden" name="aid" id="aid" readonly class="form-control col-md-7 col-xs-12"/>
<input type="text" name="number" id="tailnumber" readonly class="form-control col-md-7 col-xs-12"/>
<input type="text" name="type" id="type" class="form-control col-md-7 col-xs-12" placeholder="e.g. C172" />
<input type="text" name="colormarkings" id="colormarkings" class="form-control col-md-7 col-xs-12" />
<button type="submit" class="btn btn-success">Update info</button></div>
</form>
My jquery:
$('#editform').on('submit', function(e){
e.preventDefault();
$.ajax({
type: $(this).attr('method'),
url: $(this).attr('action'),
data: $(this).serialize(),
dataType: 'json',
cache: false,
})
.success(function(response) {
// remove all errors
$('input').removeClass('error').next('.errormessage').html('');
if(!response.errors && response.result) {
new PNotify({
title: 'Success',
text: 'Info updated successfully',
type: 'success'
});
} else {
$.each(response.errors, function( index, value) {
// add error classes
$('input[name*='+index+']').addClass('error').after('<div class="errormessage">'+value+'</div>')
});
}
});
});
Changes:-
Form opening tag is not proper, change like below:-
<form id="editform" name="editform" action="ajaxeditform.php" method="post">
try to change your jquery code first line like below:-
$('Form#editform').on('submit', function(e){ OR $('.btn-success').click(function(e){
Add jquery library also (check that it is added or not?). for example add this code before jQuery code:-
<script src="//code.jquery.com/jquery-1.12.0.min.js"></script>
add $(document).ready(function(){ in your code.like below:-
$(document).ready(function(e){
........ //your code
});
i'm trying to display a success /error message when a user login to my website through a hidden div, that is displayed by on click event jQuery. Looks like whatever i try, nothing works. Already searched over and over but can't find a solution. Any help please?
My current code:
$(document).on('submit', '#loginform',function(e){
e.preventDefault();
var formData = new FormData($(this)[0]);
$.ajax({
url: 'portal/login',
type: 'POST',
dataType:"json",
data:formData,
contentType: false,
processData: false,
success: function(data) {
if(data.status == 1) {
console.log(data.status);
$('.login_result.success').show();
} else {
$('.login_result.error').show();
}
}
});
});
$('.modaltrigger').on('click',function() {
$('#loginmodal').fadeIn(500);
});
So i'm using Ajax to validate the user login, and then at success i want to fadeIn the .login_result
EDIT
My HTML code:
<div id="loginmodal" style="display:none;">
<div id="placeHolder">
<div class="main_logo"><img src="images/logo.jpg"></div>
<form action="portal/login" method="post" class="login" name="loginform" id="loginform">
<input id="user_email" name="user_email" placeholder="Email" type="text">
<input id="user_password" name="user_password" placeholder="Senha" type="password">
<button class="search_button login_button" name="admin_login">Entrar</button>
<span><?php //echo $error; ?></span>
</form>
<div class="login_result success">Login Efetuado com sucesso, Redirecionando!</div>
<div class="login_result error">Login Inválido!</div>
</div>
I have a form:
<form method="post" action="insert.php">
<input type="text" name="firstname" placeholder="Vorname" required>
<br>
<input type="text" name="lastname" placeholder="Nachname" required>
<br>
<input type="text" name="nickname" placeholder="Spitzname" required>
<br>
<input type="email" name="email" placeholder="Email" required>
<br>
<input type="submit" value="Speichern">
</form>
As you can see my action is action="insert.php" so that calls my insert.php. A new url is created and it is opened in the browser.
But what if i dont want that? I want to stay on the same site where the form is and i would prefer not to call any php directly. i would prefer to call a javascript function. For example, my select i do with ajax:
function getData() {
$.ajax({
url: "queries.php",
data: {action: "retrieve_data"},
dataType: "json",
type: "post",
success: function(output) {
// do stuff
}
});
}
Can i also do something like that with the insert?
<html>
<body>
<form method="post" action="insert.php" id="insertForm">
<input type="text" name="firstname" placeholder="Vorname" required>
<br>
<input type="text" name="lastname" placeholder="Nachname" required>
<br>
<input type="text" name="nickname" placeholder="Spitzname" required>
<br>
<input type="email" name="email" placeholder="Email" required>
<br>
<input type="button" id="insertData" value="Speichern">
</form>
<script type="text/javascript" src="lib/js/jquery-2-1-3.min.js"></script>
<script type="text/javascript">
$(function () {
$('#insertData').click({ inputs:$('#insertForm :input') }, getData);
});
function getData(o) {
var values = {};
o.data.inputs.each(function() {
values[this.name] = $(this).val();
});
$.ajax({
url: "queries.php",
data: {action: "retrieve_data", firstname: values['firstname'], lastname: values['lastname'], nickname: values['nickname'], email: values['email']},
dataType: "json",
type: "post",
success: function(output) {
// do stuff
}
});
}
</script>
</body>
</html>
Here you go, you can always edit is as you want, or what values are optional and such.
Remember i've used a type="button" so the page doesn't reload, so the action could just stay empty.
Since you seem to be using jQuery, this is easy; as explained in the documentation. If you give your form id=insertForm this should work:
$("#insertForm").submit(function(e){
$.ajax({
url: "/insert.php",
type: "post",
data: $(this).serialize();
});
e.preventDefault();
});