Browser Back button changes dynamic url Parameters - javascript

I am working on a website, where url parameter gets updated based on user action, according to which I update the webpage without refreshing.
Consider the scenario of E-commerce where url changes when user clicks on filters and then updated products gets displayed.
Now the problem is, when user clicks on Browsers's back button the browser goes back to previous url-parameter, but page did not gets changed. I want to change the page also based on url parameter that gets changed after back button clicked.
I have tried this solution:
$($window).on('popstate', function (e) {
// Update the page also
});
The problem with this code is, this gets fired as url changes, means it does not care about if browser back button is clicked, or url is changing using the jQuery. So if I am changing url based on user interaction, the popstate callback will be called and my custom function also. To update the page I am using https requests, so http api gets called two times.
Is there any way to check if only "Back button" is clicked?

I would recommend you to change your design a litle bit and trigger all content updates (the product list in your case) by listening to url changes, not only url changes caused by the back button. So instead of triggering any re-rendering on click events, let these buttons be regular link to the url that represent your content and trigger the functionality from the popstate event.
This is how all MVVM-frameworks like Angular.js, Backbone etc are designed and meant to be used.
By doing this it will also be so much easier for you to maintain the application in the long run.
Good luck!

You can do this with sessionStorage! Below is the relevant part of an answer I always refer to for stuff like this https://stackoverflow.com/a/45408832
sessionStorage is a storage type like localStorage but it only saves your data for the current tab.
Session storage can be used like this.
sessionStorage.setItem('key', 'value'); //saves the value
sessionStorage.getItem('key'); //gets the saved value
performance.navigation.type is the browser is the variable that hold users navigation info.
if(performance.navigation.type == 2){
//User is coming with back button
}
So to put it all together, you can set/update a sessionStorage item as part of the callback of the click event for your filter, then performance.navigation.type to check if they used the back button to load the page and apply the data!

Related

Apex - Clear form when leaving page (also on redirect)

Currently, if I populate a form and leave the page, the form entries will still be present when I return to the form. Is it possible to prevent these entries from being saved?
The items' default values are populated using PS/SQL, but the content can be adjusted.
I tried creating a dynamic action to clear the items on 'Page Unload', but this didn't do anything. Is this the correct browser event, or did I simply get the implementation wrong?
Update: To provide a bit of context...
Pages:
Home
Form
DML Form (insert) - I want any modifications to not be stored
Page 3 can be accessed via Page 1 or Page 2.
If the user accesses the form via Page 2 (a different form), they will have selected a specific value and this is used to populate default values on Page 3 (via item and PL/SQL Function Body).
If the user accesses the form via Page 1, the same PL/SQL will run - this may result in Page 3 form items being empty (NULL default values).
HOWEVER, when the user edits Page 3 items (changing from default values), these values will persist when the user next accesses the form. How can I prevent this state from being captured?
You will need to clear the cache of the page. This will clear the session state of the items on the page and thus result in items being empty once again.
You may need to add this clear on several locations. If you have used column links to access the page, buttons with redirects, branches, etc. The apex URL has a part which states which pages have to be cleared, and you can generally define this clearing of a page cache declaratively.
You can also create processes where you can define which page (or pages) has to be cleared. For example, if you always want the cache to be cleared when entering the page, no matter where you came from, you could add a process on the page doing just that.
Session state is ultimately what is causing this behavior: go to the page, change some things, page gets submitted for whatever reason and causes session state to be saved.
Usually, on DML forms generated through the wizard, the cache would only be cleared when using the "create" button coming from another location (usually the overlying report).
Here is the (apex 5.0) documentation on session state and managing it.
You can do it with something like this, but first you need to add jQuery to your page. I recommend using a content delivery network (CDN). You can edit the code to clear the value in your type of forms. I hope this could help you!
jQuery CDN example
$(document).ready(function() {
$("body")
.find("input").val("")
.end()
.find("select").val("-")
.end()
.find("textarea").val("");
};
});

How to maintain states of selection on back button

I am using HTML and JavaScript to write Android APP, but I have a problem that when go back from current page to the previous page, the page is reloaded and the selection and setting when I made in the first goes to default.
For example: On the first page user can select country and city and then navigate to second page.
If user clicks on back button (which calls window.history.back(); or href="javascript:history.back(-1);")
, then all the selection he made are lost and default selections are shown.
It works fine in native browser of Android.
How to maintain state of selection?
Thanks in advance!
You need to make dummy history to disable history back button.
var originalHash = document.hash || "#dummyMain"
location.assign("#dummyBack")
location.assign(originalHash)
window.addEventListener("popstate",function(){
if(location.hash == "#dummyBack"){
window.history.pushState(null,null,originalHash)
}else{
originalHash = location.hash
}
});
The code above create dummy page history and checks if page transitions are occurred via history back button or not and if so,force page move to current page again to stop history back action.
Since You didn't put any code in the question,It's hardly possible to say it will work or not but I guess once you load this code,it should disable all page back action.
If you are using PC/Mac to use this site,please try to open developper tools/firebug javascript console and copy/paste the code and press history back button to see how it works.
I find a good way to maintain the data of previous page, which use localStorage store the data as key value before leaving this page and again when come back to this page you can get your data again from localStorage` and display it.
Because the data which is loaded by AJAX will be last on history back.
Hope this help someone may has this problem.

Javascript: Making divs hold state of display='block' when user clicks BACK button in browser

I have a few divs on a form that are hidden by default (style="display:none;"). When the user clicks a certain radio button, an onclick event executes and exposes the divs. The user is then taken to a review page upon form submit that shows him any errors. If there are any, he clicks the BACK button on his browser to go back to the form and correct them. Caching is enabled so that all of his form contents are there. The problem is, since the form is looking for an onclick event, all of the previously exposed divs are hidden again. Is there any way to make sure they stay exposed when the user clicks back to the form from the review page? I thought a document.ready function would do it, but no joy.
As Yair mentioned, you can use cookies. It cannot be done with pure JS. However, you can also use PHP.
Before the user is transferred to the second page, have JS scan the divs in question, and find which ones are visible. (I'm assuming they all have individual IDs). Store these IDs in a comma-delimited string, or array, and send it as a _POST or _GET to the new page.
Have PHP store it as a hidden value somewhere. You could use a hidden input, or a data-x on something ... as long as it's there.
Have JS on that page that watches for the back click, stops it, and then redirects the user to the previous page, and sends the string or array back to it. Have PHP on that page print it as a JS value, and have JS on pageload show all divs with matching IDs.
Cookies or localStorage if you aim for only modern browsers:
localStorage
Is there any way to make sure they stay exposed when the user clicks
back to the form from the review page? I thought a document.ready
function would do it, but no joy.
You can use cookies in order to manage state in a web-browser. Cookies will help you save the desired user's state.
All javascript code is reinitialized on browser reload. You cannot identify whether the user comes back through the browser.
You can use cookies or local storage to save a value when initial display happens and show/hide the div later on document.ready.

pushstate - back button not working

If I use ajax to change specific portions of the page, like a content section, which warrants a new URL (and requires one specifically for favoriting, or refreshing), is there some magic that I am not aware of that allows the user to click the back button and reload the content that was just there?
Or do you have to re-retrieve the data based on stored variables using popstate
Thanks!

How to store URL of clicked hyperlink

I am displaying a warning dialog box whenever user tries to navigate from current page without saving data on current page. Its working fine now I want to call a function (Spring controller, its kind of java function which handled URL mappings ) when user clicks on Ok (in warning dialog box) and then he should get redirectd to desired page.
Let me try to make it simple (Its confusing for me also):
User is on registration page, he/she made some changes and didn't save it.
Now user clicked on any other link for example he clicked on About Us link.
Now I want to execute my spring controller.
After execution of controller user should get navigated to About Us page.
For this I need to save value of clicked hyperlink and pass it to my spring controller.
So how can I store URL of clicked link (URL of About Us page in above example) ?
PS: I will really appreciate if anybody can edit my question to make it easier to understand.
if you use jQuery, you can attach an event handler to onclick to all links in the page and once clicked the handler should save the href attribute to some variable. then create a onbeforeunload event listener on your window, where you can use the value however you want, call your controller or save the value in a cookie or something.
Are all the links on the page pointing to your spring application? If there are no external links anywhere (pointing to external resource) - then you could write a simple Filter where you can save the requested page into the session.
Otherwise, if there are links to external resources - you would need to rewrite them from www.external.com to www.my.com\MagicController?requestedPage=www.external.com. Controller will save the link and send a redirect in HTTP header to the requested page. This is a common practice - even google does that (check out the google search result links for how it will look like).
Added: Weird, but google does that only on some rare occasions, so you probably won't be able to find an example there.
Don't require to preserve the href of selected tab.Do one thing attach same javascript function with each tab and pass the "this" as parameter of function.
Function of the javascript is
function Attach(ele)
{
// 1. Find the handle of selected tag and store in the variable.
ele=$(ele);
// 2. Find the value of href
var href=ele.attr("href");
// 3. Perform server side operation you want.
// 4. redirect to another page.
window.location=href;
return false;
}

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