I am trying to update an upload image to folder using php file upload and could not get the previously occured image in the database. Here is my code,problem is I could not get the previous image in the file upload section from database. Please help.
if(isset($_GET['msg']))
{
echo $_GET['msg'];
}
$id=(isset($_GET['id']))?$_GET['id']:'';
$val=view_data1_event($id);
if (isset($_POST["events"])&&isset($_POST["description"]))
{
$id=$_POST["id"];
$title=$_POST["events"];
$description=$_POST["description"];
$filetmp=$_FILES["images"]["tmp_name"];
$filename=$_FILES["images"]["name"];
$filetype=$_FILES["images"]["type"];
$filepath= "photo2/".$filename;
move_uploaded_file( $filetmp,$filepath);
$update1=update_query($title,$description,$filename,$filepath,$id);
if($update1)
{
echo "<script>location.href='hotel1_galery_event.php'</script>";
}
}
HTML
<form action="hotel2_galery_eventedit.php" method="post" class="col-sm-4" enctype="multipart/form-data">
<div class="form-group has-info">
<label>Event Related images</label>
<input type="file" name="images">
<input type="hidden" name="image_name" value="<?php echo $val->image_name?>">
<input type="hidden" name="image_path" value="<?php echo $val->image_path?>">
</div>
<button type="submit" class="btn btn-primary">
<span>UPDATE</span>
</button>
</form>
Your form method is post and you are using as get in php.
Please replace all GET with POST
if(isset($_GET['msg']))
This should be,
if(isset($_POST['msg']))
Related
I have created a user profile information update using php. To update his image, what I do is that first let him delete the image and ask him to upload a new image. If accidentally user click image update button without clicking image delete button how to show an error message as "please first delete your Image and then upload a new image".
I couldn't find any way of doing it.
A help would be really appreciated
Given below is my code
<div class="form-group">
<center><label>Update A New Profile Picture </label></br></center>
<form method="post" action="update_userinfo.php" enctype="multipart/form-data">
<center><img id="uploadPreview4" style="width: 100px; height: 100px;" /></center>
<center><input type="file" name="Filename4" id="uploadImage4" onchange="PreviewImage4();" class="form-group"><input TYPE="submit" name="updateImage" value="Update Image" class="btn btn-success" /></center>
</form>
</div>
<div class="col-md-6">
<center><label>Your Current Profile Picture </label></br>
<form method="post" action="update_userinfo.php" enctype="multipart/form-data" onSubmit="if(!confirm('Do You really want to update your profile picture?')){return false;}">
<?php
echo "<img border=\"0\" src=\"".$row['image_path4']."\" width=\"100\" height=\"100\" >";
echo "<br>"; ?>
<input TYPE="submit" name="delete" value="delete" class="btn btn-success" />
</form>
</div>
This is what i can think of if you really want to deal with this using PHP ,
considering this is your current code
<div class="form-group">
<center><label>Update A New Profile Picture </label></br></center>
<form method="post" action="update_userinfo.php" enctype="multipart/form-data">
<center><img id="uploadPreview4" style="width: 100px; height: 100px;" /></center>
<center><input type="file" name="Filename4" id="uploadImage4" onchange="PreviewImage4();" class="form-group"><input TYPE="submit" name="updateImage" value="Update Image" class="btn btn-success" /></center>
</form>
////
new code
<?php if(isset($photoDeleted) && $photoDelete=== false) :>
<center>Hey! Delete your photo first!</center>
<?php endif; ?>
////
</div>
<div class="col-md-6">
<center><label>Your Current Profile Picture </label></br>
<form method="post" action="update_userinfo.php" enctype="multipart/form-data" onSubmit="if(!confirm('Do You really want to update your profile picture?')){return false;}">
<?php
echo "<img border=\"0\" src=\"".$row['image_path4']."\" width=\"100\" height=\"100\" >";
echo "<br>"; ?>
<input TYPE="submit" name="delete" value="delete" class="btn btn-success" />
</form>
</div>
from your PHP side, check, if there is still a photo in db reload this upload page and pass photoDelete variable as false when it's loading the page php will render this as an error.
But! Wait!
Why don't you just replace/delete the previous photo with the newly updated one in your php?
assuming that there's only one record of profile photo for each user, just update your db record with the newly updated photo and delete the previous record !?
it's a better User Experience overall
I have a form with multiple fields but also a file upload. I am able to upload multiple files.
I also know that it is possible to upload files with AJAX.
So I would like to upload my files using ajax while i'm filling in every other field. But how would I link the already uploaded images then? And also prevent the images to be uploaded again?
This is the form:
<form id="form_validation" method="POST" action="{{route('storeexpense')}}" enctype="multipart/form-data">
{{ csrf_field() }}
<div class="form-group form-float">
<div class="form-line">
<input type="text" class="form-control" name="description" required>
<label class="form-label">Omschrijving</label>
</div>
</div>
<div class="form-group form-float">
<div class="form-line">
<input type="number" class="form-control" name="amount" required>
<label class="form-label">Bedrag</label>
</div>
</div>
<div class="form-group form-float">
#foreach ($types as $type)
#if ($type->id === 1)
<input name="transactiontype" type="radio" id="rdio{{$type->id}}" value="{{$type->id}}" checked />
<label for="rdio{{$type->id}}">{{$type->description}}</label>
#else
<input name="transactiontype" type="radio" id="rdio{{$type->id}}" value="{{$type->id}}" />
<label for="rdio{{$type->id}}">{{$type->description}}</label>
#endif
#endforeach
</div>
<div class="form-group form-float">
<div class="form-line">
<input type="text" class="datepicker form-control" name="date" placeholder="Please choose a date..." required>
<!-- <label class="form-label">Datum</label> -->
</div>
</div>
<div class="form-group demo-tagsinput-area">
<div class="form-line">
<input type="text" class="form-control" id="tagsinput" data-role="tagsinput" placeholder="Labels" name="tags" required>
</div>
</div>
<div class="form-group form-float">
<div class="form-line">
#if (count($errors) > 0)
<ul>
#foreach ($errors->all() as $error)
<li>{{ $error }}</li>
#endforeach
</ul>
#endif
<input type="file" name="attachments[]" multiple class="custom-file-control"/>
</div>
</div>
<button class="btn btn-primary waves-effect" type="submit">SAVE</button>
</form>
This is the PHP code that saves the information from the form:
public function store(UploadRequest $request)
{
// Save new transaction in database
$transaction = new Transaction;
$transaction->description = $request->description;
$transaction->amount = $request->amount;
$input = $request->date;
$format = 'd/m/Y';
$date = Carbon::createFromFormat($format, $input);
$transaction->date = $date;
$transaction->transactiontype_id = $request->transactiontype;
$transaction->user_id = Auth::id();
$transaction->save();
// Put tags in array
$inputtags = explode(",", $request->tags);
// Loop through every tag exists
// EXISTS: get ID
// NOT EXISTS: Create and get ID
foreach ($inputtags as $inputtag)
{
$tag = Tag::firstOrCreate(['description' => $inputtag]);
$transaction->tags()->attach($tag->id); //Put the 2 ID's in intermediate table ('tag_transaction')
}
//Check if there are files
if (!is_null($request->attachments))
{
//Loop through every file and upload it
foreach ($request->attachments as $attachment) {
$filename = $attachment->store('attachments');
// Store the filename in the database with link to the transaction
Attachment::create([
'transaction_id' => $transaction->id,
'path' => $filename
]);
}
}
Thanks,
Bart
It sounds like you want to make a fancy form that starts uploading the file as soon as you choose it and meanwhile the user can continue filling the rest of the form. If so, I'd do it like this:
Implement your main text/data form, eg.
<form method="POST" action="/save-data-endpoint.php">
<input name="email" type="text" />
<button type="submit>Submit</button>
</form>
Next to it, a form for the images. eg.
<form method="POST" class="file-upload-form" action="/save-file.php">
<input name="my-file" type="file" />
<!-- note that we wont show a submit button -->
</form>
For the user, it all looks like the same form but clicking the submit button will send only the data to the save-data-endpoint.php. Now we need some js to control this madness (I'll use jQuery for brevity). But you can use FileReader api in js, ajax progress tracking to make it even fancier. See https://developer.mozilla.org/en-US/docs/Web/API/File/Using_files_from_web_applications for more.
$(function(){ // run when document is ready
// listen when the input changes (when a file is selected)
$('.file-upload-form').on('change', function(e){
// file has been selected, submit it via ajax
// show some kind of uploading indication, eg. a spinner
$.ajax({
type:'POST',
url: $(this).attr('action'),
data: new FormData(this),
cache:false,
contentType: false,
processData: false,
success:function(data){
// the save-file.php endpoint returns an id and/or a url to the saved/resized/sanitized image
console.log(data.id, data.url);
// we then inject this id/url, into the main data form
var $hiddenInput = $('<input type="hidden" name="uploads[]" value="'+data.id+'">');
$('.main-form').append($hiddenInput);
// show a thumbnail maybe?
var $thumbnail = $('<img src="'+data.url+'" width="20" height="20" />');
$('.main-form').append($thumbnail);
// hide spinner
// reactivate file upload form to choose another file
$('.file-upload-form').find('input').val('');
},
error: function(){
console.log("error");
}
});
});
});
Your backend will get the images as they are selected, one by one. You then save them and return an id and/or a url to the image to be used in the success handler in js. After adding some images your main form should look something like this:
<form method="POST" action="/save-data-endpoint.php">
<input name="email" type="text" />
<button type="submit>Submit</button>
<input type="hidden" name="uploads[]" value="x">
<img src="...x.jpg" width="20" height="20" />
<input type="hidden" name="uploads[]" value="y">
<img src="...y.jpg" width="20" height="20" />
</form>
Now when the user fills the remaining fields and clicks submit, your server will get all the data along with an array called uploads which contains all the image ids/paths you have already saved. You can now store this data and relate it to the files.
I wont go deeper on the backend side as it can be implemented on any language. In summary the basic flow would be:
send files one at a time to a save file endpoint that returns a file identifier (can be an id, hash, full path to image, etc)
js injects those ids into the main form
the main form is submitted to a save data endpoint that returns a success or error message and stores + relates all the data in your preferred method of storage.
Hope it helps!
I have a form in which by using javascript and in a while I add content to it.
Denpending on the number of data in database different number of forms are added to the page.
<?php
while($row = mysql_fetch_array ($result)){
?>
<form method="post" accept-charset="UTF-8" >
//add some content to the form by reading from database
<div class="form-group ">
<input type="submit" name="print" id="button" value="print"/>
</div>
</form>
<?php
}//end while
?>
and below I want to redirect to another page when clicked on each "print" button.
But not only it doesn't redirect to another page but also alert just works for the first button.
Below is the code:
<script>
$("#button").click(function(){
alert('hi');
window.location.href = "design_card.php";
});
</script>
how to solve?
jquery, php or javascript solutions are acceptable. other workable solutions, if work, are good.
Thanks for your response in advance.
Check your HTML
<?php
while($row = mysql_fetch_array ($result)){
?>
<form method="post" accept-charset="UTF-8" >
//add some content to the form by reading from database
<div class="form-group ">
<input type="submit" name="print" id="button" value="print"/>
</div>
</form>
<?php
}//end while
?>
You have created multiple <input> element dynamically with duplicate id so the better way is to assign a class to them like
<?php
while($row = mysql_fetch_array ($result)){
?>
<form method="post" accept-charset="UTF-8" >
//add some content to the form by reading from database
<div class="form-group ">
<input type="submit" name="print" class="buttonClass" value="print"/>
</div>
</form>
<?php
}//end while
?>
And then use this buttonClass class as a jquery selector like this
$(".buttonClass").click(function(){
alert('hi');
window.location.href = "design_card.php";
});
Im sorry for my bad english.
Im begineer with PHP and all coding method.
I've been searching this for a days and still cannot find what I need lack to my understanding especially with php, java or ajax.
I have an emailmeform form and I have my own form on 1 php file which I want when client submit the send button, it will save the data entered previously by client to my internal database and send it to emailmeform in the same time but I cannot make this happen.
The solution I think will work is maybe ajax or javascript, but since lack of my knowledge with those codes I cannot solve this issue by my self.
Here's my code (all in 1 php script page):
<?php
session_start();
include "connection/database.php";
$sql = mysql_query("SELECT * from tb_config");
$config = mysql_fetch_array($sql);
if (isset($_POST['send'])) {
$username = $_POST['element_1'];
$password = $_POST['element_2'];
$referral = $_POST['referral'];
$a = mysql_num_rows(mysql_query("SELECT * from tb_member where username='$username'"));
if (empty($username) || empty($password)) {
echo "<script> alert('Please fill all the required form!!'); </script>";
} else if (strlen($_POST['element_2']) < 6) {
echo "<script> alert('Password at least 6 digit!!!'); </script>";
} else {
$save = mysql_query("insert into tb_member(username,password) values ('$username','$password')");
exit;
}
}
?>
<!-- this is emailmeform scipt -->
<form id="emf-form" target="_parent" class="leftLabel" enctype="multipart/form-data" method="post" action="http://www.emailmeform.com/builder/emf/to/ref">
<div id="emf-form-description"><h2>Form Register</h2></div>
</div>
<ul>
<li id="emf-li-0" class="emf-li-field emf-field-text data_container ">
<label class="emf-label-desc" for="element_0">Your Name</label>
<div class="emf-div-field"><input id="element_0" name="element_0" value="" size="30" type="text"
class="validate[optional]"/><div class="emf-div-instruction">Please fill your name</div></div>
<div class="emf-clear"></div>
</li><li id="emf-li-1" class="emf-li-field emf-field-text data_container ">
<label class="emf-label-desc" for="element_1">Username <span>*</span></label>
<div class="emf-div-field"><input id="username" name="element_1" value="<?php if (isset($_POST['element_1'])) { echo $_POST['element_1']; } ?>" size="30" type="text"
class="validate[required,length[6,15]]"/><div class="emf-div-instruction">At least 6 characters</div></div>
<div class="emf-clear"></div>
</li><li id="emf-li-2" class="emf-li-field emf-field-text data_container ">
<label class="emf-label-desc" for="element_2">Password <span>*</span></label>
<div class="emf-div-field"><input id="element_2" name="element_2" value="" size="30" type="text"
emf_mask_input="true"
class="validate[required,length[6,]]"/><div class="emf-div-instruction">At least 6 characters</div></div>
<li id="emf-li-post-button" class="middle">
<input value="Send" type="submit" name="send" onmouseover="return true;"/>
</li>
</ul>
<input name="element_counts" value="14" type="hidden" />
<input name="embed" value="forms" type="hidden" />
</form>
This script works and send to emailmeform, but wont submit any data to my internal database, BUT IF I change the action button to
<form method="post" action="">, this will submit to my internal database but not send to emailmeform. I want this work together, submit to my database and send it also to emailmeform.
I have struggling with this and still not found the answer.
Kindly please help.
Any help will be appreciated
Thanks
Refer this, it will demostrate how to insert data in database
I am creating an application that utilizes JQuery Mobile and PHP, nothing crazy here. I am trying to update a $_POST[''] variable on the page I am currently viewing.
The user clicks on an "Issue_Title" to add "Issue_Txt" to that particular list. So I need a way to know which issue_title the user clicks on so I can add it to the right place. To solve that when I retrieve the issue_title from mySQL table I format like so (testTitle is just a placeholder for debugging...I want $row['issue_title'] there so I can distinguish which title was clicked):
echo "<li data-role='fieldcontain'>"."".$row['issue_title']."</li>";
So onclick it will run the below JS function:
function NewIssueTxt(issue_title)
{
var combined = {'issue_title' : issue_title};
combined = $('#HiddenIssueTxtForm').serialize() + '&' + $.param(combined);
$.ajax({type:'POST', url: 'NewRoundDetails.php', data: combined, success: function(response){ }});
return false;
};
I can see via Javascript Console that this is POSTing as expected when I click the listview link. This should give me a $_POST['issue_title'] that I can use to submit along with the issue_txt which is all captured in the below form...which is a popup form that also appears when the user clicks the Issue_Title href.
<div data-role="popup" id="popupNewIssueTxt" data-history='false' data-theme="a" class="ui-corner-all">
<form id="NewIssueTxtForm" action="/NewRoundDetails.php" onsubmit="return submit_popupNewIssueTxt();" method="post">
<div style="padding:10px 20px;">
<h3>Issue Text:</h3>
<label for="issue_txt" class="ui-hidden-accessible">Issue Text:</label>
<input type="text" name="issue_txt" id="issue_txt" value="" />
<label for="issue_title" class="ui-hidden-accessible">Issue Title</label>
<input type="hidden" name="issue_title" id="issue_title" value="<?php echo $_POST['issue_title']; ?>"/>
<label for="date" class="ui-hidden-accessible">Date:</label>
<input type="hidden" name="date" id="date" value="<?php echo $_POST['date']; ?>"/>
<label for="dept_name" class="ui-hidden-accessible">Department Name:</label>
<input type="hidden" name="dept_name" id="dept_name" value="<?php echo $_POST['dept_name']; ?>"/>
<label for="participants" class="ui-hidden-accessible">Participants:</label>
<input type="hidden" name="participants" id="participants" value="<?php echo $_POST['participants']; ?>"/>
<label for="issue_category" class="ui-hidden-accessible">Issue Category:</label>
<input type="hidden" name="issue_category" id="issue_category" value="Work Environment"/>
<button id="NewIssueTxtButton" form="NewIssueTxtForm" type="submit" data-theme="b">Add</button>
</div>
</form>
As mentioned I confirmed the JS function is working...except I still have no value for $_POST['issue_title']. What am I doing wrong? Is the JS function not submitted fast enough...so I click the Issue_title but my form is opened before the POST happens? If that's the case how else can I get the href clicked into a usable variable?
To reiterate: I'm populating a listview with data from a mySQL DB. I need a way of knowing which link or listview is clicked so I can POST it along with other form data.