Its sounds simple, but let me explain.
I make ajax calls to update the body content and I want to alert if the updating fails in the client side, I mean after receiving response from ajax and if it fails of anycase.
$(".body").html(response_from_ajax) ;
so I tried with my basic knowledge like this
if ( ! $(".body").html(response_from_ajax) )
{
alert('error');
}
this is not working.
I don't think it can fail after getting the content from ajax call because you are just setting the html of the div. However, you can simply define the error method in the ajax call to make sure that data is recieved from the ajax call.
Related
Suppose I have a page called form.php. I then clicked a button called "add button". This button triggers an event that got detected by a jquery function. The jquery function makes an ajax call to add.php.
Inside add.php, there is code that checks if a particular record exist in the database. If it does find that the record exists, I want to do the following.
Send a response string "exist" to ajax.
The ajax, inside the .done() function, will execute a prompt that says "This record already exist, do you wish to overright"?
If the user canceled the prompt, nothing more should happened and the ajax call should be done.
If the user clicks "ok", I would like the php script to be notified of this and execute an update statement using the data from form.php.
I suspect this is impossible because after receiving a response from php, AFAIK there is no way for ajax to respond back to the php script that is currently executing.
Am I correct or there is a way to do this?
You have to add a parameter to your ajax request, like override with true and false. By default/first request you set it to false. Then the add.php does it's default and returns exists.
The the user makes his decision. If he want to override, you send the ajax request again with the override parameter to true. Your add.php will notice the parameter and does whatever it has to do.
Wrap your ajax handler in an own function with a done callback. So you can reuse the request as often as you want. Pretty easy, no double code needed as well ...
The .done() function of your first ajax call executes when the ajax call has finished successfully, so when your php script has finished completely.
If you want to do something else, you would need to make a new ajax request. That could be to the same or another script, sending in different / new / additional parameters.
Note that you have to make sure that the second script cannot be called without the first one finishing, for example by setting and checking an expiring session variable.
you can do something like this.
$.post('add.php',$(this).serialize())
.done(function(result){
var r = confirm("This record already exist, do you wish to overright");
if(result == 'exist'){
if (r == true) {
$.post('update.php',$(this).serialize()).done(function(r){
console.log(r);
});
} else {
return false;
}
}else{
console.log(result)
}
});
i am trying to display the data fetched from database in the loop and between loop i call the function and send ajax request its not working.Actually its displays the only if i used alert command. If i used alert then the browser display the div and then alert if i clicked ok then it displays the second div then again show alert.
Here is the js code
function like(divid,id,session) {
var orgnldiv=document.getElementById(divid);
var ndiv=document.createElement('DIV');
var idd=id+5000;
ndiv.id =idd;
ndiv.className="likeclass";
orgnldiv.appendChild(ndiv);
var dynamicdiv=document.getElementById(idd);
var span=document.createElement('span');
var spanid=idd+5000;
span.id=spanid;
span.className="spanclass";
dynamicdiv.appendChild(span);
var xmllhttp15;
if (window.XMLHttpRequest) {
xmlhttp15=new XMLHttpRequest();
} else {
xmlhttp15=new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp15.onreadystatechange = function() {
if (xmlhttp15.readyState==4 && xmlhttp15.status==200) {
document.getElementById(spanid).innerHTML=xmlhttp15.responseText;
}
}
xmlhttp15.open("GET","spancount.php?postid="+id+"&userid="+session);
xmlhttp15.send();
// alert(spanid);
}
please suggest me what can be the reason of this problem my code is working well only if i use alert
The reason why your code works when you use alert is because whenever the alert function is called. The program flow is paused. In other words, your loop wont continue to make another Ajax call until you dismiss the alert.As a result, the request gets handled properly and the response data appears in the span div. that is why I had mentioned to make your calls synchronous instead.
So to answer the question you asked in the comment, Yes at times too many Ajax calls can be a problem. Let's say that the loops runs more than 15-20 times, that means 15-20 simultaneous requests. Now, think about the number of times the same request is being handled by the php script? Definitely a problem here!
Even with Jquery Ajax, the chances of the loop completing successfully is also 50-50 actually because it all boils down to the amount of requests being made , the bandwidth being used and how the request is being processed at the server.
One possible way to fix this problem is : Rather than constantly requesting small peices of data again and again from the server in the loop, Make one Ajax call and get the entire data as json. Then, parse the json and append data to the spans by using the particular span id to extract the relevant data from the json object.
You might have to do a little bit of tweaking in both the above javascript and spancount.php . But it will definitely Save you A LOT of bandwidth. You gotta consider the fact that more than one person could be using your site!!
Hope that cleared up things, all the best with your project :D
I'm experiencing some extremely weird behavior with Ajax. Or maybe it's normal. I wouldn't know. I'm quite new to playing around with Ajax.
My problem is that I am making a few Ajax calls(two using $.post() and one using the standard $ajax() call), and they seem to return the data fine, but the code inside the success function only works in a very peculiar way.
I have noticed that some things work if placed first in line to be executed; but why is that? It really doesn't make any sense to me. In this case I would like the span with the id link_span to be updated dynamically, as my Ajax calls link and unlink devices from each other.
(the correct_classes function counts how many links have been linked and adds it to the link_counter variable that I've made global with the window object).
But as the span only wants to update if the corresponding code is placed on top, it's kinda useless.
Another problem is also that .ajaxComplete() and other such event handlers don't always get called. For example, I attempted to show and hide a loader gif by using .ajaxComplete() to close it when ajax stop. But this only works with one of my calls which is the standard $.ajax call.
I'm really confused.
Any help would be great, and please ask me to clarify if there's something I haven't made clear enough.
Here is a small snippet of what I'm talking about:
$.post( "<?php echo base_url(); ?>connections/ajax_link", datax).done(function( resp,status ) {
$("#loader_overlay").css('display','none');
display_confirmbox();
resp=JSON.parse(resp);
var str = resp['parent_selector'];
var arr = mystr.toString().split("||");
correct_classes(arr[1], resp);
$( '#link_span' ).text( '( ' + window.link_counter + ' ) links found' ); //this doesnt work unless its on top
});
Update
It seems that the problem is caused by correct_classes();
the array from the ajax call gets passed to the function in which jQuery complains about something, and causes the rest of the ajax code to halt. Yet everything inside correct_classes() gets executed. The error in question is this:
TypeError: invalid 'in' operand e
specifically what is causing the problem seems to be this(i commented everything else out and this is:
$.each( val, function( i, value ) {
var mystr = value;
}
I really cant figure out why it complains about this code when it seems to work.
i'm not sure to have understand your problem.... but if you use 3 async ajax call ($.post or $.ajax is indifferent $.post is a contract syntax to call $.ajax({type:"post"})) you need to wait the full loading of all calls for use their response.
so.. if one of your call evalue window.link_counter you need to wait his response before call the code you have post.
For wait the complete load you may nast the call inside the success function of the prev call.
for you knowlage there is an attribute of $.post() dataType if you set it to "json" you not need to parse the response because Jquery do it for you, this code is useless:
resp=JSON.parse(resp);
and, the method .done() is calling whether the call is successful if it fails, $.post() has a success function callback. Use it, it's better, and use .fail() to catch call error.
See documentation about $.post(): here
however... the element who have this id #link_span is generated by one of ajax call?
i am really banging my head here for more then a day, i am trying to send a request and get the response from another site. i'm doing it with jsonp (from the obvious reason). but the response is not a JavaScript function definition, so it keeps failing.
can anyone in this planet help me get the response the right way.
i attached the code i wrote, again: because the response is not in json it's not working. (try to run it yourself and you'll see).
any suggestions?
<script>
function test()
{
$.ajax({
dataType: 'jsonp',
jsonp: 'jsonp_callback',
url: 'https://www.facebook.com/ajax/typeahead/first_degree.php?viewer=1000009843914&token=1-1&filter[0]=user&options[0]=pending_request&lazy=1&token=v7&stale_ok=1&__a=1&__user=1000009843914& viewer=1000009843914',
});
}
function jsonp_callback(data)
{
var val=JSON.stringify(data);
myString = val.slice( 11 );
$('#container').html(myString);
/*for (;;);*/
}
test();
</script>
The server must be programmed to include the JSONP callback within its script file. If it only knows to return JSON, it will have no effect when the dynamic script tag is inserted into the page since JSON can at most provide an object--but it won't go anywhere unless the same file calls the function. In this way, it is different from Ajax, since a dynamically inserted script tag can only interact with your own code if it knows to call one of your functions. Just as an example, it might return:
jsonp_callback({facebooKData:[...]});
You should investigate how the Facebook API supports JSONP (not just JSON) for whatever you are trying to do. Typically APIs will accept a "callback" variable to determine which callback function it should use (which jQuery handles for you).
I have a problem wit a $.post request. No errors, but the return is empty. Before I start bugging the server admin, of who the service is, with this problem. I want to make sure I did not make any mistake myself.
Below the code I'm using:
var post_data = JSON.stringify({'str_action':'log_element', 'int_id':'TEST', 'str_value':'EMPTY'});
$.post('http://url/', post_data, debug_return_data);
function debug_return_data(data)
{
alert(data);
}
Problem is that the returned data in the alert is empty. Did I make any mistake in my code?
Thanks in advance.
The Ajax call looks correct, check the response in firebug or chrome dev tools to make sure the server is actually returning data.
If you are making the AJAX call to anther server other than the one in the address bar it will be blocked as a cross-domain call. Use JSONP if you want to do this:
http://devlog.info/2010/03/10/cross-domain-ajax/
$.post('http://url/', post_data, function(data)
{
alert(data);
});
this is in the jquery documentation