I have a form.
<form action="form.php" method="POST" name="form1" id="f1">
On this form is an input for a name.
<input type="text" class="form-control" id="n1" placeholder="Name" required>
The user inputs their name and clicks submit, the form.php then kicks in and this name is emailed to an email address.
$name = $_POST['n1'];
If this is successful the user is redirected to another page via;
header("Location: /anotherpage.html");
Up to this point everything works fine.
On this page is a HTML table with a table data cell;
<td id="table1"></td>
Q. What I am trying to do is when the user is redirected to this page the name they submit appears in the tables data cell.
I have tried a couple of things with no success.
On the HTML side;
value="<?php echo $name;?>" & value="<?php echo $_POST['n1'];?>" within the td tag.
<?php echo $name;?> & <?php echo $_POST['n1'];?> between the td tags.
& on the PHP side after the redirect header;
getElementById('n1').value = $name;
getElementById('n1').value = $_POST['n1'];
Is there a way of doing this?
Look forward to hearing from anyone
Kind Regards
You can send the name over the url using the header using PHP...
// check the submission of your form using the name set in the submit button...
if(isset($_POST['submit'])){
// DO NOT SKIP ON SANITIZING YOUR INPUTS!!!!!
// This example is very basic, I am not showing how to sanitize inputs
$fname = filter_var(strip_tags($_POST['fname'], FILTER_SANITIZE_STRING));
$lname = filter_var(strip_tags($_POST['lname'], FILTER_SANITIZE_STRING));
// do your email stuff
// after you have done all your other code, send the name
// key/value pair over the url using the header...
header("Location: someotherpage.html?fname=".fname ."&lname=".lname);
}
Once you have sent the values over the url to the someotherpage.html page you can use URLSearchParams to search the url for key parameters to get their paired value/s. window.location.search => The query string portion of the URL. This includes the question mark, and everything following. Use .get() to get the url's parameters using their key. Then you can assign them using javascript with the dataset attribute => element.dataset.fname = firstName.
let parameters = new URLSearchParams(window.location.search);
let firstName = parameters.get('fname');
let lastName = parameters.get('lname');
let div = document.getElementById('data');
div.dataset.fname = `${firstName} ${lastName}`;
Returns the following on someotherpage.html :
I think that this problem occurs often on a web application development. But I'll try to explain in details my problem.
I'd like to know how to correct this behavior, for example, when I have a block of code like this :
<?
if (isset($_POST['name'])) {
... operation on database, like to insert $_POST['name'] in a table ...
echo "Operation Done";
die();
}
?>
<form action='page.php' method='post' name="myForm">
<input type="text" maxlength="50" name="name" class="input400" />
<input type="submit" name="Submit" />
</form>
When the form gets submitted, the data get inserted into the database, and the message Operation Done is produced. Then, if I refreshed the page, the data would get inserted into the database again.
How this problem can be avoided? Any suggestion will be appreciated :)
Don't show the response after your create action; redirect to another page after the action completes instead. If someone refreshes, they're refreshing the GET requested page you redirected to.
// submit
// set success flash message (you are using a framework, right?)
header('Location: /path/to/record');
exit;
Set a random number in a session when the form is displayed, and also put that number in a hidden field. If the posted number and the session number match, delete the session, run the query; if they don't, redisplay the form, and generate a new session number. This is the basic idea of XSRF tokens, you can read more about them, and their uses for security here: http://en.wikipedia.org/wiki/Cross-site_request_forgery
Here is an example:
<?php
session_start();
if (isset($_POST['formid']) && isset($_SESSION['formid']) && $_POST["formid"] == $_SESSION["formid"])
{
$_SESSION["formid"] = '';
echo 'Process form';
}
else
{
$_SESSION["formid"] = md5(rand(0,10000000));
?>
<form action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]); ?>" method="post">
<input type="hidden" name="formid" value="<?php echo htmlspecialchars($_SESSION["formid"]); ?>" />
<input type="submit" name="submit" />
</form>
<?php } ?>
I ran into a similar problem. I need to show the user the result of the POST. I don't want to use sessions and I don't want to redirect with the result in the URL (it's kinda secure, I don't want it accidentally bookmarked). I found a pretty simple solution that should work for the cases mentioned in other answers.
On successfully submitting the form, include this bit of Javascript on the page:
<script>history.pushState({}, "", "")</script>
It pushes the current URL onto the history stack. Since this is a new item in history, refreshing won't re-POST.
UPDATE: This doesn't work in Safari. It's a known bug. But since it was originally reported in 2017, it may not be fixed soon. I've tried a few things (replaceState, etc), but haven't found a workaround in Safari. Here are some pertinent links regarding the issue:
Safari send POST request when refresh after pushState/replaceState
https://bugs.webkit.org/show_bug.cgi?id=202963
https://github.com/aurelia/history-browser/issues/34
Like this:
<?php
if(isset($_POST['uniqid']) AND $_POST['uniqid'] == $_SESSION['uniqid']){
// can't submit again
}
else{
// submit!
$_SESSION['uniqid'] = $_POST['uniqid'];
}
?>
<form action="page.php" method="post" name="myForm">
<input type="hidden" name="uniqid" value="<?php echo uniqid();?>" />
<!-- the rest of the fields here -->
</form>
I think it is simpler,
page.php
<?php
session_start();
if (isset($_POST['name'])) {
... operation on database, like to insert $_POST['name'] in a table ...
$_SESSION["message"]="Operation Done";
header("Location:page.php");
exit;
}
?>
<html>
<body>
<div style='some styles'>
<?php
//message here
echo $_SESSION["message"];
?>
</div>
<form action='page.php' method='post'>
<!--elements-->
</form>
</body>
</html>
So, for what I needed this is what works.
Based on all of the above solutions this allows me to go from a form to another form, and to the n^ form , all the while preventing the same exact data from being "saved" over and over when a page is refreshed (and the post data from before lingers onto the new page).
Thanks to those who posted their solution which quickly led me to my own.
<?php
//Check if there was a post
if ($_POST) {
//Assuming there was a post, was it identical as the last time?
if (isset($_SESSION['pastData']) AND $_SESSION['pastData'] != $_POST) {
//No, Save
} else {
//Yes, Don't save
}
} else {
//Save
}
//Set the session to the most current post.
$_session['pastData'] = $_POST;
?>
We work on web apps where we design number of php forms. It is heck to write another page to get the data and submit it for each and every form. To avoid re-submission, in every table we created a 'random_check' field which is marked as 'Unique'.
On page loading generate a random value and store it in a text field (which is obviously hidden).
On SUBMIT save this random text value in 'random_check' field in your table. In case of re-submission query will through error because it can't insert the duplicate value.
After that you can display the error like
if ( !$result ) {
die( '<script>alertify.alert("Error while saving data OR you are resubmitting the form.");</script>' );
}
No need to redirect...
replace die(); with
isset(! $_POST['name']);
, setting the isset to isset not equal to $_POST['name'], so when you refresh it, it would not add anymore to your database, unless you click the submit button again.
<?
if (isset($_POST['name'])) {
... operation on database, like to insert $_POST['name'] in a table ...
echo "Operation Done";
isset(! $_POST['name']);
}
?>
<form action='page.php' method='post' name="myForm">
<input type="text" maxlength="50" name="name" class="input400" />
<input type="submit" name="Submit" />
</form>
This happen because of simply on refresh it will submit your request again.
So the idea to solve this issue by cure its root of cause.
I mean we can set up one session variable inside the form and check it when update.
if($_SESSION["csrf_token"] == $_POST['csrf_token'] )
{
// submit data
}
//inside from
$_SESSION["csrf_token"] = md5(rand(0,10000000)).time();
<input type="hidden" name="csrf_token" value="
htmlspecialchars($_SESSION["csrf_token"]);">
I think following is the better way to avoid resubmit or refresh the page.
$sample = $_POST['submit'];
if ($sample == "true")
{
//do it your code here
$sample = "false";
}
I am new to AJAX and am in the process of converting some regular HTML forms to AJAX.
My existing implementation is as follows - form (on page1.php) posts to page2.php which does some validation on post data and redirects to an error page if something is missing. If the input is fine, it includes page3.php which processes the request and redirects back to page1.php.
php/page1.php
<form method="post" action="/php/page2.php" >
<input type="text" name="input1" placeholder="Howdy..." />
<input type="text" name="input2" placeholder="Howdy..." />
<input type="submit" value="Submit" />
</form>
php/page2.php
<?php
// perform some validation on inputs
if (empty($_POST['input1']))
{
$location ='Location: /php/error.php';
header($location);
exit;
}
// Inputs are fine
include('/php/page3.php');
?>
page3.php
<?php
// do some form processing
// redirect back to page1.php
$location = 'Location: /php/page1.php";
header($location);
exit;
?>
To convert to AJAX, I am using #SSL's solution on this SO link How to show loading gif when request goes Ajax
http://jsfiddle.net/clickthelink/Uwcuz/1/
The error from validation and success page are both displayed back on page1.php via the callback function.
php/page2.php
<?php
// perform some validation on inputs
if (empty($_POST['input1']))
{
// Echo erorr code isntead of redirect
echo "Please enter input1";
return;
//$location ='Location: /php/error.php';
//header($location);
//exit;
}
// Inputs are fine
include('/php/page3.php');
?>
page3.php
<?php
// do some form processing
// Echo success instead of redirect
echo "SUCCESS";
// redirect back to page1.php
//$location = 'Location: /php/page1.php";
//header($location);
//exit;
?>
This part is working fine.
My question (finally) is how do I handle users who have javascript disabled? I know the form will get submitted appropriately but I wont get the redirect back in case of the error or success. I would like to retain header() redirect type of functionality in this case also. Is this possible? I would appreciate the help.
You want to detect if this is an xhr request, and default to the non-ajax behavior if it is not.
I would look at $_SERVER['HTTP_X_REQUESTED_WITH']
Keep your current form setup as-is, if it is working for you without javascript.
For javascript enabled browsers you can hijack the 'submit' event on the form. Capture the event and post the form, via ajax, to scripts/pages that handle and return the data in a javascript-friendly format for final consumption.
For example, using jquery:
<form method="post" action="/php/page2.php" id="js-form" >
<input type="text" name="input1" placeholder="Howdy..." />
<input type="text" name="input2" placeholder="Howdy..." />
<input type="submit" value="Submit" />
</form>
<script>
$(document).ready(function(){
$('#js-form').on('submit',function(e){
// logic to submit ajax form and handle response
// return false to cancel native browser form submission.
return false;
});
});
</script>
Another idea is to keep the pages you already have, but send a flag with the ajax request to disable the browser redirect headers. For example, add 'src=ajax' when submitting the form via ajax. Then in the script use logic to say:
<?php
if( !empty($_REQUEST['src'] && $_REQUEST['src'] == 'ajax' ) {
// add redirect logic here.
}
?>
I'm making a simple todo list: http://jsbin.com/pemeqeni/1/edit?html,output
I want to be able to email myself the list, and I'm wondering how to do this with PHP specifically. I thought about scraping the HTML with DOMdocument, but I think that will only get the content from the static HTML page, which will never have list items. My other idea is to dynamically create a bunch of hidden input fields in the emailForm and dynamically delete them just as I do with the list items. Are there any other options? What's the standard protocol for something like this?
Something like this should work for getting all list elements.
<script>
function getEachListElement() {
var testList = document.getElementsByClassName("todoBody");
for (var i = 0; i < testList.length; i++) {
document.writeln(testList[i].innerHTML);
}
}
</script>
Try it out by changing your form action to this
<form name="emailForm" method="GET" action="JavaScript:getEachListElement()">
Then you can just create a string that you pass to PHP to email to yourself.
Have you tried the php mail function?
ie
<?
mail( $email, $subject , $text );
?>
Instead of get I would use post then set up a php script you call where you put your values(strings) into variables using $_post and use the mail function to mail those variables(strings).
just to be more clear your html would look like this
<form name="emailForm" method="POST" action="getContent.php">
<input type="text" name="email" value="email"><input type="submit" value="send">
</form>
Your getContent.php would then look like this
<?
$myemail = "myemail#tada.com";
$email = $_POST["email"];
mail ($myemail, 'The shiz you wanted', $email);
?>
I a have PHP form where I collect a bunch of values from text inputs, but for one input I have the input filled in via javascript (user selects a date from a calendar, that date then populates a text input). I've setup a simplified version of this:
<?php
$displayForm = true;
if ($_POST['submitFlag'] == 1) {
// Form was submitted. Check for errors and submit.
$displayForm = false;
$installationTime = $_POST['installation-time'];
// send e-mail notification
$recipients = "test#test.com";
$subject = "Test Email - Test Form Submission";
$message = wordwrap('Someone has filled out the secure form on test.com. Here\'s what they had to say:
Installation Time: ' . $installationTime .'
');
$headers = "From: test#test.com";
mail($recipients, $subject, $message, $headers);
// Output thank you message
?>
<h2>Thank You!</h2>
<?php if($installationTime == NULL){echo 'test failed: value submitted was null.';}else{echo 'test passed: value submitted was not null.';} ?>
<p>Your form has been submitted. Thank you for your interest in test.com.</p>
<?php
}
if ($displayForm) {
// If form was not submitted or errors detected, display form.
?>
<div class="note"><span class="required">*</span> Click me to set value of input.</div>
<form name="contactForm" id="contactForm" method="post" enctype="multipart/form-data" action="<?php echo $_SERVER['PHP_SELF']; ?>?state=submit">
<label for="installation-time" class="service-time">The time you have selected for installation is: <span class="required">*</span></label>
<input type="text" name="installation-time" id="installation-time" disabled value="<?php echo $_POST['installation-time']; ?>" />
<input type="hidden" name="submitFlag" id="submitFlag" value="1" />
<input type="submit" name="submit" id="submit" value="Sign-Up" />
</form>
<?php
} // End of block displaying form if needed.
?>
And then in jQuery I do one of these:
$('.note').click(function(){
$('#installation-time').val('test string');
});
When I submit the form, the PHP variable that's supposed to collect that value is null. Every other input in the form works, and if I remove the javascript and manually enter the exact same text that I had set with JavaScript into the input it works as well.
The question really is why populating a field with javascript as opposed to manually typing the exact same string into a text input would break things. Again there are no errors and the input is populated correctly on the front end. Somehow posting the form just doesn't pick up on the value when it's set by javascript vs. typed manually. There has to be something really fundamental I'm missing here.
Any idea what's going on here? I've spent hours puzzling over this to no avail.
Update:
Code updated, test page:
http://dev.rocdesign.info/test/
Solution: can't post a disabled input. I actually tested that back in the beginning and must have missed that removing the "disabled" on the input made it work, so I mistakenly ruled it out and moved on.
Thanks for the responses everyone. And for anyone else with this problem: use a hidden input to post the value.