Develop Reference

How do I submit this form without page reload?

So basically I have this interest slider plugin that calculates the repayments on a loan over a certain period of time - https://loancalc.000webhostapp.com/
But the problem I am having is submitting the form without reloading the page, currently you enter your name and email.
I have included this ajax script on line 1146 of slider.js but the slider continues to reload the page when submitting the form.
I am told it could be because i'm not enqueuing the script (for wordpress) properly.
jQuery('.qis-register').on('submit', 'input', function(){
event.preventDefault();
var name = $("input#yourname").val();
var email = $("input#youremail").val();
if (name == ""){
$("input#yourname").focus;
return false;
}
else if (email == ""){
$("input#youremail").focus;
return false;
}
else{
jQuery.ajax({
type: "POST",
url: "quick-interest-slider.php",
data: {
name:name,
email:email,
qissubmit:$(".qissubmit").val(),
qisapply:$(".qisapply").val(),
part2submit:$(".part2submit").val(),
},
done: function(msg){
console.log(msg);
}
});
}});
The full code is here (slider.js, quick-interest-slider.php, register.php) - https://github.com/Curnow93/quick-interest-slider/tree/master/quick-interest-slider

There's no submit event on the input. It should be on the form. Also, you need to pass the event to the callback function.
jQuery('.qis_form').on('submit', function(event) {
Also your selector doesn't select anything. I have updated it using the right selector.

submit form with ajax validation jquery / standard javascript

I'll start with an apology - I'm a .NET coder with little (no) front-end experience.
When the user clicks on Submit, the form needs to call a REST service, if the service returns true then the user is presented with a warning that a duplicate exists and are asked whether they want to continue. Appreciate any help.
I have the Submit button ONCLICK wired up to Approve()
When the checkForDuplicateInvoice() gets called, it passes the control back to the calling function right away before the ajax call has a chance to get the result. The effect is that the Validate() function finishes without taking into account whether or not a duplicate invoice exists.
I need help in modifying the form so that when the user clicks on the submit button, the form validates (including the ajax call to the db) before finally submitting.
I've modified the code based on Jasen's feedback.
I'm including https://ajax.googleapis.com/ajax/libs/jquery/2.1.4/jquery.min.js in my header.
The error I get now is "Object doesn't support property or method 'button'"
What I have now for my form submission/validation is:
$(document).ready(function () {
$("#process").button().click( function () {
if (ValidateFields()) { // internal validation
var companyCode = document.getElementById("_1_1_21_1").value;
var invoiceNo = document.getElementById("_1_1_25_1").value;
var vendorNo = document.getElementById("_1_1_24_1").value;
if (vendorNo == "undefined" || invoiceNo == "undefined" || companyCode == "undefined") {
return false;
}
$.ajax({ // external validation
type: "GET",
contentType: "application/json;charset=utf-8",
//context: $form,
async: false,
dataType: "jsonp",
crossDomain: true,
cache: true,
url: "http://cdmstage.domain.com/services/rest/restservice.svc/CheckDuplicateInvoice?InvoiceNumber=" + invoiceNo + "&VendorNumber=" + vendorNo + "&CompanyCode=" + companyCode,
success: function (data) {
var result = data;
var exists = result.CheckForInvoiceDuplicateResult.InvoiceExists;
var valid = false;
if (exists) {
if (confirm('Duplicate Invoice Found! Click OK to override or Cancel to return to the form.')) {
valid = true;
}
}
else {
valid = true; // no duplicate found - form is valid
}
if (valid) {
document.getElementById("_1_1_20_1").value = "Approve";
doFormSubmit(document.myForm);
}
},
error: function (xhr) {
alert(xhr.responseText);
}
});
}
});
});

First review How do I return the response from an asynchronous call? Understand why you can't return a value from the ajax callback functions.
Next, disassociate the submit button from the form to prevent it from performing default submission. Test it to see it does nothing.
<form>
...
<button type="button" id="process" />
</form>
Then wire it up to make your validation request
$("#process").on("click", function() {
if (valid()) {
$(this).prop("disabled", true); // disable the button to prevent extra user clicks
// make ajax server-side validation request
}
});
Then you can make your AJAX request truly asynchronous.
$.ajax({
async: true,
...,
success: function(result) {
if (exists) {
// return true; // returning a value is futile
// make ajax AddInvoice call
}
}
});
Pseudo-code for this process
if (client-side is valid) {
server-side validation: {
on response: if (server-side is valid) {
AddInvoice: {
on response: if (successful) {
form.submit()
}
}
}
}
}
In the callback for the server-side validation you make the AddInvoice request.
In the callback for AddInvoice you call your form.submit().
In this way you nest ajax calls and wait for each response. If any fail, make the appropriate UI prompt and re-enable the button. Otherwise, you don't automatically submit the form until both ajax calls succeed and you call submit() programmatically.

I want the same form page when error is raised instead of alert message

//This is my function which invokes when my form is submitted
$('#addDataBtn').click(function(){
//here im going to add all my form data to a variable
var fd = {};
fd["orgId"]=$('#orgId').val();
fd["orgSystem"]=$('#orgSystem').val();
fd["hostName"]=$('#hostName').val();
fd["systemId"]=$('#systemId').val();
fd["instanceNo"]=$('#instanceNo').val();
fd["client"]=$('#client').val();
fd["username"]=$('#username').val();
fd["password"]=$('#password').val();
fd["language"]=$('#language').val();
fd["createdBy"]= $('#createdby').val();
fd["updatedBy"]= $('#updatedby').val();
//here im making a ajax call and posting my form data
$.ajax({
url : './add-org-sap-info.gis',
type: 'POST',
data:JSON.stringify(fd),
dataType: 'json',
contentType: "application/json; charset=utf-8",
//this is my logic when i submit a valid form this function will be working
success :function(res){
if(res != null && res=="success"){
$.ajax({
url : './org-sap-info.gis',
type: 'POST',
success :function(res){
if(res != null && res.length > 0)
$('#totbody').html(res);
},
error:function(){
alert("There is someting error at server side.");
}
});
}
//here if i have any errors it should return a alert message
else{
alert(res);
return false;
}
},
// and even here if i fail to submit a valid form this should show me a alert message
The problem is when I'm submitting the empty form it should give me the same form instead of giving me the alert message, can someone tells me how can I get the same form page instead of getting the alert message.
As I'm using spring annotation based validations when I submit the invalid form, I should get the errors messages instead of alert message, all my java code is working well but I'm getting problem in the jsp file.
Can someone tell how it get my validation error mesages?
error:function(){
alert("There is something error at server side.");
}
});
});

Prevent form submission in jQuery by ID

I am using jQuery Ajax function to check the existence of user email in the database on jquery change function. in Ajax responsive there are two possibilities that either user email exists or not. If it exists it shows the error message. Now I wanted to prevent the form from submitting if the Ajax responsive is false
jQuery("#userEmail").change(function(){
//my code goes here
if(result == 'False'){
//prevent form here
}
else {
// else condition goes here
}
});

You can put a global variable like
emailValidated = false
And on
jQuery("#userEmail").change(function(){
//my code goes here
if(result == 'False'){
emailValidated = false;
}
else {
// else condition goes here
emailValidated = true;
}
});
After that on form submit check the value of the emailValidated variable.
$(form).submit(function(){
if(emailValidated) {
this.submit();
}
else {
return false;
}
})

Use e.preventDefault() to prevent form from submission.
jQuery("#userEmail").change(function(e){
if(result == 'False'){
e.preventDefault();
}
else {
}
});

Do something like this:
var result;
$.ajax({
url: url,
// Put all the other configuration here
success: function(data){
if(data == something) // replace something with the server response
result = true; // Means that the user cannot submit the form
},
});
$('#formID').submit(function(){
if(result){
alert('Email already exists.');
return false;
}
});

Steps are like :
get the email value passed by the user from input field in Jquery.
The POST that data to your PHP query file and get the response data on "success: function(data)" function of jquery.
Display that data data on the page..
Check below link for a reference.
http://www.sitepoint.com/jquery-ajax-validation-remote-rule/

You need use the submit event handler:
jQuery("#userEmail").closest("form").submit(function(event){
var $email = jQuery("#userEmail", this);
//the email field is not `this`, but `$email` now.
//your code goes here
if(result == 'False'){
event.preventDefault();
}
else {
// else condition goes here
}
});
You can still attach other behaviours to the change event if needed. The important thing is to do event.preventDefault() on the submit event.

How do I submit a form using jQuery after AJAX validation?

My form has one input which needs to be validated before submitting. After a successful validation I try to submit the form, but it doesn't submit.
My code looks like this:
$(document).ready(function() {
$("#myForm").submit(function () {
checkInputData();
return false; // to prevent default submit
});
});
The validation function:
function checkInputData() {
var id = $($("#id")).val(); // value, which needs to be validated
$.get("check.php?id=" + id,
function(result){
if(result == 1) {
//if the result is 1, need to submit
$("#myForm").unbind(); // to prevent recursion?
$("#myForm").submit(); // doesnt work
} else {
// dont submit, give some visual feedback, etc...
}
});
}
What am i doing wrong? Thanks.

You need to return the result from your AJAX validation request. You can do this by setting this check to being async: false, this means the checkInputData() will wait for the result to come back, and you can return it, controlling the submission of the form.
In your code it's not waiting for the $.get action to happen, and it appears to skip over meaning your code will always appear to return true; from the checkInputData() call. You don't need to return false in submit, if used as below.
I have used the $.ajax call in place of $.get because it allows you to control the async property, but it essentially does the same thing. You can read more about it here.
function checkInputData() {
var value = $("#id").val(); // Value to be validated
var passedValidation = false;
$.ajax("check.php?id=" + value, {
async: false,
success: function(result){
// Do whatever check of the server data you need here.
if(result == "1") {
// Good result, allow the submission
passedValidation = true;
} else {
// Show an error message
}
}
});
return passedValidation;
}
$(document).ready(function() {
$("#myForm").on("submit", function () {
return checkInputData();
});
});
I assume you have a button such as below, within your form with id myForm:
<input type="submit" value="Submit Form" />

It's not getting submitted may be because you are not returning 1 on successful validation for result in below if condition
if(result == 1) {
In check.php your output should be 1, like echo '1'; if input is valid. And make sure there is not any other output before or after it.

AMember is correct your always returning false, there are a few solution. One solution is for you to bind your validation to a button element or any element that will not submit the form.
HTML
<form id="myForm">
.
input elements
.
<button class= "submit" type="button" onclick="submit">Submit</button>
</form>
Document Ready
$(function()
{
var $submit = $(".submit");
$submit.click(function ()
{
checkInputData();
});
});
Validation Callback Function
function checkInputData()
{
var id = $('#id').val(); // value, which needs to be validated
$.get("check.php?id=" + id, function(result)
{
if(result == 1)
{
var $myForm = $("#myForm");
//if the result is 1 submit.
$myForm.submit();
}
else
{
// dont submit, give some visual feedback, etc...
}
});
}

$(document).ready(function() {
$("#myForm").submit(function (e) {
checkInputData();
//return false; // to prevent default submit <-- THIS IS WRONG
e.preventDefault(); //Try this :)
});
});
Returning false will prevent it from submitting in all cases.