<input type="text" value="[tabelas][something][oas]" id="allInput">
<script type="text/javascript">
allInput = document.getElementById('allInput');
var nivel = new Array('tabelas', 'produto');
for (var i =0; i < nivel.length ; i++ )
{
alert(" oi => " + allInput.value + " <-- " + nivel[i]) ;
var re = new RegExp("^\[" + nivel[i] + "\]\[.+\].+", "g");
alert(re);
allInput.value = allInput.value.replace(
re, "OLA");
alert(" oi 2 => " + allInput.value + " <-- " + nivel[i]) ;
}
</script>
Basically I whant to replace "something2 in the [tabelas][something][otherfield] by a number of quantity, I have been playing with regexp and had different results from this using .replace(/expression/,xxx ) and new RegExp() .
Best regards and thank you for any help.
You need to double-escape so the escape is seen by the regexp constructor, not the Javascript parser."\[" will result in the string [, "\\[" will result in \[.
Keep in mind that the regexp \[.+\] matches strings like [abc][def]. You probably want \[\w+\] or something similar.
If you construct a RegExp from the new RegExp(...) syntax, then you need two backslashes to escape a character.
new RegExp("^\\[" + nivel[i] + "\\]\\[.+\\].+", "g");
Related
I'm very new to js and programming, and i'd appreciate some help.
Suppose I have the following array (It is a single element array, they are not seperate elements)
var array =
[
'Foo\n' +
'bar23123\n' +
'barbarfoo\n' +
'foo, bar foo\n' +
'foo\n' +
'\n' +
'\n' +
'Bar\n' +
'\n' +
'\n'
]
Assuming there are multiple elements in the array, how can I write a regex expression to count and match the number of literal '\n' in between Foo\n and Bar\n in each element.
I wrote a partial solution to iterate through and return the count of all \n but how do I narrow my search to only return the values in between the two strings?
Here is the code:
let slashN = [];
for(let slash of array){
var reg = RegExp('\\n' , 'g')
slashN.push(slash.match(reg).length)
}
console.log(slashN);
I get the correct count, but I want to refine the regex expression.
Any help is highly appreciated.
You may use
var reg = /(?<=Foo\n.*?)\n(?=.*?Bar\n)/gs;
See the regex demo. Details:
(?<=Foo\n.*?) - a positive lookbehind that matches a location that is immediately preceded with Foo + newline and then any 0 or more chars, as few as possible
\n - a newline
(?=.*?Bar\n) - a positive lookahead that matches a location immediately followed with any 0+ chars as few as possible and then Bar + newline.
JavaScript demo:
var array =
[
'Foo\n' +
'bar23123\n' +
'barbarfoo\n' +
'foo, bar foo\n' +
'foo\n' +
'\n' +
'\n' +
'Bar\n' +
'\n' +
'\n'
];
let slashN = [];
for(let slash of array){
var reg = /(?<=Foo\n.*?)\n(?=.*?Bar\n)/gs;
slashN.push(slash.match(reg).length)
}
console.log(slashN);
I am a newbie on regular expression.
Could anybody suggest a regex to split string like below using Javascript?
The text I am dealing with should be split by a space character but sometimes it contains space within the text snippet like below:
Input:
SST+CONF!001 001 "407968017" "Projector Serial Number"
Desired output:
['SST+CONF!001', '001', '407968017', 'Projector Serial Number']
Please help!
Thank you!
This is longer than a one liner regex, but it converts the input to the format of the desired output you are looking for using split and regex:
var yourstring = 'SST+CONF!001 001 "407968017" "Projector Serial Number"';
// Regex to replace " with '
yourstring = yourstring.replace (/"/g,"'");
// Split where " " is
strArray = yourstring.split(" ");
var output = "[";
for (var i = 0; i < strArray.length; i++) {
if(i < 2){
strArray[i] = "'" + strArray[i] + "'";
}
if (i < 3){
output += strArray[i] + ", ";
}
else {
output += strArray[i] + " ";
}
}
// Regex to replace last character with ]
output = output.replace(/.$/, "]");
console.log(output);
Hope it helps!
Use the split function and use the regex provided inside it. It splits the array based on the regex. The regex finds all the space in the string
var a='SST+CONF!001 001 407968017 Projector Serial Number';
var b=a.split(/\s/g)
console.log(b)
I am using a regular Expression for a glosary function on a website, but it can not "handle" special charters as æ, ø and å. The regEx is as follows:
var re = new RegExp("\\b" + pat + "\\b", "g");
How can i modify the RegEx above to handle special charters?
You may use the solution from here:
function getWholeWords(input, word) {
var pL = "a-zA-Z\\xAA\\xB5\\xBA\\xC0-\\xD6\\xD8-\\xF6\\xF8-\\u02C1\\u02C6-\\u02D1\\u02E0-\\u02E4\\u02EC\\u02EE\\u0370-\\u0374\\u0376\\u0377\\u037A-\\u037D\\u037F\\u0386\\u0388-\\u038A\\u038C\\u038E-\\u03A1\\u03A3-\\u03F5\\u03F7-\\u0481\\u048A-\\u052F\\u0531-\\u0556\\u0559\\u0561-\\u0587\\u05D0-\\u05EA\\u05F0-\\u05F2\\u0620-\\u064A\\u066E\\u066F\\u0671-\\u06D3\\u06D5\\u06E5\\u06E6\\u06EE\\u06EF\\u06FA-\\u06FC\\u06FF\\u0710\\u0712-\\u072F\\u074D-\\u07A5\\u07B1\\u07CA-\\u07EA\\u07F4\\u07F5\\u07FA\\u0800-\\u0815\\u081A\\u0824\\u0828\\u0840-\\u0858\\u08A0-\\u08B2\\u0904-\\u0939\\u093D\\u0950\\u0958-\\u0961\\u0971-\\u0980\\u0985-\\u098C\\u098F\\u0990\\u0993-\\u09A8\\u09AA-\\u09B0\\u09B2\\u09B6-\\u09B9\\u09BD\\u09CE\\u09DC\\u09DD\\u09DF-\\u09E1\\u09F0\\u09F1\\u0A05-\\u0A0A\\u0A0F\\u0A10\\u0A13-\\u0A28\\u0A2A-\\u0A30\\u0A32\\u0A33\\u0A35\\u0A36\\u0A38\\u0A39\\u0A59-\\u0A5C\\u0A5E\\u0A72-\\u0A74\\u0A85-\\u0A8D\\u0A8F-\\u0A91\\u0A93-\\u0AA8\\u0AAA-\\u0AB0\\u0AB2\\u0AB3\\u0AB5-\\u0AB9\\u0ABD\\u0AD0\\u0AE0\\u0AE1\\u0B05-\\u0B0C\\u0B0F\\u0B10\\u0B13-\\u0B28\\u0B2A-\\u0B30\\u0B32\\u0B33\\u0B35-\\u0B39\\u0B3D\\u0B5C\\u0B5D\\u0B5F-\\u0B61\\u0B71\\u0B83\\u0B85-\\u0B8A\\u0B8E-\\u0B90\\u0B92-\\u0B95\\u0B99\\u0B9A\\u0B9C\\u0B9E\\u0B9F\\u0BA3\\u0BA4\\u0BA8-\\u0BAA\\u0BAE-\\u0BB9\\u0BD0\\u0C05-\\u0C0C\\u0C0E-\\u0C10\\u0C12-\\u0C28\\u0C2A-\\u0C39\\u0C3D\\u0C58\\u0C59\\u0C60\\u0C61\\u0C85-\\u0C8C\\u0C8E-\\u0C90\\u0C92-\\u0CA8\\u0CAA-\\u0CB3\\u0CB5-\\u0CB9\\u0CBD\\u0CDE\\u0CE0\\u0CE1\\u0CF1\\u0CF2\\u0D05-\\u0D0C\\u0D0E-\\u0D10\\u0D12-\\u0D3A\\u0D3D\\u0D4E\\u0D60\\u0D61\\u0D7A-\\u0D7F\\u0D85-\\u0D96\\u0D9A-\\u0DB1\\u0DB3-\\u0DBB\\u0DBD\\u0DC0-\\u0DC6\\u0E01-\\u0E30\\u0E32\\u0E33\\u0E40-\\u0E46\\u0E81\\u0E82\\u0E84\\u0E87\\u0E88\\u0E8A\\u0E8D\\u0E94-\\u0E97\\u0E99-\\u0E9F\\u0EA1-\\u0EA3\\u0EA5\\u0EA7\\u0EAA\\u0EAB\\u0EAD-\\u0EB0\\u0EB2\\u0EB3\\u0EBD\\u0EC0-\\u0EC4\\u0EC6\\u0EDC-\\u0EDF\\u0F00\\u0F40-\\u0F47\\u0F49-\\u0F6C\\u0F88-\\u0F8C\\u1000-\\u102A\\u103F\\u1050-\\u1055\\u105A-\\u105D\\u1061\\u1065\\u1066\\u106E-\\u1070\\u1075-\\u1081\\u108E\\u10A0-\\u10C5\\u10C7\\u10CD\\u10D0-\\u10FA\\u10FC-\\u1248\\u124A-\\u124D\\u1250-\\u1256\\u1258\\u125A-\\u125D\\u1260-\\u1288\\u128A-\\u128D\\u1290-\\u12B0\\u12B2-\\u12B5\\u12B8-\\u12BE\\u12C0\\u12C2-\\u12C5\\u12C8-\\u12D6\\u12D8-\\u1310\\u1312-\\u1315\\u1318-\\u135A\\u1380-\\u138F\\u13A0-\\u13F4\\u1401-\\u166C\\u166F-\\u167F\\u1681-\\u169A\\u16A0-\\u16EA\\u16F1-\\u16F8\\u1700-\\u170C\\u170E-\\u1711\\u1720-\\u1731\\u1740-\\u1751\\u1760-\\u176C\\u176E-\\u1770\\u1780-\\u17B3\\u17D7\\u17DC\\u1820-\\u1877\\u1880-\\u18A8\\u18AA\\u18B0-\\u18F5\\u1900-\\u191E\\u1950-\\u196D\\u1970-\\u1974\\u1980-\\u19AB\\u19C1-\\u19C7\\u1A00-\\u1A16\\u1A20-\\u1A54\\u1AA7\\u1B05-\\u1B33\\u1B45-\\u1B4B\\u1B83-\\u1BA0\\u1BAE\\u1BAF\\u1BBA-\\u1BE5\\u1C00-\\u1C23\\u1C4D-\\u1C4F\\u1C5A-\\u1C7D\\u1CE9-\\u1CEC\\u1CEE-\\u1CF1\\u1CF5\\u1CF6\\u1D00-\\u1DBF\\u1E00-\\u1F15\\u1F18-\\u1F1D\\u1F20-\\u1F45\\u1F48-\\u1F4D\\u1F50-\\u1F57\\u1F59\\u1F5B\\u1F5D\\u1F5F-\\u1F7D\\u1F80-\\u1FB4\\u1FB6-\\u1FBC\\u1FBE\\u1FC2-\\u1FC4\\u1FC6-\\u1FCC\\u1FD0-\\u1FD3\\u1FD6-\\u1FDB\\u1FE0-\\u1FEC\\u1FF2-\\u1FF4\\u1FF6-\\u1FFC\\u2071\\u207F\\u2090-\\u209C\\u2102\\u2107\\u210A-\\u2113\\u2115\\u2119-\\u211D\\u2124\\u2126\\u2128\\u212A-\\u212D\\u212F-\\u2139\\u213C-\\u213F\\u2145-\\u2149\\u214E\\u2183\\u2184\\u2C00-\\u2C2E\\u2C30-\\u2C5E\\u2C60-\\u2CE4\\u2CEB-\\u2CEE\\u2CF2\\u2CF3\\u2D00-\\u2D25\\u2D27\\u2D2D\\u2D30-\\u2D67\\u2D6F\\u2D80-\\u2D96\\u2DA0-\\u2DA6\\u2DA8-\\u2DAE\\u2DB0-\\u2DB6\\u2DB8-\\u2DBE\\u2DC0-\\u2DC6\\u2DC8-\\u2DCE\\u2DD0-\\u2DD6\\u2DD8-\\u2DDE\\u2E2F\\u3005\\u3006\\u3031-\\u3035\\u303B\\u303C\\u3041-\\u3096\\u309D-\\u309F\\u30A1-\\u30FA\\u30FC-\\u30FF\\u3105-\\u312D\\u3131-\\u318E\\u31A0-\\u31BA\\u31F0-\\u31FF\\u3400-\\u4DB5\\u4E00-\\u9FCC\\uA000-\\uA48C\\uA4D0-\\uA4FD\\uA500-\\uA60C\\uA610-\\uA61F\\uA62A\\uA62B\\uA640-\\uA66E\\uA67F-\\uA69D\\uA6A0-\\uA6E5\\uA717-\\uA71F\\uA722-\\uA788\\uA78B-\\uA78E\\uA790-\\uA7AD\\uA7B0\\uA7B1\\uA7F7-\\uA801\\uA803-\\uA805\\uA807-\\uA80A\\uA80C-\\uA822\\uA840-\\uA873\\uA882-\\uA8B3\\uA8F2-\\uA8F7\\uA8FB\\uA90A-\\uA925\\uA930-\\uA946\\uA960-\\uA97C\\uA984-\\uA9B2\\uA9CF\\uA9E0-\\uA9E4\\uA9E6-\\uA9EF\\uA9FA-\\uA9FE\\uAA00-\\uAA28\\uAA40-\\uAA42\\uAA44-\\uAA4B\\uAA60-\\uAA76\\uAA7A\\uAA7E-\\uAAAF\\uAAB1\\uAAB5\\uAAB6\\uAAB9-\\uAABD\\uAAC0\\uAAC2\\uAADB-\\uAADD\\uAAE0-\\uAAEA\\uAAF2-\\uAAF4\\uAB01-\\uAB06\\uAB09-\\uAB0E\\uAB11-\\uAB16\\uAB20-\\uAB26\\uAB28-\\uAB2E\\uAB30-\\uAB5A\\uAB5C-\\uAB5F\\uAB64\\uAB65\\uABC0-\\uABE2\\uAC00-\\uD7A3\\uD7B0-\\uD7C6\\uD7CB-\\uD7FB\\uF900-\\uFA6D\\uFA70-\\uFAD9\\uFB00-\\uFB06\\uFB13-\\uFB17\\uFB1D\\uFB1F-\\uFB28\\uFB2A-\\uFB36\\uFB38-\\uFB3C\\uFB3E\\uFB40\\uFB41\\uFB43\\uFB44\\uFB46-\\uFBB1\\uFBD3-\\uFD3D\\uFD50-\\uFD8F\\uFD92-\\uFDC7\\uFDF0-\\uFDFB\\uFE70-\\uFE74\\uFE76-\\uFEFC\\uFF21-\\uFF3A\\uFF41-\\uFF5A\\uFF66-\\uFFBE\\uFFC2-\\uFFC7\\uFFCA-\\uFFCF\\uFFD2-\\uFFD7\\uFFDA-\\uFFDC";
var rx = RegExp("(?:^|[^_0-9" + pL + "])(" + word + ")(?![_0-9" + pL + "])", "ig"); // Build the regex (might be moved out from the function)
var words = [];
while ((m = rx.exec(input)) !== null) {
words.push(m[1]); // Add an occurrence
}
return words;
}
var word = "æøå";
var input = "æøå, AæøåZ, BæøåY, and æøå!";
document.body.innerHTML = "<pre>" + JSON.stringify(getWholeWords(input, word), 0, 4) + "</pre>";
Or a regex that will look for a word only if it is enclosed with whitespace/start/end of the string:
var re = new RegExp("(?:^|\\s)(" + pat.replace(/[-\/\\^$*+?.()|[\]{}]/g, '\\$&') + ")(?!\\S)", "g");
and grab Group 1 value.
This is my js code:
html = html.replace("/["+increment+"]/gi", '[' + counter + ']');
where increment is 0 and counter is 1
or
html = html.replace("/[0]/gi", '[1]');
My version does not replace the [0] with [1] in my string. Why ?
You need to use the RegExp constructor as the regex is dynamic
var regex = new RegExp("\\[" + increment + "\\]", 'gi')
html = html.replace(regex, '[' + counter + ']');
Also you could sanitize the dynamic variable if you want
if (!RegExp.escape) {
//A escape function to sanitize special characters in the regex
RegExp.escape = function (value) {
return value.replace(/[\-\[\]{}()*+?.,\\\^$|#\s]/g, "\\$&")
};
}
//You could also escape the dynamic value it is an user input
var regex = new RegExp("\\[" + RegExp.escape(increment) + "\\]", 'gi')
html = html.replace(regex, '[' + counter + ']');
Use this way:
html = html.replace(new RegExp("\\["+increment+"\\]", "gi"), '[' + counter + ']');
This makes use of the dynamic values.
I have a jquery code that trims the leading and trailing character (passed from the calling program). I am using a variable in RegExp to replace the character with blank. How can I make the RegExp work for any character passed from the calling program? Here is the simplified code:
var time = ":1h:45m:34s:";
var chr= ':'; //can have . or , or any other character
var regex = new RegExp("(^" + chr + ")|(" + chr+ "$)" , "g"); //works for colon but not for dot.
//var regex = new RegExp("(^/" + chr + ")|(/" + chr+ "$)" , "g"); //for dot I added / but not for colon.
var formattedtime = time.replace(regex, "");
Expected Outputs:
1. time = ":1h:45m:34s:";
chr = ":";
Output: 1h:45m:34s
2. time = "1h:45m:34s";
chr = ":";
Output: 1h:45m:34s
3. time = ".45m.34s";
chr = ".";
Output: 45m.34s
4. time = "1h.45m.34s.";
chr = ".";
Output: 1h.45m.34s
How can I make the regexp work for any character?
You need to escape meta characters (like . and several others) to get literals. You do that by adding a backslash before them.
JS doesn't have any built in function for that, so you could use this:
function quotemeta(str){
return str.replace(/[.+*?|\\^$(){}\[\]-]/g, '\\$&');
}
Used like so:
new RegExp("^(?:" + quotemeta(chr) + ")+|(?:" + quotemeta(chr) + ")+$" , "g");
var chr= ':/';
...
var regex = new RegExp("(^[" + chr + "])|([" + chr+ "]$)" , "g");
Regex should this way:-
For Colon, /^(\:)|(\:)$/gim
For Dot, /^(\.)|(\.)$/gim
OR
/^(\:|\w|\.)|(\:|\w|\.)$/gim
LIVE DEMO