I have an image in a table. Specifically a graph of profiling information that might be quite tall (one vertical pixel is data from one source, one horizontal pixel is one unit of time). I'ld like to specify a maximum height for the image and re-scale it vertically so that it can't extend too far down the page. But I want to preserve the width (the page can scale horizontally). i.e. I specifically want to change the aspect-ratio of the source image.
My html looks, vaguely like this and it mostly works.
<style>
img.capped {
max-height : 500px;
width : 100%;
}
</style>
...
<tr><th>Profile</th></tr>
<tr><td><img src=... class=capped></td></tr>
However if the image's width is less than the width of the string "Profile" my image gets scaled upward horizontally and vertically.
Is there a way, using CSS, to cap the vertical size of an image, resizing if necessary, but leave the width alone?
You can force the width by using min-width
img {
max-height: 100px;
min-width: 100%;
}
<img src="https://placeholdit.imgix.net/~text?txtsize=33&txt=350%C3%97150&w=350&h=150" />
Related
REFERENCE: http://www.templatewire.com/preview/landscaper/
I want to make a web page, and in that page, I want to have divs/sections each the size of the screen.
Now, I mean, the width and height of the monitor, and it won't resize again, and will stay the width and height of that monitor, regardless of the browser size, and regardless of how much content is inside it.
The link shows you what I mean, but I have a 1920x1080 browser window, you can see the top and bottom of the sections above and below it. I don't want the top and bottom of neighbouring sections to be seen if the monitor is very big, nor do I want the section to not be fully visible if the monitor's too small.
Example, say I had 5 sections like in the reference, and my browser window was 1920x1080, the overall height of that document would be 1920*5400.
(I want it to be the height of the screen minus the height on the nav bar.)
You can use Viewport units (the browser window size). 100vh is the height of the screen. If you got sections that bigger than the height of little screen you can use the min-height property and set it to 100vh.
Since you didn't place your code, this is generally example of use case:
section { min-height: 100vh;}
Read more here:
https://developer.mozilla.org/en-US/docs/Web/CSS/length
Good luck!
It appears you're looking for viewport percentage lenghts.
To give any element current viewport's height, in CSS, one should use:
your-selector {
height: 100vh;
display: block;
}
If the element is a <div> or any other element with a default value of block for display, it obviously doesn't need the second rule.
See it working:
your-selector {
height: 100vh;
display: block;
transition: background-color .3s linear;
}
/* let's add a hover, for testing */
your-selector:hover {
background-color: red;
}
body {
margin: 0;
min-height: 200vh;
}
<your-selector>Test</your-selector>
Note: you can also apply viewport percentage lengths to other properties, such as min-height, max-height, etc...
Note: although default viewport is browser window, that's can change. For example, 3d transforms turn any regular DOM element into a viewport for their children, affecting behavior of viewport percentage lengths, as well as behavior of position:fixed in any of their children.
I have got a tiny problem, im creating a website and i want to give an image a max-height. The image may only have the same height of another div.
You can check the layout here: http://bit.ly/1OAGsLR
Its about the 1920x1080 image, and i needs to be the same height as the div with class box left to it. If right the image should scale well.
But im trying all i know but i dont get it working, can someone get this working with CSS or do i need to use Javascript for this?
Thanks in advance!
Your image is looking the way you want when the screen width is at or above 1400px. You should consider using css media queries to move or adjust the image at different screen widths. Your layout could easily be handled using a css framework like foundation or bootstrap which would take care of css media query breakpoints for you.
If you are intentionally trying to not use a css framework, I'd check out this css media queries tutorial to get you started.
You need to make your container div wider.
Your container is 1200px wide, and your boxes are 560 + 40 padding wide each.
That means that the max width of you image is 560px.
Now to conserve it's aspect ratio of 16:9, the max height of the image is 560 / 16 * 9 = 315 pixels.
Okay, your main problem is that heights don't like to be defined this way. I have a solution for you that will 'solve' this issue, but its not very pretty and you might want to look into doing this with javascript anyhow. Below is a very rough example mockup.
body > div {
width: 100%;
max-width: 500px;
background: green;
padding: 10px;
position: relative;
}
body > div > div {
width: 50%;
padding: 20px;
}
body > div > img {
position: absolute;
right: 20px;
top: 20px;
max-width: 50%;
/* make sure to fall back to 80% so theres at least some gutter for older browsers */
max-height: 80%;
/* use calc to make the image the height of the relative parent minus padding */
max-height: calc(100% - 40px);
}
<div>
<div>Push<br />Push<br />Push<br />Push<br />Push<br /></div>
<img src="http://placehold.it/350x150" />
</div>
In short, this will place your image to the right of your box, give it a max-height (because positioning can do that) and a max-width (so smaller screen sizes don't freak out).
Now you could easily translate this a more general system where .box + .boxget a absolute position, or you could define a class for the box that has to push content and add that to the first box, making all other boxes absolute.
I fixed it by using JS, im using the following script:
<script type="text/javascript">
function changeheight(){
var Height = document.getElementById('box').clientHeight;
document.getElementById('imagebox').style.height = Height+'px';
}
</script>
I have a responsive background image with a smaller image positioned over it. I am trying to keep the smaller image at a specific location when the window is resized.
Both images scale properly, and the left position works so far, but not the top position.
img {
max-width:100%;
}
#dot {
position: absolute;
top: 17%;
left: 66.5%;
width: 10%;
height: 0;
padding-bottom: 10%;
}
I have found some questions with answers that suggest:
Vertical Alignment or Positioning with Javascript
I've also looked into .position() and .offset(), not sure if either would work.
I think my best solution would be to calculate the Y offset using the current window height as a reference but I am not sure what my JS or Jquery code should look like.
Here is my jsfiddle:
http://jsfiddle.net/melissadpelletier/xBu79/21/
I'm not sure exactly what you're trying to do with your images, but you could create a new smaller image (green dot) with the same aspect ratio as your background image, and have the dot placed where it needs to be within that aspect ratio. Then stretch the width of that to be 100% and the two images are basically overlapping, but the top image (smaller image) has a transparent background. Not sure if that all makes sense, but I made a new image and did the fiddle thing, which I'm new to: http://jsfiddle.net/ydack/
img
{
width:100%;
}
#dot
{
width: 100%;
position: absolute;
top:0;
left:0;
}
#dotImg
{
top: 0;
left: 0;
width: 100%;
}
I mistakenly placed the green dot's position based on the black outline, not the full background image, so the dot is slightly up and right of where it needs to be. BUT, the position is maintained while re-sizing the window. Hacky, but it could work!
You are definitely gonna need some javascript for this. What you can do is calculate the height and width of the image whenever you resize your browser window. Then simply use some math to calculate the position of the dot relative to those dimensions.
var height = $('#image').height();
var width = $('#image').width();
/* change the fractions here according to your desired percentages */
$('#dot').css({left: width/2, top: height/2});
$(window).resize(function() {
height = $('#image').height();
width = $('#image').width();
/* change the fractions here according to your desired percentages */
$('#dot').css({left: width/2, top: height/2});
});
Try this code: http://jsfiddle.net/LimitedWard/FFQt2/3/
Note that you will need to also resize the dot according to the height/width of the image if you want it to always fit inside that box.
Edit: after further investigation, it is possible to do this in CSS; however, it's a lot sloppier because the dot doesn't follow the image if the window is too wide. This jQuery solves that problem by using pixel-based positioning.
http://jsfiddle.net/sajrashid/xBu79/24/
plenty of errors mainly not closing tags
<div id='background'>
<img src='http://i.imgur.com/57fZEOt.png'/>
<div id='dot'>
<img src='http://i.imgur.com/yhngPvm.png'/>
</div>
</div>
I have a large image whose height is bigger than the screen height. I have no problem with the width. I need to crop it so that the top 65% of the screen contains this image.
<body>
<img class="img" src="image.jpg" alt="img">
<p>Description</p>
</body>
If I write a CSS as below, the whole image gets compressed to fit in 65% screen. Moreover, if I resize the screen, the image automatically starts attempting to fit in the top 65%, making the whole screen look disturbed.
body, html { height:100% }
img.img { height:65% }
I want instead, the image to be cropped so that the leftover fits in the 65%, and then it stays that way. That is, if I now resize the window, let the vertical scrollbar appear. How can I achieve this?
(PS: I didn't want to give a fixed height because I want the webpage to be viewed in different devices like mobile phone and iPads too.
I think this is what I need:
Get the maximum height of the device (not the current height of the browser screen as the user might have minimized it for some reason)
Crop the image in such a way that it fits the top 65%, and display it
Keep the image size that way irrespective of the user changing the screen size
But I am not sure how to achieve it.)
Is this what you are seeking: http://jsfiddle.net/JjwMw/1/
body, html {
height: 100%;
margin: 0;
padding: 0;
}
.container {
height: 65%;
width: 100%;
position: relative;
top: -22.75%; /* 65*35/100 */
background-image: url(http://placehold.it/1024x768);
background-size: cover;
background-position: center bottom;
}
Note that the image is now a background-image and is leveraging the background-size property which is not supported in IE8 (...who cares?). If the image cannot be a background image, you scale a div proportionally to fill the width using a padding hack (Proportionally scale a div with CSS based on max-width (similar to img scaling)) and have the inside image set to 100% width and height.
Maybe this can be useful to you:
http://demo.solemone.de/overflow-image-with-vertical-centering-for-responsive-web-design/
Also a search for css cliping property here or in google should bring enough info
I'm trying try to show a couple of images at 65% of their original size using this CSS rule:
div#midline .artistEntry img {
height: 65%;
width: 65%;
}
It seems to work fine in IE and Firefox
But in Chrome it looks terrible. It seems that the width of the image has been correctly reduced, but the height has actually been expanded.
Is there a way to proportionally resize an image using CSS that works in all modern browsers? If not, I'd (relucantly) consider a JavaScript/jQuery solution
#midline .artistEntry img {
height : auto;
width : 65%;
}
Setting one of the dimensions to auto (which is the default) should keep the aspect ratio intact while stretching the other dimension to a percent of it's parents dimension.
Here is a demo: http://jsfiddle.net/Mu6h7/ (re-size the preview panel to see the aspect ratio stay intact)
remove the height or width rule. By defining height and width, it will grab both of those, if you remove one it will scale correctly.