userIP.php
<?php echo $_SERVER['REMOTE_ADDR']; ?>
Now I'm trying to use a callback using javascript but I can't seem to display the data somewhere else.
This is how I am retriving the data..
var oReq = new XMLHttpRequest();
oReq.open("get", "userIP.php", true);
oReq.send(null);
oReq.onload = function()
{
document.write(this.responseText);
};
It does display my IP..
but how can I use that data from oReq inside this var?
var params = "&user_ip=" + HERE + "&user_agent=" + navigator.userAgent;
UPDATED ANSWER:
Since the params variable is set before the initial request is finished, the data ends up being undefined. The fix is to set it after the request as seen here:
http://pastebin.com/Cd8KkH5g
OLD ANSWER:
I haven't tested this yet, so I hope it works.
Create a variable outside of the onload function
var loadedText;
Replace the function with
oReq.onload = function()
{
loadedText = this.responseText;
};
Then use the variable inside of your parameters.
var params = "&user_ip=" + loadedText + "&user_agent=" + navigator.userAgent;
Related
I'm trying to program a java script script that based on whether a user logs in properly or not will redirect them to a separate PHP script. The issue is that I can't seem to figure out how to get the file parameter of the request so that I can see if the request I'm looking for is there. How do I get the file parameter of a request in java script?
Sorry for misconceptions, what i mean by the file attribute is what is under the "file" section for each request in the following.
example
So if under the file tab of the packet, it set a certain file, how would i differentiate?
It's not clear what you're asking.
The part " so that I can see if the request I'm looking for is there" tells me, you want to debug your website, or at least, that's my interpretation of it.
If you use Chrome or Firefox Developer Edition, you can press F12 (or CTRL + SHIFT + J) to open the developer console.
Change to the tab "Network, and you'll see all the XMLHTTPRequests.
Click on a specific request, and you'll see its details.
A basic XmlHttpReuqest goes like this:
function reqListener () {
console.log(this.responseText);
}
var oReq = new XMLHttpRequest();
oReq.addEventListener("load", reqListener);
oReq.open("GET", "http://www.example.org/example.txt");
oReq.send();
And you get the result of your request in the callback function reqListener.
See also https://developer.mozilla.org/en-US/docs/Web/API/XMLHttpRequest/Using_XMLHttpRequest
If you want to get the request handler's URL, that goes like this:
function reqListener (e) {
//console.log(this.responseText);
console.log(e);
console.log(e.currentTarget.responseURL);
}
var oReq = new XMLHttpRequest();
oReq.addEventListener("load", reqListener);
oReq.open("GET", "https://stackoverflow.com/questions/58407228");
oReq.send();
And if you want to get a parameter called "file" inside an url, this goes like
function getUrlVars(urlHref)
{
var vars = [], hash;
var hashes = urlHref.slice(urlHref.indexOf('?') + 1).split('&');
var i;
for (i = 0; i < hashes.length; i++)
{
hash = hashes[i].split('=');
vars.push(decodeURIComponent(hash[0]));
vars[decodeURIComponent(hash[0])] = decodeURIComponent(hash[1]);
} // Next i
return vars;
} // End Function getUrlVars
var dictParameters = getUrlVars("http://www.example.com/handler?file=bla.bin");
if (dictParameters.contains("file"))
{
console.log(dictParameters["file"]);
}
As for XMLHTTPRequest, it doesn't have a property called file.
Also, this is 2019, you should be using the FETCH-API with async and await, not the XMLHttpRequest-API, which doesn't use promises.
Here's a getting started overview.
Edit:
Ah, I see:
If you have a url, such as
var url = "http://www6.scratch99.com/web-development/javascript/test.js?abc=def";
you do
var url = "http://www6.scratch99.com";
var urlParts = url.replace('http://','').replace('https://','').split(/[/?#]/);
var domain = urlParts[0];
to get the domain part. Then you subtract the domain (+protocol), and end it at ? or #:
Full code:
var url = "http://www6.scratch99.com/web-development/javascript/test.js?abc=def";
// var url = "http://www6.scratch99.com";
// var url = "http://www6.scratch99.com?test=123";
var protocol = url.substr(0, url.indexOf(":") + 3)
var urlParts = url.substr(protocol.length).split(/[/?#]/);
var domain = urlParts[0];
var fileParts = url.substr(protocol.length + domain.length);
var file = fileParts.split(/[?#]/)[0];
and if you want the filename only:
var pathParts = file.split('/');
var fileOnly = pathParts[pathParts.length-1];
I'm trying to pass two javascript variables to PHP. When there's only one then it's working but I have no clue how to send two at once. Here's my code
function save(nr) {
var xr = new XMLHttpRequest();
var url = 'saveColor.php';
var text = document.getElementById('color'+nr).value;
var vars1 = "newText="+text;
var vars2 = "variable="+nr;
xr.open("POST", url, true);
xr.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
xr.send(vars1);
}
So sending the "vars1" variable works fine, but where or how I should put "vars2" to send them at once? Something like
xr.send(vars1, vars2);
Doesn't work.
This will work fine:
var data = new FormData();
data.append('var1', 'var1value');
data.append('var2', 'var2value');
and then use it like you tried before
xr.send(data);
It can also be implemented this way
var strURL = "auto_ppm_plan_generation_table.php?ppm_frequency=" + ppm_frequency + "&ppm_month=" + ppm_month + "&ppm_week=" + ppm_week;
i have a problem with my file js that call multiple http requests.
I have a button that call the function VisualizzaReport that is in my file visualizzaReport.js
Here is the function VisualizzaReport(select is the ID of the user)
function visualizzaReport(select){
reportUtente(select)
loadPianificazione(select)
}
Here the function reportUtente(select)
function reportUtente(select) {
var url = "../loadReportUtenteServlet?";
url += "type=perso_atti&value=" + select.value;
xmlhttp.onreadystatechange = handlerForReportUtente;
xmlhttp.open("GET", url);
xmlhttp.send("");
}
Here the function loadPianificazione(select)
function loadPianificazione(select) {
var url = "../loadPianificazione2Servlet?";
url += "type=pianificazioni&value=" + select.value;
xmlhttp.onreadystatechange = handlerForPianificazioneUtente;
xmlhttp.open("GET", url);
xmlhttp.send("");
}
my problem is that the function reportUtente is launched but has not effect because it seems that it is substitute by loadPianificazione function.
How can i call loadPianificazione only when reportUtente has finished his execution?
In your case I suggest you use either jQuery or AngularJs for this purposes.
jQuery example:
$.get('url1.com', function(){
$.get('url2.com');
})
You will request url2.com only when first request has finished.
You appear to be using a single, global xmlhttp variable.
Then you call two functions which do things with it. The second one will overwrite xmlhttp.onreadystatechange before the first request has finished so the second function you put there will be called for each request.
Don't do that. Create a new instance of XMLHttpRequest for each request, and keep it in a local scope so that it doesn't interfere with other instances.
function reportUtente(select) {
var url = "../loadReportUtenteServlet?";
url += "type=perso_atti&value=" + select.value;
var xmlhttp = new XMLHttpRequest(); // New instance here
xmlhttp.onreadystatechange = handlerForReportUtente;
xmlhttp.open("GET", url);
xmlhttp.send("");
}
You haven't shared handlerForReportUtente but it should look something like:
function handlerForReportUtente() {
alert(this.responseText); // Use `this` to get the right XHR object
}
I'm trying to pass value to PHP code using AJAX.
Javascript
function countop() {
var href = window.location.href;
var href2 = href.split('/', 7);
xmlhttp.open('GET', '/count.php?val_for_count='+href2[6], true);
xmlhttp.send();
};
PHP
$x = $_GET['val_for_count'];
echo $x;
I don't get $x printed and I don't know why.
You have two problems.
First, xmlhttp is never declared, so your code throws a reference error.
var xmlhttp = new XMLHttpRequest();
Second, you never look at the HTTP response!
xmlhttp.addEventListener("load", function (event) {
document.body.appendChild(
document.createTextNode(
this.responseText
)
);
});
You have to create a new instance of XMLHttpRequest before using it:
var xmlhttp = new XMLHttpRequest();
And if you want to print the result of your request in your document, you can do it like this:
xmlhttp.onreadystatechange = function() {
if (xmlhttp.readyState == 4 && xmlhttp.status == 200) {
document.body.innerHTML = xmlhttp.responseText;
}
};
I am trying to read a local file on the server with a standard function loadDoc(url, cfunc), then
1) search for a particular string in the file (getLine());
2) if possible, store that line to a variable.
For point 1 I pass a string to the callback.
2) Getting the response is problematic because XMLHTTPRequest is asynchronous. At this moment the error is:
"ReferenceError: xhttp is not defined"
function main(){
var url="data.txt"
var str="1,0,"; //just an example
var myCallBackWithVar = function(){
getLine(str);
};
loadDoc(url, myCallBackWithVar);
//Can I get the line here somehow?
}
function loadDoc(url, cfunc) {
var xhttp=new XMLHttpRequest();
xhttp.onreadystatechange = function() {
if (xhttp.readyState == 4 && xhttp.status == 200) {
cfunc(xhttp);
}
}
xhttp.overrideMimeType('text/plain');
xhttp.open("GET", url, true);
xhttp.send();
}
//Find string with the desired data in txt file
function getLine(str) {
var data=xhttp.responseText;
//Find the line from the txt file
var start=data.indexOf(str);
var end=data.indexOf(";",start);
var line=data.substring(start,end);
return line;
}
data.txt is something like this:
some data here
0,0,9;
1,0,10;
1,1,11;
I have already tried to pass the XMLHTTPRequest objetct getLine(xhttp,str). How to solve points 1 and 2? I'd rather keep it jQuery free for the moment. Thanks
Can I get the line here somehow?
I don't think that's a good idea. You can't be sure that your app will work correctly. XHR is a async function and you should use async architecture.
Here the example how this functionality can be done.
var text; // define global variable
var str = "1,0,"; //just an example
function main(){
var url = "data.txt";
var cb = function (data){
text = getLine(data);
// you can use text var here
// or in anyewhere in your code
}
loadDoc(url, cb);
}
function loadDoc(url, cb) {
var xhr = new XMLHttpRequest();
xhr.onreadystatechange = function() {
if (xhr.readyState == 4 && xhr.status == 200) {
cb(xhr.responseText);
}
}
xhr.overrideMimeType('text/plain');
xhr.open("GET", url, true);
xhr.send();
}
//Find string with the desired data in txt file
function getLine(data) {
if(data) {
//Find the line from the txt file
var start = data.indexOf(str);
var end = data.indexOf(";", start);
var line = data.substring(start, end);
return line;
}
}
On complete, you don't need to pass the whole xhttp variable through too the callback function. When you do this:
function getLine(str) {
var data=xhttp.responseText;
xhttp is already out of scope. To fix this, the parameter name would also have to be xhttp.
A better way would be to do :
cfunc(xhttp.responseText);
and then
var data=str
This way, you are passing only what you need as an argument.