Can't get xmlhttp.responseText value - javascript

I am trying to get the xmlhttp.responseText value, but I have no response from the xmlhttp. I was wondering if there is something wrong with my code:
SCRIPT
var xmlhttp;
function show(){
loadXMLDoc("includes/edit.php",function(){
if (xmlhttp.readyState==4 && xmlhttp.status==200){
alert(xmlhttp.responseText);
}
});
}
function loadXMLDoc(url,cfunc){
if (window.XMLHttpRequest){// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp=new XMLHttpRequest();
}
else{// code for IE6, IE5
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange=cfunc;
xmlhttp.open("GET",url,true);
xmlhttp.send();
}
HTML
< a href="#" style="text-align: right; font-size: 10px;" onclick="show()">SHOW</a>
EDIT.PHP
print "1";

I don't see anything wrong with your code per se, but there are a lot of interactions that are opaque from this code snippet.
I can offer some troubleshooting tips, however:
Add a console log in your callback function (the one that you are running alert() in). Just "console.log('function is running');" on the first line. Then see if you get that far. I would put one in the opening line of show() as well -- maybe your click event isn't doing what you think it is.
Have your PHP server-side file write something to a log so you can be sure that the request is being received where you think it is.
Open your browser developer console and watch the network panel. You should be able to see the entire XHR transaction there. Is it being sent at all? If so, is it returning the content you expect?
If all this doesn't help, setup a test in jsfiddle and post the link here. We'll be able to help in a lot more detail that way.
Good luck.

Related

Calling second XMLHttpRequest after first one XMLHttpRequest (failed)

First one XMLHttpRequest is calling script to update MySQL database it can run multiple times depending on the situation. Script insertLocation will do the job, but in the end I am calling second XMLHttpRequest which should update file made from database. The problem is the second XMLHttpRequest will never read from updated database so there are data missing from first XMLHttpRequest.
However when I look to database, the data are there. I tried even sleeping before the creating of the file, but it did not helped. It seems like calling 2 XMLHttpRequest is not possible. I know about that third parameter of .open() , that when its set to false it will wait for request to be done, but it is now working. Here is my code:
insertToDatabase(lat,lng,id);
//there I tried 10 second sleep
updateDatabaseFile();
function updateDatabaseFile() {
if (window.XMLHttpRequest) {
// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp=new XMLHttpRequest();
} else { // code for IE6, IE5
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.open("GET","updateCoords.php",false);
xmlhttp.send();
alert("updated");
}
function insertToDatabase(lat,lng,id) {
if (window.XMLHttpRequest) {
// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp=new XMLHttpRequest();
} else { // code for IE6, IE5
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.open("GET","insertLocation.php?lat="+lat+"&lng="+lng+"&id="+id,false);
xmlhttp.send();
alert("inserted")
}
One lats thing, when I run the updateDatabaseFile.php manually it will do the job. So I think the problem might be that changes done to database are made when this whole script ends so that is why I am getting incomplete data when reading.
EDIT: the alert("inserted") will open after the alert("updated") so there is the fail. The second one will finish first.

xmlhttp status 200 message when adding DOCTYPE to page

I have the following code placed into a function and when the function is called it loads my XML file and displays it in a message box:
if (window.XMLHttpRequest)
{// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp=new XMLHttpRequest();
}
else
{// code for IE6, IE5
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange=function()
{
if (xmlhttp.readyState==4 && xmlhttp.status==200)
{
alert(xmlhttp.responseText);
} else
{
alert('Panel not communicating.Reason: '+xmlhttp.status);
}
}
xmlhttp.open("POST","myfile.xml",false);
xmlhttp.send();
The above code does everything like it's meant to.
However, as soon as I add the following code to the top the page:
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd">
when I load my function it comes up with the following message:
Panel not communicating.Reason: 200
however it still loads my XML file like how I want it to.
After searching around it says that xmlhttp status 200 means "OK"
Does anyone know why it's displaying this message?
It probably means that xmlhttp.readyState is transitioning to a state other than 4 ("complete") -- this can occur if the whole page doesn't download instantly, which is likely. Your function should probably return immediately when xmlhttp.readyState != 4, rather than treating that as an error condition.
You should also strongly consider using a Javascript framework such as jQuery here, as it will save you a lot of unnecessary effort. For instance, all of the code you've got here can be reduced to:
$.post("myfile.xml", function(data) {
alert(data);
}).error(function() {
alert("Panel not communicating.");
});
I think the code you added is not supposed to appear in XML, it was for HTML, so the browser may fail to parse the file, which made the xmlhttp.readyState==2, I am not sure for this value, may you check it.

Javascript is working on Safari, but fails on others

There is some problem that I can't find out why the code worked on Safari, but failed on other browsers.
There is the html part
and the main javascript part.
The main problem that I find is:
While executing the function downloadurl(url, function), cannot find the XML tags "Info", and the markers array length is 0 on many browsers. However, it's ok on Safari. The part of javascript code is like:
downloadUrl("http://travel-taoyuan.tycg.gov.tw/content/travel/xmlcontentlist1.aspx", function(doc) {
var xml = xmlParse(doc);
var markers = xml.documentElement.getElementsByTagName("Info");
......
To alert markers, it will return "0".
And actually it should be "174"(Safari's result).
Thanks for answering my question.
hmmm, seems to be a syntax error. Different browsers will use a different syntax, and so it won't execute (or at best, not properly if your lucky).
Try something along the lines of....
<script type="text/javascript">
if (window.XMLHttpRequest)
{// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp=new XMLHttpRequest();
}
else
{// code for IE6, IE5
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.open("GET","http://travel-taoyuan.tycg.gov.tw/content/travel/xmlcontentlist1.aspx",false);
xmlhttp.send();
xmlDoc=xmlhttp.responseXML;
var x=xmlDoc.getElementsByTagName("theMainTagName"); //TODO: this is the main tag ^(see note)
for (i=0;i<x.length;i++)
{
//TODO: code to handle each xml element
//this is the code to get the value from a particular tag: x[i].getElementsByTagName("theTagName")[0].childNodes[0].nodeValue
}
</script>
NOTE: ^the 'main' tag is, for example, in the case of this xml document, the 'main' tag is 'CATALOG'
Hope this helps. Sorry if it's not very clear, been a while since I worked with xml/javascript. Comment if you want further explanation

Load html file into a div with javascript?

I have a div which I want to populate with different html files from my server. Is there a simple way to do this? All I ever find are jquery samples and I don't want to use a library.
I have tried this:
document.getElementById('main').innerHTML = 'menu.html';
But that obviously just loaded text!
Some simple Ajax will do the trick for you. This is untested, but should give you the right idea:
var xmlhttp;
if (window.XMLHttpRequest)
{// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp=new XMLHttpRequest();
}
else
{// code for IE6, IE5
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange=function()
{
if (xmlhttp.readyState==4 && xmlhttp.status==200)
{
document.getElementById("main").innerHTML=xmlhttp.responseText;
}
}
xmlhttp.open("GET","menu.html",true);
xmlhttp.send();
Simplest way is to use a library, which the entire point of, they wrote the code for u. right?
Use the jQuery example. It is as good as it gets.
Is there a simple way? No, not without a library. That being said, you can do it on your own if you choose - that might be all that's necessary for you to come crawling back into the arms of jQuery ;)
Resource: XHR on Mozilla Developer Network

Path issue in ajax ,in a wordpress site

I have a wordpress site
for ex, www.test.com
There is a js file (forms.js)in the script folder of mytheme folder.
ie (theme/mytheme/script/forms.js)
There is a mail.php page in mytheme folder
ie (theme/mytheme/mail.php)
Following is the content of forms.js
function submitFormToEmail()
{
var xmlhttp;
if (window.XMLHttpRequest)
{// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp=new XMLHttpRequest();
}
else
{// code for IE6, IE5
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange=function()
{
if (xmlhttp.readyState==4 && xmlhttp.status==200)
{
//document.getElementById("results").innerHTML=xmlhttp.responseText;
alert("Form received, thank you!");
}
}
xmlhttp.open("GET","/mail.php",true);
xmlhttp.send();
}
I will call "submitFormToEmail",if we click a image in the page *www.test.com/hello_test*
Where "hello_test" page lies in theme/mytheme/.
But the mail.php is not working.
Let me know ,how can we set the path of mail.php in the function "submitFormToEmail", so that it will work
Calling /mail.php will look for the mail.php file at http://www.test.com/mail.php. Just fix the path?
Either directly code the correct path into the javascript file or use php to dynamically get it using get_bloginfo. There are several ways to do this, but probably the best way is to create a hidden element on the page that contains the url and then fetch this when building your ajax request. Otherwise you'd have to set php to parse js files and include it in there. Doesn't seem like a good way to me though.
get_bloginfo('template_url');

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