My script’s AJAX calls the following PHP file and prints a table with $attrib and text boxes.
Can somebody tell me how to collect the $attrib and text box in an array or something like that?
Code tried is giving values like "assetattrib%5B%5D=model". So please help me to correct this or show me a new way to do the same.
echo "<table border='1' cellspacing='12' cellpadding='4' style='border-collapse: collapse' width='700' id=addattrib >";
while ($row = mysql_fetch_assoc($results)) {
$attrib = $row['attrib'];
echo "<tr bgcolor='white'>
<td class='value'>$attrib</td>
<td class='value'><input type=text name=assetattrib[] value = '' </td>
</tr>";
}
echo "</table>";
echo "<input type=submit name='btnSaveAsset' id = 'btnSaveAsset' value='Save' >";
I tried the code below.
$(document).on("click", "#btnSaveAsset", function() {
$(document.getElementsByName('assetattrib[]')).each(function() {
var x = $(this).serialize();
alert(x);
});
});
IMPORTANT:
PHP mysql_ extension is deprecated and using it represents a major security issue. According to php.net
This extension is deprecated as of PHP 5.5.0, and has been removed as of PHP 7.0.0. Instead, either the mysqli or PDO_MySQL extension should be used.
Now the actual answer:
I suggest some changes in your HTML, if you can make them:
Wrap the table where the <input>s are into a <form> element
Give the generated <input>s the name attribute given by $attrib, for example <input name="user" />
If you cannot modify the PHP/HTML code let me know and we'll find a workaround
I updated your jsfiddle using this changes. Your PHP code should end up like this:
<form id="btnSaveAsset" onsubmit="return false;">
<table border='1' cellspacing='12' cellpadding='4' style='border-collapse: collapse' width='700' id='addattrib'>
<?php while ($row = mysql_fetch_assoc($results)) {
$attrib = $row['attrib']; ?>
<tr bgcolor='white'>
<td class='value'><?php echo $attrib; ?></td>
<td class='value'><input type='text' name='<?php echo $attrib; ?>' /> </td>
</tr>
<?php } ?>
</table>
<input type=submit name='btnSaveAsset' id='btnSaveAsset' value='Save' />
</form>
Then, you collect your data with one of this options:
$(document).on("click", "#btnSaveAsset", function () {
var data = $("#myForm").serializeArray();
console.log(data); // Array of objects
});
OR
$(document).on("click", "#btnSaveAsset2", function () {
var tempData = $("#myForm").serializeArray();
var data = {};
$.each(tempData, function () {
data[this.name] = this.value;
});
console.log(data); // Just an object
});
Here is the jsfiddle updated: http://jsfiddle.net/jormaechea/sy0wx8gb/1/
Check your JS console (Press F12 and go to Console tab) to see the results.
Related
I have a table of customers. Each customer has a first and a last name. The two text fields of the table are editable. So users can update the information when they press Save. The problem is that I cannot get the specific row information,I only get the first row results
I tried to match to the names with the input field but I had no success.
<?php foreach($customer as $each){ ?>
<td class="first_name" id="first" contenteditable="true"><?php echo
$each['first_name']; ?></td>
<td class="last_name" id="last" contenteditable="true"><?php echo
$each['last_name']; ?></td>
<td > <button type="button" onclick="save('<?php echo $each['first_name'];?
>','<?php echo $each['last_name'];?>');" >Save</button></td>
<? } ?>
<script type="text/javascript">
function save(first,second) {
<?php foreach($customer as $each){?>
var first_name = "<?php echo $each['first_name']?>";
var last_name = "<?php echo $each['last_name']?>";
if (first_name==first && last_name == second){
var fname = document.querySelectorAll(".first_name");
console.log(fname[0]);
}
<?php } ?>
}
</script>
You would have to use a different query selector. Assign a classname or an attribute to the elements you want to select (e.g name for querying with .name) then querySelectorAll method will return an array of the elements that matched your query.
The main problem that I see is that you create unnecessary foreach loop inside a javascript function using php.
You can dynamically create your table and the contents inside it, that's fine. But the javascript does not care about that and you should not create javascript with php. So I would do it this way.
I wrap the td's in tr's cause i'm assuming you are putting that data in tr.
<?php foreach($customer as $each){ ?>
<tr class="customer-row">
<td class="first_name" contenteditable="true"><?php echo
$each['first_name']; ?></td>
<td class="last_name" contenteditable="true"><?php echo
$each['last_name']; ?></td>
<td><button type="button" class="save">Save</button></td>
</tr>
<? } ?>
Then outside the php foreach loop i would create my script.
<script type="text/javascript">
var saveBtn = document.querySelectorAll(".save");
for(var i = 0; i < saveBtn.length; i++) {
// attach click event to every button.
saveBtn[i].addEventListener("click", function() {
var _this = this;
var _tr = _this.closest(".customer-row");
var fname = _tr.querySelector(".first_name").innerText;
var lname = _tr.querySelector(".last_name").innerText;
console.log("Name: ", fname + " " + lname");
// below you can implement your check name logic...
}
}
</script>
I'm not 100% sure if my js will not throw errors, but it should give you an indication that you should separate your server-side from client-side logic.
I'm avoiding using a database for my latest project and so I am using files and folders. I list folders of a directory as buttons and each one loads a screen with a list of files within it. I'm now trying to load in the file's contents dynamically without refresh to avoid loosing the menu (list of files shown on screen as buttons). I'm trying to use ajax but because the file buttons are created using a foreach php loop, the value I pass to javascript/ajax when I click one of the file buttons is incorrect as it always wants to pass the first button's value in the list!
Here is the PHP code:
<?php
if(isset($_POST['FolderContent'])) {
foreach (glob($_POST['FolderContent']."/*.*") as $file) {
if(is_file($file)){
$fileNoExt = substr($file, 0, -4); //Remove file extension so the menu item shows only the name of the file
$character = explode('/', $fileNoExt);
$filePathTrimmed = trim(end($character));
echo "<form method='POST'>
<input type='submit' ID='selectBtn' value='$filePathTrimmed' onclick='return displayData();'/>
<input type='hidden' id='dataField' name='content' value='$file'/>
<input type='hidden' name='title' value='$filePathTrimmed'/>
</form>";
} else {
echo "Files not found!";
}
}
}
?>
And this is the JS:
<script>
function displayData()
{
var btnData = document.getElementByID('selectBtn').value;
alert("The currently selected button is "+btnData);
});
}
</script>
As you can see the PHP loops and creates a form for each button plus hidden fields. The JS just tries to grap the value of the button clicked and alert it. Problem is that the value is always the first file in the list.
What am I doing wrong please? If I use a class on the button instead of an ID then I will need to state the number in the array:
var btnData = document.getElementsByClassName('selectBtn')[0].value;
But this means I'd need to know the place within the array and make using the value pretty pointless.
I'm pretty stuck - or thick!
Thanks.
You need to use this inside onclick='return displayData(); and then use it in your function like below:-
Working snippet:-
function displayData(ele){
var btnData = ele.value;
alert("The currently selected button is "+btnData);
return false;
}
<form method='POST'>
<input type='submit' value='hi' onclick='return displayData(this);'/>
<input type='hidden' name='content' value='$file'/>
<input type='hidden' name='title' value='$filePathTrimmed'/>
</form>
You are setting the same id value for each separate form. You should ensure that all the id attribute values are unique for all html elements as a rule of thumb to avoid unpredictable behaviours in the dom.
<?php
if(isset($_POST['FolderContent'])) {
foreach (glob($_POST['FolderContent']."/*.*") as $idx => $file) {
if(is_file($file)){
$fileNoExt = substr($file, 0, -4); //Remove file extension so the menu item shows only the name of the file
$character = explode('/', $fileNoExt);
$filePathTrimmed = trim(end($character));
echo "<form method='POST'>
<input type='submit' id='selectBtn-{$idx}' value='$filePathTrimmed' onclick='return displayData(this.id);'/>
<input type='hidden' id='dataField' name='content' value='$file'/>
<input type='hidden' name='title' value='$filePathTrimmed'/>
</form>";
} else {
echo "Files not found!";
}
}
}
?>
And javascript:
<script>
function displayData(clicked_id)
{
var btnData = document.getElementByID(clicked_id).value;
alert("The currently selected button is "+btnData);
return false;
}
</script>
Solution: I used 'return false' at the end of the javascript/ajax code block, and 'this' in the php code to pass current data held in 'value' - thanks Alive to Die.
I also I made use of the 'name' attribute to store and access further data data.
PHP:
echo "<form method='POST'>
<input type='submit' id='selectBtn' name='$file' value='$filePathTrimmed' onclick='return displayData(this);'/>
</form>";
JS:
<script>
function displayData(fileName)
{
var btnData =fileName.name;
var name = fileName.value;
$.ajax({
type : "POST",
url : "DisplayFileContents.php",
data : {"data": btnData, "name": name},
success : function(result) {
$('.page-content').html(result);
$('body').animate({scrollTop: 0}, 200);
}
});
return false;
};
DisplayFileContents.php:
<?php
$filename=$_POST['data'];
$title = $_POST['name'];
echo "<h2>".$title."</h2>";
echo "<pre>";
Include $filename;
echo "</pre>";
?>
I'm trying to make an HTML table dynamically. I'm just testing with sample, but It's not working as well as I expected. So, I'm asking this question. Let me show you this simple table, it is MySQL database. and I create HTML table.
What I want to do is when I click some node, like a '250', this number will be editable. Edited data will be saved to the MySQL database. So I use the contenteditable="true" attribute value, and when this node loses focus, run some JavaScript function that new data will be saved.
But... It's not working well. Honestly I don't know what the problem is exactly. Google chrome spit up "Uncaught Syntax Error, Unexpected token } ", But I couldn't find what the actual problem is. I'm newbie on this... Could you some guys help me?
sample.html
<body>
<?php
require_once("db_connect.php");
$sql = "SELECT * FROM test";
$result = $conn->query($sql);
?>
<table border="1" style="border-collapse:collapse;">
<thead>
<tr><th>name</th><th>price</th></tr>
</thead>
<tbody>
<?php
while($row = $result->fetch_assoc()){
echo
"<tr>
<td contenteditable='true' onBlur='saveToDatabase(this,'name','$id')'>{$row['name']}</td>
<td contenteditable='true' onBlur='saveToDatabase(this,'price','$id')'>{$row['price']}</td>
</tr>\n";
}
?>
</tbody>
</table>
<script>
function saveToDatabase(editableObj, column, id) {
$.ajax({
url: "saveedit.php",
type: "POST",
data:'column='+column+'&editval='+editableObj.innerHTML+'&id='+id,
success: function(data){
$(editableObj).css("background","#FDFDFD");
}
});
}
</script>
</body>
</html>
saveedit.php
<?php
require_once("db_connect.php");
$result = mysql_query("UPDATE test SET ". $_POST["column"]. " = '".$_POST["editval"]."' WHERE id=".$_POST["id"]);
?>
You made it contenteditable but PHP needs an parameter. For example
<input type="text" name="parameter">
will send as $_POST['parameter'] but in your code <td> elements don't have a name. So PHP doesn't know if there is a parameter or what name is.
Maybe you can write your own editable function in Javascript like this:
function doTextArea(i) {
document.getElementById(i).innerHTML="<input type='text' name='table_value'>ssss.";
}
and your php loop can be like this ( I assume it is for loop):
for ($i = 1; $i <= 10; $i++) {
echo
"<tr>
<td><p id=$i ondblclick='doTextArea($i)'> sadasdasdasd</p></td>
</tr>\n";
}
Ive this php code in global.php to generate a table
<table>
<tbody>
<?php
for($i=1; $i<=30; $i++)
{
echo '
<tr class="adding">
<td>'.$i.'</td>
<td><input type="text" class="barcode" name="barcode[]" size="13" maxlength="13"></td>
<td><input type="text" class="prodotto" name="prodotto[]"></td>
<td><input type="text" class="prezzo" name="prezzo[]"></td>
</tr>';
}
?>
</tbody>
</table>
<script src="js/global.js"></script>
and this is my global.js file
$(document).on("blur", ".barcode", function(){
var barcode =$(this).find('input.barcode').val();
if(barcode!='')
{
$.post('ajax/barcode_prodotto.php', {name: barcode}, function(data){
$(this).find('input.prodotto').val(data);
});
}
});
and this is barcode_prodotto.php that I'm using to retrive data from DB using jquery post function as described:
<?php
mysql_connect("localhost","root","");
mysql_select_db('test');
if(isset( $_POST['name'])===true && empty($_POST['name'])===false){
$query=mysql_query("
SELECT prodotto as prodotto
FROM barcode_prodotto
WHERE barcode_prodotto='".mysql_real_escape_string(trim($_POST['name']))."'");
echo (mysql_num_rows($query)!==0)? mysql_result($query, 0, 'prodotto') : 'prodotto not found';
}
?>
It doesnt work but I'm sure that the problem is on global.js file because I the others 2 php files with id and not class and everything were ok.
Change your global js to this:get the current object in some other variable to use inside post ajax call and find the td input to place the value inside.
$(document).on("blur", ".barcode", function(){
var that=this;
var barcode =$(this).val();
// console.log(barcode);
if(barcode!='')
{
$.post('testing.php', {name: barcode}, function(data){
$(that).closest("tr").children('td').slice(2,3).find("input").val(data);
});
}
});
demo
I'm working on a MySQL update form and struggle to make a drop down selectbox that will autofill the rest of the form with data from mysql. Basically its a table that consist of users and their credentials. When updating a second table with this form i want to be able to select the username from a drop menu and let that selection autofill the rest of the credentials before moving on to the rest of the form.
Here is some of the code for setting up the select and input:
<?php
//DB Connect
...
// Get array of users
$select_users = "SELECT * FROM users";
if (!mysql_query($select_users)) {
die('Error: ' . mysql_error());
} //all good so far
$select_users_result = mysql_query($select_users);
?>
<select id="selectbox" name="navn" onchange="populateData(this.value)">
<option>USER</option>
<?php
$klubb = array();
$klasse = array();
while ($row = mysql_fetch_array($select_users_result, MYSQL_ASSOC)) {
echo "<option value='" . $row['navn'] . "'>". $row['navn'] ."</option>";
//echoing these vars will output all rows for the column specified...
$klubb[] = $row['klubb'];
$klasse[] = $row['klasse'];
}
mysql_close();
?>
</select>
<tr>
<td>Klubb: </td>
<td><input id="klubb" type="text" name="klubb" class="cred_input" />
</td>
</tr>
<tr>
<td>Klasse: </td>
<td><input id="klasse" type="text" name="klasse" class="cred_input" /> </td>
</tr>
And then some javascript
<script>
function populateData()
{
//alert('in populateData');
y = document.getElementById("selectbox");
document.getElementById("klasse").value = [y.selectedIndex];
document.getElementById("klubb").value = [y.selectedIndex];
}
</script>
The result here is a number in the <td>klubb and <td>klasse based on my selection in the drop menu.
How can i connect the arrays with that index number in the javascript so that it will show the actual data from the array ?
I've been seeking an answers for a few days now but can't find anything that answers my question.
Thanks for any help!
Well you can use AJAX for that.
For a tutorial on how to use AJAX and PHP script with Mysql This can help you.
First you need to create a PHP script that will gather the data you need for filling up the forms.
Setup the AJAX to be triggered everytime you choose something in your Drop Down List and pass its value on the PHP script you created.
On your AJAX script configure it to call the PHP script you created for retrieving the data (a value will be thrown in this script based on your drop down list).
Once you receive a response from your AJAX call just use a simple Javascript to fill up the forms based on the data your received.
Another tip is to use JQuery since it is easier for you to setup your AJAX request.
Use AJAX here.
In the populateData() function, use ajax to send the request to retrieve the user credentials & through Javascript, populate your textboxes with the retrieved values.
You could echo the two php arrays as javascript objects, and then access those in your populate function (this is the quick solution). But a better way is to ajax in the actual data
<script>
var klasse = <?=json_encode($klasse)?>
var klubb = <?=json_encode($klubb)?>
</script>
Well you can use Ajax. Make this as your form.
<?php
//DB Connect
...
// Get array of users
$select_users = "SELECT * FROM users";
if (!mysql_query($select_users)) {
die('Error: ' . mysql_error());
} //all good so far
$select_users_result = mysql_query($select_users);
?>
<select id="selectbox" name="navn" onchange="populateData(this.value)">
<option>USER</option>
<?php
$klubb = array();
$klasse = array();
while ($row = mysql_fetch_array($select_users_result, MYSQL_ASSOC)) {
echo "<option value='" . $row['navn'] . "'>". $row['navn'] ."</option>";
//echoing these vars will output all rows for the column specified...
$klubb[] = $row['klubb'];
$klasse[] = $row['klasse'];
}
mysql_close();
?>
</select>
<div id="some_container">
</div>
Your AJAX request :-
<script type="text/javascript">
$('select').on('change', function() {
var selectedVal = this.value; // or $(this).val()
$(document).ready(function() {
$.ajax({ //create an ajax request to load_page.php
type: "GET",
url: "file.php?selectedVal="+selectedVal,
dataType: "html", //expect html to be returned
success: function(response){
$("#some_container").html(response);
}
});
});
});
</script>
file.php
<?php
echo '
<tr>
<td>Klubb: </td>
<td><input id="klubb" type="text" name="klubb" class="cred_input" value="$phpValueHere"/>
</td>
</tr>
<tr>
<td>Klasse: </td>
<td><input id="klasse" type="text" name="klasse" class="cred_input" value="$phpValueHere> </td>
</tr>';
?>
In your file.php, get the value of selectedVal via $_GET['selectedVal'] and then extract data from table, after extracting echo the data in those input boxes.