Develop Reference

how to refresh div without refreshing all php data

I would think this is simple but cannot figure it out for the life of me.. I want to refresh a div without refreshing everything.. I have a timer on each image that counts down from 24 hrs to 0 then disappears.. it all works but I cant seem to just refresh the timer div..
My php -
$date = date('Y-m-d H:i:s');
$sql = "SELECT * FROM images";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
$path = $row['path'];
$user = $row['user'];
$update = $row['update_date'];
$timeFirst = strtotime($date);
$timeSecond = strtotime($update);
$timeSecond = $timeSecond + 86400;
$timer = $timeSecond - $timeFirst;
if($timer <= 0){
}else{
echo '<img id="pic" src="/v2/uploads/'.$path.'"/>';
echo '<div id="user">#'.$user.'</div>';
echo '<div id="timer">'.$timer.' </div>';
}
}
}
I would like to refresh just the timer at 1 second intervals not the images.. I know I can use ajax to call it from an external file that loads all the content also as far as I know..Still new at this. *side not this is chopped up code for the example not all of it.

As per my comment, you could do something like this:
Add class "timer" to your #timer element (if you have more than one #timer element, use different ID for each element).
Create php script which returns new $timer whenever it's called:
ajax-timer.php
<?php
/* include file where $conn is defined */
$response = array();
$date = date('Y-m-d H:i:s');
$sql = "SELECT * FROM images";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
$update = $row['update_date'];
$timeFirst = strtotime($date);
$timeSecond = strtotime($update);
$timeSecond = $timeSecond + 86400;
$timer = $timeSecond - $timeFirst;
if($timer > 0) {
//Add just timer to response array
$response[] = $timer;
}
}
}
//Return json response and handle it later in ajax:
echo json_encode(array(
'result'=>empty($response) ? 0 : 1,
'data'=>$response));
die();
Request data from ajax-timer.php with $.ajax and populate data when response is received:
timer-update.js
var ajaxTimerThread = 0;
var ajaxTimerRunning = false;
function ajaxTimerRun() {
//Prevent running function more than once at a time.
if(ajaxTimerRunning)
return;
ajaxTimerRunning = true;
$.post('ajax-timer.php', {}, function (response) {
ajaxTimerRunning = false;
try {
//Try to parse JSON response
response = $.parseJSON(response);
if (response.result == 1) {
//We got timer data in response.data.
for(var i = 0; i < response.data.length; i++) {
var $timer = $('.timer').eq(i);
if($timer.length) {
$timer.html(response.data[i]);
}
}
}
else {
//Request was successful, but there's no timer data found.
//do nothing
}
//Run again
ajaxTimerThread = setTimeout(ajaxTimerRun, 1000); //every second
}
catch (ex) {
//Could not parse JSON? Something's wrong:
console.log(ex);
}
});
}
$(document).ready(function() {
// Start update on page load.
ajaxTimerRun();
})

Toss your existing php code into a separate .php file
Then use a jquery method called load() to load that php file into your div.
$(document).ready(function() {
$("#div_ID_you_want_to_load_into").load("your_php_file.php");
var pollFrequency = function() {
if (document.hidden) {
return;
}
$("#div_ID_you_want_to_load_into").load('your_php_file.php?randval='+ Math.random());
};
setInterval(pollFrequency,18000); // microseconds, so this would be every 18 seconds
});
Now, within this code above is something is not needed, but can be helpful, and that is the if (document.hidden) {return;} which is basically a command to the browser that if the browser tab is not in-focus do not fire off the setInterval poll.
Also a good idea to keep in the randval= math stuff, just to make sure there is no caching.

Moment js stops working after ajax call

Below is my code to convert time to a fancy style for eg. 1 min ago, 9 hours ago etc using moment.js.
<script>
$(document).ready(function() {
var out = "";
var diffDays = moment.utc("<?php echo $row["created_date"]; ?>", "YYYY-MM-DD hh:mm").fromNow();
out += "<span class='glyphicon glyphicon-time hours'></span> "+ diffDays;
$("#divContent<?php echo $row["postid_userid"]; ?>").html(out);
});
</script>
The code is working fine.
I have an ajax load more option on the same page to load more posts when scrolling.
My main problem is that, the moment js I am using stopped working after ajax call. Is this the problem because the code is not getting moment.js on my ajax page get_results.php ?
This is my ajax function (which is on the same page and calls the other page to load more posts)
<script type="text/javascript">
$(window).scroll(function(){
if ($(window).scrollTop() == $(document).height() - $(window).height()){
var val = document.getElementById("id").value;
document.getElementById("id").value = Number(val)+5;
$.ajax({
type: 'post',
url: 'get_results.php',
data: {
getresult:val
},
success: function (response) {
loading = false;
if(response.trim().length == 0){
//notify user if nothing to load
$('.loading-info').html("No more posts!");
document.getElementById("loading-info").style.display = "block";
return;
}
else
{
var content = document.getElementById("all_rows");
content.innerHTML = content.innerHTML+response;
}
$('.loading-info').hide(); //hide loading animation once data is received
}
});
}
});
And this is the get_results.php page:
<?php session_start();
$user_id=$_SESSION['user_id'];
include "mydbfile.php";
if(isset($_POST['getresult']))
{
$no = $_POST['getresult'];
?>
<?php
$select =$conn->prepare("select * from ----- ");
$select->execute();
while($row =$select->fetch())
{
?>
//design to display more posts
<?php
}
} exit(); ?>

AJAX get() data

I have a block of jQuery which uses the $.get() method in a setInterval(). I don't understand how to get data from the second URL to the jQuery code.
Jquery:
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.5/jquery.min.js"></script>
<script type="text/javascript">
setInterval(function() {
$.getJSON("check_time.php", function(update) {
if (update) {
$("#slideshow").load("phppage.php");
}
});
}, 600000);
</script>
PHP - check_time.php
<?php
require_once('connect_pdo.php');
header('Content-type: application/json');
$stmt = $conn->prepare("$sqlst = $conn->prepare("SELECT COUNT(*) AS count
FROM ads
WHERE lastupdate > NOW() - INTERVAL 10 MINUTE");
$sqlst->execute();
$row = $sqlst->fetch();");
$stmt ->execute();
$row = $stmt ->fetch();
$update = $row['count'] > 0;
$updtstatus = json_encode($update);
echo "$updtstatus";
?>
I am not getting the variable from check_time.php to the update variable in function(update).

Small alter in php page
$updtstatus = json_encode(array('count'=>$update));
echo $updtstatus;
Now your JSON is in fact something like this {"count":"true"}.
So change your if statement slightly.
$.getJSON("check_time.php", function(update) {
if (update.count===true) {
$("#slideshow").load("phppage.php");
} else {
console.log("No results");
}
});
This fiddle simulates the above answer

Your jQuery functions expects data to be returned in JSON format, so simply do so :) I've also found some flaws within your PHP code. This should do the trick:
$.get('check_time.php', function(data) {
console.log(data); // Console logging is always good
if (data.status) {
alert('Load slideshow');
}
});
check_time.php
<?php
require_once('connect_pdo.php');
$json = []; // The JSON array which will be returned
$stmt = $conn->prepare("SELECT COUNT(*) AS count FROM ads WHERE lastupdate > NOW() - INTERVAL 10 MINUTE");
$stmt->execute();
$json['status'] = (bool) $stmt->rowCount(); // Status is either false (0) or true (> 0)
echo json_encode($json);

JQuery form submission generates a new form

I have a JQuery script that submits user input to a PHP script in the same file, and then displays the result of what the PHP script does with the input. That part works fine. The issue that I’m having is that, upon submission, the JQuery script (at least, I think it's the script) also generates a new submission box below the original.
I’m not sure why. I thought at first that it was an issue with the input type, with the asynchronous part, or even with where I had the form in the overall code, but none of those seem to be playing any role. I'm still a beginner and I'm just not seeing the issue.
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.0/jquery.min.js"></script>
<form id = "my_form">
verb <input type = "text" id ="word1"/>
<input type = "submit"/></form>
<div id="name"></div>
<script>
$(document).ready(function(){
$("#my_form").on('submit', function(e)
{
e.preventDefault();
var verb = $ ("#word1").val();
var tag = "#Latin ";
var url = "http://en.wiktionary.org/wiki/"+verb+tag;
$.ajax({
url: "Parser.php",
data: {"verb": verb},
type: "POST",
async: true,
success: function(result){
$("#name").html(result);
$("#name").append(url);
}
});
});
});</script>
RESULT:
PHP
<?php
$bank = array();
function endsWith($haystack, $needle) {
return $needle === "" || (($temp = strlen($haystack) - strlen($needle)) >= 0 && strpos($haystack, $needle, $temp) !== false);
}
function check_end_array($str, $ends)
{
foreach ($ends as $try) {
if (substr($str, -1*strlen($try))===$try) return $try;
}
return false;
}
function db_connect() {
static $connection;
if(!isset($connection)) {
$connection = mysqli_connect('127.0.0.1','username','password','Verb_Bank');
}
if($connection === false) {
return mysqli_connect_error();
}
return $connection;
}
function db_query($query) {
$connection = db_connect();
$result = mysqli_query($connection,$query);
return $result;
}
function db_quote($value) {
$connection = db_connect();
return "'" . mysqli_real_escape_string($connection,$value) . "'";
}
$y = false;
if (isset($_POST['verb'])){
$y=db_quote($_POST['verb']);
echo $y;
echo "\n";
$m = db_query("SELECT `conjugation` FROM normal_verbs WHERE (" . $y . ") LIKE CONCAT('%',root,'%')");
if($m !== false) {
$rows = array();
while ($row = mysqli_fetch_assoc($m)) {
$rows[] = $row;
}
}
foreach ($rows as $key => $value){
if (in_array("first",$value)==true){
echo "first conjugation verb\n";}
$y = $_POST["verb"];
$x = $y;
foreach ($bank as $key => $value)
(series of IF-statements)
}}?>

As Roamer-1888 says's the problem lies in server side, you are returning a html which has a input too. You need to change your code to return only the result string which you append to the div. Else if this is not possible doing at server side as it might require you to change lot of code, then you can strip off the input element from the result and then append it to the div. Like below.
success: function(result){
var div = document.createElement('div');
div.innerHTML = result;
$(div).find('input').remove();
$("#name").html(div.innerHTML);
$("#name").append(url);
}

Set interval with AJAX

The purpose is to display a DIV when you click on a button and then display text inside that DIV that comes from my database. Thing is that data in databse changes, so text inside that div also. I would need a setInterval... with AJAX
I'm new in javascript and don't know the good way to go...
HTML:
<div onClick="showDiv();"> click </div>
<div style="display: none;" id="div">
Info from database:
<span style="display: hidden;" id="data1"> DATA 1 </span>
<span style="display: hidden;" id="data2"> DATA 2 </span>
</div>
javascript:
function showDiv()
{
document.querySelector("#div").style.display = "block";
setInterval(function () {getData()}, 1000);
}
function getData()
{
$.post(
'process.php',
{
},
function(data){
if(data == '1'){
document.querySelector("#data1").style.display = "inline";
}
else if(data == '2'){
document.querySelector("#data2").style.display = "inline";
}
},
'text'
);
return false;
}
//don't know how to just take data from database without sending by POST or GET.
php:
<?php
SELECT x FROM database
if(x == 1)
{echo '1';}
else if(x == 2)
{echo '2';}
?>

Get data using AJAX : Learn here. Your code to setInterval() is correct or you can do this : setInterval(getData,1000);
Display data in spans :
document.getElementById("data1").innerHTML = "your content from database";
document.getElementById("data2").innerHTML = "your content from database";

You're not giving a lot of info so I will give you a basic example of getting data from a mySQL database with jQuery, Ajax and PHP.
First you need to include jQuery to the head of your document
<script src="http://code.jquery.com/jquery-latest.js"></script>
And then use Ajax
function showDiv(){
document.getElementById("div").style.display = "";
setInterval(function (){ getData('something'); }, 1000);
}
jQuery.noConflict();
jQuery(document).ready(function($){
getData = function(variable){
var postVar = variable;
var postVar2 = "exemple";
$.ajax({
type: "POST",
url: "php/file.php",
data: 'variable=' + postVar + "&" +
'variable2=' + postVar2,
success: function(data){
data = $.trim(data);
var dataSplit = data.split("++==09s27d8fd350--b7d32n0-97bn235==++");
if(dataSplit[0] == "1"){
document.getElementById("data1").innerHTML = dataSplit[1];
}
if(dataSplit[0] == "2"){
document.getElementById("data2").innerHTML = dataSplit[1];
}
}
});
}
});
Finally, you need to create an external php file (in this example "file.php" in the folder "php") to get the data from your database with mysqli
<?php
// to prevent error, I check if the post variable is set and
// if it's not only full of spaces
if(isset($_POST['variable']) && preg_replace("/\s+/", "", $_POST['variable']) != ""){
$con = mysqli_connect("hostname", "username", "password", "database_name");
$query = mysqli_query($con, "SELECT * FROM `table_name` WHERE `column_name` = '".$_POST['variable']."'");
$results = array(); $row = 0;
while($info = mysqli_fetch_array($query, MYSQLI_ASSOC)){
$results[$row] = array();
$results[$row]['column_name1'] = $info['column_name1'];
$results[$row]['column_name2'] = $info['column_name2'];
$row++;
}
foreach($results as $result => $data){
echo "1" . "++==09s27d8fd350--b7d32n0-97bn235==++" .
'<div>'.$data['column_name1'].'</div>'.
'<div>'.$data['column_name2'].'</div>';
}
}
?>
Hope it helps!