Regular expression start and end with word [closed] - javascript

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The below code is full of string. I want to select cbUserURLs array variable.
var someurl =new Array('a','b');
var cbUserURLs =new Array('url1','url2',...);
.. //some code
What is the regular expression should I use here?

You just need use cbUserURLs.*\); if what you want is

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How to remove the array in a string? [closed]

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loginTime: "[2021-01-18 06:18:57.000000]";
I need this to -> "2021-01-18 06:18:57.000000";
how to remove the array and make it just string?
You could use something like this
"[2021-01-18 06:18:57.000000]".replace(/\[|\]/g, '')
Matches the character "[" and "]", replaces them with nothing.

Delete number after slash in javascript [closed]

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Hey lets say I have url like this:
http://google.com/1/2
How do I delete last number(after last slash character)? all numbers can vary in length.
var URL = "http://google.com/1/2";
var newUrl = URL.substring(0, URL.lastIndexOf('/'));
console.log(newUrl);

how to summarize this string in javascript? [closed]

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i want summarize this line in javascript!
how is it possible?
var c='['+']'+'('+')'+';'+':'+'<'+'>'+
'='+'<='+'/='+'>='+'+'-'+'&'+'*'+'/'+'=>';
I searched for character escapes but i found nothing!
I think this is what you want:
var opr_re = /\[|\]|\(|\)|;|:|<|>|=|<=|\/=|>=|\+|-|&|\*|\/|=>/;
\ is the escape character in regular expressions.

Email regular expression Javascript [closed]

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I have a email regex . But i want to allow only 1 to 20 characters before the # symbol in the regex.
([\w-\"]+(?:\.[\w-\"]+))#((?:[\w-]+\.)*\w[\w-]{0,255})\.([a-z]{2,6}(?:\.[a-z]{2})?)
Any help would be appreciated.
You're better off checking outside of the regex, but there happens to be a way in this specific case:
(?=[^#]{1,20}#)([\w-\"]+(?:\.[\w-\"]+))#...

Regular expression needed [closed]

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I want the regular expression to extract the &[1], &[2},&[3],&[4] values from the following string, with comma delimited.
var str = "Sum({[Account].&[1]+[Account].&[2]+[Account].&[3]+[Account].&[4]})";
Thanks for your help
(&\[\d+\]) Seperates them in to groups, you have to delimit them with commas yourself but that's not a big problem.. :P
Btw.: This is a great test for regex testing purposes http://rubular.com/r/0kLKf1gTaD

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