I'm having some trouble getting my form to submit data to my PHP file.
Without the AJAX script that I have, the form takes the user through to 'xxx.php' and submits the data on the database, however when I include this script, it prevents the page from refreshing, displays the success message, and fades in 'myDiv' but then no data appears in the database.
Any pointers in the right direction would be very much appreciated. Pulling my hair out over this one.
HTML
<form action='xxx.php' id='myForm' method='post'>
<p>Your content</p>
<input type='text' name='content' id='content'/>
<input type='submit' id='subbutton' name='subbutton' value='Submit' />
</form>
<div id='message'></div>
JavaScript
<script>
$(document).ready(function(){
$("#subbutton").click(function(e){
e.preventDefault();
var content = $("#content").attr('value');
$.ajax({
type: "POST",
url: "xxx.php",
data: "content="+content,
success: function(html){
$(".myDiv").fadeTo(500, 1);
},
beforeSend:function(){
$("#message").html("<span style='color:green ! important'>Sending request.</br></br>");
}
});
});
});
</script>
A couple of small changes should get you up and running. First, get the value of the input with .val():
var content = $("#content").val();
You mention that you're checking to see if the submit button isset() but you never send its value to the PHP function. To do that you also need to get its value:
var submit = $('#subbutton').val();
Then, in your AJAX function specify the data correctly:
$.ajax({
type: "POST",
url: "xxx.php",
data: {content:content, subbutton: submit}
...
quotes are not needed on the data attribute names.
On the PHP side you then check for the submit button like this -
if('submit' == $_POST['subbutton']) {
// remainder of your code here
Content will be available in $_POST['content'].
Change the data atribute to
data:{
content:$("#content").val()
}
Also add the atribute error to the ajax with
error:function(e){
console.log(e);
}
And try returning a var dump to $_POST in your php file.
And the most important add to the ajax the dataType atribute according to what You send :
dataType: "text" //text if You try with the var dump o json , whatever.
Another solution would be like :
$.ajax({
type: "POST",
url: "xxxwebpage..ifyouknowhatimean",
data: $("#idForm").serialize(), // serializes the form's elements.
dataType:"text" or "json" // According to what you return in php
success: function(data)
{
console.log(data); // show response from the php script.
}
});
Set the data type like this in your Ajax request: data: { content: content }
I think it isnt a correct JSON format.
Related
I try to get post data from using alert() and its worked problem is that data is not passing to php page result is always {"success":false,"result":0}
What I want is send password to php page and hash it using password_hash() and return result
$('#spass').on('submit',function(){
var that=$(this),
contents=that.serialize();
alert(contents);
$.ajax({
url:'passwordhashing.php',
dataType:'json',
data:contents,
success:function(data){
alert(JSON.stringify(data));
console.log(data);
}
});
return false;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<form id="spass" >
<h4>Change Your Password</h4>
<input type='password'name="passc" >
<!--<input type='password' name="cpass" id="cpass"> -->
<input type="submit">
</form>
**this my php code**
<?php
header('Content-type: text/javascript');
$json=array(
'success'=>false,
'result'=>0
);
if(isset($_POST['passc']) && !empty($_POST['passc'])) {
$pass=password_hash($_POST['passc'],PASSWORD_DEFAULT);
$json['success']=true;
$json['result']=$pass;
}
echo json_encode($json);
?>
You can test that your data has not actually been passed to a PHP page.
In the PHP code, do the following: echo $ _POST ['YOUR_VARIABLE'].
Check the INSPECT_ELEMENT / NETWORK browser to make sure you actually send data to the correct link. Your link may be relative, so you may be sending data to the wrong link.
So, try to put the entire link in the ajax url
$ .ajax ({
url: 'HTTP: //WHOLE_LINK_IN_HERE.COM/passwordhashing.php',
});
SET method in Ajax: type: "POST"
$.ajax({
type: "POST",
url: url,
data: data,
success: success,
dataType: dataType
});
**i used $.post() instead of using $.ajax() and it fix my problem**
$('#spass').on('submit',function(){
var that=$(this),
contents=that.serialize();
alert(contents);
$.post({
url:'passwordhashing.php',
dataType:'json',
data:contents,
success:function(data){
alert(JSON.stringify(data));
console.log(data);
}
});
return false;
});
Having some difficulty understanding how to access type="file" input on the server side. Below is the code I'm using. I use AJAX because I want my web app to not require refreshing, and am using a slightly roundabout way of submitting my form so I can have a better UI.
My HTML:
<form id="updateProfileImageForm" enctype="multipart/form-data">
<div class="updateProfileImageContainer">
<img src="images/profile/generic.png" class="updateProfileImage">
<div class="updateProfileImageOverlay" onclick="changeImageToUpload()">
<div class="updateProfileImageOverlayText">Upload new image</div>
</div>
<input type="file" id="imageToUpload" name="image" style="display: none;" onChange="$(this).closest('form').trigger('submit');"></input>
</div>
</form>
My JS:
function changeImageToUpload() {
$('#imageToUpload').trigger('click');
}
$('#updateProfileImageForm').submit(function(e) {
e.preventDefault();
var form_data = new FormData(this);
$.ajax({
type: 'POST',
url: '/changeProfile',
data: form_data,
processData: false,
success: function(response) {
if(response.message != null) {
alert(response.message);
} else {
// Change profile image displayed
$('.updateProfileImage').attr("src", response.newProfileImage);
alert('Profile picture successfully updated! Refresh your browser to update your window!');
}
}
})
});
My Server PHP:
if (isset($_FILES['image'])) {
$image = $_FILES['image'];
}
Var_dump on $_FILES shows an empty array, while var_dump on $_POST shows a lot of information (which I'm assuming is my data file). However, accessing the 'image' property on either $_POST or $_FILES (through either $_POST['image'] or $_FILES['image']) gives me either "undefined index" or "undefined variable".
Would you guys be so kind as to educate me on:
What's the difference between $_POST and $_FILES?
How should I be accessing the file in this case?
Thanks!
You're missing a necessary config option in your ajax request, you need to set contentType to false
$.ajax({
type: 'POST',
url: '/changeProfile',
data: form_data,
processData: false,
contentType: false,
success: function(response) {
if(response.message != null) {
alert(response.message);
} else {
// Change profile image displayed
$('.updateProfileImage').attr("src", response.newProfileImage);
alert('Profile picture successfully updated! Refresh your browser to update your window!');
}
}
})
jQuery.ajax sets the content type by default to application/x-www-form-urlencoded which is incorrect for your FormData object, if you set it to false it will be set correctly by the underlying XMLHTTTPRequest object.
Idea behind it.
Instead of using file as post to PHP, simply convert image to base64 and receive that string using ajax in php.
Refer to this URL
I am trying to submit a form which will insert data into a mysql database which is working fine. I then would like to return the id of the new inserted row (id auto increment in mysql table) as I want to open up a modal once the form is submitted so I can provide a link which includes id as a parameter in the url.
To send the data for the form I am using the following code:
$(document).ready(function(){
$("#submitForm").click(function(){
var string = $('#commentForm').serialize();
// AJAX Code To Submit Form.
$.ajax({
type: "POST",
url: "SubmitData.php",
data: string,
cache: false,
success: function(result){
//alert(result);
}
});
});
});
The SubmitData.php file then inserts the form data into the database.
In the SubmitData.php I can create a variable to pick up the id of the newly inserted row like
$last_id = mysqli_insert_id($conn);
Is there a way I can return the $last_id from the SubmitData.php file within the same function?
Yes return from SubmitData.php the id using the following echo:
echo json_encode(['id'=>$last_id]);
js:
$(document).ready(function(){
$("#submitForm").click(function(){
var string = $('#commentForm').serialize();
// AJAX Code To Submit Form.
$.ajax({
type: "POST",
url: "SubmitData.php",
data: string,
cache: false,
success: function(result){
alert(result.id);//this will alert you the last_id
}
});
});
});
print last id in that php file
echo $last_id;
get that in ajax success function
success: function(result){
alert(result);
}
Im learning Ajax...normally I dont like posting about a subject I know very little of but I believe Im on the right path here (maybe not...?) so I will take a chance to find out.
Ive got 3 select boxes each box populates with values based on the the selection of the box before it:
Everything is working perfectly, when the user clicks submit I want to send the 3 textbox values to 3 php variables and echo it on the same page...
Now my data is not echoing (the data of the variables are not displaying) but when I look in my console on firefox I can see the value of the variables...
Here is the selection made on the select boxes
Here is what im seeing in my console
Yet it is does not echo on the page....?
jQuery(document).click(function(e){
var self = jQuery(e.target);
if(self.is("#resultForm input[type=submit], #form-id input[type=button], #form-id button")){
e.preventDefault();
var form = self.closest('form'), formdata = form.serialize();
//add the clicked button to the form data
if(self.attr('name')){
formdata += (formdata!=='')? '&':'';
formdata += self.attr('name') + '=' + ((self.is('button'))? self.html(): self.val());
}
jQuery.ajax({
type: "POST",
url: form.attr("action"),
data: formdata,
success: function(data) {
console.log(data);
}
});
}
});
PHP below form
if(!empty($_SERVER['HTTP_X_REQUESTED_WITH']) && strtolower($_SERVER['HTTP_X_REQUESTED_WITH']) == 'xmlhttprequest') {
$sport = $_POST['sport'];
$round = $_POST['round'];
$tournament=$_POST['tournament'];
echo $sport;
echo $round;
echo $tournament;
}
I don't see anything in your code that would make the values display on the page. You would need to either do some DOM insertion in your AJAX success function, or do a full page refresh and echo the data out via PHP (but that would probably defeat the purpose of doing an AJAX call in the first place.)
If you want to go the AJAX route, I would suggest editing your PHP to the following:
echo json_encode(array(
'sport' => $sport,
'round' => $round,
'tournament' => $tournament
));
This will return a JSON object for your jQuery AJAX call to consume.
In your jQuery success function, do something with those values, like so:
jQuery.ajax({
type: "POST",
url: form.attr("action"),
data: formdata,
dataType: 'json',
success: function(data) {
$('<div></div>').text(data.sport).appendTo('body');
$('<div></div>').text(data.round).appendTo('body');
$('<div></div>').text(data.tournament).appendTo('body');
}
});
Note the additional dataType argument to $.ajax. To do it the right way, you'll also want to set your headers in your PHP response to "application/json"
You ajax is just displaying the output in console. Change the ajax success to display it in page.
Make changes after success as:
success:function(data){
$('someelementclassorid').text(data);
}
I have a module where the forms created are dynamic. So the number of inputs can defer always. Also, the array key can also defer.
My current method of posting form is this:
name = form_options[option_1] value = 1
On submitting the form using POST, I get the form as array in $_POST, which looks like this.
form_options(
option_1 => 1
)
But, now I am trying to implement the same thing using AJAX. So, I would need a common module to get all form values.
I found a way to do it.
var objectResult = $('#options_form').serializeArray();
console.log(objectResult);
This gives me a result like this:
0: Object
name: "form_options[option_1]"
value: "1"
How can parse this result to get an array like $_POST array, which I can send as data in AJAX.
P.S: All the form elements have name field as form_options[key]
You should use this for get post data in PHP file.
// You can use like this
var objectResult = $('#options_form').serializeArray();
$.ajax({
type: "POST", // Enter Request type GET/POST
url: 'action.php', // Enter your ajax file URL here,
dataType: 'json', // If you are using dataType JSON then in php file use die( json_encode($resultArray) );
data: objectResult, // Put your object here
beforeSend: function(){
alert('before');
},
error: function(data) {
console.log(data);
},
success: function(response){
console.log(response);
}
});
// In php file get values like this way
$_POST['form_options']
try like this,
In JQuery:
var objectResult = $('#options_form').serializeArray();
$.ajax({
type: 'POST',
url: 'yoururl'',
data: objectResult ,
success:function(data){
alert(data);
}
});
In your php:
<?php echo var_dump($_POST);?>
You can use jquery serialize with ajax directly, there is no need to use serializeArray:
$.ajax({
type:"post",
url:"formHandleSkript.php",
data: $("#options_form").serialize(),
success: function(response){
$(".result").html(response);
}
});
For more information see http://api.jquery.com/serialize/