Jquery css 'display:block' not work - javascript

I am attempting to create a simple validation function for my contact form.
Click here At the moment, once details are submitted the form keeps display:none even when entries are incorrect. I have tried to target the form id Which doesn't seem to be working either.
below is a snippet of my function
var form = $('#ajax-contact');
var formMessages = $('#form-messages');
form.validate();
$(form).submit(function(e) {
if ($('#ajax-contact').valid()) {
$('#ajax-contact').validate({
rules: {
name: {
rangelength: [2, 40],
},
email: {
rangelength: [2, 40],
email: true,
required: true
},
errorClass: "error",
highlight: function (input) {
$(input).closet('.required').removeClass('has-success').addClass('has-error');
}
}
})
} else {
$("#ajax-contact").css({'display:block'});
console.log('not working');
}
})

.css should be used this way:
$("#ajax-contact").css('display','block');
and if you have multiple .css to be set then you can go with
$("#ajax-contact").css({'display':'block','position':'relative'});

Try css({display: "block"}) as it takes an object as options. Not an array

Related

validating that a canvas has been drawn in

I'm implementing an online waiver where a client has to sign into canvas before they can complete the form. I use Signature_Pad from szimek and jquery-validate and would like to have the canvas (which is part of the form) be included. I tried a custom formatter, like so:
let wrapper = document.getElementById("signature_pad");
var signaturePad = new SignaturePad(wrapper.querySelector("canvas"), {
backgroundColor: 'white'
});
jQuery.validator.addMethod("checkSignature", function(value, element) {
return signaturePad.isEmpty() == false;
}, "Signature must be provided");
$("form[name='form-waiver']").validate({
rules: {
WaiverName: {
required: true,
minlength: 2
},
signature_pad: {
checkSignature: true
}
},
messages: {
WaiverName: "The name has to be filled out"
},
successClass: "valid",
errorClass: "invalid",
submitHandler: function (form) {
...
}
};
However, the form validates even if the canvas is empty. Is there a method to include the canvas in the form validation?

Multiple instances of jQuery Validation Plugin on a JSP page

SOLVED: $.extend() twice in a row simply overwrites the previous object because objects are passed by reference. My fix was to do this:
var updateUserObj = $.extend({}, validationPluginDefaults);
var newUserObj = $.extend({}, validationPluginDefaults);
Then the validators are executed like this:
var whateverValidator = $.extend(updateUserObj,{new rules})
Update: Further research shows that what I'm trying to do appears to be correct but the problem may be in the object I am extending - "validationPluginDefaults"). Here it is below:
var validationPluginDefaults = {
ignore: [],
errorElement: 'p', //default input error message container <p>
errorClass: 'text-error', // default input error message class
focusInvalid: true, //focus on the first invalid field
messages: {},
invalidHandler: function (event, validator) { //display error alert on form submit
},
highlight: function (el) { // hightlight error inputs
//jQuery(el).closest('.control-group').addClass('error'); // set error class to the control group
},
success: function (err, el) {
jQuery(el).next(".text-error").hide();
jQuery(el).next(".text-error").remove();
},
errorPlacement: function (error, element) {
error.insertAfter(element);
},
onfocusin: function () {},
onfocusout: function () {}
};
From my testing it appears that even though I have two separate forms on a JSP page and each has different validation that I can still only use one jQuery Validate Plugin instance per page; is this correct?
Here's my code:
// Define validation rules for form one
var formOneValidator = $.extend(validationPluginDefaults,{
rules: {
firstName: {
minlength: 2,
onlyAlphaAndHyphen: true,
required: true,
},
lastName: {
minlength: 2,
required: true,
},
email: {
required: true,
email: true
}
}
});
var formTwoValidator = $.extend(validationPluginDefaults,{
rules: {
newFirstName: {
minlength: 2,
onlyAlphaAndHyphen: true,
required: true,
},
newLastName: {
minlength: 2,
required: true,
},
newEmail: {
required: true,
email: true,
}
}
});
$("#formOne").validate(formOneValidator);
$("#formTwo").validate(formTwoValidator);
What happens here is that formOne validator takes on all the rules of formTwoValidator after this code executes.
Is the solution to have only one validator and swap out rules depending on which form I'm in? It just seems strange that I wouldn't be able to define separate validators for each form on the page. Am I fundamentally misunderstanding something here?
you could use knockout and give each page a different view model which handles the different validation. That is how i would do it but i'm sure there will be a better answer.

Using jQuery Validation Plugin with dynamic form elements

I have a page that contains multiple forms, and each form can contain any number of elements that have a common root in its name. I'm trying to use this answer to validate a form when it's submitted, but I get a TypeError: a.data(...) is undefined error on jquery.validate.js. My code is below.
var valForm = function(kit_id) {
$('input[name^="kit_desc_"]').each(function() {
$(this).rules("add", {
required: true,
messages: {
required: "Please enter a description"
}
});
});
$("#frm_" + kit_id).validate({
errorElement: "div",
errorPlacement: function(error, element) {
$("#error_modal").html(error);
}
});
if (! $("#frm_" + kit_id).valid()) {
// a dialog box will appear listing the errors.
$("#error_modal").dialog();
}
};
The function is called when a link is clicked.
Save
Any suggestions?
I think you have to call .validate() on the form before you can call .rules() on the inputs in that form. You should also call .rules() only on the inputs in the form you're submitting.
var valForm = function(kit_id) {
var form = $("#frm_" + kit_id);
form.validate({
errorElement: "div",
errorPlacement: function(error, element) {
$("#error_modal").html(error);
}
});
form.find('input[name^="kit_desc_"]').each(function() {
$(this).rules("add", {
required: true,
messages: {
required: "Please enter a description"
}
});
});
if (! form.valid()) {
// a dialog box will appear listing the errors.
$("#error_modal").dialog();
}
};

Jquery validation not working second time

The problem is this jquery validation is not working in my form second time. Its working first time perfectly but second time its shows error message but form is going to submit. The code is here
(function ($, W, D) {
var JQUERY4U = {};
JQUERY4U.UTIL =
{
setupFormValidation: function () {
//form validation rules
$("#aspnetForm").validate({
rules: {
firstname: "required",
lastname: "required",
company: "required",
jobtitle: {
required: true,
},
phone: {
required: true,
number: true
},
email: {
required: true,
email: true
},
},
messages: {
firstname: "Please enter your first name",
lastname: "Please enter your last name",
company: "Please enter your company name",
jobtitle: "Please enter your job title",
phone: "Please enter a valid phone number",
email: "Please enter a valid email address",
},
submitHandler: function (form) {
$('#aspnetForm').on('submit', function (e) {
e.preventDefault();
if (flag) {
createListItem();
}
});
//form.submit(function (e) {
// e.preventDefault();
// if (flag) {
// createListItem();
// }
//});
}
});
}
}
//when the dom has loaded setup form validation rules
$(D).ready(function ($) {
JQUERY4U.UTIL.setupFormValidation();
$('#newsletterModal').on('hidden.bs.modal', '.modal', function () {
clearFields();
});
$('#newsletterModal').on('shown.bs.modal', function (e) {
$('#lblMsg').empty();
});
});
})(jQuery, window, document);
can any one help me
Your submitHandler callback function...
submitHandler: function (form) {
$('#aspnetForm').on('submit', function (e) {
e.preventDefault();
if (flag) {
createListItem();
}
});
}
Do not put a submit event handler inside of the submitHandler callback! It's unclear to me what you're trying to do but the submitHandler callback function of the plugin has already captured & replaced the default submit event of the form.
Also, whenever you declare your own submitHandler function, you are over-riding the default built into the plugin. Since I see nothing inside of your custom submitHandler that submits the form, the form will never be submitted.
You'll either need to remove the submitHandler to allow the form to be submitted (when valid) as per the default functionality OR you'll need to put $(form).submit() inside of it someplace.
submitHandler: function (form) {
if (flag) {
createListItem();
}
$(form).submit();
}
NOTE:
Wrapping up everything like this is superfluous, unnecessary, verbose, and arcane...
(function($,W,D) {
var JQUERY4U = {};
JQUERY4U.UTIL =
{
setupFormValidation: function() {
$("#aspnetForm").validate({ .... });
}
}
$(D).ready(function($) {
JQUERY4U.UTIL.setupFormValidation();
});
})(jQuery, window, document);
It serves no useful purpose other than to cause more confusion to those seeking guidance. It comes from a popular, yet poorly explained, online demo/tutorial by Sam Deering that is linked to/from many places.
The entire mess above can be removed and simply replaced by putting the .validate() method inside of the DOM ready event handler function...
$(document).ready(function() {
$("#aspnetForm").validate({ .... });
});

Automatically close qtip2 using JQuery .validate()

I'm working on a form which implements QTip2 to display a tooltip once someone tries to submit a form where data is missing. Everything works as intended, however I would like the tooltip to be removed once the error class is removed (effectively once someone types in the input field). I have the following code for my validation currently:
$('#form0').validate({
rules: {
Name: "required",
Email: {
required: true,
email: true
},
Subject: "required",
Message: "required"
},
errorPlacement: function (error, element) {
$('#Name').qtip({
content: 'Please enter your name',
position: {
target: 'mouse', // Track the mouse as the positioning target
adjust: { x: 5, y: 5 } // Offset it slightly from under the mouse
},
style: { classes: 'qtip-red' }
});
return true;
},
errorClass: "form-error"
});
As you can see, once someone tries to submit the form the class "form-error" is assigned to the input field, so I would like the tooltip to be removed as well once this class is removed. I tried the following, but it did not work, not sure why:
onHide: function() { $(this).qtip('destroy'); }
I found a solution to this problem by adding the following code inside errorPlacement {}:
events: { show: function (event, api) { if (!element.hasClass('form-error')) event.preventDefault(); } },
show: {
delay: 0,
target: element
},
hide: { target: element },

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