Showing dropdown list when I clicked on - javascript

<script>
$(document).ready(function({$("#more").click(function()$(".dropdown").fadeToggle("slow")});});
</script>
This is my script for more option. I want to show the dropdown list when I clicked and hide it when I clicked again. Whit this code, all I can get is hiding when I clicked and showing when I clicked again. I want to make it reverse.
How can I change the default display?

Your code works, it just has some typo's.
And to define the default state, change the display property of .dropdown to none
$(document).ready(function() {
$("#more").click( function() {
$(".dropdown").fadeToggle("slow")
});
});
.dropdown {
display: none;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="more">click for more</div>
<div class="dropdown">Droppie down</div>

you can use CSS display:none property to hide the div on page load.
eg:
#more{
display:none;
}

$("#more" ).on('click', function() {
$( ".dropdown" ).fadeToggle( "slow", "linear" );
});

Related

jQuery hide dropdown menu

I have a dropdown menu that shows with the following jQuery script:
jQuery(document).ready(function($) {
$('#block-mln-main-menu li').click(function(){
$(this).find('.test').toggle();
});
});
What I want to achieve is when the user clicks anywhere else on the page, it slides up or hides. I am literally at a loss on how to achieve this.
Any help is greatly appreciated.
added a fiddle : http://jsfiddle.net/aL7Xe/999/
Yoy can try stop propagation event.
CSS:
.showup{width:100px;height:100px; background:red; display:none;}
.click{cursor:pointer;}
HTML
<div class="click">click me</div>
<div class="showup">Click somewhere else!</div>
JQUERY
$(document).ready(function(){
$('.click').click(function(event){
event.stopPropagation();
$(".showup").slideToggle("fast");
});
$(".showup").on("click", function (event) {
event.stopPropagation();
});
});
$(document).on("click", function () {
$(".showup").hide();
});
Toggle will only work it user click on the same object it you want to hide it when click elsewhere try
jQuery(document).ready(function($) {
$(this).not('#block-mln-main-menu li').click(function(){
$(this).find('.test').hide();
});
});
What I understand is that you want to show dropdown menu when an user clicks on it. If the user again clicks on it or anywhere on the page it should close.
CSS
.hide {
display: none;
}
JS
$('.menu-label').on('click', function() {
$('.drop-down-menu').toggleClass('hide');
});
To hide the menu when user click anywhere on page
$('body').on('click', function() {
$('.drop-down-menu').addClass('hide');
});

javascript to control css positioning

I have the following script in my page to close out a dropdown submenu when the close button is clicked:
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.3/jquery.min.js"></script>
<script type="text/javascript">
$(function() {
$(".closebutton").click(function() {
clearTimeout();
var c = $(this).closest("li");
c.find(".dropdown").css("left", "-9999px")
});
});
</script>
Once the "close button" is pressed, the dropdown no longer appears again when I hover over the parent li since the css has been changed to "left: -9999px". What script should I add that returns the css to "left: 0px;" again when I hover once more on the parent li without reloading the page?
Thanks!
This finds the closest li to the close button, and when its hovered finds the .dropdown element and sets the .dropdown to left: 0.
$('.closebutton').closest('li').hover(function() {
$(this).find('.dropdown').css('left', '0px');
});
You could use the $.mouseover() event and change the left property back to 0px. It would look something like this:
'<script type="text/javascript">
$(function() {
$(".closebutton").mouseover(function() {
var d = $(this).closest("li");
d.find(".dropdown").css("left", "0px");
});
});
</script>'
Hope that helps!
Try using the .show() and .hide() events in jQuery rather than changing the css and the .hover() to execute the .show().
c.find(".dropdown").hide();

jQuery show div only if has class

I have some problems with show/hide element. I have 2 popups on one page and I need hide one popup if another popup has class.
For example:
<body class="home">
<div class="popup main"></div>
<div class="popup"></div>
</body>
So, if body.home has .main I need to show only .main popup and hide or remove another .popup.
I'va tried
if ($('.home').find('.main')) {
$('.home').find('.main').show();
$('.home').find('.popup').remove();
}
But it does not working as I need, because in some reason I'll have code only with one popup block
<body class="home">
<div class="popup"></div>
</body>
Just try this,
if($(".popup").hasClass('main')){
$(".popup").hide();
$(".main").show();
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<body class="home">
<div class="popup main">main</div>
<div class="popup">another</div>
</body>
$( '.home .popup' ).not( ".main" ).remove();
You may want something like this:
$('.popup.main').length &&
$('.popup').show().not('.main').remove() ||
$('.popup').show();
JSFiddle
The above code is basically a "shortcut" of this:
// if there's a popup with class .main:
if($('.popup.main').length){
// show it:
$('.popup.main').show();
// and remove the one without class .main:
$('.popup').not('.main').remove();
// else, if there's no popup with class .main:
}else{
// show the .popup:
$('.popup').show();
}
If you want to show/hide element, use jQuery.hide() or jQuery.show(). If you use jQuery.remove() then u don't have chance to do it again because it was removed from DOM tree.
check with hasClass()
if ($('.home .popup').hasClass('main')) {
$('.home .popup').hide();
$('.home .main').show();
}
This will hide all popups, then show only that has .main class
Working pen
Edit
ok this in not working when .home has only one child.
Try solving this with css
.home .popup:not(.main) {
display: none;
}
.home .popup:only-child {
display: block !important;
}
with this code you only have to add/remove .main class to manage visibility
Working pen with css

Changing a image for another after clicking on it with jquery

this is going to be my first question so far cause i always do a research before using forums, but i dont get this to work.
I have an Image that works as a button for a toggle animation (button.png) and i want that image to change after clicking on it for another image (button2.png), and once you click the second image it changes again to the first image, i have:
<script type="text/javascript">
$(document).ready(function() {
// when click on the tag with id="btn"
$('#btn').click(function() {
// change the state of the "#idd"
$('#idd').toggle(800, function() {
// change the button text according to the state of the "#idd"
if ($('#idd').is(':visible')) {
$('#btn').attr('images/button2.png', this.href); // Show Less.. button
} else {
$('#btn').attr('images/button.png', this.href); //Learn More.. button
}
});
});
});
</script>
and my Html:
<div id="idd" style="display:none;">
- Here my hidden content -
</div>
<!-- Button -->
<img src="images/button.png" style="cursor: pointer;" id="btn">
What im doing wrong? Please Help :(
Check the syntax for .attr. It should be something like
$('#btn').attr('src', 'your image src');
Function Reference: http://api.jquery.com/attr/
To change the value of src you use 'attr' like this:
$('#btn').attr('src', 'images/button2.png');
Here is a DEMO
HTML
<div id="idd" class='display-none'>
- Here my hidden content -
</div>
<!-- Button -->
<img src="http://placekitten.com/40/40" id="btn">
CSS
.display-none {
display:none;
}
jQuery
var btn = $('#btn');
var idd = $('#idd');
btn.click(function() {
idd.toggle(800, function() {
// change the button text according to the state of the "#idd"
if (idd.hasClass('display-none')) {
btn.attr('src', 'http://placekitten.com/50/50');
idd.removeClass('display-none');
} else {
btn.attr('src', 'http://placekitten.com/40/40');
idd.addClass('display-none');
}
});
});
take one division e.g #play-pause-button and other in this i.e #play-pause. now put ur images in the src of inner division , on the click of outer divison source of innner division will change..
here is simillar example i'm working on. hope will help you.!
$('#play-pause-button').click(function () {
// $('#play-pause-button').play();
if ($("#media-video").get(0).paused) {
$("#media-video").get(0).play();
$("#play-pause").attr('src', "Image1 path");
}
else {
$("#media-video").get(0).pause();
$("#play-pause").attr('src', "Image2 path");
}
});
You should use css to associate image(s) on your "button" and a css class to determine which to show.
You can then use Jquery's ToggleClass() to add/remove the class. You can use the same class to show/hide your hidden content.
markup
<div id="idd">
- Here my hidden content -
</div>
<div id="btn">Click Me</div>
css
#idd.off {
display:none;
}
#btn {
border:1px solid #666;
width:100px; height:100px;
background:#fff url(images/button.png) no-repeat 0 0; // Show Less.. button
}
#btn.off {
background:#fff url(images/button2.png) no-repeat 0 0; //Learn More.. button
}
jquery
$('#btn').click(function(){
$('#idd').toggleClass('off');
$('#btn').toggleClass('off');
});

How to show the child div on mouse hover of parent div

I have a number of parent divs (.parent_div), which each contain a child div (.hotqcontent) where I output data from my database using a loop.
The following is my current markup:
<div class="content">
<div class="parent_div">
<div class="hotqcontent">
content of first div goes here...
</div>
<hr>
</div>
<div class="parent_div">
<div class="hotqcontent">
content of second div goes here...
</div>
<hr>
</div>
<div class="parent_div">
<div class="hotqcontent">
content of third div goes here...
</div>
<hr>
</div>
<div class="parent_div">
<div class="hotqcontent">
content of fourth div goes here...
</div>
<hr>
</div>
</div>
What I would like to achieve is when a user hovers / mouseovers a parent div, the contents of the child div contained within should be revealed.
To achieve this I wrote the following jQuery script but it doesn't appear to be working. It's not even showing the alert!
<script>
$(document).ready(function() {
$(function() {
$('.parent_div').hover(function() {
alert("hello");
$('.hotqcontent').toggle();
});
});
});
</script>
How can I modify or replace my existing code to achieve the desired output?
If you want pure CSS than you can do it like this....
In the CSS below, on initialization/page load, I am hiding child element using display: none; and then on hover of the parent element, say having a class parent_div, I use display: block; to unhide the element.
.hotqcontent {
display: none;
/* I assume you'll need display: none; on initialization */
}
.parent_div:hover .hotqcontent {
/* This selector will apply styles to hotqcontent when parent_div will be hovered */
display: block;
/* Other styles goes here */
}
Demo
Try this
$(document).ready(function() {
$('.parent_div').hover(function() {
alert("hello");
$(this).find('.hotqcontent').toggle();
});
});
Or
$(function() {
$('.parent_div').hover(function() {
alert("hello");
$(this).find('.hotqcontent').toggle();
});
});
You can use css for this,
.parent_div:hover .hotqcontent {display:block;}
This can be done with pure css (I've added a couple of bits in just to make it a bit neater for the JSFIDDLE):
.parent_div {
height: 50px;
background-color:#ff0000;
margin-top: 10px;
}
.parent_div .hotqcontent {
display: none;
}
.parent_div:hover .hotqcontent {
display:block;
}
This will ensure that your site still functions in the same way if users have Javascript disabled.
Demonstration:
http://jsfiddle.net/jezzipin/LDchj/
With .hotqcontent you are selecting every element with this class. But you want to select only the .hotqcontent element underneath the parent.
$('.hotqcontent', this).toggle();
$(document).ready(function(){
$('.parent_div').on('mouseover',function(){
$(this).children('.hotqcontent').show();
}).on('mouseout',function(){
$(this).children('.hotqcontent').hide();
});;
});
JSFIDDLE
you don't need document.ready function inside document.ready..
try this
$(function() { //<--this is shorthand for document.ready
$('.parent_div').hover(function() {
alert("hello");
$(this).find('.hotqcontent').toggle();
//or
$(this).children().toggle();
});
});
and yes your code will toggle all div with class hotqcontent..(which i think you don't need this) anyways if you want to toggle that particular div then use this reference to toggle that particular div
updated
you can use on delegated event for dynamically generated elements
$(function() { //<--this is shorthand for document.ready
$('.content').on('mouseenter','.parent_div',function() {
alert("hello");
$(this).find('.hotqcontent').toggle();
//or
$(this).children().toggle();
});
});
you can try this:
jQuery(document).ready(function() {
jQuery("div.hotqcontent").css('display','none');
jQuery("div.parent_div").each(function(){
jQuery(this).hover(function(){
jQuery(this).children("div.hotqcontent").show(200);
}, function(){
jQuery(this).children("div.hotqcontent").hide(200);
});
});
});

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