I want to create a session var. I have a web page with some tabs that don't recharge when I active one another. So, I don't know how to set my session var.
Indeed, my first tab will generate the session var when the user submit the form into this tab. I'm trying to do it with ajax. So in my ajax file, I have this to set my var :
if(pg_num_rows($res) == 1)
{
$flag=false;
$message = "L'identifiant de l'essai existe déjà dans la base";
array_push($tab_erreur,$cpt,$message);
}else {
$sessionIDEssai=$ligne[1]; //Here is my session var
}
After, I want to return that value with an other like this :
echo json_encode($tab_erreur),$sessionIDEssai;
First of all I don't know if it's correct, because I can't get it in my callback function.
function insert_essai_callback(responseObject,ioArgs) .
{
var jsonobject = eval(responseObject);
console.log(jsonobject);
}
I can get the first var $tab_erreur.
And after I don't know how to set my session var for all my tabs. I think that at the return of the ajax, I will get the value and I could set it and use it, but I'm not sure.
EDIT
I send an array in my ajax request like that :
$(document).ready(function(){
$('#submit_button_essai').click(function(){
$.post("ajax_insert_essai.php",{arr:data_essai}, insert_essai_callback,'json');
});
});
Ajax
$.ajax({
type : 'POST',
url : './session.php',
dataType: "json",
data: data,
success : function(data){},
error : function(){}
});
PHP
<?php
session_start();
$_SESSION['data']=$_POST['data'];
echo $_SESSION['data'];
?>
});
Data is what you send through a POST, now echo can return that data or a different amount of data to your Ajax request as a response.
Using, $.post():
$.post({
url: url,
data: data,
success: success,
dataType: dataType
});
However, $.ajax(), is much much better, since you have more control over the flow, and if success do this etc.
Related
I'm trying to POST some data to another page with AJAX but no info is going, i'm trying to pass the values of two SELECT (Dropdown menus).
My AJAX code is the following:
$('#CreateHTMLReport').click(function()
{
var DeLista = document.getElementById('ClienteDeLista').value;
var AteLista = document.getElementById('ClienteParaLista').value;
$.ajax(
{
url: "main.php",
type: "POST",
data:{ DeLista : DeLista , AteLista : AteLista },
success: function(data)
{
window.location = 'phppage.php';
}
});
});
Once I click the button with ID CreateHTMLReport it runs the code above, but it's not sending the variables to my phppage.php
I'm getting the variables like this:
$t1 = $_POST['DeLista'];
$t2 = $_POST['ParaLista'];
echo $t1;
echo $t2;
And got this error: Notice: Undefined index: DeLista in...
Can someone help me passing the values, I really need to be made like this because I have two buttons, they are not inside one form, and when I click one of them it should redirect to one page and the other one to another page, that's why I can't use the same form to both, I think. I would be great if someone can help me with this, on how to POST those two values DeLista and ParaLista.
EDIT
This is my main.php
$('#CreateHTMLReport').on('click',function() {
$.ajax({
// MAKE SURE YOU HAVE THIS PAGE CREATED!!
url: "main.php",
type: "POST",
data:{
// You may as well use jQuery method for fetching values
DeLista : $('#ClienteDeLista').val(),
AteLista : $('#ClienteParaLista').val()
},
success: function(data) {
// Use this to redirect on success, this won't get your post
// because you are sending the post to "main.php"
window.location = 'phppage.php';
// This should write whatever you have sent to "main.php"
//alert(data);
}
});
});
And my phppage.php
if(!empty($_POST['DeLista'])) {
$t1 = $_POST['DeLista'];
# You should be retrieving "AteLista" not "ParaLista"
$t2 = $_POST['AteLista'];
echo $t1.$t2;
# Stop so you don't write the default text.
exit;
}
echo "Nothing sent!";
And I'm still getting "Nothing Sent".
I think you have a destination confusion and you are not retrieving what you are sending in terms of keys. You have two different destinations in your script. You have main.php which is where the Ajax is sending the post/data to, then you have phppage.php where your success is redirecting to but this is where you are seemingly trying to get the post values from.
/main.php
// I would use the .on() instead of .click()
$('#CreateHTMLReport').on('click',function() {
$.ajax({
// MAKE SURE YOU HAVE THIS PAGE CREATED!!
url: "phppage.php",
type: "POST",
data:{
// You may as well use jQuery method for fetching values
DeLista : $('#ClienteDeLista').val(),
AteLista : $('#ClienteParaLista').val()
},
success: function(data) {
// This should write whatever you have sent to "main.php"
alert(data);
}
});
});
/phppage.php
<?php
# It is prudent to at least check here
if(!empty($_POST['DeLista'])) {
$t1 = $_POST['DeLista'];
# You should be retrieving "AteLista" not "ParaLista"
$t2 = $_POST['AteLista'];
echo $t1.$t2;
# Stop so you don't write the default text.
exit;
}
# Write a default message for testing
echo "Nothing sent!";
You have to urlencode the data and send it as application/x-www-form-urlencoded.
I need to have a "global" variable because I need to use it in different page and I want to modify it too: I think that I need to use $_SESSION
I need to change this variable, when the user click on dropdown or list.
I have this:
SOLUTION 1
PageA:
$('#list.test li').on('click',function(){
choice=$(this).attr('id');
$.ajax({
url: "PageB.php",
data: {word : choice},
dataType: "html",
success: function (data) {
$('#content_table').html(data);
}
});
});
PageB
session_start();
$_SESSION['b']=$_GET['word'];
echo $_SESSION['b']; // It works
PageC for verify the result
session_start();
echo $_SESSION['b']; // Error !!
In my PageC, I have an error ( Notice: Undefined index: b )
Is it possible to update session variable with ajax ?
SOLUTION 2
PageA: I want to passe the id JS var to PHP var
$('#list.test li').on('click',function(){
choice=$(this).attr('id');
<?php $_SESSION['b'] ?> = choice; //<--- it is possible ?
$.ajax({
url: "PageB.php",
data: {word : choice},
dataType: "html",
success: function (data) {
$('#content_table').html(data);
}
});
});
This solution doesn't work because AJAX and PHP are note in the same side (client/server).
Thank you
You can push data to cookies via JavaScript, smth like document.cookie = "key=value";
And receive it on back-end like $_COOKIE["key"];.
$_SESSION['b']=$_GET['projet']; should be $_SESSION['b']=$_GET['word'];
so, this is probably a dumb question, but is it possible to execute the header function in a php file if I'm getting a response with AJAX?
In my case, I have a login form that gets error codes from the PHP script (custom error numbers hardcoded by me for testing) through AJAX (to avoid reloading the page) and alerts the associated message with JS, but if the username and password is correct, I want to create a PHP cookie and do a redirect. However I think AJAX only allows getting data, right?
This is my code:
JS
$.ajax({
type: 'POST',
url: 'validate.php',
data: $this.serialize(),
success: function(response) {
var responseCode = parseInt(response);
alert(codes[responseCode]);
}
});
PHP
if(empty($user)){
echo 901;
}else{
if(hash_equals($user->hash, crypt($password, $user->hash))){
setCookie(etc...); //this is
header('admin.php'); //what is not executing because I'm using AJAX
}else{
echo 902;
}
}
Please sorry if the question doesn't even make sense at all but I couldn't find a solution. Thanks in advance!
EDIT: I did not include the rest of the code to avoid complicating stuff, but if you need it for giving an anwser I'll add it right away! (:
You're right, you can't intermix like that. The php would simply execute right away, since it has no knowledge of the javascript and will be interpreted by the server at runtime, whereas the js will be interpreted by the browser.
One possible solution is to set a cookie with js and redirect with js as well. Or you could have the server that receives the login request set the cookie when the login request succeeds and have the js do the redirect after it gets a successful response from the server.
You can't do like that because ajax request process in backed and return the particular response and if you want to store the cookies and redirect then you should do it in javascript side while you get the response success
$.ajax({
type: 'POST',
url: 'validate.php',
data: $this.serialize(),
success: function(response) {
var responseCode = parseInt(response);
alert(codes[responseCode]);
window.location = "admin.php";
}
});
if(empty($user)){
setCookie(etc...); //this is
echo 901;
}else{
if(hash_equals($user->hash, crypt($password, $user->hash))){
echo response// what every you want to store
}else{
echo 902;
}
}
If the ajax response satisfies your condition for redirection, you can use below:
$.ajax({
type: 'POST',
url: 'validate.php',
data: $this.serialize(),
success: function(response) {
var responseCode = parseInt(response);
alert(codes[responseCode]);
window.location="%LINK HERE%";
}
});
It's kind of ironic that you use ajax to avoid loading the page, but you'll be redirecting in another page anyway.
test sending data in json format:
Javascript
$.ajax({
type: 'POST',
url: 'validate.php',
data: $this.serialize(),
success: function(response) {
if(response.success){
window.location="%LINK HERE%";
}else{
var responseCode = parseInt(response.code);
alert(responseCode);
...
}
}
});
PHP
header("Content-type: application/json");
if(empty($user)){
echo json_encode(['success' => false, 'code' => 901]);
}else{
if(hash_equals($user->hash, crypt($password, $user->hash))){
echo json_encode(['success' => true, 'data' => response]);
}else{
echo json_encode(['success' => false, 'code' => 902]);
}
}
My php is updating the table but not refreshing in javascript have tried several different ways of doing this and nothing is working.
PHP
$sql = "UPDATE INTOXDM.ASTP_FORM SET SUPERVISOR_EID = '".$newSuper."' WHERE FORMID = '".$formId."'";
$row = $xdm->fetch($sql);
$return["color"] = $row['APPRENTICE_SIGNATURE'];
$return["json"] = json_encode($return);
echo json_encode($return);
?>
Javascipt
var data = {
"formId": formID,
"newSuper": newSuper
};
data = $.param(data);
$.ajax({
type: "POST",
dataType: "json",
url: "src/GetInfo.php",
data: data,
success: function() {
location.reload();
}
});
I'd start by modifing the code like this:
var data = {
"formId": formID,
"newSuper": newSuper
};
// No need for serialization here,
// the 'data' parameter of jQuery.ajax accepts JS object
// data = $.param(data);
$.ajax({
type: "POST",
dataType: "json",
url: "src/GetInfo.php",
data: data,
// As suggested by Rocket Hazmat, try to add an error callback here
error: function(jQueryXHR, textStatus, errorMessage) {
console.log("Something went wrong " + errorMessage);
},
success: function(jsonResponse) {
// Try to reference the location object from document/window
// wd = document or window as seen here http://stackoverflow.com/questions/2624111/preferred-method-to-reload-page-with-javascript
// Also watch out, usually browsers require a user confirmation before reloading if the page contains POST data
// One of these should be fine
wd.location.assign(wd.location.href) : go to the URL
wd.location.replace(wd.location.href) : go to the URL and replace previous page in history
wd.location.reload(<true/false/blank>) : reload page from server/cache/cache
}
});
Also, this might be a shot in the dark but the parameter dataType gave me problems sometime in the past, so if you are sure about the json returned by your php script, you could use the eval function to jsonify the response
$.ajax({
...
// Remove data type
// dataType: "json",
...
success: function(plainTextResponse) {
// Eval response, NOT SAFE! But working
var jsonResponse = eval('('+ plainTextResponse +')');
...
}
});
Your ajax is expecting json data and your php is sending malformed json string. Send a correct json string and your script will work fine.
Your php json_encode should be like this:
$data = json_encode($return);
echo $data;
Im learning Ajax...normally I dont like posting about a subject I know very little of but I believe Im on the right path here (maybe not...?) so I will take a chance to find out.
Ive got 3 select boxes each box populates with values based on the the selection of the box before it:
Everything is working perfectly, when the user clicks submit I want to send the 3 textbox values to 3 php variables and echo it on the same page...
Now my data is not echoing (the data of the variables are not displaying) but when I look in my console on firefox I can see the value of the variables...
Here is the selection made on the select boxes
Here is what im seeing in my console
Yet it is does not echo on the page....?
jQuery(document).click(function(e){
var self = jQuery(e.target);
if(self.is("#resultForm input[type=submit], #form-id input[type=button], #form-id button")){
e.preventDefault();
var form = self.closest('form'), formdata = form.serialize();
//add the clicked button to the form data
if(self.attr('name')){
formdata += (formdata!=='')? '&':'';
formdata += self.attr('name') + '=' + ((self.is('button'))? self.html(): self.val());
}
jQuery.ajax({
type: "POST",
url: form.attr("action"),
data: formdata,
success: function(data) {
console.log(data);
}
});
}
});
PHP below form
if(!empty($_SERVER['HTTP_X_REQUESTED_WITH']) && strtolower($_SERVER['HTTP_X_REQUESTED_WITH']) == 'xmlhttprequest') {
$sport = $_POST['sport'];
$round = $_POST['round'];
$tournament=$_POST['tournament'];
echo $sport;
echo $round;
echo $tournament;
}
I don't see anything in your code that would make the values display on the page. You would need to either do some DOM insertion in your AJAX success function, or do a full page refresh and echo the data out via PHP (but that would probably defeat the purpose of doing an AJAX call in the first place.)
If you want to go the AJAX route, I would suggest editing your PHP to the following:
echo json_encode(array(
'sport' => $sport,
'round' => $round,
'tournament' => $tournament
));
This will return a JSON object for your jQuery AJAX call to consume.
In your jQuery success function, do something with those values, like so:
jQuery.ajax({
type: "POST",
url: form.attr("action"),
data: formdata,
dataType: 'json',
success: function(data) {
$('<div></div>').text(data.sport).appendTo('body');
$('<div></div>').text(data.round).appendTo('body');
$('<div></div>').text(data.tournament).appendTo('body');
}
});
Note the additional dataType argument to $.ajax. To do it the right way, you'll also want to set your headers in your PHP response to "application/json"
You ajax is just displaying the output in console. Change the ajax success to display it in page.
Make changes after success as:
success:function(data){
$('someelementclassorid').text(data);
}