I'm a newbie in ajax, I've created this array through a function in js from a btn table: I've tried it many ways with no success, there's nothing printed in my *.php.. even with print_r, var__dump, etc
console.log(data)
{"datos":[{"value":false,"id":"173"},{"value":false,"id":"172"},{"value":false,"id":"171"},{"value":false,"id":"170"}]}
big question is: How can I pass this array to php, because I need to update a table sql with those values
JS:
$('#update').click(function(e){
e.preventDefault();
var datos = [],
data = '',
checkStatus = document.getElementsByName('check');
for(var i=0;i<checkStatus.length;i++){
var item = {
"value": checkStatus[i].checked,
"id": checkStatus[i].getAttribute('data-id')
}
datos.push(item);
}
data = JSON.stringify({datos:datos});
$.ajax({
type: "POST",
url: "updateTable.php",
datatype: "json",
data: {data},
cache: false,
success: function(){
console.log(data);
}
});
});
PHP:
????????
On the server side ..
var_dump(json_decode($json));
or for each
$json = '{"foo-bar": 12345}';
$obj = json_decode($json);
print $obj->{'foo-bar'}; // 12345
Related
I have a dynamic table and i want to send in controller by ajax. I have code ajax like this :
$(".save").click(function(e){
var items = new Array();
$("#list-item tr.item").each(function () {
$this = $(this)
var ref_item_id = $this.find("#ref_item_id").val();
var ref_pic_id = $this.find("#ref_pic_id").val();
var price= $this.find("#price").val();
var qty= $this.find("#qty").val();
items.push({ ref_item_id : ref_item_id, ref_pic_id : ref_pic_id, price: price, qty : qty});
});
$.ajax({
type: "POST",
contentType: "application/json; charset=utf-8",
url: '<?php echo base_url("transac/save")?>',
dataType: "json",
data: JSON.stringify({'items': items }),
success: function (data) {
var obj = $.parseJSON(data);
alert(obj.lenth);
},
error: function (result) { alert(result); }
});
})
now, how get data in controller and save in table database. My Controller like this :
public function penjualan_save(){
$items = $this->input->post("items");
// next code ???
}
I hope you can help me. Thanks
first thing, your don't need JSON.stringify({'items': items }), just use:
data: {'items': items },
and in your controller, just create a model and pass your post data into it, for example:
public function penjualan_save(){
$items = $this->input->post("items");
$this->load->model('model_name');
$this->model_name->insert($items);
}
then you need to define a function for your model, like this:
public function insert($data)
{
// if you didn't call database library in autoload.php
$this->load->database();
$this->db->insert_batch('mytable', $data);
}
I'm trying to grasp more than I should at once.
Let's say I have 2 inputs and a button, and on button click I want to create a json containing the data from those inputs and send it to the server.
I think this should do it, but I might be wrong as I've seen a lot of different (poorly explained) methods of doing something similar.
var Item = function(First, Second) {
return {
FirstPart : First.val(),
SecondPart : Second.val(),
};
};
$(document).ready(function(){
$("#send_item").click(function() {
var form = $("#add_item");
if (form) {
item = Item($("#first"), $("#second"));
$.ajax ({
type: "POST",
url: "post.php",
data: { 'test' : item },
success: function(result) {
console.log(result);
}
});
}
});
});
In PHP I have
class ClientData
{
public $First;
public $Second;
public function __construct($F, $S)
{
$this->First = F;
$this->Second = S;
}
}
if (isset($_POST['test']))
{
// do stuff, get an object of type ClientData
}
The problem is that $_POST['test'] appears to be an array (if I pass it to json_decode I get an error that says it is an array and if I iterate it using foreach I get the values that I expect to see).
Is that ajax call correct? Is there something else I should do in the PHP bit?
You should specify a content type of json and use JSON.stringify() to format the data payload.
$.ajax ({
type: "POST",
url: "post.php",
data: JSON.stringify({ test: item }),
contentType: "application/json; charset=utf-8",
success: function(result) {
console.log(result);
}
});
When sending an AJAX request you need to send valid JSON. You can send an array, but you need form valid JSON before you send your data to the server. So in your JavaScript code form valid JSON and send that data to your endpoint.
In your case the test key holds a value containing a JavaScript object with two attributes. JSON is key value coding in string format, your PHP script does not not how to handle JavaScript (jQuery) objects.
https://jsfiddle.net/s1hkkws1/15/
This should help out.
For sending raw form data:
js part:
$.ajax ({
type: "POST",
url: "post.php",
data: item ,
success: function(result) {
console.log(result);
}
});
php part:
..
if (isset($_POST['FirstPart']) && isset($_POST['SecondPart']))
{
$fpart = $_POST['FirstPart'];
$spart = $_POST['SecondPart'];
$obj = new ClientData($fpart, $spart);
}
...
For sending json string:
js part:
$.ajax ({
type: "POST",
url: "post.php",
data: {'test': JSON.stringify(item)},
success: function(result) {
console.log(result);
}
});
php part:
..
if (isset($_POST['test']))
{
$json_data = $_POST['test'];
$json_arr = json_decode($json_data, true);
$fpart = $json_arr['FirstPart'];
$spart = $json_arr['SecondPart'];
$obj = new ClientData($fpart, $spart);
}
...
Try send in ajax:
data: { 'test': JSON.stringify(item) },
instead:
data: { 'test' : item },
I'm triyng to retrieve JSON format data using $.ajax method of jquery from a php page, I get this error parseerror when the code runs, but if I see the response of the server with firebug it's Ok.
Here's my script code:
$.ajax({
url: "php/selectedObjectRequest.php",
type: "POST",
dataType: 'json',
data: {},
success: function(data) {
var prova = jQuery.parseJSON(data);
alert(prova.museum);
},
error: function(jqXHR,textStatus,errorThrown) {
alert(textStatus);
}
});
And that's my server side code:
$arrayToEncode = array(
'museum' => 'bellearti',
'atwork' => 'davide',
'beaconCode' => '78888',
'qrCode' => '2252222'
);
echo json_encode($arrayToEncode);
How I can solve?
solved:
My error was an echo to test before
echo json_encode($arrayToEncode);
pay attention.
The parameter data in your success handler will be preprocessed because you told jQuery that the dataType was JSON. You should be able to just use data.museum. To make sure, console.log(data); to see what it is.
the answer is:
change prova.museum to data.museum
$.ajax({
url: "php/selectedObjectRequest.php",
type: "POST",
dataType: 'json',
data: {},
success: function(data) {
alert(data.museum); // add data.museum instant of prova.museum
},
error: function(jqXHR,textStatus,errorThrown) {
alert(textStatus);
}
});
FIDDLE
Change the format
$arrayToEncode[] = array(
'museum' => 'bellearti',
'atwork' => 'davide',
'beaconCode' => '78888',
'qrCode' => '2252222');
echo json_encode($arrayToEncode, JSON_UNESCAPED_UNICODE);
So that you can call the return value like
for (var j = 0; j < data.length; j++) {
console.log(data[j].museum);
console.log(data[j].atwork);
console.log(data[j].beaconCode);
console.log(data[j].qrCode);
}
Try using this:
var parsed = JSON.parse(data);
This usually works for me.
I am trying to pass the form field values to a php function located into a file. The problem is that I can't understand how to pass that serialized form data to the function from this ajax to a function in php.
$('#insert_news').submit(function(event) {
event.preventDefault();
var form = $('#insert_news').serialize();
$.ajax({
type: 'POST',
url: 'includes/ajax.php',
data: {
action: 'insert_news',
$('#insert_news').serialize(); // how do I add this data here?
},
success: function(datas) {
$('#message').html(datas).show() /*fadeIn(1000).fadeOut(1000)*/ ;
}
});
});
This ajax passed the values to the file ajax.php right beyond. And from ajax.php is called the function located in functions.php.
ajax.php
if (isset($_POST['action']) && $_POST['action'] == 'insert_news') {
$cp->insert_into_table('newss', array(
'NewsTitle' => $_POST['title'],
'NewsDescrption' => $_POST['description'],
'Date' => date('Y-m-d H:i:s'),
'status' => '1'
)
);
}
function.php
public function insert_into_table($table_name, array $data){
foreach($data as $col=>$value) {
$cols[] = $col;
$values[] = '\''.$value.'\'';
}
$cols = implode(', ', $cols);
$values = implode(', ', $values);
$this->db->query("INSERT INTO $table_name ($cols) VALUES ($values)");
echo "INSERT INTO $table_name ($cols) VALUES ($values)";
}
The issue is serialize() produces a URL encoded key value paired string, so you can't mix that with your data object.
You can use serializeArray() to get an array of objects, representing the form elements, then iterate over them and add them to a data object:
var data = { action: 'insert_news' };
$.each($('#insert_news').serializeArray(), function(){
data[this.name] = this.value;
});
$.ajax({
type: 'POST',
url: 'includes/ajax.php',
data: data,
success: function(datas) {
$('#message').html(datas).show() /*fadeIn(1000).fadeOut(1000)*/ ;
}
});
Side note: your PHP code is vulnerable to SQL Injection. Consider using a Prepared Statement instead of concatenating user input into the SQL.
You can pass serialized data via ajax to a function the way you are doing but your code needs slight modification.
$('#insert_news').submit(function(event) {
event.preventDefault();
var form = $('#insert_news').serialize();
$.ajax({
type: 'POST',
url: 'includes/ajax.php',
data: {
action: 'insert_news',
serializedData: form // use variable to assign data here
},
success: function(datas) {
$('#message').html(datas).show() /*fadeIn(1000).fadeOut(1000)*/ ;
}
});
});
I think you can use alternate like this
First : add hidden input for action on your form
<input type="hidden" name="action" value="insert_news"/>
Then your ajax post like this
$('#insert_news').submit(function(event) {
event.preventDefault();
$.ajax({
type: 'POST',
url: 'includes/ajax.php',
data: $(this).serialize(), // $(this) is from <form id="insert_news">
success: function(datas) {
$('#message').html(datas).show() /*fadeIn(1000).fadeOut(1000)*/ ;
}
});
});
And then use print_r on your ajax.php
print_r($_POST);
$('#insert_news').submit(function(event) {
var name = $("#t1").val();
var pass = $("#t2").val(); //add more var as u need
var key = 0;
var formName = new FormData();
formName.append(key++,name)
formName.append(key++,pass) //append the the var to formdata
$.ajax({
url : 'includes/ajax.php',
dataType : 'text',
cache : false,
contentType : false,
processData : false,
data : formName,
type : 'post',
success : function(data){
$('#message').html(data).show() /*fadeIn(1000).fadeOut(1000)*/ ;
}
});
});
this works fine for me :-)
I have array containg image path ,
GenerateReport[0] ="../images/Desert1.jpg"
GenerateReport[1] ="../images/Desert2.jpg"
GenerateReport[2] ="../images/Desert3.jpg"
GenerateReport[3] ="../images/Desert4.jpg"
GenerateReport[4] ="../images/Desert5.jpg"
I am trying to pass this array with following code,
$.ajax({
type: "POST",
url: "generatePdf.php",
data: {
genRep: "sample value"
},
success: function(data) {
alert(data);
console.log('getting '+data);
}
});
sample value is passed successfully , but how can i pass array to ajax and use it on another page?? i tried passing array and using with below code but it is not working
$data1 = $_REQUEST['genRep'];
echo "tested".$data1[0];
Try like
genRep = [];
$.ajax({
type: "POST",
url: "generatePdf.php",
data: {
genRep: GenerateReport
},
success: function(data) {
alert(data);
console.log('getting '+data);
}
});
It will send your array as genRep
try to use json object. in object you can store your images path
var data=[]; // array
var data[0] = 'something';
var data[1] = 'something1';
var data = { 'name': name, 'email' : email, 'contact' : contact, 'type' : type, 'msg' : msg }; // object
$.ajax({
url : 'contact.php',
type : 'POST',
data : {contact:JSON.stringify(data)}, // for json object
data : {contact: data}, // for array
success : function (msg)
{
alert(msg);
}
})
contact.php
$info = $_POST['contact'];
$info = json_decode($info,true); // for json object
echo $info.name; // for json object
echo $info[0]; // will print something...
$arr = array();
$arr[0] = "Mark Reed";
$arr[1] = "34";
$arr[2] = "Australia";
echo json_encode ($arr);
use this on the php page
and use the following to get the output
success:function(msg){
id_numbers = JSON.parse(msg);
alert(id_numbers)
}
Try:
$.ajax({
url: "generatePdf.php",
type: 'POST',
data: form_data,
dataType:"json",
success: function(data) {
alert(data[0]);
}
On the PHP side, you'll be wanting to print:
print json_encode($photos);
Made Some Change
print json_encode(array("photolist"=>$photos));
Then on the server, you'd access these with:
data.photolist[0]; //First photo
I have tested it, this will definitely work !
JS:
var GenerateReport = [];
GenerateReport[0] ="../images/Desert1.jpg";
GenerateReport[1] ="../images/Desert2.jpg";
GenerateReport[2] ="../images/Desert3.jpg";
GenerateReport[3] ="../images/Desert4.jpg";
GenerateReport[4] ="../images/Desert5.jpg";
$.ajax({
type: 'POST',
url: 'generatePdf.php',
data: 'image_array='+GenerateReport,
success: function(msg) {
alert(msg);
}
});
generatePdf.php :
<?php
$image_string = $_POST['image_array'];
$image_array = explode(",", $image_string);
print_r($image_array);
?>
Then you can loop over the $image_array to get the values.
try this
GenerateReport[0] ="../images/Desert1.jpg"
GenerateReport[1] ="../images/Desert2.jpg"
GenerateReport[2] ="../images/Desert3.jpg"
GenerateReport[3] ="../images/Desert4.jpg"
GenerateReport[4] ="../images/Desert5.jpg"
corrected code:
var imagedata = '';
$.each(GenerateReport,function(index,value))
{
if(imagedata=='')
{
imagedata = imagedata +'image'+index+'='+value;
}
else
{
imagedata = imagedata +'&image'+index+'='+value;
}
});
$.ajax({
type: "POST",
url: "generatePdf.php",
data: imagedata //pass string imagedata
success: function(data) {
alert(data);
console.log('getting '+data);
}
});
imagedata should have sting like this:
image1=../images/Desert1.jpg&image2=../images/Desert2.jpg and so on
if(isset($_REQUEST['genRep']))
{
$data = $_REQUEST['genRep'];
print_r($data1);
echo "tested".$data1[0];
createPdf($data);
}
My code was correct , there was no value on index 0 , thats why it was not printing anything .My Mistake !!!