I am workng on a project in which I have to put back button functionality. Unfortunatly I can't seem to work it out. I have created a back button and it works. But if the user wants to edit the previous form and then submit data again, so it edits the query. I have tried it in my project but it adds another record in the database and doesn't update the previous one. I know I am not using any update query here. Now I am stuck how would it works I can't think of a good logic. I have made a simple form for example. It is written below.
<?php
$con = mysqli_connect('localhost','root','','test1');
if (isset($_POST['sub'])) {
$first_name = $_POST['fname'];
$second_name = $_POST['lname'];
$sql = "INSERT INTO `tbl`(`first_name`, `last_name`) VALUES
('$first_name', '$second_name')";
$run = mysqli_query($con, $sql);
}
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>
<body>
<form method="POST" action="nextpage.php">
First_name: <input type="text" name="fname">
Second_name: <input type="text" name="lname">
<input type="submit" name="sub" value="submit">
</form>
</body>
</html>
nextpage.php
<?php
$con = mysqli_connect('localhost','root','','test1');
?>
<html>
<body>
<h1>Next Page</h1>
<p>The query is submitted press ok to forward and back if you want to go back</p>
<button>OK</button>
<button onclick="history.go(-1);">Back</button>
</body>
</html>
Thanks for your expert advice in advance.
If I understand correctly.. ..you have a lot of work to do to be able to to 'UPDATE' a record that you have just created.
Dont bother trying to go 'back' to the original form, go forwards to a new 'edit' form, passing the ID from the record that you have just created.
Use the ID to SELECT that record from the DB and pre-populate the 'edit' form. Add a hidden ID field to the form. Then on submission of the 'edit' form, UPDATE the existing record, using the ID.
I think you are taking the "back" button too literally. you are emulating the browser's back button. Instead, update your link text to "edit the submitted record", and either modify the submit page with the capability of editing it, (eg. a hidden input field with the index value of the last created item), or redirect to a page dedicated to editing the submitted record. the user will see it as going back, but the functionality will be different.
submitform:
<?php
$edit = false;
if(isset($_GET['editid']){
$edit = true;
//get the record, and display it in the fields below
}
$con = mysqli_connect('localhost','root','','test1');
if (isset($_POST['sub'])) {
$first_name = $_POST['fname'];
$second_name = $_POST['lname'];
$sql = "INSERT INTO `tbl`(`first_name`, `last_name`) VALUES
('$first_name', '$second_name')";
$run = mysqli_query($con, $sql);
}
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>
<body>
<form method="POST" action="nextpage.php">
First_name: <input type="text" name="fname" <?=($edit)?"value=\"".$req["fname"]."\":""?>>
Second_name: <input type="text" name="lname">
<input type="submit" name="sub" value="submit">
</form>
</body>
</html>
nextpage.php
<?php
$con = mysqli_connect('localhost','root','','test1');
?>
<html>
<body>
<h1>Next Page</h1>
<p>The query is submitted press ok to forward and back if you want to go back</p>
<button>OK</button>
<button onclick="submitform.php?editid=<?=mysqli_last_return_id()?>">Back</button>
</body>
</html>
Here's the answer to my own question..Hope it would help someone..
test.php
<?php
session_start();
$con=mysqli_connect('localhost','root','','test1');
if(isset($_POST['sub'])){
$first_name=$_POST['fname'];
$second_name=$_POST['lname'];
$sess_username=$_SESSION['user_name'];
$sql="INSERT INTO `tbl`(`first_name`, `last_name`,`sess_username`)
VALUES ('$first_name','$second_name','$sess_username')";
$run=mysqli_query($con, $sql);
header("location:nextpage.php");
}
if(isset($_POST['upd'])){
$first_name=$_POST['fname'];
$second_name=$_POST['lname'];
$id=#$_GET['id'];
$upd="UPDATE `tbl` SET
`first_name`='$first_name',`last_name`='$second_name' WHERE `id`='$id'";
$query=mysqli_query($con, $upd);
header("location:nextpage.php");
}
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<script type="text/javascript" src="http://code.jquery.com/jquery.js">
</script>
<script type="text/javascript">
$(document).ready(function () {
if(window.location.href.indexOf("id") > -1) {
$('.submit').hide();
$('.update').show();
}
});
</script>
<title>Untitled Document</title>
</head>
<body>
<form method="POST" action="">
First_name:<input type="text" name="fname">
Second_name:<input type="text" name="lname">
<input class="update" type="submit" value="Update" name="upd"
style="display:none;">
<input class="submit" type="submit" name="sub" value="submit">
</form>
</body>
</html>
nextpage.php
<?php
session_start();
$con=mysqli_connect('localhost','root','','test1');
$sql="SELECT * FROM `tbl` WHERE
`sess_username`='".$_SESSION['user_name']."'";
$run=mysqli_query($con, $sql);
while($res=mysqli_fetch_assoc($run)){
$id=$res['id'];
$firstname=$res['first_name'];
$lastname=$res['last_name'];
$sess=$res['sess_username'];
}
?>
<html>
<body>
<h1>Next Page</h1>
<p>The query is submitted press ok to forward and back if you want to go
back</p>
<button >OK</button>
<form method="POST" action="test.php">
<?php echo "<a href='test.php?id=$id;'>Back</a>"; ?>
</form>
</body>
</html>
Related
I Use below html page for tag-it. But when i submit the form, i can't get the value from form.
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<title>Untitled Document</title>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<script src="//ajax.googleapis.com/ajax/libs/jqueryui/1.11.1/jquery-ui.min.js"></script>
<script src="http://girlzunderground.com/code/tagit.js"></script>
<script >
$(function() {
$('#demo3').tagit({
tagSource:function( request, response ) {
$.ajax({
url: "http://localhost/test.com/tag/tagdb.php",
dataType: "json",
data: {
q: request.term
},
success: function( data ) {
response( data );
}
});
},
triggerKeys:['enter', 'comma', 'tab'],
allowNewTags: false
});
});
//http://girlzunderground.com/php/profile-tags.php?t=books&txt=book
</script>
</head>
<body>
<div class="box">
<form action="display.php" method="post">
<ul id="demo3" class="tagit">
<li class="tagit-new" >
<input id="test1" name="test1[]" style="width:200px;" class="tagit-input ui-autocomplete-input" type="text" autocomplete="off" role="textbox" aria-autocomplete="list" aria-haspopup="true"/>
</li>
</ul>
<input type="text" value="qqq" name="q"/>
<input type="submit" value="submit"/>
</form>
</div>
</body>
</html>
But when i submit the form, i can't get input "test1" value. But i can get input "q" value.
This is my display.php page
<?php
$Category=$_POST['test1'];
$q=$_POST['q'];
echo $q;
//exit();
$allCourse=NULL;
$count=0;
foreach($Category as $Cat)
{
$count=$count+1;
$allCourse=$allCourse.'~'.$Cat;
}
$allCourse=$allCourse.'~';
echo $allCourse;
?>
How can i get my tag-it value from html form..
How can I validate my CSV format and I am using "required" in my html form to validate null value. I try to use onclick function to validate using alert box but alert box not function after I add php code inside javascript. Below is my code. Can anyone suggest a solution to me?
<?php
require_once "lib/base.inc.php";
?>
<script>
function storeQueEmail(){
<?php
$file = $_FILES[csv][tmp_name];
$handle = fopen($file,"r");
//loop through the csv file and insert into database
do {
if ($data[0]) {
$record['contact_first'] = $data[0];
$record['contact_last'] = $data[1];
$record['contact_email'] = $data[2];
$record['subject'] = $_REQUEST['subject'];
$record['message'] = $_REQUEST['message'];
$record['status'] = 0;
$oAdminEmail->insertQueEmail($record);
}
} while ($data = fgetcsv($handle,1000,",","'"));
?>;
alert('jyfkyugu');
window.location.href="cronjob_sendemail.php";
</script>
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<title>Import a CSV File with PHP & MySQL</title>
</head>
<body>
<form action="" method="post" enctype="multipart/form-data" name="form1" id="form1" >
Subject : <br/>
<input type="text" name="subject" id="subject" required/> <br/>
Choose your file: <br />
<input name="csv" type="file"id="csv" required/> <br/>
Content : <br/>
<textarea name="message" cols="50" rows="10" required></textarea><br/>
<input type="submit" name="submit" value="Submit" onclick="storeQueEmail()"/>
</form>
</body>
</html>
I'm trying to create a form submission and before the form is submitted, I want to verify the credentials.
I have both this so far
HTML formatted for XHTML
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en">
<head>
<title> Registration Form</title>
<meta http-equiv="content-type" content="text/html; charset=utf-8"/>
<meta name="description" content="This is a form submission with validation"/>
<script type="text/javascript" src="validScript.js"></script>
</head>
<body>
<h1>Registration Form</h1>
<form id="registration" action="" onsubmit="return validation();" method="post" enctype="text/plain">
<p>Name: <input type="text" name="name" id="name"/></p>
<p class="error">Email Address: <input type="text" name="emailAddress" id="emailAddress"/></p>
<p><input type="submit" name="submit" value="Submit"/></p>
</form>
</body>
</html>
JavaScript:
function validation()
{
var vname = document.registration.name;
if(nameValid(vname))
{
return true;
}
return false;
}
function nameValid(vname)
{
var name_len = vname.value.length;
if (name_len == 0)
{
alert("Name is required");
vname.focus();
return false;
}
return true;
}
I'm having issues where it won't display alert the user that he/she prompted an empty name. I'm trying to valid the name and after this I'll add more functions for email address and other fields to be added. Note that this will later be used to email the form to a domain. Can someone help me figure out this problem?
Thanks
your validation function is incorrect, should be:
function validation()
{
var vname = document.getElementById("name");
if(nameValid(vname))
{
return true;
}
return false;
}
For access form elements values use document.getElementById("ElementID").value or use a javascript library like Jquery
In form add name="registration" and then check.
it will alert as you want.
and the reason is document.registration.name , where registeration is form name , not id.
If you're using jQuery I can recommend this plugin:
http://validval.frebsite.nl/
I tried quite some validation plugins before I came to this one: It has extensive validation options and it's not too fancy on the dialogs; This means easy to customize the look and feel.
I can't seem to figure out what I'm doing wrong with this no matter how many things I try. I've looked through Google for a related issue but found nothing specific. Hopefully someone can help me.
The script runs through a external .js file calling a list of music albums, then listing the song of the album chosen via ajax. The user can then edit of delete the songs. Everything works fine until I submit the edited information through a form. When I click the submit button I get a web developer error "updateSong is not a function"
Here's the form:
<?php
include("database.php");
$song = $_GET['song'];
$query = "SELECT * FROM song INNER JOIN genre ON song.gID = genre.gID INNER JOIN album ON song.alID = album.alID WHERE sID = '$song'";
$result = mysql_query($query);
while($row = mysql_fetch_array($result)) {
echo ("
<form action='#' method='POST' name='updateSong' onSubmit='updateSong(\"$song\")'>
<input name='songName' type='text' value='$row[songName]' />
<input type='text' id='genreSearch' name='genre' alt='Genre Search' onkeyup='searchSuggest();' autocomplete='off' value='$row[genreName]'/>
<div id='genre_search_suggest'></div>
<input name='songURL' type='text' value='$row[songUrl]' />
<input name='sID' type='hidden' value='$row[sID]' />
<input name='Submit' type='Submit' value='Update Song' />
</form>
");
}
?>
Here's the javascript:
function updateSong(sID) {
if(ajax) {
var song = sID;
alert("2");
ajax.open('get', './song_update.php' + encodeURIComponent(sID));
alert("3");
ajax.onreadystatechange = function() {
handleResponse(ajax);
}
ajax.send(null);
return false;
}
}
//EDIT//
Here's the page it's loaded into. I removed the unnecessary stuff around what this question is dealing with.
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<title>Untitled Document</title>
<link href="style.css" rel="stylesheet" type="text/css" />
<link href="artistPageStyle.css" rel="stylesheet" type="text/css" />
<script type="text/javascript" src="javascripts/artistAjax.js"></script>
</head>
<body>
<div id="mediaPlayerBox">
<div id="artistAlbumList">
<?php
$query = "SELECT * FROM `album` INNER JOIN artist ON album.aID = artist.aID WHERE artist.LoginKey = '$token'";
$result = mysql_query($query);
while($row = mysql_fetch_array($result)) {
echo ("<div id='artistAlbumBox'><div id='artistAlbum'><a href='#' onclick='loadAlbum($row[alID])'><img src='$row[albumCover]' width='75px' height='75px' border='0px' ></a></div><div id='artistAlbumLabel'>$row[albumName]</div></div>");
}
?>
</div>
</div>
</body>
</html>
Shouldn't it be: onSubmit='updateSong("$song")'?
try doing onSubmit='return updateSong($song)'
It's saying it is not a function because it isn't loaded, are you loading the external script in the display page at all?
I am trying to get this to be if your name is Bob then you are register if not Sorry you are not allowed access but i can not figure out what I am doing wrong can someone help me thanks.
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title></title>
<meta http-equiv="content-type" content="text/html;charset=iso-8859-1" />
</head>
<script type="text/javascript">
function verify() {
var name="Please enter your name: ";
if (firstName=="Bob") {
alert("Now registered");
}
else {
window.alert("Sorry you aren't allowed acess.")
return false;
}
</script>
<form name="myForm" action="#" method="post" enctype="text/plain">
<input type="text" name="BOB">First Name<br>
<input type="button" value="Submit" onclick="verify();">
</form>
</body>
</html>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title></title>
<meta http-equiv="content-type" content="text/html;charset=iso-8859-1" />
</head>
<script type="text/javascript">
function verify() {
var name="Please enter your name: ";
var firstName = document.getElementById('firstName').value;
if (firstName=="Bob") {
alert("Now registered");
return true;
}
else {
window.alert("Sorry you aren't allowed acess.")
return false;
} }
</script>
<form name="myForm" action="#" method="post" onsubmit="return verify();" enctype="text/plain">
<input id="firstName" type="text" name="BOB"/>First Name<br>
<input type="button" value="Submit"/>
</form>
</body>
</html>
you have to use onsubmit on form tag and it must return true or false
Note that you are missing the closing braces for the function, this code works:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title></title>
<meta http-equiv="content-type" content="text/html;charset=iso-8859-1" />
</head>
<script type="text/javascript">
function verify()
{
var name="Please enter your name: ";
if (myForm.firstName.value=="Bob")
{
alert("Now registered");
}
else
{
alert("Sorry you aren't allowed acess.")
return false;
}
}
</script>
<form name="myForm" action="#" method="post" enctype="text/plain">
<input type="text" name=firstName>First Name<br>
<input type="button" value="Submit" onclick="verify();">
</form>
</body>
</html>
This should work.
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title></title>
<meta http-equiv="content-type" content="text/html;charset=iso-8859-1" />
</head>
<body>
<script type="text/javascript">
function verify() {
var firstName = document.getElementById('firstName').value;
if (firstName == "Bob") {
alert("Now registered");
return true;
} else {
window.alert("Sorry you aren't allowed access.");
return false;
}
}
</script>
<form name="myForm" action="#" method="post" onsubmit="return verify();" enctype="text/plain">
<input id="firstName" type="text" name="BOB"/>First Name<br>
<input type="submit" value="Submit"/>
</form>
</body>
</html>
Update your javascript like so:
<script type="text/javascript">
function verify() {
var name="Please enter your name: ";
if (document.myForm.firstName.value=="Bob") {
alert("Now registered");
return true;
}
else {
window.alert("Sorry you aren't allowed acess.")
return false;
}
}
</script>
Then update your HTML form to this:
<form name="myForm" action="#" method="post" enctype="text/plain">
<input type="text" name="firstName" value="">First Name<br>
<input type="button" value="Submit" onclick="verify();">
</form>
your onsubmit should be on the form handler (the open tag of the "form"), not on the button.
Several issues:
You don't have a javascript variable firstName anywhere. The script probably stops there.
Your form markup for the first name field is strange (why are you naming the text box "BOB"? You should give it an ID.
You need to access the form element in javascript properly.
When submitting a form, it is better to use a submit input type and hookup the form onsubmit (in this regard the answer by #Pravat is correct, though not on the other points).
This line does nothing - var name="Please enter your name: ";
Firstly the Javascript does not know what firstname is
To fix this you need to do two things:
Use the HTML <input name="BOB" id="firstName" value="" />. Note the id attribute, we'll use this to let the JS find the element we want to examine.
Then in Javascript we can find what the user has entered in the input using document.getElementById('firstName').value.
This should let you do your comparison.
To fix minor parts of your code, I believe you forgot to open your <body> tag
your also missing a } for your function
self-close your input and br tags
Try to use:
var firstName = document.getElementById('firstName').value;
and put missing } for verify function
see this..., you also have a } missing... just before the < /script> ... the missing } is the one that closes the verify function.