Develop Reference

Redirect to URL with value in a search form using ACTION and POST method

I have a search form, where user enter a keyword:
<form method="post" action="domain.com/gallery/<?php echo $_POST["something"]; ?>" >
<input type="text" name="something" required/>
<input type="submit"/>
</form>
<?php
if (isset($_POST["something"])) {
echo $_POST["something"];
}
?>
I want go to url "domain.com/gallery/keyword" after form submission.
The problem is that I can't, with the code above it redirects to "domain.com/gallery/", without keyword value...
I'm using POST and ACTION, because "isset($_POST["something"])" is not working with other methods like onsubmit, e.g. "onsubmit="window.location = 'domain.com/gallery/' + something.value; return false;""

I think you have to change the value of action attribute. You can doing it with javascript:
<form method="post" action="domain.com/gallery/" onSubmit="changeTarget(this)">
The javascript:
function changeTarget(currentForm)
{
//read initial attribute value
actionAttribute = currentForm.getAttribute('action');
//read form field value
enteredKeyword = currentForm.omething.value;
//Concantinate both values and set it as new target
currentForm.setAtrribute('action') = actionAttribute + enteredKeyword;
//Nessacary return statement
return true;
}

Try this
<form method="post" action="{samePage}.php" >
<input type="text" name="something" required/>
<input type="submit"/>
</form>
<?php
if (isset($_POST["something"])) {
$url="domain.com/gallery/".<?php echo $_POST["something"];
header("Location: $url")?>
}
?>

JQuery AJAX - passing data from form to PHP script

My task is triggering php script from HTML form, which is updating JSON file from which HTML is generated. Here is how i am trying to do that.
HTML Form:
<form method="post">
<label for="board">Board to update:</label><br>
<input type="text" id="board" name="board"><br><br>
<input type="button" value="Submit" onclick="update()">
</form>
Javascript:
function update() {
var board=$('#board').val();
$.post('update.php',{boardname:board}, function() {
alert("update successfull");
})
}
and PHP:
<?php
$q=$_POST['boardname'];
echo ($q);
shell_exec('curl https://cyberland.club/' . $q . '/?num=1000 > posts.json');
?>
There is no error after clicking button, but website is not updating. Can you tell me why is that? What am i doing wrong? I was using this tutorial https://www.youtube.com/watch?v=jVAaxkbmCts

Validate form with ISSET when using js delay function

I am trying to validate if the correct form is being sent with isset(), but this validation is not TRUE when a javascript delay is being applied. How come? What is the best way to check if the correct form was submitted via the POST method? See my code below. Maybe a hidden field would do the trick, but I actually really would like to know why the below code is not going through.
<script type="text/javascript">
window.addEventListener('load', function onload(){
var ccform = document.getElementById('cc_form');
if(ccform){
ccform.addEventListener('submit', function before_submit(e){
setTimeout(function wait(){
// After waiting, submit the form.
ccform.submit();
}, 2000);
// Block the form from submitting.
e.preventDefault();
});
}
});
</script>
<?php
if ($_SERVER['REQUEST_METHOD'] == 'POST' && isset($_POST['cc_form_submit'])) {
//Send the form
//Not working
echo 'ready to send!';
}
if ($_SERVER['REQUEST_METHOD'] == 'POST') {
//Send the form
//Working
echo 'ready to send without ISSET!';
}
?>
<form action="" method="post" class="cc_form" id="cc_form">
<button class="cc_form_submit" type="submit" name="cc_form_submit">Send!</button>
</form>

In your example, there are so many possible solutions:
Solution 1:
You can use a hidden value inside your form and then check this value in isset() method like:
<form method="post">
<input type="hidden" name="form1" />
<button>Submit</button>
</form>
<form method="post">
<input type="hidden" name="form2" />
<button>Submit</button>
</form>
<?php
if(isset($_POST['form1'])){
// do somthing
}
if(isset($_POST['form2'])){
// do somthing
}
?>
Solution 2:
You can use input type submit instead of <button> like:
<form method="post">
<input type="submit" name="form1">
</form>
<form method="post">
<input type="submit" name="form2">
</form>
<?php
if(isset($_POST['form1'])){
// do somthing
}
if(isset($_POST['form2'])){
// do somthing
}
?>
Solution 3:
You can use different action for multiple <form> like:
<form method="post" action="form1.php">
</form>
<form method="post" action="form2.php">
</form>
Edit:
As per your comment
don't know why if ($_SERVER['REQUEST_METHOD'] == 'POST' && isset($_POST['cc_form_submit'])) { is not working.
Its not working because, you are using name= attribute with <button>, in this case solution 2 will work for you.

How to simply post javascript data to PHP with HTML form

I have this in my javascript code:
var data = signaturePad.toDataURL('image/png');
document.write(data);
the output looks slimier to that:
data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAAZAAAADICAYAAADGFbfiAAAHFklEQVR4Xu3VsQ0AAAjDMPr/0/yQ2exdLKTsHAECBAgQCAILGxMCBAgQIHAC4gkIECBAIAkISGIzIkCAAAEB8QMECB...
Instead of document.write(data); I want to post the data to the self page by using a simple HTML form with hidden filed that can hold the data from JS. then, I want to use PHP to handle $_POST and store the data in a variable...
<?php
// check for form submission...
if(isset($_POST['send'])) {
// get the data
$data = $_POST['data'];
}
?>
HTML form:
<form method="post">
<input type="hidden" name="data" value="">
<input type="submit" name="send" value="submit">
</form>
I understand that I can somehow do it with AJAX but I couldn't figure out with the form, how should I get this done?
I guess that I'm looking for 2 solutions - first, how to use the form with JS to store the data in the hidden field and afterwords, maybe how to post it via AJAX to PHP if it can't be just posted to the same page...

There is a lot of ways to achieve this. In regards to the way you are asking, with a hidden form element.
change your form to:
<form method="post" name="myform" method="post" action="script.php">
<input type="hidden" name="data" value="">
<input type="submit" name="send" value="submit">
</form>
Javascript:
var data = signaturePad.toDataURL('image/png');
document.myform.data.value = data;
document.forms["myform"].submit();
Or Jquery:
var data = signaturePad.toDataURL('image/png');
$('form input[name="data"]').val(data);
$("form").submit();

use like this
<?php
$data="<script>signaturePad.toDataURL('image/png')</script>";
?>
<form method="post">
<input type="hidden" name="data" value="<?php echo $data; ?>">
<input type="submit" name="send" value="submit">
</form>
works all the time.

passing textarea data from view to controller codeigniter

I have a form in my home_view.php that uses textarea that goes like this:
<form action="<?php echo base_url();?>add" method="post">
<textarea name="add-list" id="add-list" rows="10" cols="75"> </textarea>
<input type="submit" id="add-btn" class="btn btn-primary" value="Add" />
</form>
In my controller, I have this:
public function add(){
$value = $this->input->post('add-list');
echo "<script type='text/javascript'>alert('$value'); window.location.href='".base_url()."'</script>";
//more code here
}
The problem is the alert only pops up when I have a one-liner input. How can I get all the inputs of the user including new line ('\n')?

You can use nl2br function :
$value = nl2br($this->input->post('add-list'));