I'm trying to combine two arrays of objects, based on two properties, and rewrite the names of other properties in the joined dataset.
This is what the datasets look like:
var xData = [
{ row_id: 1, date: '2013-04-01', cost: 18 },
{ row_id: 2, date: '2013-04-01', cost: 27 } ...
];
var yData = [
{ row_id: 1, date: '2013-04-01', cost: 48 },
{ row_id: 3, date: '2013-04-01', cost: 37 } ...
];
The properties I want to join on are the row_id and date properties, and I want to rewrite cost to x_cost and y_cost respectively. I also want to deal with missing values. So this is what I want to end up with:
var combinedData = [
{ row_id: 1, date: '2013-04-01', x_cost: 18, y_cost: 48 },
{ row_id: 2, date: '2013-04-01', x_cost: 27, y_cost: null },
{ row_id: 3, date: '2013-04-01', x_cost: null, y_cost: 37 } ...
];
This is my code right now. It's pretty horrible:
combineXAndYDatasets: function(xData, yData) {
// Index both datasets by ID and date.
var x_indexed_by_id_and_date = {};
xData.forEach(function(d) {
var k = d.row_id + '_' + d.date;
x_indexed_by_id_and_date[k] = d;
});
var y_indexed_by_id_and_date = {};
yData.forEach(function(d) {
var k = d.row_id + '_' + d.date;
y_indexed_by_id_and_date[k] = d;
});
var combinedData = [];
// Iterate over ydata, join with xdata if possible.
for (var row_id in y_indexed_by_id_and_date) {
var row = JSON.parse(JSON.stringify(y_indexed_by_id_and_date[row_id]));
row.y_cost = +y_indexed_by_id_and_date[row_id].cost;
if (row_id in x_indexed_by_id_and_date) {
row.x_cost = +x_indexed_by_id_and_date[row_id].cost;
} else {
row.x_cost = null;
}
combinedData.push(row);
}
// Iterate over xdata, add anything that wasn't in ydata.
for (var x_row_id in x_indexed_by_id_and_date) {
if (!(x_row_id in y_indexed_by_id_and_date)) {
var x_row = JSON.parse(JSON.stringify(x_indexed_by_id_and_date[x_row_id]));
x_row.y = null;
x_row.x = +x_row.cost;
combinedData.push(x_row);
}
}
return combinedData;
}
What can I do to make this less awful?
I'm using jQuery, and I could add e.g. Underscore if that would help.
You could take advantage of reduce to reduce each array to a dictionary and then convert that dictionary back into an array. Something like this (vanilla JS, not IE 8 compatible out-of-the-box):
var xData = [
{ row_id: 1, date: '2013-04-01', cost: 18 },
{ row_id: 2, date: '2013-04-01', cost: 27 }
];
var yData = [
{ row_id: 1, date: '2013-04-01', cost: 48 },
{ row_id: 3, date: '2013-04-01', cost: 37 }
];
var xDataDict = xData.reduce(function(p,c) {
createDictionaryEntry(p,c,c.cost,null)
return p;
},{});
xAndYDataDict = yData.reduce(function(p,c) {
createDictionaryEntry(p,c,null,c.cost)
return p;
}, xDataDict);
var combinedData = Object.keys(xAndYDataDict).map(function(key) {
return xAndYDataDict[key];
});
alert(JSON.stringify(combinedData));
function createDictionaryEntry(p,c,x_cost,y_cost) {
var key = c.row_id + "-" + c.date;
if (p[key]) {
p[key].x_cost = p[key].x_cost || x_cost;
p[key].y_cost = p[key].y_cost || y_cost;
} else {
p[key] = {
row_id: c.row_id,
date: c.date,
x_cost: x_cost,
y_cost: y_cost
}
}
}
Note that combinedData won't be in any guaranteed order, so if that's important, you can always sort it afterwards.
Using underscore:
var xData = [
{ row_id: 1, date: '2013-04-01', cost: 18 },
{ row_id: 2, date: '2013-04-01', cost: 27 }
];
var yData = [
{ row_id: 1, date: '2013-04-01', cost: 48 },
{ row_id: 3, date: '2013-04-01', cost: 37 }
];
var xDataDict = _.reduce(xData, function(p,c) {
createDictionaryEntry(p,c,c.cost,null)
return p;
},{});
xAndYDataDict = _.reduce(yData,function(p,c) {
createDictionaryEntry(p,c,null,c.cost)
return p;
}, xDataDict);
var combinedData = _.map(Object.keys(xAndYDataDict),function(key) {
return xAndYDataDict[key];
});
alert(JSON.stringify(combinedData));
function createDictionaryEntry(p,c,x_cost,y_cost) {
var key = c.row_id + "-" + c.date;
if (p[key]) {
p[key].x_cost = p[key].x_cost || x_cost;
p[key].y_cost = p[key].y_cost || y_cost;
} else {
p[key] = {
row_id: c.row_id,
date: c.date,
x_cost: x_cost,
y_cost: y_cost
}
}
}
<script src="//cdnjs.cloudflare.com/ajax/libs/underscore.js/1.8.3/underscore-min.js"></script>
Related
I have javascript array object as below. My need is to sum value base on seach id in the array object.
var array = [
{ id: 1, val: 10 },
{ id: 2, val: 25 },
{ id: 3, val: 20 },
{ id: 1, val: 30 },
{ id: 1, val: 25 },
{ id: 2, val: 10 },
{ id: 1, val: 20 }
],
For example sum of value for id 1 is 10 + 30 + 25 + 20 = 85 , It may be something link linq but I'm not sure in javascript. Thanks for all answers.
You can use a combination of filter and reduce to get the result you want:
sumOfId = (id) => array.filter(i => i.id === id).reduce((a, b) => a + b.val, 0);
Usage:
const sumOf1 = sumOfId(1); //85
Reading material:
Array.prototype.filter
Array.prototype.reduce
A way to do it with a traditional for loop
var array = [
{ id: 1, val: 10 },
{ id: 2, val: 25 },
{ id: 3, val: 20 },
{ id: 1, val: 30 },
{ id: 1, val: 25 },
{ id: 2, val: 10 },
{ id: 1, val: 20 }
];
var sums = {};
for (var i = 0; i < array.length; i++) {
var obj = array[i];
sums[obj.id] = sums[obj.id] === undefined ? 0 : sums[obj.id];
sums[obj.id] += parseInt(obj.val);
}
console.log(sums);
running example
You can use reduce() and findIndex()
var array = [
{ id: 1, val: 10 },
{ id: 2, val: 25 },
{ id: 3, val: 20 },
{ id: 1, val: 30 },
{ id: 1, val: 25 },
{ id: 2, val: 10 },
{ id: 1, val: 20 }
];
let res = array.reduce((ac,a) => {
let ind = ac.findIndex(x => x.id === a.id);
ind === -1 ? ac.push(a) : ac[ind].val += a.val;
return ac;
},[])
console.log(res);
JS noob here ... I guess something like this should be here too :-)
let newArray = {}
array.forEach((e) => {
!newArray[e.id] && (newArray[e.id] = 0);
newArray[e.id] += e.val;
});
You can loop on the array and check the ids.
var array = [
{ id: 1, val: 10 },
{ id: 2, val: 25 },
{ id: 3, val: 20 },
{ id: 1, val: 30 },
{ id: 1, val: 25 },
{ id: 2, val: 10 },
{ id: 1, val: 20 }
];
var sum = 0;
var id = 1;
$.each(array, function(index, object){
if (object.id == id) {
sum += object.val;
}
});
console.log(sum);
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
Using Array#reduce and Map you can get the sum for each id like so. This also uses destructuring to have quicker access to properties.
const data=[{id:1,val:10},{id:2,val:25},{id:3,val:20},{id:1,val:30},{id:1,val:25},{id:2,val:10},{id:1,val:20}];
const res = data.reduce((a,{id,val})=>{
return a.set(id, (a.get(id)||0) + val);
}, new Map())
console.log(res.get(1));
console.log(res.get(2));
If you wanted to output all the sums, then you need to use Array#from
const data=[{id:1,val:10},{id:2,val:25},{id:3,val:20},{id:1,val:30},{id:1,val:25},{id:2,val:10},{id:1,val:20}];
const res = Array.from(
data.reduce((a,{id,val})=>{
return a.set(id, (a.get(id)||0) + val);
}, new Map())
);
console.log(res);
If the format should be similar as to your original structure, you need to add a Array#map afterwards to transform it.
const data=[{id:1,val:10},{id:2,val:25},{id:3,val:20},{id:1,val:30},{id:1,val:25},{id:2,val:10},{id:1,val:20}];
const res = Array.from(
data.reduce((a,{id,val})=>{
return a.set(id, (a.get(id)||0) + val);
}, new Map())
).map(([id,sum])=>({id,sum}));
console.log(res);
You could take GroupBy from linq.js with a summing function.
var array = [{ id: 1, val: 10 }, { id: 2, val: 25 }, { id: 3, val: 20 }, { id: 1, val: 30 }, { id: 1, val: 25 }, { id: 2, val: 10 }, { id: 1, val: 20 }],
result = Enumerable
.From(array)
.GroupBy(null, null, "{ id: $.id, sum: $$.Sum('$.val') }", "$.id")
.ToArray();
console.log(result);
.as-console-wrapper { max-height: 100% !important; top: 0; }
<script src="https://cdnjs.cloudflare.com/ajax/libs/linq.js/2.2.0.2/linq.js"></script>
Here is another option, introducing an Array.prototype.sum helper:
Array.prototype.sum = function (init = 0, fn = obj => obj) {
if (typeof init === 'function') {
fn = init;
init = 0;
}
return this.reduce(
(acc, ...fnArgs) => acc + fn(...fnArgs),
init
);
};
// .sum usage examples
console.log(
// sum simple values
[1, 2, 3].sum(),
// sum simple values with initial value
[1, 2, 3].sum(10),
// sum objects
[{ a: 1 }, { a: 2 }, { a: 3 }].sum(obj => obj.a),
// sum objects with initial value
[{ a: 1 }, { a: 2 }, { a: 3 }].sum(10, obj => obj.a),
// sum custom combinations
[{ amount: 1, price: 2 }, { amount: 3, price: 4 }]
.sum(product => product.amount * product.price)
);
var array = [{ id: 1, val: 10 }, { id: 2, val: 25 }, { id: 3, val: 20 }, { id: 1, val: 30 }, { id: 1, val: 25 }, { id: 2, val: 10 }, { id: 1, val: 20 }];
// solutions
console.log(
array.filter(obj => obj.id === 1).sum(obj => obj.val),
array.filter(({id}) => id === 1).sum(({val}) => val),
array.sum(({id, val}) => id === 1 ? val : 0)
);
references:
Array.prototype.reduce
Array.prototype.filter
Arrow functions used in sum(obj => obj.val)
Object destructing assignment used in ({id}) => id === 1
Rest parameters used in (acc, ...fnArgs) => acc + fn(...fnArgs)
Conditional (ternary) operator used in id === 1 ? val : 0
I want to make an array of objects grouped by the date property.
let data = [
{ Age: "(60-100)", Date: "28/05/20" },
{ Age: "(60-100)", Date: "28/05/20" },
{ Age: "(4-6)", Date: "28/05/20" },
{ Age: "(60-100)", Date: "29/05/20" },
{ Age: "(38-43)", Date: "29/05/20" },
{ Age: "(4-6)", Date: "29/05/20" },
{ Age: "(38-43)", Date: "30/05/20" },
{ Age: "(38-43)", Date: "30/05/20" }
];
I want the output like
result = [
{ Date: "28/05/20", "(60-100)": 2, "(4-6)": 1 },
{ Date: "29/05/20", "(38-43)": 1, "(4-6)": 1, "(60-100)": 1 },
{ Date: "30/05/20", "(38-43)": 2 },
]
Try this:
function groupByDate(data){
let groupedData = [];
data.forEach(element => {
//Search for the object containing the specified date
let objIndex = groupedData.findIndex(object => {return object.Date == element.Date;})
//If date is not created, create it
if (objIndex == -1){
groupedData.unshift({Date: element.Date})
objIndex = 0;
}
//If age is not created, create it. Else add 1 to specified age.
if(typeof groupedData[objIndex][element.Age] == 'undefined'){
groupedData[objIndex][element.Age] = 1;
} else {
groupedData[objIndex][element.Age]++;
}
});
return groupedData;
}
If you also want to sort by date, you could check out this post.
Hope it helped you!
Give this a try.
let data = [
{ Age: "(60-100)", Date: "28/05/20" },
{ Age: "(60-100)", Date: "28/05/20" },
{ Age: "(4-6)", Date: "28/05/20" },
{ Age: "(60-100)", Date: "29/05/20" },
{ Age: "(38-43)", Date: "29/05/20" },
{ Age: "(4-6)", Date: "29/05/20" },
{ Age: "(38-43)", Date: "30/05/20" },
{ Age: "(38-43)", Date: "30/05/20" }
];
let res = [];
data.map((d, index) => {
if (!res.some(val => val.Date === d.Date)) {
d[`${d.Age}`] = 1
res.push(d)
delete(d.Age)
} else {
let index = res.findIndex(val => val.Date == d.Date);
let _d = res[index];
if (_d.hasOwnProperty(`${d.Age}`)) {
_d[`${d.Age}`] = parseInt(_d[`${d.Age}`] + 1)
} else {
_d[`${d.Age}`] = 1
}
res[index] = _d;
}
})
console.log(res)
try this:
var result={};
for(var item of data) {
if(result[item.Date]==undefined) result[item.Date]={};
if(result[item.Date][item.Age]==undefined) result[item.Date][item.Age]=0;
result[item.Date][item.Age]++;
}
This gives you an object (not an array) with keys of Date and values as object with keys of Age and values as count.
If you still need an array, you can iterate over the result and construct an array.
result=={
"28/05/20": {
"(60-100)": 2,
"(4-6)": 1
},
"29/05/20": {
"(60-100)": 1,
"(38-43)": 1,
"(4-6)": 1
},
"30/05/20": {
"(38-43)": 2
}
}
If you want the array, you can create resultArr=[], iterate over keys of result, tempObj, add key "Date" and value of iterated key, then iterate over keys of iterated key, add each "Age" with it's count, then push tempObj into resultArr...
Condensed version based on #Dante Culaciati approach with optional sort parameter.
const condenseAge = (arr, isSort = true) => {
let r = [];
arr.map((val) => {
let i = r.findIndex(obj => obj.Date == val.Date);
(i < 0) && r.unshift({Date: val.Date}) && (i = 0);
(!r[i][val.Age]) ? r[i][val.Age] = 1 : r[i][val.Age]++;
});
return !isSort?r:r.sort((a,b)=>(ac=a['Date'].split('/'), bc=b['Date'].split('/'), new Date(ac[2],ac[1],ac[0]) - new Date(bc[2],bc[1],bc[0])));
}
console.log(condenseAge([
{ Age: "(4-6)", Date: "02/06/20"},
{ Age: "(60-100)", Date: "28/05/20" },
{ Age: "(60-100)", Date: "28/05/20" },
{ Age: "(4-6)", Date: "28/05/20" },
{ Age: "(60-100)", Date: "29/05/20" },
{ Age: "(38-43)", Date: "29/05/20" },
{ Age: "(4-6)", Date: "29/05/20" },
{ Age: "(38-43)", Date: "30/05/20" },
{ Age: "(38-43)", Date: "30/05/20" }
]));
I have the following array:
var objArray = [
{ num: 1, date: '1/12/2017' },
{ num: 3, date: '1/12/2017' },
{ num: 7, date: '1/12/2017' },
{ num: 1, date: '1/13/2018' },
{ num: 3, date: '1/16/2018' },
{ num: 4, date: '1/16/2018' }
];
I want to combine those with same dates so that the output array looks like this:
var outputArr = [
{ num: 11, date: '1/12/2017' },
{ num: 1, date: '1/13/2018' },
{ num: 7, date: '1/16/2018' }
];
I'm adding all num with similar dates and creating a single new object.
I have a very large dataset of objects like this so I'm trying to reduce the amount of processing time for this.
I've got the arrays sorted by date so that it mirrors objArray.
For loops seems cumbersome since I'm taking the first date in the array and checking every other element in the array a la the following pseudo-code:
var newArr = [];
for(i = 0; i < objArray.length; i++) {
for(j = 0; j < objArray.length; j++) {
var tempArr = [];
// check every date manually
// add similar to new array
tempArr.push({ similar items });
}
newArr.push(tempArr):
}
// Do another couple loops to combine those like arrays into another array
There has to be a more elegant way to perform this than running multiple for loops.
Any suggestions would be appreciated.
Simply use Array.reduce() to create a map and group values by date, Object.values() on the map will give you the desired output value:
let arr = [ { num: 1, date: '1/12/2017' }, { num: 3, date: '1/12/2017' }, { num: 7, date: '1/12/2017' }, { num: 1, date: '1/13/2018' }, { num: 3, date: '1/16/2018' }, { num: 4, date: '1/16/2018' } ];
let result = Object.values(arr.reduce((a, {num, date})=>{
if(!a[date])
a[date] = Object.assign({},{num, date});
else
a[date].num += num;
return a;
},{}));
console.log(result);
Using lodash,
// Aggregate num from unique dates
var g = _.groupBy(objArray,'date')
Object.keys(g).map(k=>({num:g[k].reduce((a,c)=>c.num+a,0),date:k}))
var objArray = [
{ num: 1, date: '1/12/2017' },
{ num: 3, date: '1/12/2017' },
{ num: 7, date: '1/12/2017' },
{ num: 1, date: '1/13/2018' },
{ num: 3, date: '1/16/2018' },
{ num: 4, date: '1/16/2018' }
];
let outputArr = Array.from(objArray.reduce((acc, obj)=>{
acc.set(obj.date, (acc.get([obj.date]) || 0) + obj.num);
return acc;
}, new Map()))
.map(kv=>({num: kv[1], date: kv[0]}))
console.log(outputArr);
gives:
[ { num: 11, date: '1/12/2017' },
{ num: 1, date: '1/13/2018' },
{ num: 7, date: '1/16/2018' } ]
You could also remove the if statements and use a Set if you wanted to be even more declarative.
var objArray = [
{ num: 1, date: '1/12/2017' },
{ num: 3, date: '1/12/2017' },
{ num: 7, date: '1/12/2017' },
{ num: 1, date: '1/13/2018' },
{ num: 3, date: '1/16/2018' },
{ num: 4, date: '1/16/2018' }
];
var mSet = new Set(objArray.map(d => d.date));
return Array.from(mSet).map(d => {
return
{
date: d,
sum: (objArray
.filter(o => o.date === d)
.map(n => n.num)
.reduce((a, c) => a + c, 0))
}
);
This returns:
[{ date: 1/12/2017, sum: 11},
{ date: 1/13/2018, sum: 1 },
{ date: 1/16/2018, sum: 7 }]
Here's another way. It's more verbose, but if you're just starting out it might be easier to understand as opposed to using array methods like reduce().
objArray = [
{ num: 1, date: '1/12/2017' },
{ num: 3, date: '1/12/2017' },
{ num: 7, date: '1/12/2017' },
{ num: 1, date: '1/13/2018' },
{ num: 3, date: '1/16/2018' },
{ num: 4, date: '1/16/2018' }
]
function combineObj(data) {
let validator= new Set();
let combinedArr = [];
let numCount = 0;
// Create a list of unique properties to match against:
data.forEach((e) => validator.add(e.date));
// For each value in the validator, create a new object in a new array
// and add the unique values from the validator to the respective property:
validator.forEach((e) => {
combinedArr.push({
num: 0,
date: e
});
})
// Lastly, for each object in the combinedArr, use a counter to sum up the total values of each property
// as you loop through your data:
combinedArr.forEach((e) => {
numCount = 0;
data.forEach((ee) => {
if (e.date === ee.date) {
numCount += ee.num;
e.num = numCount;
}
})
})
return combinedArr;
}
Returns:
[
{ num: 11, date: '1/12/2017' },
{ num: 1, date: '1/13/2018' },
{ num: 7, date: '1/16/2018' }
]
Having this array:
const xx = [
{
name: "Alex",
income: 324300,
total: 3030000
},
{
name: "Snake",
income: 3433000,
total: 34323000
},
{
name: "Wake",
income: 4,
total: 3
}
];
I want to loop through it and do something if the value is an int (income and total). How do i go about doing it?
This is what i have tried so far, i dont really know how to take out the objects value and test if it is an int
for (var key in xx) {
var arr = xx[key];
for( var i = 0; i < arr.length; i++ ) {
var obj = arr[ i ];
}
}
}
try:
const xx = [
{
name: "Alex",
income: 324300,
total: 3030000
},
{
name: "Snake",
income: 3433000,
total: 34323000
},
{
name: "Wake",
income: 4,
total: 3
}
];
xx.forEach(item => {
Object.keys(item).forEach(key => {
if (!isNaN(parseInt(item[key])) && isFinite(item[key])) {
// do something here
console.log('INT: ' + item[key]);
}
});
});
You need to exchange internal for with the external. and use:
typeof xx[i][k] === "number" OR xx[i][k] === +xx[i][k] to check if value is
a number.
parseInt(xx[i][k]) === xx[i][k] to check if value is an integer
number.
See example:
const xx = [{
name: "Alex",
income: 324300,
total: 3030000
}, {
name: "Snake",
income: 34.33000,
total: 34323000
}, {
name: "Wake",
income: 4,
total: 3
}];
for (var i = 0; i < xx.length; i++) {
for (var k in xx[i]) {
//if(parseInt(xx[i][k]) === xx[i][k]) //integer
//if(typeof xx[i][k] == "number") //number
if (xx[i][k] === +xx[i][k]) { //number
console.log(k + ": " + xx[i][k]);
}
}
}
I am hoping somebody will point me in right direction here. I have an Array with number of objects that have Date, Set and Value as Properties.
I need to convert this on client side to an Array of Arrays where each member Array holds data like this: [ Date, Value of Set 0, Value of Set 1 ]
I'm looking for a solution that will work with any number of "Sets", which is the part that makes it complicated for me. Any proposed solution may require jQuery or some other javascript library set you use to get this done. I don't have a problem with that, let's just get it done. :)
Please refer to initial and end data sets below:
First one is with just two sets:
var data = [
{ Date: "2/10/2013", Set: 0, Value: 1 },
{ Date: "2/10/2013", Set: 1, Value: 0 },
{ Date: "2/11/2013", Set: 0, Value: 15 },
{ Date: "2/11/2013", Set: 1, Value: 8 },
{ Date: "2/12/2013", Set: 0, Value: 12 },
{ Date: "2/12/2013", Set: 1, Value: 11 },
{ Date: "2/13/2013", Set: 0, Value: 15 },
{ Date: "2/13/2013", Set: 1, Value: 19 },
{ Date: "2/14/2013", Set: 0, Value: 10 },
{ Date: "2/14/2013", Set: 1, Value: 20 }
];
var endData = [
[ "2/10/2013", 1, 0 ],
[ "2/11/2013", 15, 8 ],
[ "2/12/2013", 12, 11 ],
[ "2/13/2013", 15, 19 ],
[ "2/14/2013", 10, 20 ]
];
And here is an example of 3 sets.
So, for example if data was like this:
var data = [
{ Date: "2/10/2013", Set: 0, Value: 1 },
{ Date: "2/10/2013", Set: 1, Value: 2 },
{ Date: "2/10/2013", Set: 2, Value: 3 },
{ Date: "2/11/2013", Set: 0, Value: 10 },
{ Date: "2/11/2013", Set: 1, Value: 15 },
{ Date: "2/11/2013", Set: 2, Value: 20 }
];
Returned array would need to be like this:
var endData = [
[ "2/10/2013", 1, 2, 3 ],
[ "2/10/2013", 10, 15, 20 ]
];
Any pointers are appreciated.
Use a loop and a global dat variable to keep track of where you are in the list:
var endData=[], dat='', row=[];
for (var i=0; i<data.length; i++) {
var obj=data[i], val=obj.Value;
if (dat!=obj.Date) {
if (i) endData.push(row);
dat = obj.Date;
row = [dat, val];
} else {
row.push(val);
}
}
endData.push(row); // last one
http://jsfiddle.net/mblase75/rgJbq/
;(function() {
var data = [
{ Date: "2/10/2013", Set: 0, Value: 1 },
{ Date: "2/10/2013", Set: 1, Value: 0 },
{ Date: "2/11/2013", Set: 0, Value: 15 },
{ Date: "2/11/2013", Set: 1, Value: 8 },
{ Date: "2/12/2013", Set: 0, Value: 12 },
{ Date: "2/12/2013", Set: 1, Value: 11 },
{ Date: "2/13/2013", Set: 0, Value: 15 },
{ Date: "2/13/2013", Set: 1, Value: 19 },
{ Date: "2/14/2013", Set: 0, Value: 10 },
{ Date: "2/14/2013", Set: 1, Value: 20 }
];
var endData = {};
for (var i = 0; i < data.length; ++i) {
var date = data[i].Date;
if (endData[date] === undefined)
endData[date] = [];
endData[date].push(data[i].Value);
}
var finalData = [];
for (var ed in endData) {
var a = [ed];
for (var i = 0; i < endData[ed].length; ++i) {
a.push(endData[ed][i]);
}
finalData.push(a);
}
console.log(finalData);
})();
The output looks like:
var finalData = [
["2/10/2013", 1, 0],
["2/11/2013", 15, 8],
["2/12/2013", 12, 11],
["2/13/2013", 15, 19],
["2/14/2013", 10, 20]
];
var endData = [];
var indexes = {};
for(var i = 0, len = data.length; i < len; i++) {
if(indexes[data[i].Date] === undefined) {
indexes[data[i].Date] = endData.length;
endData.push([data[i].Date]);
}
endData[indexes[data[i].Date]][data[i].Set + 1] = data[i].Value;
}