I want to display rows of employee images and, on hover, have a further description box pop up next to the image containing the person's name/biography.
I know hide/show div on hover can be used to achieve this effect, but I'm unsure as to how it will effect the row/col layout.
Any help would be appreciated.
HTML:
<div class="row">
<div class="col-xs-3">
<div class="thumbnail">
<img>
</div>
<div class="thumbnail">
<img>
</div>
<div class="thumbnail">
<img>
</div>
<div class="thumbnail">
<img>
</div>
</div>
<div class="col-xs-3">
<div class="thumbnail">
<img>
</div>
<div class="thumbnail">
<img>
</div>
<div class="thumbnail">
<img>
</div>
<div class="thumbnail">
<img>
</div>
</div>
<div class="col-xs-3">
<div class="thumbnail">
<img>
</div>
<div class="thumbnail">
<img>
</div>
<div class="thumbnail">
<img>
</div>
<div class="thumbnail">
<img>
</div>
</div>
</div>
I believe what you're looking for is a Popover which should lay on top of the existing grid and not interfere with the placement of your images.
You can trigger it to fire on hover by setting a data attribute on each popover like this:
data-trigger="hover"
or by passing it into the initializer like this:
.popover({ trigger: "hover" })
Demo in Stack Snippets:
$('[data-toggle="popover"]').popover({
placement: "auto",
trigger: "hover"
})
<link href="//cdnjs.cloudflare.com/ajax/libs/twitter-bootstrap/3.3.2/css/bootstrap.css" rel="stylesheet"/>
<script src="//cdnjs.cloudflare.com/ajax/libs/jquery/2.1.3/jquery.js"></script>
<script src="//cdnjs.cloudflare.com/ajax/libs/twitter-bootstrap/3.3.2/js/bootstrap.js"></script>
<div class="row">
<div class="col-xs-4">
<div class="thumbnail">
<img src="http://i.imgur.com/wq83mXh.jpg" data-toggle="popover"
title="Mark Otto" data-content="3,972 commits / 496,347 ++ / 484,436 --" >
</div>
</div>
<div class="col-xs-4">
<div class="thumbnail">
<img src="http://i.imgur.com/RLuBL13.png" data-toggle="popover"
title="Chris Rebert"data-content="1,114 commits / 33,796 ++ / 46,366 --">
</div>
</div>
<div class="col-xs-4">
<div class="thumbnail">
<img src="http://i.imgur.com/UP58UYq.jpg" data-toggle="popover"
title="fat" data-content="805 commits / 143,748 ++ / 100,852 --">
</div>
</div>
</div>
Related
I want to change selected (or default) image when users clicked other images thumbs. I tried that with below codes but dosen't work.. Where do I mistake in here ?
Here are simple jquery codes;
<script>
$('img.thumbnail').click(function () {
$('#productImage').attr('src',$(this).attr('src').replace('60/60','400/200'));
})
</script>
and html;
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script>
<div class="col-md-5">
<img id="productImage" src='http://via.placeholder.com/400/200?text={{$product->product_name}}'>
<hr>
<div class="row">
<div class="col-xs-3">
<img src="http://via.placeholder.com/60/60?text=otherimage1">
</div>
<div class="col-xs-3">
<img src="http://via.placeholder.com/60/60?text=otherimage2">
</div>
<div class="col-xs-3">
<img src="http://via.placeholder.com/60/60?text=otherimage3">
</div>
</div>
Your img doen't contain class .thumbnail it is opposite like this,
$('.thumbnail img').click(function () {
$('#productImage').attr('src', $(this).attr('src').replace('60/60','400/200'));
});
And also check your <img> tag.
You were not calling the right selector.
$('a.thumbnail').click(function () {
$('#productImage').attr('src',$(this).children('img').attr('src').replace('60/60','400/200'));
})
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script>
<div class="col-md-5">
<img id="productImage" src='https://via.placeholder.com/400/200?text=nothing'>
<hr>
<div class="row">
<div class="col-xs-3">
<img src="https://via.placeholder.com/60/60?text=otherimage1">
</div>
<div class="col-xs-3">
<img src="https://via.placeholder.com/60/60?text=otherimage2">
</div>
<div class="col-xs-3">
<img src="https://via.placeholder.com/60/60?text=otherimage3">
</div>
</div>
Try attaching the click event to a.thumbnail elements and than do a jQuery.find('img') to get the thumbnail image's src attribute:
$('a.thumbnail').click(function () {
var src = $(this).find('img').attr('src').replace('60/60','400/200');
$('#productImage').attr('src', src);
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script>
<div class="col-md-5">
<img id="productImage" src="http://via.placeholder.com/400/200?text=otherimage0">
<hr>
<div class="row">
<div class="col-xs-3">
<img src="http://via.placeholder.com/60/60?text=UrunResimi1">
</div>
<div class="col-xs-3">
<img src="http://via.placeholder.com/60/60?text=otherimage2">
</div>
<div class="col-xs-3">
<img src="http://via.placeholder.com/60/60?text=otherimage3">
</div>
</div>
$(document).ready(function(){
$('.thumbnail img').click(function () {
$('#productImage').attr('src',$(this).attr('src').replace('60/60','400/200'));
});
});
Your jquery selector is incorrect. It should be in this format and make sure you have document.ready function to make it work properly in all the browsers online or offline.
Plnkr Link
I have a problem with owl carousel and till now I don't have any ideas how to fix it.
So on the image 1 you can see the normal behaviour of the slider. On the second one you will see the extended functionality of it. The idea is very simple, when user click on the element, he should expand it, but when the element is expanded all other element goes to 2 rows and I don't want to happen.
Image 1
Image 2
also Source code of one element
<div class="element box-shadow">
<div class="child">
<div class="row">
<div class="col-xs-12 col-md-8">
<span>05.</span>
<h3>Graphic Designer</h3>
<p class="inventive">Inventive Studio</p>
<p class="view-more">View more <img src="assets/images/view-more.svg" /></p>
</div>
<div class="col-xs-12 col-md-4 portfolio-image" >
<img src="assets/images/inventive-small-img.png" />
</div>
</div>
</div>
<div class="parent hidden">
<div class="row">
<div class="col-md-12">
<div class="card">
<div class="row">
<div class="col-xs-12 col-md-8">
<div class="row " style="margin-bottom: 15px;" >
<div class="col-xs-12 col-md-3">
<img src="assets/images/inventive-small-img.png" style="width:34px" class="rounded-circle">
</div>
<div class="col-xs-12 col-md-9 text no-padding" >
<h3>Graphic Designer</h3>
<p class="inventive">Inventive Studio</p>
</div>
</div>
</div>
<div class="col-xs-12 col-md-4 social-el" style="padding-left:0;">
<div class="stars">
<img class="mr-2" src="assets/images/full_star.svg" />
<img class="mr-2" src="assets/images/full_star.svg" />
<img class="mr-2" src="assets/images/half_star.svg" />
<img class="mr-2" src="assets/images/empty_star.svg" />
<img src="assets/images/empty_star.svg" />
</div>
</div>
</div>
<img src="assets/images/inventive-studio-img.png" class="img-fluid">
<div class="content">
<p >Designing and producing catalogs, sales sheets, proposals, scenario illustrations, brochures, posters, custom displays for trade shows and in-house exhibits and all others items.</p>
<div class="row">
<div class="col-xs-12 col-md-6">
<a class="view-less" href="#"><img src="assets/images/view-more.svg"/> View Less</a>
</div>
<div class="col-xs-12 col-md-6">
<div class="stars">
<img src="assets/images/Facebook.svg"/>
<img class="mr-10" src="assets/images/twitter.svg"/>
</div>
</div>
</div>
</div>
</div>
</div>
</div>
</div>
</div>
also will share and jquery code
$(".owl-carousel").owlCarousel({
margin:10,
loop: true,
autoWidth: true,
items:3,
rewind: true,
autoplay: true,
responsiveClass:true,
});
$('.work').each(function(i, el) {
$parent = $(el);
$('.element', $parent).each(function(i, item) {
$element = $(item)
$element.on('click', function(e) {
$current = $(this)
console.log($current)
if ($('.parent', $current).hasClass('hidden')) {
$('.parent', $current).removeClass('hidden');
$current.addClass('expand-element');
$current.css('border-radius', 10)
$('.child', $current).addClass('hidden');
} else {
$current.removeClass('expand-element');
$('.parent', $current).removeClass('visible').addClass('hidden');
$current.css('border-radius', 20)
$('.child', $current).removeClass('hidden');
}
})
})
})
Here is my HTML and Javascript code, and basically as you can see currently what it does is show/hide a row of 3 images upon button click.
Thing is, that there are another 2 rows just like this one and I need to know how I can change the javascript code to make the show/hide thing work for all of them.
I know it has something to do with looping through an array of buttons, but I have no idea of Javascript.
Here it is :
<style>
.show-tapas{
display: none;
}
.show-tapas.showing{
display: block;
}
</style>
<div class="row">
<div class="col-md-12">
<div class="load-more-button">
Tapas
</div>
</div>
</div>
<div class="row show-tapas">
<div class="col-md-4 col-sm-6">
<a href="images/menu_tapas_1_1.jpeg" data-lightbox="image-1"><div class="thumb">
<div class="portfolio-item">
<div class="image">
<img src="images/menu_tapas_1_0.jpeg">
</div>
</div>
</a>
</div>
<div class="col-md-4 col-sm-6">
<a href="images/menu_tapas_2_1.jpeg" data-lightbox="image-1"><div class="thumb">
<div class="portfolio-item">
<div class="image">
<img src="images/menu_tapas_2_0.jpeg">
</div>
</div></div>
</a>
</div>
<div class="col-md-4 col-sm-6">
<a href="images/menu_tapas_3_1.jpeg" data-lightbox="image-1"><div class="thumb">
<div class="portfolio-item">
<div class="image">
<img src="images/menu_tapas_3_0.jpeg">
</div>
</div></div>
</a>
</div>
</div>
<script>
var a = document.querySelector('.load-more-button');
var b = document.querySelector('.show-tapas');
a.addEventListener("click",function(e){
e.preventDefault
b.classList.contains("showing") ? b.classList.remove("showing") : b.classList.add("showing");
})
</script>
Thank you very much!!!
In this code I only see one row with the class .show-tapas.
Anyway, you should use querySelectorAll to take every matched items.
var button = document.querySelector('.load-more-button');
var tapas = document.querySelectorAll('.show-tapas');
button.addEventListener("click",function(e){
tapas.forEach(b => $(b).toggle());
})
Pro-tip: If you have JQuery you might consider using $(b).toggle() instead of b.classList.contains("showing") ? b.classList.remove("showing") : b.classList.add("showing");
How to combine JQuery.show() whit mine working animation so I can display text.
I would like to achieve the same effect like here on this working example .But I don't want to use "data" prefix for displaying text, I want to use jquery.show(). I am having trouble understanding where and how to put mine text for each button and showing it on the middleBubble.
Only difference between mine example and this one, is that mine middleBubble is toggling.
How can I make this work's and implement jquery show() library in working animation?
HTML for mine example:
<section class='circle-animation'>
<div class="container-fluid">
<div class="row">
<div class="hidden-xs hidden-sm">
<div class="col-sm-6 col-sm-offset-3 col-sm-pull-1">
<div id="middlepapir" class="jumbotron">
<div class="row">
<img class="papir img-responsive" src="img/circle/11.png" alt="">
<div class="row">
<div class="move1 col-sm-4 col-xs-4 col-md-push-4">
<img class="position1 round" src="img/circle/off/home-all-icon-off.png">
</div>
</div>
<div class="row">
<div class="move2 col-sm-4 col-xs-4 col-md-push-1">
<img class="position2 round" src="img/circle/off/home-cover-icon-off.png">
</div>
</div>
<div class="row">
<div class="move3 col-sm-4 col-xs-4 col-md-push-7">
<img class="position3 round" src="img/circle/off/home-design-icon-off.png">
</div>
</div>
<div class="row">
<div class="move4 col-sm-4 col-xs-4">
<img class="position4 round" src="img/circle/off/home-diy-icon-off.png">
</div>
</div>
<div class="row">
<div class="move5 col-sm-4 col-xs-4 col-md-push-8">
<img class="position5 round" src="img/circle/off/home-marketing-icon-off.png">
</div>
</div>
<div class="row">
<div class="move6 col-sm-4 col-xs-4 col-md-push-1">
<img class="position6 round" src="img/circle/off/home-other-icon-off.png">
</div>
</div>
<div class="row">
<div class="move7 col-sm-4 col-xs-4 col-md-push-4">
<img class="position7 round" src="img/circle/off/home-special-icon-off.png">
</div>
</div>
<div class="row">
<div class="move8 col-sm-4 col-xs-4 col-md-push-7">
<img class="position8 round" src="img/circle/off/home-vip-icon-off.png">
</div>
</div>
</div>
</div>
</div>
</div>
</div>
</div>
</section>
Jquery for HTML section:
// jQuery script for are Circle div whit Scroll Reveal Script
$(document).ready(function(){
/*==========================================
SCROLL REVEL SCRIPTS
=====================================================*/
window.scrollReveal = new scrollReveal();
/*==========================================
WRITE YOUR SCRIPTS BELOW
=====================================================*/
$('.round').click(function(){
$('.papir').animate({
width: ['toggle', 'swing'],
height: ['toggle', 'swing'],
});
});
});
This is more difficult to examine without your CSS, however, it seems that you missed the layout that your example used. They have a separate area for the main text called id="middleBubble". This is the area that the text is being replaced in.
They are performing the replacement here:
$("#middleBubble").html("<p><b>" + $(this).data("bubble1") + "</b><br />" + $(this).data("bubble2") + "</p>");
where "this" is the element (in this case the image) that has been hovered over. The data is stored in the data-bubble1 and data-bubble2 attributes. You could store it there (the replacement text for each section) or you could store it as a keyed JSON object and use the id of the image to key which values to use. I would recommend the later, but to each their own.
I have a jQuery slide down animation, but I would like to implement it to the paste section bellow.
Content is for a smaller device so every button need to have slide down element attached on him self.
Can some one show me how can I do this.
Mine jQuery slideDown code:
$(".squere").click(function(){
$(".content").hide(800);
$(".squere").removeClass("active");
$(this).addClass("active");
$(this).next(".content").slideDown(1000);
});
Mine Content:
<div id="squere" class='container hidden-lg hidden-md '>
<div class="row">
<div class="col-sm-4 col-xs-4">
<img class="img-responsive img-circle homepageGridDefault" src="img/circle/home-all-icon-off.png">
</div>
<div class="col-sm-4 col-xs-4">
<img class="img-responsive img-circle" src="img/circle/home-cover-icon-off.png">
</div>
<div class="col-sm-4 col-xs-4">
<img class="img-responsive img-circle" src="img/circle/home-diy-icon-off.png">
</div>
</div>
<div class="row">
<div class="col-sm-4 col-xs-4">
<img class="img-responsive img-circle" src="img/circle/home-marketing-icon-off.png">
</div>
<div class="col-sm-4 col-xs-4">Strange book here :)</div>
<div class="col-sm-4 col-xs-4">
<img class="img-responsive img-circle" src="img/circle/home-other-icon-off.png">
</div>
</div>
<div class="row">
<div class="col-sm-4 col-xs-4">
<img class="img-responsive img-circle" src="img/circle/home-special-icon-off.png">
</div>
<div class="col-sm-4 col-xs-4">
<img class="img-responsive img-circle" src="img/circle/home-vip-icon-off.png">
</div>
<div class="col-sm-4 col-xs-4">
<img class="img-responsive img-circle" src="img/circle/home-designe-icon-off.png">
</div>
</div>
Fiddle example, this is the whole dive and it is responsive so do not mind the upper circle in the html section.
Simply use sildeDown and slideUp can resolve your problem.Try this fiddle. Just used slideUp and slide Down method in place of adding and removing active class.
$(document).ready(function(){
$('.content').hide();
});
$(document).on('click',".center",function(){
$(".content").slideUp(300);
$(this).next(".content").slideDown(300);
});
Ok. I've just modified your code and added just 3 images and a content div as below:
DEMO
HTML
<div class="container">
<div class="row">
<div class="col-sm-4 col-xs-4">
<a href="#" class="center">
<img src="http://imgsrc.hubblesite.org/hu/db/images/hs-2003-28-a-thumb.jpg" class="img-circle" alt=""/>
</a>
<div class="content">
Content Image 1
</div>
</div>
<div class="col-sm-4 col-xs-4">
<a href="#" class="center">
<img src="http://imgsrc.hubblesite.org/hu/db/images/hs-1994-02-c-thumb.jpg" class="img-circle" alt=""/>
</a>
<div class="content">
Content Image 2
</div>
</div>
<div class="col-sm-4 col-xs-4">
<a href="#" class="center">
<img src="http://imgsrc.hubblesite.org/hu/db/images/hs-2005-37-a-thumb.jpg" class="img-circle" alt=""/>
</a>
<div class="content">
Content Image 3
</div>
</div>
</div>
</div>
JS
$(document).ready(function(){
$('.content').hide();
});
$(document).on('click',".center",function(){
if($(this).hasClass('active'))
{
return;
}
$(".content").hide(800);
$(".center").removeClass("active");
$(this).addClass("active");
$(this).next(".content").show(1000);
});
Note: These are just basic animations. If you really want to perform some extra-ordinary animations then you need to check on .animate jquery function.
Please use id selector # instead of class selector .
$("#squere").click(function(){
$(".content").hide(800);
$("#squere").removeClass("active");
$(this).addClass("active");
$(this).next(".content").slideDown(1000);
});
Might be it is your issue.
$("#squere").removeClass("active");
$(this).addClass("active");
These lines will not make any effect, because you are removing and adding same css class.