sprintf equivalent for client-side JavaScript - javascript

I know that console.log supports at least some of the basic features of printf from C through messing around, but I was curious of a way to take advantage of console.log's implementation to create something similar to sprintf. I know you can't simply use .bind or .apply since console.log doesn't actually return the string, so is there a way around this?
If this isn't actually possible, is there some other little-known native implementation that's only a few lines of code away from achieving sprintf in JavaScript?
For those who do not know what sprintf is exactly, here is some documentation from tutorialspoint. Example usage I'm looking for is below:
var string1 = sprintf("Hello, %s!", "world");
var string2 = sprintf("The answer to everything is %d.", 42);

Keep it simple
var sprintf = (str, ...argv) => !argv.length ? str :
sprintf(str = str.replace(sprintf.token||"$", argv.shift()), ...argv);
Since Javascript handles data types automatically, there is no need for type options.
If you need padding, "15".padStart(5,"0") = ("00000"+15).slice(-5) = "00015".
Usage
var sprintf = (str, ...argv) => !argv.length ? str :
sprintf(str = str.replace(sprintf.token||"$", argv.shift()), ...argv);
alert(sprintf("Success after $ clicks ($ seconds).", 15, 4.569));
sprintf.token = "_";
alert(sprintf("Failure after _ clicks (_ seconds).", 5, 1.569));
sprintf.token = "%";
var a = "%<br>%<br>%";
var b = sprintf("% plus % is %", 0, 1, 0 + 1);
var c = sprintf("Hello, %!", "world");
var d = sprintf("The answer to everything is %.", 42);
document.write(sprintf(a,b,c,d));

Try utilizing eval , .replace
var sprintf = function sprintf() {
// arguments
var args = Array.prototype.slice.call(arguments)
// parameters for string
, n = args.slice(1, -1)
// string
, text = args[0]
// check for `Number`
, _res = isNaN(parseInt(args[args.length - 1]))
? args[args.length - 1]
// alternatively, if string passed
// as last argument to `sprintf`,
// `eval(args[args.length - 1])`
: Number(args[args.length - 1])
// array of replacement values
, arr = n.concat(_res)
// `res`: `text`
, res = text;
// loop `arr` items
for (var i = 0; i < arr.length; i++) {
// replace formatted characters within `res` with `arr` at index `i`
res = res.replace(/%d|%s/, arr[i])
}
// return string `res`
return res
};
document.write(sprintf("%d plus %d is %d", 0, 1, 0 + 1)
+ "<br>"
+ sprintf("Hello, %s!", "world")
+ "<br>"
+ sprintf("The answer to everything is %d.", 42)
);

Related

How to get odd and even position characters from a string?

I'm trying to figure out how to remove every second character (starting from the first one) from a string in Javascript.
For example, the string "This is a test!" should become "hsi etTi sats!"
I also want to save every deleted character into another array.
I have tried using replace method and splice method, but wasn't able to get them to work properly. Mostly because replace only replaces the first character.
function encrypt(text, n) {
if (text === "NULL") return n;
if (n <= 0) return text;
var encArr = [];
var newString = text.split("");
var j = 0;
for (var i = 0; i < text.length; i += 2) {
encArr[j++] = text[i];
newString.splice(i, 1); // this line doesn't work properly
}
}
You could reduce the characters of the string and group them to separate arrays using the % operator. Use destructuring to get the 2D array returned to separate variables
let str = "This is a test!";
const [even, odd] = [...str].reduce((r,char,i) => (r[i%2].push(char), r), [[],[]])
console.log(odd.join(''))
console.log(even.join(''))
Using a for loop:
let str = "This is a test!",
odd = [],
even = [];
for (var i = 0; i < str.length; i++) {
i % 2 === 0
? even.push(str[i])
: odd.push(str[i])
}
console.log(odd.join(''))
console.log(even.join(''))
It would probably be easier to use a regular expression and .replace: capture two characters in separate capturing groups, add the first character to a string, and replace with the second character. Then, you'll have first half of the output you need in one string, and the second in another: just concatenate them together and return:
function encrypt(text) {
let removedText = '';
const replacedText1 = text.replace(/(.)(.)?/g, (_, firstChar, secondChar) => {
// in case the match was at the end of the string,
// and the string has an odd number of characters:
if (!secondChar) secondChar = '';
// remove the firstChar from the string, while adding it to removedText:
removedText += firstChar;
return secondChar;
});
return replacedText1 + removedText;
}
console.log(encrypt('This is a test!'));
Pretty simple with .reduce() to create the two arrays you seem to want.
function encrypt(text) {
return text.split("")
.reduce(({odd, even}, c, i) =>
i % 2 ? {odd: [...odd, c], even} : {odd, even: [...even, c]}
, {odd: [], even: []})
}
console.log(encrypt("This is a test!"));
They can be converted to strings by using .join("") if you desire.
I think you were on the right track. What you missed is replace is using either a string or RegExp.
The replace() method returns a new string with some or all matches of a pattern replaced by a replacement. The pattern can be a string or a RegExp, and the replacement can be a string or a function to be called for each match. If pattern is a string, only the first occurrence will be replaced.
Source: String.prototype.replace()
If you are replacing a value (and not a regular expression), only the first instance of the value will be replaced. To replace all occurrences of a specified value, use the global (g) modifier
Source: JavaScript String replace() Method
So my suggestion would be to continue still with replace and pass the right RegExp to the function, I guess you can figure out from this example - this removes every second occurrence for char 't':
let count = 0;
let testString = 'test test test test';
console.log('original', testString);
// global modifier in RegExp
let result = testString.replace(/t/g, function (match) {
count++;
return (count % 2 === 0) ? '' : match;
});
console.log('removed', result);
like this?
var text = "This is a test!"
var result = ""
var rest = ""
for(var i = 0; i < text.length; i++){
if( (i%2) != 0 ){
result += text[i]
} else{
rest += text[i]
}
}
console.log(result+rest)
Maybe with split, filter and join:
const remaining = myString.split('').filter((char, i) => i % 2 !== 0).join('');
const deleted = myString.split('').filter((char, i) => i % 2 === 0).join('');
You could take an array and splice and push each second item to the end of the array.
function encrypt(string) {
var array = [...string],
i = 0,
l = array.length >> 1;
while (i <= l) array.push(array.splice(i++, 1)[0]);
return array.join('');
}
console.log(encrypt("This is a test!"));
function encrypt(text) {
text = text.split("");
var removed = []
var encrypted = text.filter((letter, index) => {
if(index % 2 == 0){
removed.push(letter)
return false;
}
return true
}).join("")
return {
full: encrypted + removed.join(""),
encrypted: encrypted,
removed: removed
}
}
console.log(encrypt("This is a test!"))
Splice does not work, because if you remove an element from an array in for loop indexes most probably will be wrong when removing another element.
I don't know how much you care about performance, but using regex is not very efficient.
Simple test for quite a long string shows that using filter function is on average about 3 times faster, which can make quite a difference when performed on very long strings or on many, many shorts ones.
function test(func, n){
var text = "";
for(var i = 0; i < n; ++i){
text += "a";
}
var start = new Date().getTime();
func(text);
var end = new Date().getTime();
var time = (end-start) / 1000.0;
console.log(func.name, " took ", time, " seconds")
return time;
}
function encryptREGEX(text) {
let removedText = '';
const replacedText1 = text.replace(/(.)(.)?/g, (_, firstChar, secondChar) => {
// in case the match was at the end of the string,
// and the string has an odd number of characters:
if (!secondChar) secondChar = '';
// remove the firstChar from the string, while adding it to removedText:
removedText += firstChar;
return secondChar;
});
return replacedText1 + removedText;
}
function encrypt(text) {
text = text.split("");
var removed = "";
var encrypted = text.filter((letter, index) => {
if(index % 2 == 0){
removed += letter;
return false;
}
return true
}).join("")
return encrypted + removed
}
var timeREGEX = test(encryptREGEX, 10000000);
var timeFilter = test(encrypt, 10000000);
console.log("Using filter is faster ", timeREGEX/timeFilter, " times")
Using actually an array for storing removed letters and then joining them is much more efficient, than using a string and concatenating letters to it.
I changed an array to string in filter solution to make it the same like in regex solution, so they are more comparable.

Javascript array remove odd commas

I need to create a string like this to make works the mapserver request:
filterobj = "POLYGON((507343.9 182730.8, 507560.2 182725.19999999998, 507568.60000000003 182541.1, 507307.5 182563.5, 507343.9 182730.8))";
Where the numbers are map coordinates x y of a polygon, the problem is with Javascript and OpenLayer what I have back is an array of numbers, How can I remove just the ODD commas (first, third, fifth...)?
At the moment I've created the string in this way:
filterobj = "POLYGON((" +
Dsource.getFeatures()[0].getGeometry().getCoordinates() + " ))";
And the result is:
POLYGON((507343.9, 182730.8,507560.2, 182725.19999999998, 507568.60000000003, 182541.1, 507307.5, 182563.5,507343.9, 182730.8));
It's almost what I need but, I need to remove the ODD commas from the Dsource.getFeatures()[0].getGeometry().getCoordinates() array to make the request work, how can I do that?
The format that you need is WKT, and OpenLayers comes with a class that allows you to parse its geometries as WKT easily, as below:
var wktFormatter = new ol.format.WKT();
var formatted = wktFormatter.writeFeature(Dsource.getFeatures()[0]);
console.log(formatted); // POLYGON((1189894.0370893013 -2887048.988883849,3851097.783993299...
Look at code snippet :
Help method : setCharAt ,
Take all commas ,
take all odds commas with i % 2 == 0
// I need to start from somewhere
function setCharAt(str,index,chr) {
if(index > str.length-1) return str;
return str.substr(0,index) + chr + str.substr(index+1);
}
var POLYGON = [507343.9, 182730.8,507560.2, 182725.19999999998, 507568.60000000003, 182541.1, 507307.5, 182563.5,507343.9, 182730.8];
var REZ = "";
REZ = POLYGON.toString();
var all_comma = [];
for(var i=0; i<REZ.length;i++) {
if (REZ[i] === ",") all_comma.push(i);
}
for(var i=0; i<all_comma.length;i++) {
if (i % 2 == 0 ) {
REZ = setCharAt(REZ,all_comma[i],' ');
}
}
console.log(REZ);
// let return nee element intro POLYGON
// reset
POLYGON = REZ.split(',');
console.log(POLYGON);
What about this:
const str = Dsource.getFeatures()[0].getGeometry().getCoordinates()
// str = "1,2,3,4,5,6"
str.split(',').map((v, i) => {
return (i % 2) ? v : v + ','
}).join(' ')
// "1, 2 3, 4 5, 6"
There are a couple of ways to go, both involve getting rid of whitespace first. The first matches coordinate pairs, removes the comma, then pastes them back together.
The second splits into individual numbers, then formats them with reduce. Both should be ECMA-262 ed5 (2011) compatible but I don't have an old enough browser to test them.
var s = '507343.9, 182730.8,507560.2, 182725.19999999998, 507568.60000000003, 182541.1, 507307.5, 182563.5,507343.9, 182730.8';
var re = /\d+\.?\d*,\d+\.?\d*/g;
// Solution 1
var x = s.replace(/\s/g,'').match(re).map(function(x){return x.replace(',',' ')}).join();
console.log(x);
// Solution 2
var t = s.replace(/\s/g,'').split(',').reduce(function (acc, v, i) {
i%2? (acc[acc.length - 1] += ' ' + v) : acc.push(v);
return acc;
}, []).join(',');
console.log(t);
One approach would be using Array.reduce():
var input = '1.0, 2.0, 3.0, 4.0, 5.0, 6.0';
var output = input
.split(',')
.reduce((arr, num, idx) => {
arr.push(idx % 2 ? arr.pop() + ' ' + num : num);
return arr;
}, [])
.join(',');
// output = '1.0 2.0, 3.0 4.0, 5.0 6.0'

How do get input 2^3 to Math.pow(2, 3)?

I have this simple calculator script, but it doesn't allow power ^.
function getValues() {
var input = document.getElementById('value').value;
document.getElementById('result').innerHTML = eval(input);
}
<label for="value">Enter: </label><input id="value">
<div id="result">Results</div>
<button onclick="getValues()">Get Results</button>
I tried using input = input.replace( '^', 'Math.pow(,)');
But I do not know how to get the values before '^' and after into the brackets.
Example: (1+2)^3^3 should give 7,625,597,484,987
Use a regular expression with capture groups:
input = '3 + 2 ^3';
input = input.replace(/(\d+)\s*\^\s*(\d+)/g, 'Math.pow($1, $2)');
console.log(input);
This will only work when the arguments are just numbers. It won't work with sub-expressions or when you repeat it, like
(1+2)^3^3
This will require writing a recursive-descent parser, and that's far more work than I'm willing to put into an answer here. Get a textbook on compiler design to learn how to do this.
I don't think you'll be able to do this with simple replace.
If you want to parse infix operators, you build two stacks, one for symbols, other for numbers. Then sequentially walk the formula ignoring everything else than symbols, numbers and closing parenthesis. Put symbols and numbers into their stacks, but when you encounter closing paren, take last symbol and apply it to two last numbers. (was invented by Dijkstra, I think)
const formula = '(1+2)^3^3'
const symbols = []
const numbers = []
function apply(n2, n1, s) {
if (s === '^') {
return Math.pow(parseInt(n1, 10), parseInt(n2, 10))
}
return eval(`${n1} ${s} ${n2}`)
}
const applyLast = () => apply(numbers.pop(), numbers.pop(), symbols.pop())
const tokenize = formula => formula.split(/(\d+)|([\^\/\)\(+\-\*])/).filter(t => t !== undefined && t !== '')
const solver = (formula) => {
const tf = tokenize(formula)
for (let l of formula) {
const parsedL = parseInt(l, 10)
if (isNaN(parsedL)) {
if (l === ')') {
numbers.push(applyLast())
continue
} else {
if (~['+', '-', '*', '/', '^'].indexOf(l))
symbols.push(l)
continue
}
}
numbers.push(l)
}
while (symbols.length > 0)
numbers.push(applyLast())
return numbers.pop()
}
console.log(solver(formula))
Get your input into a string and do...
var input = document.getElementById('value').value;
var values = input.split('^'); //will save an array with [value1, value 2]
var result = Math.pow(values[0], values[1]);
console.log(result);
This only if your only operation is a '^'
EDIT: Saw example after edit, this no longer works.
function getValues() {
var input = document.getElementById('value').value;
// code to make ^ work like Math.pow
input = input.replace( '^', '**');
document.getElementById('result').innerHTML = eval(input);
}
The ** operator can replace the Math.pow function in most modern browsers. The next version of Safari (v10.1) coming out any day supports it.
As said in other answers here, you need a real parser to solve this correctly. A regex will solve simple cases, but for nested statements you need a recursive parser. For Javascript one library that offers this is peg.js.
In your case, the example given in the online version can be quickly extended to handle powers:
Expression
= head:Term tail:(_ ("+" / "-") _ Term)* {
var result = head, i;
for (i = 0; i < tail.length; i++) {
if (tail[i][1] === "+") { result += tail[i][3]; }
if (tail[i][1] === "-") { result -= tail[i][3]; }
}
return result;
}
Term
= head:Pow tail:(_ ("*" / "/") _ Pow)* { // Here I replaced Factor with Pow
var result = head, i;
for (i = 0; i < tail.length; i++) {
if (tail[i][1] === "*") { result *= tail[i][3]; }
if (tail[i][1] === "/") { result /= tail[i][3]; }
}
return result;
}
// This is the new part I added
Pow
= head:Factor tail:(_ "^" _ Factor)* {
var result = 1;
for (var i = tail.length - 1; 0 <= i; i--) {
result = Math.pow(tail[i][3], result);
}
return Math.pow(head, result);
}
Factor
= "(" _ expr:Expression _ ")" { return expr; }
/ Integer
Integer "integer"
= [0-9]+ { return parseInt(text(), 10); }
_ "whitespace"
= [ \t\n\r]*
It returns the expected output 7625597484987 for the input string (1+2)^3^3.
Here is a Python-based version of this question, with solution using pyparsing: changing ** operator to power function using parsing?

VBA JavaScript object doesn't support this property or method

Im trying to get the Text Statistics function from https://github.com/cgiffard/TextStatistics.js/blob/master/index.js
Working in Excel
I have minified the JavaScript code to shorten the concatenations
Function Text_Statistics1(textString As String)
Dim code As String
code = "function text_stats(teststringtoprocess){(function(e){function t(e){var t=['li','p','h1','h2','h3','h4','h5','h6','dd'];t.forEach(function(t){e=e.replace('</'+t+'>','.')});e=e.replace(/<[^>]+>/g,'').replace(/[,:;()\-]/,' ').replace(/[\.!?]/,'.').replace(/^\s+/,'').replace(/[ ]*(\n|\r\n|\r)[ ]*/,' ').replace(/([\.])[\. ]+/,'.').replace(/[ ]*([\.])/,'. ').replace(/\s+/,' ').replace(/\s+$/,'');e+='.';return e}function r(e){return new n(e)}var n=function(n){this.text=n?t(n):this.text};n.prototype.fleschKincaidReadingEase=function(e){e=e?t(e):this.text;return Math.round((206.835-1.015*this.averageWordsPerSentence(e)-84.6*this.averageSyllablesPerWord(e))*10)/10};n.prototype.fleschKincaidGradeLevel=function(e){e=e?t(e):this.text;return Math.round((.39*this.averageWordsPerSentence(e)+11.8*this.averageSyllablesPerWord(e)-15.59)*10)/10};n.prototype.gunningFogScore=function(e){e=e?t(e):this.text;"
code = code + "return Math.round((this.averageWordsPerSentence(e)+this.percentageWordsWithThreeSyllables(e,false))*.4*10)/10};n.prototype.colemanLiauIndex=function(e){e=e?t(e):this.text;return Math.round((5.89*(this.letterCount(e)/this.wordCount(e))-.3*(this.sentenceCount(e)/this.wordCount(e))-15.8)*10)/10};n.prototype.smogIndex=function(e){e=e?t(e):this.text;return Math.round(1.043*Math.sqrt(this.wordsWithThreeSyllables(e)*(30/this.sentenceCount(e))+3.1291)*10)/10};n.prototype.automatedReadabilityIndex=function(e){e=e?t(e):this.text;"
code = code + "return Math.round((4.71*(this.letterCount(e)/this.wordCount(e))+.5*(this.wordCount(e)/this.sentenceCount(e))-21.43)*10)/10};n.prototype.textLength=function(e){e=e?t(e):this.text;return e.length};n.prototype.letterCount=function(e){e=e?t(e):this.text;e=e.replace(/[^a-z]+/ig,'');return e.length};n.prototype.sentenceCount=function(e){e=e?t(e):this.text;return e.replace(/[^\.!?]/g,'').length||1};n.prototype.wordCount=function(e){e=e?t(e):this.text;return e.split(/[^a-z0-9]+/i).length||1};n.prototype.averageWordsPerSentence=function(e){e=e?t(e):this.text;"
code = code + "return this.wordCount(e)/this.sentenceCount(e)};n.prototype.averageSyllablesPerWord=function(e){e=e?t(e):this.text;var n=0,r=this.wordCount(e),i=this;e.split(/\s+/).forEach(function(e){n+=i.syllableCount(e)});return(n||1)/(r||1)};n.prototype.wordsWithThreeSyllables=function(e,n){e=e?t(e):this.text;var r=0,i=this;n=n===false?false:true;e.split(/\s+/).forEach(function(e){if(!e.match(/^[A-Z]/)||n){if(i.syllableCount(e)>2)r++}});return r};n.prototype.percentageWordsWithThreeSyllables=function(e,n){e=e?t(e):this.text;return this.wordsWithThreeSyllables(e,n)/this.wordCount(e)*100};n.prototype.syllableCount=function(e){var t=0,n=0,r=0;e=e.toLowerCase().replace(/[^a-z]/g,'');var i={simile:3,forever:3,shoreline:2};if(i.hasOwnProperty(e))return i[e];var s=[/cial/,/tia/,/cius/,/cious/,/giu/,/ion/,/iou/,/sia$/,/[^aeiuoyt]{2,}ed$/,/.ely$/,/[cg]h?e[rsd]?$/,/rved?$/,/[aeiouy][dt]es?$/,/[aeiouy][^aeiouydt]e[rsd]?$/,/^[dr]e[aeiou][^aeiou]+$/,/[aeiouy]rse$/];"
code = code + "var o=[/ia/,/riet/,/dien/,/iu/,/io/,/ii/,/[aeiouym]bl$/,/[aeiou]{3}/,/^mc/,/ism$/,/([^aeiouy])\1l$/,/[^l]lien/,/^coa[dglx]./,/[^gq]ua[^auieo]/,/dnt$/,/uity$/,/ie(r|st)$/];var u=[/^un/,/^fore/,/ly$/,/less$/,/ful$/,/ers?$/,/ings?$/];u.forEach(function(t){if(e.match(t)){e=e.replace(t,'');n++}});r=e.split(/[^aeiouy]+/ig).filter(function(e){return!!e.replace(/\s+/ig,'').length}).length;t=r+n;s.forEach(function(n){if(e.match(n))t--});o.forEach(function(n){if(e.match(n))t++});return t||1};typeof module!='undefined'&&module.exports?module.exports=r:typeof define!='undefined'?define('textstatistics',[],function(){return r}):e.textstatistics=r})(this);"
'code = code + " return textstatistics(s).fleschKincaidReadingEase();" & _
'"return stat.fleschKincaidReadingEase();" & _
code = code + "return textstatistics(teststringtoprocess).fleschKincaidReadingEase();}"
'code = code + "return textstatistics(teststringtoprocess);}"
Dim o As New ScriptControl
o.Language = "JScript"
With o
.AddCode code
Text_Statistics1 = .Run("text_stats", textString)
End With
End Function
I'm getting object doesn't support this property or method - I think its due to the instantiation of Text Statistics.
Do I need to convert the javascript to just be a set of functions?
UPDATE:
Slightly different approach using eval
Function Text_Stat(textString As String, textstat As String)
Dim code As String
code = "(function(e){function t(e){var t=['li','p','h1','h2','h3','h4','h5','h6','dd'];t.forEach(function(t){e=e.replace('</'+t+'>','.')});e=e.replace(/<[^>]+>/g,'').replace(/[,:;()\-]/,' ').replace(/[\.!?]/,'.').replace(/^\s+/,'').replace(/[ ]*(\n|\r\n|\r)[ ]*/,' ').replace(/([\.])[\. ]+/,'.').replace(/[ ]*([\.])/,'. ').replace(/\s+/,' ').replace(/\s+$/,'');e+='.';return e}function r(e){return new n(e)}var n=function(n){this.text=n?t(n):this.text};n.prototype.fleschKincaidReadingEase=function(e){e=e?t(e):this.text;return Math.round((206.835-1.015*this.averageWordsPerSentence(e)-84.6*this.averageSyllablesPerWord(e))*10)/10};n.prototype.fleschKincaidGradeLevel=function(e){e=e?t(e):this.text;" & _
"return Math.round((.39*this.averageWordsPerSentence(e)+11.8*this.averageSyllablesPerWord(e)-15.59)*10)/10};n.prototype.gunningFogScore=function(e){e=e?t(e):this.text;return Math.round((this.averageWordsPerSentence(e)+this.percentageWordsWithThreeSyllables(e,false))*.4*10)/10};n.prototype.colemanLiauIndex=function(e){e=e?t(e):this.text;return Math.round((5.89*(this.letterCount(e)/this.wordCount(e))-.3*(this.sentenceCount(e)/this.wordCount(e))-15.8)*10)/10};n.prototype.smogIndex=function(e){e=e?t(e):this.text;return Math.round(1.043*Math.sqrt(this.wordsWithThreeSyllables(e)*(30/this.sentenceCount(e))+3.1291)*10)/10};n.prototype.automatedReadabilityIndex=function(e){e=e?t(e):this.text;" & _
"return Math.round((4.71*(this.letterCount(e)/this.wordCount(e))+.5*(this.wordCount(e)/this.sentenceCount(e))-21.43)*10)/10};n.prototype.textLength=function(e){e=e?t(e):this.text;return e.length};n.prototype.letterCount=function(e){e=e?t(e):this.text;e=e.replace(/[^a-z]+/ig,'');return e.length};n.prototype.sentenceCount=function(e){e=e?t(e):this.text;return e.replace(/[^\.!?]/g,'').length||1};n.prototype.wordCount=function(e){e=e?t(e):this.text;return e.split(/[^a-z0-9]+/i).length||1};n.prototype.averageWordsPerSentence=function(e){e=e?t(e):this.text;return this.wordCount(e)/this.sentenceCount(e)};n.prototype.averageSyllablesPerWord=function(e){e=e?t(e):this.text;var n=0,r=this.wordCount(e),i=this;e.split(/\s+/).forEach(function(e){n+=i.syllableCount(e)});return(n||1)/(r||1)};n.prototype.wordsWithThreeSyllables=function(e,n){e=e?t(e):this.text;" & _
"var r=0,i=this;n=n===false?false:true;e.split(/\s+/).forEach(function(e){if(!e.match(/^[A-Z]/)||n){if(i.syllableCount(e)>2)r++}});return r};n.prototype.percentageWordsWithThreeSyllables=function(e,n){e=e?t(e):this.text;" & _
"return this.wordsWithThreeSyllables(e,n)/this.wordCount(e)*100};n.prototype.syllableCount=function(e){var t=0,n=0,r=0;e=e.toLowerCase().replace(/[^a-z]/g,'');var i={simile:3,forever:3,shoreline:2};if(i.hasOwnProperty(e))return i[e];var s=[/cial/,/tia/,/cius/,/cious/,/giu/,/ion/,/iou/,/sia$/,/[^aeiuoyt]{2,}ed$/,/.ely$/,/[cg]h?e[rsd]?$/,/rved?$/,/[aeiouy][dt]es?$/,/[aeiouy][^aeiouydt]e[rsd]?$/,/^[dr]e[aeiou][^aeiou]+$/,/[aeiouy]rse$/];var o=[/ia/,/riet/,/dien/,/iu/,/io/,/ii/,/[aeiouym]bl$/,/[aeiou]{3}/,/^mc/,/ism$/,/([^aeiouy])\1l$/,/[^l]lien/,/^coa[dglx]./,/[^gq]ua[^auieo]/,/dnt$/,/uity$/,/ie(r|st)$/];" & _
"var u=[/^un/,/^fore/,/ly$/,/less$/,/ful$/,/ers?$/,/ings?$/];u.forEach(function(t){if(e.match(t)){e=e.replace(t,'');n++}});r=e.split(/[^aeiouy]+/ig).filter(function(e){return!!e.replace(/\s+/ig,'').length}).length;t=r+n;s.forEach(function(n){if(e.match(n))t--});o.forEach(function(n){if(e.match(n))t++});return t||1};typeof module!='undefined'&&module.exports?module.exports=r:typeof define!='undefined'?define('textstatistics',[],function(){return r}):e.textstatistics=r})(this);" & _
"var stat = new textstatistics('Your text here');alert(stat.sentenceCount('This. dfgdfg. is. a. long. sentence.'));"
Dim o As New ScriptControl
o.Language = "JScript"
With o
.AllowUI = True
.AddCode code
.Eval "stat.sentenceCount('This. dfgdfg. is. a. long. sentence.')"
'result = .Eval(code)
'Debug.Print .Eval("'Hello World'.substring(1, 4);")
'result = .Eval(result)
'Text_Stat = .Run(result)
End With
End Function
JSFiddle shows it working here http://jsfiddle.net/hwr26dkf/
UPDATE: 01/10/2014
Final Working VBA version thanks to Michael Petch
Function Text_Statistics(statType As Integer, textString As String)
Dim wc, sc As Integer
Dim s1, s2, code As String
Dim oTextStats As Object
Dim o As New ScriptControl
code = "function cleanText(e){var t=['li','p','h1','h2','h3','h4','h5','h6','dd'];t.forEach(function(t){e=e.replace('</'+t+'>','.')});e=e.replace(/<[^>]+>/g,'').replace(/[,:;()\-]/,' ').replace(/[\.!?]/,'.').replace(/^\s+/,'').replace(/[ ]*(\n|\r\n|\r)[ ]*/,' ').replace(/([\.])[\. ]+/,'.').replace(/[ ]*([\.])/,'. ').replace(/\s+/,' ').replace(/\s+$/,'');e+='.';return e}function textStatistics(e){return new TextStatistics(e)}if(!Array.prototype.forEach){Array.prototype.forEach=function(e){var t=this.length;" & _
"if(typeof e!='function')throw new TypeError;var n=arguments[1];for(var r=0;r<t;r++){if(r in this)e.call(n,this[r],r,this)}}}if(!Array.prototype.filter){Array.prototype.filter=function(e){'use strict';if(this===void 0||this===null){throw new TypeError}var t=Object(this);var n=t.length>>>0;if(typeof e!=='function'){throw new TypeError}var r=[];var i=arguments.length>=2?arguments[1]:void 0;for(var s=0;s<n;s++){if(s in t){var o=t[s];if(e.call(i,o,s,t)){r.push(o)}}}return r}}var TextStatistics=function(t){this.text=t?cleanText(t):this.text};TextStatistics.prototype.fleschKincaidReadingEase=function(e){e=e?cleanText(e):this.text;return Math.round((206.835-1.015*this.averageWordsPerSentence(e)-84.6*this.averageSyllablesPerWord(e))*10)/10};TextStatistics.prototype.fleschKincaidGradeLevel=function(e){e=e?cleanText(e):this.text;" & _
"return Math.round((.39*this.averageWordsPerSentence(e)+11.8*this.averageSyllablesPerWord(e)-15.59)*10)/10};TextStatistics.prototype.gunningFogScore=function(e){e=e?cleanText(e):this.text;return Math.round((this.averageWordsPerSentence(e)+this.percentageWordsWithThreeSyllables(e,false))*.4*10)/10};TextStatistics.prototype.colemanLiauIndex=function(e){e=e?cleanText(e):this.text;return Math.round((5.89*(this.letterCount(e)/this.wordCount(e))-.3*(this.sentenceCount(e)/this.wordCount(e))-15.8)*10)/10};" & _
"TextStatistics.prototype.smogIndex=function(e){e=e?cleanText(e):this.text;return Math.round(1.043*Math.sqrt(this.wordsWithThreeSyllables(e)*(30/this.sentenceCount(e))+3.1291)*10)/10};TextStatistics.prototype.automatedReadabilityIndex=function(e){e=e?cleanText(e):this.text;return Math.round((4.71*(this.letterCount(e)/this.wordCount(e))+.5*(this.wordCount(e)/this.sentenceCount(e))-21.43)*10)/10};TextStatistics.prototype.textLength=function(e){e=e?cleanText(e):this.text;return e.length};TextStatistics.prototype.letterCount=function(e){e=e?cleanText(e):this.text;e=e.replace(/[^a-z]+/ig,'');return e.length};TextStatistics.prototype.sentenceCount=function(e){e=e?cleanText(e):this.text;" & _
"return e.replace(/[^\.!?]/g,'').length||1};TextStatistics.prototype.wordCount=function(e){e=e?cleanText(e):this.text;return e.split(/[^a-z0-9]+/i).length||1};TextStatistics.prototype.averageWordsPerSentence=function(e){e=e?cleanText(e):this.text;return this.wordCount(e)/this.sentenceCount(e)};TextStatistics.prototype.averageSyllablesPerWord=function(e){e=e?cleanText(e):this.text;" & _
"var t=0,n=this.wordCount(e),r=this;e.split(/\s+/).forEach(function(e){t+=r.syllableCount(e)});return(t||1)/(n||1)};TextStatistics.prototype.wordsWithThreeSyllables=function(e,t){e=e?cleanText(e):this.text;var n=0,r=this;t=t===false?false:true;e.split(/\s+/).forEach(function(e){if(!e.match(/^[A-Z]/)||t){if(r.syllableCount(e)>2)n++}});return n};TextStatistics.prototype.percentageWordsWithThreeSyllables=function(e,t){e=e?cleanText(e):this.text;return this.wordsWithThreeSyllables(e,t)/this.wordCount(e)*100};" & _
"TextStatistics.prototype.syllableCount=function(e){var t=0,n=0,r=0;e=e.toLowerCase().replace(/[^a-z]/g,'');var i={simile:3,forever:3,shoreline:2};if(i.hasOwnProperty(e))return i[e];var s=[/cial/,/tia/,/cius/,/cious/,/giu/,/ion/,/iou/,/sia$/,/[^aeiuoyt]{2,}ed$/,/.ely$/,/[cg]h?e[rsd]?$/,/rved?$/,/[aeiouy][dt]es?$/,/[aeiouy][^aeiouydt]e[rsd]?$/,/^[dr]e[aeiou][^aeiou]+$/,/[aeiouy]rse$/];var o=[/ia/,/riet/,/dien/,/iu/,/io/,/ii/,/[aeiouym]bl$/,/[aeiou]{3}/,/^mc/,/ism$/,/([^aeiouy])\1l$/,/[^l]lien/,/^coa[dglx]./,/[^gq]ua[^auieo]/,/dnt$/,/uity$/,/ie(r|st)$/];" & _
"var u=[/^un/,/^fore/,/ly$/,/less$/,/ful$/,/ers?$/,/ings?$/];u.forEach(function(t){if(e.match(t)){e=e.replace(t,'');n++}});r=e.split(/[^aeiouy]+/ig).filter(function(e){return!!e.replace(/\s+/ig,'').length}).length;t=r+n;s.forEach(function(n){if(e.match(n))t--});o.forEach(function(n){if(e.match(n))t++});return t||1}"
With o
.Language = "JScript"
.AddCode code
' Create a TextStatistics object initially with no text.
' textStatistics is a function that creates TextStatistics objects
Set oTextStats = .Eval("textStatistics()")
' Now simply call TextStatistics methods directly
wc = oTextStats.averageWordsPerSentence(textString)
sc = oTextStats.syllableCount(textString)
' Alternatively you can create a TextStatistics object with the text
' and call the methods with a blank string to return the values
' for the string passed in the constructor
'Set oTextStats = .Eval("textStatistics('" + textString + "')")
'wc = oTextStats.wordCount("")
'sc = oTextStats.sentenceCount("")
Select Case statType
Case 1
Text_Statistics = oTextStats.wordCount(textString)
Case 2
Text_Statistics = oTextStats.sentenceCount(textString)
Case 3
Text_Statistics = oTextStats.fleschKincaidReadingEase(textString)
Case 4
Text_Statistics = oTextStats.fleschKincaidGradeLevel(textString)
Case 5
Text_Statistics = oTextStats.gunningFogScore(textString)
Case 6
Text_Statistics = oTextStats.colemanLiauIndex(textString)
Case 7
Text_Statistics = oTextStats.smogIndex(textString)
Case 8
Text_Statistics = oTextStats.automatedReadabilityIndex(textString)
Case 9
Text_Statistics = oTextStats.textLength(textString)
Case 10
Text_Statistics = oTextStats.letterCount(textString)
Case 11
Text_Statistics = oTextStats.averageWordsPerSentence(textString)
Case 12
Text_Statistics = oTextStats.averageSyllablesPerWord(textString)
End Select
End With
End Function
I spent some time this afternoon learning Javascript and then trying to figure out what is going on with your TextStatistics class when run in Microsoft's ScriptControl object. Rather than start with the mangled code in VBA I went back to the code in github that the OP referenced. The first thing I discovered is that ScriptControl will parse and execute the anonymous global function however once that code is added by ScriptControl it seems to lose track of the TextStatistics object. So the first thing I did was simply remove the anonymous global function by removing this at the top:
(function(glob) {
and removing these line at the bottom:
(typeof module != "undefined" && module.exports) ? (module.exports = textStatistics) : (typeof define != "undefined" ? (define("textstatistics", [], function() { return textStatistics; })) : (glob.textstatistics = textStatistics));
})(this);
Once I removed that as a source of problems I discovered that I could create new instances of TextStatistics but I could not assign text to them properly. Neither as a parameter using new or through calling a method like sentenceCount(). This had me perplexed. Since creating an instance of TextStatistics couldn't be done properly I decided to review the constructor. It is simple but it called cleanText. One thing that stood out at me was the forEach. On a hunch I did some digging about Javascript / ScriptControl and then forEach. I learned that ScriptControl uses ECMAScript and not Javascript. Once I had that straight I found a link with this information which includes this comment: about the forEach method:
This method is a JavaScript extension to the ECMA-262 standard; as such it may not be present in other implementations of the standard. To make it work you need to add following code at the top of your script:
And this code:
if (!Array.prototype.forEach) {
Array.prototype.forEach = function (fun /*, thisp*/ ) {
var len = this.length;
if (typeof fun != 'function') throw new TypeError();
var thisp = arguments[1];
for (var i = 0; i < len; i++) {
if (i in this) fun.call(thisp, this[i], i, this);
}
};
}
After providing my original answer, the OP discovered that functions involving syllables didn't work. There is another function that showed up in a later ECMA specification that ScriptControl didn't support. That was the polyfill filter function on arrays. According to this Mozilla documentation:
filter was added to the ECMA-262 standard in the 5th edition; as such it may not be present in all implementations of the standard. You can work around this by inserting the following code at the beginning of your scripts, allowing use of filter in ECMA-262 implementations which do not natively support it.
The code provided that meets the specification:
if (!Array.prototype.filter) {
Array.prototype.filter = function(fun/*, thisArg*/) {
'use strict';
if (this === void 0 || this === null) {
throw new TypeError();
}
var t = Object(this);
var len = t.length >>> 0;
if (typeof fun !== 'function') {
throw new TypeError();
}
var res = [];
var thisArg = arguments.length >= 2 ? arguments[1] : void 0;
for (var i = 0; i < len; i++) {
if (i in t) {
var val = t[i];
// NOTE: Technically this should Object.defineProperty at
// the next index, as push can be affected by
// properties on Object.prototype and Array.prototype.
// But that method's new, and collisions should be
// rare, so use the more-compatible alternative.
if (fun.call(thisArg, val, i, t)) {
res.push(val);
}
}
}
return res;
};
}
Was it so simple? Was this the cause of those problems? Yes it was. I added that code to the top of the script and VBA and ScriptControl were content. So before minifying and converting all " to ' the Javascript code in its entirety looks like this:
if (!Array.prototype.forEach) {
Array.prototype.forEach = function (fun /*, thisp*/ ) {
var len = this.length;
if (typeof fun != 'function') throw new TypeError();
var thisp = arguments[1];
for (var i = 0; i < len; i++) {
if (i in this) fun.call(thisp, this[i], i, this);
}
};
}
if (!Array.prototype.filter) {
Array.prototype.filter = function(fun/*, thisArg*/) {
'use strict';
if (this === void 0 || this === null) {
throw new TypeError();
}
var t = Object(this);
var len = t.length >>> 0;
if (typeof fun !== 'function') {
throw new TypeError();
}
var res = [];
var thisArg = arguments.length >= 2 ? arguments[1] : void 0;
for (var i = 0; i < len; i++) {
if (i in t) {
var val = t[i];
// NOTE: Technically this should Object.defineProperty at
// the next index, as push can be affected by
// properties on Object.prototype and Array.prototype.
// But that method's new, and collisions should be
// rare, so use the more-compatible alternative.
if (fun.call(thisArg, val, i, t)) {
res.push(val);
}
}
}
return res;
};
}
function cleanText(text) {
// all these tags should be preceeded by a full stop.
var fullStopTags = ['li', 'p', 'h1', 'h2', 'h3', 'h4', 'h5', 'h6', 'dd'];
fullStopTags.forEach(function (tag) {
text = text.replace('</' + tag + '>', '.');
});
text = text.replace(/<[^>]+>/g, '') // Strip tags
.replace(/[,:;()\-]/, ' ') // Replace commans, hyphens etc (count them as spaces)
.replace(/[\.!?]/, '.') // Unify terminators
.replace(/^\s+/, '') // Strip leading whitespace
.replace(/[ ]*(\n|\r\n|\r)[ ]*/, ' ') // Replace new lines with spaces
.replace(/([\.])[\. ]+/, '.') // Check for duplicated terminators
.replace(/[ ]*([\.])/, '. ') // Pad sentence terminators
.replace(/\s+/, ' ') // Remove multiple spaces
.replace(/\s+$/, ''); // Strip trailing whitespace
text += '.'; // Add final terminator, just in case it's missing.
return text;
}
var TextStatistics = function TextStatistics(text) {
this.text = text ? cleanText(text) : this.text;
};
TextStatistics.prototype.fleschKincaidReadingEase = function (text) {
text = text ? cleanText(text) : this.text;
return Math.round((206.835 - (1.015 * this.averageWordsPerSentence(text)) - (84.6 * this.averageSyllablesPerWord(text))) * 10) / 10;
};
TextStatistics.prototype.fleschKincaidGradeLevel = function (text) {
text = text ? cleanText(text) : this.text;
return Math.round(((0.39 * this.averageWordsPerSentence(text)) + (11.8 * this.averageSyllablesPerWord(text)) - 15.59) * 10) / 10;
};
TextStatistics.prototype.gunningFogScore = function (text) {
text = text ? cleanText(text) : this.text;
return Math.round(((this.averageWordsPerSentence(text) + this.percentageWordsWithThreeSyllables(text, false)) * 0.4) * 10) / 10;
};
TextStatistics.prototype.colemanLiauIndex = function (text) {
text = text ? cleanText(text) : this.text;
return Math.round(((5.89 * (this.letterCount(text) / this.wordCount(text))) - (0.3 * (this.sentenceCount(text) / this.wordCount(text))) - 15.8) * 10) / 10;
};
TextStatistics.prototype.smogIndex = function (text) {
text = text ? cleanText(text) : this.text;
return Math.round(1.043 * Math.sqrt((this.wordsWithThreeSyllables(text) * (30 / this.sentenceCount(text))) + 3.1291) * 10) / 10;
};
TextStatistics.prototype.automatedReadabilityIndex = function (text) {
text = text ? cleanText(text) : this.text;
return Math.round(((4.71 * (this.letterCount(text) / this.wordCount(text))) + (0.5 * (this.wordCount(text) / this.sentenceCount(text))) - 21.43) * 10) / 10;
};
TextStatistics.prototype.textLength = function (text) {
text = text ? cleanText(text) : this.text;
return text.length;
};
TextStatistics.prototype.letterCount = function (text) {
text = text ? cleanText(text) : this.text;
text = text.replace(/[^a-z]+/ig, '');
return text.length;
};
TextStatistics.prototype.sentenceCount = function (text) {
text = text ? cleanText(text) : this.text;
// Will be tripped up by 'Mr.' or 'U.K.'. Not a major concern at this point.
return text.replace(/[^\.!?]/g, '').length || 1;
};
TextStatistics.prototype.wordCount = function (text) {
text = text ? cleanText(text) : this.text;
return text.split(/[^a-z0-9]+/i).length || 1;
};
TextStatistics.prototype.averageWordsPerSentence = function (text) {
text = text ? cleanText(text) : this.text;
return this.wordCount(text) / this.sentenceCount(text);
};
TextStatistics.prototype.averageSyllablesPerWord = function (text) {
text = text ? cleanText(text) : this.text;
var syllableCount = 0,
wordCount = this.wordCount(text),
self = this;
text.split(/\s+/).forEach(function (word) {
syllableCount += self.syllableCount(word);
});
// Prevent NaN...
return (syllableCount || 1) / (wordCount || 1);
};
TextStatistics.prototype.wordsWithThreeSyllables = function (text, countProperNouns) {
text = text ? cleanText(text) : this.text;
var longWordCount = 0,
self = this;
countProperNouns = countProperNouns === false ? false : true;
text.split(/\s+/).forEach(function (word) {
// We don't count proper nouns or capitalised words if the countProperNouns attribute is set.
// Defaults to true.
if (!word.match(/^[A-Z]/) || countProperNouns) {
if (self.syllableCount(word) > 2) longWordCount++;
}
});
return longWordCount;
};
TextStatistics.prototype.percentageWordsWithThreeSyllables = function (text, countProperNouns) {
text = text ? cleanText(text) : this.text;
return (this.wordsWithThreeSyllables(text, countProperNouns) / this.wordCount(text)) * 100;
};
TextStatistics.prototype.syllableCount = function (word) {
var syllableCount = 0,
prefixSuffixCount = 0,
wordPartCount = 0;
// Prepare word - make lower case and remove non-word characters
word = word.toLowerCase().replace(/[^a-z]/g, '');
// Specific common exceptions that don't follow the rule set below are handled individually
// Array of problem words (with word as key, syllable count as value)
var problemWords = {
'simile': 3,
'forever': 3,
'shoreline': 2
};
// Return if we've hit one of those...
if (problemWords.hasOwnProperty(word)) return problemWords[word];
// These syllables would be counted as two but should be one
var subSyllables = [
/cial/,
/tia/,
/cius/,
/cious/,
/giu/,
/ion/,
/iou/,
/sia$/,
/[^aeiuoyt]{2,}ed$/,
/.ely$/,
/[cg]h?e[rsd]?$/,
/rved?$/,
/[aeiouy][dt]es?$/,
/[aeiouy][^aeiouydt]e[rsd]?$/,
/^[dr]e[aeiou][^aeiou]+$/, // Sorts out deal, deign etc
/[aeiouy]rse$/ // Purse, hearse
];
// These syllables would be counted as one but should be two
var addSyllables = [
/ia/,
/riet/,
/dien/,
/iu/,
/io/,
/ii/,
/[aeiouym]bl$/,
/[aeiou]{3}/,
/^mc/,
/ism$/,
/([^aeiouy])\1l$/,
/[^l]lien/,
/^coa[dglx]./,
/[^gq]ua[^auieo]/,
/dnt$/,
/uity$/,
/ie(r|st)$/];
// Single syllable prefixes and suffixes
var prefixSuffix = [
/^un/,
/^fore/,
/ly$/,
/less$/,
/ful$/,
/ers?$/,
/ings?$/];
// Remove prefixes and suffixes and count how many were taken
prefixSuffix.forEach(function (regex) {
if (word.match(regex)) {
word = word.replace(regex, '');
prefixSuffixCount++;
}
});
wordPartCount = word.split(/[^aeiouy]+/ig)
.filter(function (wordPart) {
return !!wordPart.replace(/\s+/ig, '').length;
})
.length;
// Get preliminary syllable count...
syllableCount = wordPartCount + prefixSuffixCount;
// Some syllables do not follow normal rules - check for them
subSyllables.forEach(function (syllable) {
if (word.match(syllable)) syllableCount--;
});
addSyllables.forEach(function (syllable) {
if (word.match(syllable)) syllableCount++;
});
return syllableCount || 1;
};
function textStatistics(text) {
return new TextStatistics(text);
}
After taking this function and adding it to the code variable (See OP's Visual Basic code) I was able to create an instance of this control and call methods on it. There are a couple of different ways to use TextStatistics in VBA:
Dim wc, sc As Integer
Dim s1, s2, code As String
Dim oTextStats As Object
Dim o As New ScriptControl
code = "function cleanText(e){var t=['li','p','h1','h2','h3','h4','h5','h6','dd'];t.forEach(function(t){e=e.replace('</'+t+'>','.')});e=e.replace(/<[^>]+>/g,'').replace(/[,:;()\-]/,' ').replace(/[\.!?]/,'.').replace(/^\s+/,'').replace(/[ ]*(\n|\r\n|\r)[ ]*/,' ').replace(/([\.])[\. ]+/,'.').replace(/[ ]*([\.])/,'. ').replace(/\s+/,' ').replace(/\s+$/,'');e+='.';return e}function textStatistics(e){return new TextStatistics(e)}if(!Array.prototype.filter){Array.prototype.filter=function(e){'use strict';if(this===void 0||this===null){throw new TypeError}var t=Object(this);" & _
"var n=t.length>>>0;if(typeof e!=='function'){throw new TypeError}var r=[];var i=arguments.length>=2?arguments[1]:void 0;for(var s=0;s<n;s++){if(s in t){var o=t[s];if(e.call(i,o,s,t)){r.push(o)}}}return r}}if(!Array.prototype.forEach){Array.prototype.forEach=function(e){var t=this.length;if(typeof e!='function')throw new TypeError;var n=arguments[1];for(var r=0;r<t;r++){if(r in this)e.call(n,this[r],r,this)}}}var TextStatistics=function(t){this.text=t?cleanText(t):this.text};" & _
"TextStatistics.prototype.fleschKincaidReadingEase=function(e){e=e?cleanText(e):this.text;return Math.round((206.835-1.015*this.averageWordsPerSentence(e)-84.6*this.averageSyllablesPerWord(e))*10)/10};TextStatistics.prototype.fleschKincaidGradeLevel=function(e){e=e?cleanText(e):this.text;return Math.round((.39*this.averageWordsPerSentence(e)+11.8*this.averageSyllablesPerWord(e)-15.59)*10)/10};TextStatistics.prototype.gunningFogScore=function(e){e=e?cleanText(e):this.text;" & _
"return Math.round((this.averageWordsPerSentence(e)+this.percentageWordsWithThreeSyllables(e,false))*.4*10)/10};TextStatistics.prototype.colemanLiauIndex=function(e){e=e?cleanText(e):this.text;return Math.round((5.89*(this.letterCount(e)/this.wordCount(e))-.3*(this.sentenceCount(e)/this.wordCount(e))-15.8)*10)/10};TextStatistics.prototype.smogIndex=function(e){e=e?cleanText(e):this.text;return Math.round(1.043*Math.sqrt(this.wordsWithThreeSyllables(e)*(30/this.sentenceCount(e))+3.1291)*10)/10};" & _
"TextStatistics.prototype.automatedReadabilityIndex=function(e){e=e?cleanText(e):this.text;return Math.round((4.71*(this.letterCount(e)/this.wordCount(e))+.5*(this.wordCount(e)/this.sentenceCount(e))-21.43)*10)/10};TextStatistics.prototype.textLength=function(e){e=e?cleanText(e):this.text;return e.length};TextStatistics.prototype.letterCount=function(e){e=e?cleanText(e):this.text;e=e.replace(/[^a-z]+/ig,'');return e.length};TextStatistics.prototype.sentenceCount=function(e){e=e?cleanText(e):this.text;" & _
"return e.replace(/[^\.!?]/g,'').length||1};TextStatistics.prototype.wordCount=function(e){e=e?cleanText(e):this.text;return e.split(/[^a-z0-9]+/i).length||1};TextStatistics.prototype.averageWordsPerSentence=function(e){e=e?cleanText(e):this.text;return this.wordCount(e)/this.sentenceCount(e)};TextStatistics.prototype.averageSyllablesPerWord=function(e){e=e?cleanText(e):this.text;var t=0,n=this.wordCount(e),r=this;e.split(/\s+/).forEach(function(e){t+=r.syllableCount(e)});return(t||1)/(n||1)};" & _
"TextStatistics.prototype.wordsWithThreeSyllables=function(e,t){e=e?cleanText(e):this.text;var n=0,r=this;t=t===false?false:true;e.split(/\s+/).forEach(function(e){if(!e.match(/^[A-Z]/)||t){if(r.syllableCount(e)>2)n++}});return n};TextStatistics.prototype.percentageWordsWithThreeSyllables=function(e,t){e=e?cleanText(e):this.text;return this.wordsWithThreeSyllables(e,t)/this.wordCount(e)*100};TextStatistics.prototype.syllableCount=function(e){var t=0,n=0,r=0;e=e.toLowerCase().replace(/[^a-z]/g,'');" & _
"var i={simile:3,forever:3,shoreline:2};if(i.hasOwnProperty(e))return i[e];var s=[/cial/,/tia/,/cius/,/cious/,/giu/,/ion/,/iou/,/sia$/,/[^aeiuoyt]{2,}ed$/,/.ely$/,/[cg]h?e[rsd]?$/,/rved?$/,/[aeiouy][dt]es?$/,/[aeiouy][^aeiouydt]e[rsd]?$/,/^[dr]e[aeiou][^aeiou]+$/,/[aeiouy]rse$/];var o=[/ia/,/riet/,/dien/,/iu/,/io/,/ii/,/[aeiouym]bl$/,/[aeiou]{3}/,/^mc/,/ism$/,/([^aeiouy])\1l$/,/[^l]lien/,/^coa[dglx]./,/[^gq]ua[^auieo]/,/dnt$/,/uity$/,/ie(r|st)$/];var u=[/^un/,/^fore/,/ly$/,/less$/,/ful$/,/ers?$/,/ings?$/];" & _
"u.forEach(function(t){if(e.match(t)){e=e.replace(t,'');n++}});r=e.split(/[^aeiouy]+/ig).filter(function(e){return!!e.replace(/\s+/ig,'').length}).length;t=r+n;s.forEach(function(n){if(e.match(n))t--});o.forEach(function(n){if(e.match(n))t++});return t||1}"
s1 = "the quick brown fox jumps over the lazy dog"
s2 = "help me! Some Short sentence fragments. Just a test"
With o
.Language = "JScript"
.AddCode code
' Create a TextStatistics object initially with no text.
' textStatistics is a function that creates TextStatistics objects
Set oTextStats = .Eval("textStatistics()")
' Now simply call TextStatistics methods directly
wc = oTextStats.wordCount(s1)
sc = oTextStats.sentenceCount(s2)
' Alternatively you can create a TextStatistics object with the text
' and call the methods with a blank string to return the values
' for the string passed in the constructor
Set oTextStats = .Eval("textStatistics('" + s1 + "')")
wc = oTextStats.wordCount("")
sc = oTextStats.sentenceCount("")
End With

How to add a space in a specific index of a string? [duplicate]

How can I insert a string at a specific index of another string?
var txt1 = "foo baz"
Suppose I want to insert "bar " after the "foo" how can I achieve that?
I thought of substring(), but there must be a simpler more straight forward way.
Inserting at a specific index (rather than, say, at the first space character) has to use string slicing/substring:
var txt2 = txt1.slice(0, 3) + "bar" + txt1.slice(3);
You could prototype your own splice() into String.
Polyfill
if (!String.prototype.splice) {
/**
* {JSDoc}
*
* The splice() method changes the content of a string by removing a range of
* characters and/or adding new characters.
*
* #this {String}
* #param {number} start Index at which to start changing the string.
* #param {number} delCount An integer indicating the number of old chars to remove.
* #param {string} newSubStr The String that is spliced in.
* #return {string} A new string with the spliced substring.
*/
String.prototype.splice = function(start, delCount, newSubStr) {
return this.slice(0, start) + newSubStr + this.slice(start + Math.abs(delCount));
};
}
Example
String.prototype.splice = function(idx, rem, str) {
return this.slice(0, idx) + str + this.slice(idx + Math.abs(rem));
};
var result = "foo baz".splice(4, 0, "bar ");
document.body.innerHTML = result; // "foo bar baz"
EDIT: Modified it to ensure that rem is an absolute value.
Here is a method I wrote that behaves like all other programming languages:
String.prototype.insert = function(index, string) {
if (index > 0)
{
return this.substring(0, index) + string + this.substring(index, this.length);
}
return string + this;
};
//Example of use:
var something = "How you?";
something = something.insert(3, " are");
console.log(something)
Reference:
http://coderamblings.wordpress.com/2012/07/09/insert-a-string-at-a-specific-index/
Just make the following function:
function insert(str, index, value) {
return str.substr(0, index) + value + str.substr(index);
}
and then use it like that:
alert(insert("foo baz", 4, "bar "));
Output: foo bar baz
It behaves exactly, like the C# (Sharp) String.Insert(int startIndex, string value).
NOTE: This insert function inserts the string value (third parameter) before the specified integer index (second parameter) in the string str (first parameter), and then returns the new string without changing str!
UPDATE 2016: Here is another just-for-fun (but more serious!) prototype function based on one-liner RegExp approach (with prepend support on undefined or negative index):
/**
* Insert `what` to string at position `index`.
*/
String.prototype.insert = function(what, index) {
return index > 0
? this.replace(new RegExp('.{' + index + '}'), '$&' + what)
: what + this;
};
console.log( 'foo baz'.insert('bar ', 4) ); // "foo bar baz"
console.log( 'foo baz'.insert('bar ') ); // "bar foo baz"
Previous (back to 2012) just-for-fun solution:
var index = 4,
what = 'bar ';
'foo baz'.replace(/./g, function(v, i) {
return i === index - 1 ? v + what : v;
}); // "foo bar baz"
This is basically doing what #Base33 is doing except I'm also giving the option of using a negative index to count from the end. Kind of like the substr method allows.
// use a negative index to insert relative to the end of the string.
String.prototype.insert = function (index, string) {
var ind = index < 0 ? this.length + index : index;
return this.substring(0, ind) + string + this.substr(ind);
};
Example:
Let's say you have full size images using a naming convention but can't update the data to also provide thumbnail urls.
var url = '/images/myimage.jpg';
var thumb = url.insert(-4, '_thm');
// result: '/images/myimage_thm.jpg'
If anyone is looking for a way to insert text at multiple indices in a string, try this out:
String.prototype.insertTextAtIndices = function(text) {
return this.replace(/./g, function(character, index) {
return text[index] ? text[index] + character : character;
});
};
For example, you can use this to insert <span> tags at certain offsets in a string:
var text = {
6: "<span>",
11: "</span>"
};
"Hello world!".insertTextAtIndices(text); // returns "Hello <span>world</span>!"
Instantiate an array from the string
Use Array#splice
Stringify again using Array#join
The benefits of this approach are two-fold:
Simple
Unicode code point compliant
const pair = Array.from('USDGBP')
pair.splice(3, 0, '/')
console.log(pair.join(''))
Given your current example you could achieve the result by either
var txt2 = txt1.split(' ').join(' bar ')
or
var txt2 = txt1.replace(' ', ' bar ');
but given that you can make such assumptions, you might as well skip directly to Gullen's example.
In a situation where you really can't make any assumptions other than character index-based, then I really would go for a substring solution.
my_string = "hello world";
my_insert = " dear";
my_insert_location = 5;
my_string = my_string.split('');
my_string.splice( my_insert_location , 0, my_insert );
my_string = my_string.join('');
https://jsfiddle.net/gaby_de_wilde/wz69nw9k/
I know this is an old thread, however, here is a really effective approach.
var tn = document.createTextNode("I am just to help")
t.insertData(10, "trying");
What's great about this is that it coerces the node content. So if this node were already on the DOM, you wouldn't need to use any query selectors or update the innerText. The changes would reflect due to its binding.
Were you to need a string, simply access the node's text content property.
tn.textContent
#=> "I am just trying to help"
You can do it easily with regexp in one line of code
const str = 'Hello RegExp!';
const index = 6;
const insert = 'Lovely ';
//'Hello RegExp!'.replace(/^(.{6})(.)/, `$1Lovely $2`);
const res = str.replace(new RegExp(`^(.{${index}})(.)`), `$1${insert}$2`);
console.log(res);
"Hello Lovely RegExp!"
Well, we can use both the substring and slice method.
String.prototype.customSplice = function (index, absIndex, string) {
return this.slice(0, index) + string+ this.slice(index + Math.abs(absIndex));
};
String.prototype.replaceString = function (index, string) {
if (index > 0)
return this.substring(0, index) + string + this.substr(index);
return string + this;
};
console.log('Hello Developers'.customSplice(6,0,'Stack ')) // Hello Stack Developers
console.log('Hello Developers'.replaceString(6,'Stack ')) //// Hello Stack Developers
The only problem of a substring method is that it won't work with a negative index. It's always take string index from 0th position.
You can use Regular Expressions with a dynamic pattern.
var text = "something";
var output = " ";
var pattern = new RegExp("^\\s{"+text.length+"}");
var output.replace(pattern,text);
outputs:
"something "
This replaces text.length of whitespace characters at the beginning of the string output.
The RegExp means ^\ - beginning of a line \s any white space character, repeated {n} times, in this case text.length. Use \\ to \ escape backslashes when building this kind of patterns out of strings.
another solution, cut the string in 2 and put a string in between.
var str = jQuery('#selector').text();
var strlength = str.length;
strf = str.substr(0 , strlength - 5);
strb = str.substr(strlength - 5 , 5);
jQuery('#selector').html(strf + 'inserted' + strb);
Using slice
You can use slice(0,index) + str + slice(index). Or you can create a method for it.
String.prototype.insertAt = function(index,str){
return this.slice(0,index) + str + this.slice(index)
}
console.log("foo bar".insertAt(4,'baz ')) //foo baz bar
Splice method for Strings
You can split() the main string and add then use normal splice()
String.prototype.splice = function(index,del,...newStrs){
let str = this.split('');
str.splice(index,del,newStrs.join('') || '');
return str.join('');
}
var txt1 = "foo baz"
//inserting single string.
console.log(txt1.splice(4,0,"bar ")); //foo bar baz
//inserting multiple strings
console.log(txt1.splice(4,0,"bar ","bar2 ")); //foo bar bar2 baz
//removing letters
console.log(txt1.splice(1,2)) //f baz
//remving and inseting atm
console.log(txt1.splice(1,2," bar")) //f bar baz
Applying splice() at multiple indexes
The method takes an array of arrays each element of array representing a single splice().
String.prototype.splice = function(index,del,...newStrs){
let str = this.split('');
str.splice(index,del,newStrs.join('') || '');
return str.join('');
}
String.prototype.mulSplice = function(arr){
str = this
let dif = 0;
arr.forEach(x => {
x[2] === x[2] || [];
x[1] === x[1] || 0;
str = str.splice(x[0] + dif,x[1],...x[2]);
dif += x[2].join('').length - x[1];
})
return str;
}
let txt = "foo bar baz"
//Replacing the 'foo' and 'bar' with 'something1' ,'another'
console.log(txt.splice(0,3,'something'))
console.log(txt.mulSplice(
[
[0,3,["something1"]],
[4,3,["another"]]
]
))
I wanted to compare the method using substring and the method using slice from Base33 and user113716 respectively, to do that I wrote some code
also have a look at this performance comparison, substring, slice
The code I used creates huge strings and inserts the string "bar " multiple times into the huge string
if (!String.prototype.splice) {
/**
* {JSDoc}
*
* The splice() method changes the content of a string by removing a range of
* characters and/or adding new characters.
*
* #this {String}
* #param {number} start Index at which to start changing the string.
* #param {number} delCount An integer indicating the number of old chars to remove.
* #param {string} newSubStr The String that is spliced in.
* #return {string} A new string with the spliced substring.
*/
String.prototype.splice = function (start, delCount, newSubStr) {
return this.slice(0, start) + newSubStr + this.slice(start + Math.abs(delCount));
};
}
String.prototype.splice = function (idx, rem, str) {
return this.slice(0, idx) + str + this.slice(idx + Math.abs(rem));
};
String.prototype.insert = function (index, string) {
if (index > 0)
return this.substring(0, index) + string + this.substring(index, this.length);
return string + this;
};
function createString(size) {
var s = ""
for (var i = 0; i < size; i++) {
s += "Some String "
}
return s
}
function testSubStringPerformance(str, times) {
for (var i = 0; i < times; i++)
str.insert(4, "bar ")
}
function testSpliceStringPerformance(str, times) {
for (var i = 0; i < times; i++)
str.splice(4, 0, "bar ")
}
function doTests(repeatMax, sSizeMax) {
n = 1000
sSize = 1000
for (var i = 1; i <= repeatMax; i++) {
var repeatTimes = n * (10 * i)
for (var j = 1; j <= sSizeMax; j++) {
var actualStringSize = sSize * (10 * j)
var s1 = createString(actualStringSize)
var s2 = createString(actualStringSize)
var start = performance.now()
testSubStringPerformance(s1, repeatTimes)
var end = performance.now()
var subStrPerf = end - start
start = performance.now()
testSpliceStringPerformance(s2, repeatTimes)
end = performance.now()
var splicePerf = end - start
console.log(
"string size =", "Some String ".length * actualStringSize, "\n",
"repeat count = ", repeatTimes, "\n",
"splice performance = ", splicePerf, "\n",
"substring performance = ", subStrPerf, "\n",
"difference = ", splicePerf - subStrPerf // + = splice is faster, - = subStr is faster
)
}
}
}
doTests(1, 100)
The general difference in performance is marginal at best and both methods work just fine (even on strings of length ~~ 12000000)
Take the solution. I have written this code in an easy format:
const insertWord = (sentence,word,index) => {
var sliceWord = word.slice(""),output = [],join; // Slicing the input word and declaring other variables
var sliceSentence = sentence.slice(""); // Slicing the input sentence into each alphabets
for (var i = 0; i < sliceSentence.length; i++)
{
if (i === index)
{ // checking if index of array === input index
for (var j = 0; j < word.length; j++)
{ // if yes we'll insert the word
output.push(sliceWord[j]); // Condition is true we are inserting the word
}
output.push(" "); // providing a single space at the end of the word
}
output.push(sliceSentence[i]); // pushing the remaining elements present in an array
}
join = output.join(""); // converting an array to string
console.log(join)
return join;
}
Prototype should be the best approach as many mentioned. Make sure that prototype comes earlier than where it is used.
String.prototype.insert = function (x, str) {
return (x > 0) ? this.substring(0, x) + str + this.substr(x) : str + this;
};

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