I have written a simple code. In order to avoid flooding a JSON server, i want to break up the JSON response in pieces. So my jquery code should be parsing one variable ("page") to the php page that handles the JSON Oauth Request. On success, it should append the DIV with the latest responses.
My code should be working, except for the fact that my ajax post is not being received by my php file.
Here goes
archief.html
$("#klik").click(function() {
console.log("fire away");
page = page + 1;
$("#archief").load("trytocombinenewageandgettagsendates.php");
console.log(page);
$.ajax({
type: 'POST',
url: "trytocombinenewageandgettagsendates.php",
data: page,
success: function() {
console.log(page);
$.get("trytocombinenewageandgettagsendates.php", function(archief) {
$('#archief').append(archief);
});
},
error: function(err) {
alert(err.responseText);
}
});
return false;
});
The php file doesn't receive anything.
var_dump($_POST);
gives me array(0) { }.
Very strange, i'd really appreciate the help!
You are sending a string instead of key-value pairs. If you want to use $_POST you need to send key-value pairs:
...
$.ajax({
type: 'POST',
url: "trytocombinenewageandgettagsendates.php",
data: { 'page': page },
success: function() {
...
If you send a single value or string, you would need to read the raw input.
Also, you are sending 2 GET requests and 1 POST request to the same file. Is that intentional? Note that only the POST request will have the $_POST variable set.
Thank you for your help and not letting me post "this still doens't work" posts :)
I made the mistake of loading the "unConsulted" php file [$.get("trytocombinenewageandgettagsendates.php"] upon success. Instead, i append the response of the PHP.
The working code below:
$("#klik").click(function() {
console.log("fire away");
page = page + 1;
//$("#archief").load("trytocombinenewageandgettagsendates.php");
console.log(page);
$.ajax({
type: 'POST',
url: "trytocombinenewageandgettagsendates.php",
data: { 'page': page },
success: function(response){
$("#archief").append(response);
},
error: function(err) {
alert(err.responseText);
}
});
return false;
Related
Hi there is it possible to redirect to another page using ajax? I have this piece of code that I have been working on to try this.
<script type="text/javascript">
$(document.body).on('click', '#btnPrintPrev', function() {
$.ajax({
url: '/pdfdatacal',
data: {
dummydata: "This is a dummy data"
},
});
});
</script>
Now it should be able to carry data to another page and redirect there. Problem is it doesn't.
This is what I am using in my route
Route::get('/pdfdatacal', 'GenerateReportController#pdfdatacal');
Then in the controller
public function pdfdatacal(Request $request) {
return $request->data['dummydata'];
}
My expected result should be a blank page containing the value of dummydata but it doesn't do that in my code. How do I accomplish this?
first your ajax must be something like
$.ajax({
url: '/pdfdatacal',
method: 'post',
data: { dummydata: "This is a dummy data" },
dataType: "JSON",
success: function(response){
console.log(response); // just to check if the data is being passed
// do something you want if ever .
}
});
then in your routes
Route::post('/pdfdatacal', 'GenerateReportController#pdfdatacal');
in your controller
public function pdfdatacal(Request $request) {
return response()->json($request->dummydata);
}
hope it helps ..
Use
window.location.href = "http://yourwebsite.com/pdfdatacal";
In your success call
The idea is that you send data to your controller, it sends back a response, then you redirect from javascript to where you want.
$.ajax({
url: '/pdfdatacal',
type : 'GET',
data : {
dummydata: "This is a dummy data"
},
success : function(data) {
window.location.href = "http://yourwebsite.com/pdfdatacal";
}
});
But if your controller does nothing with the data you send, then you don't need to use ajax at all, simple redirect using javascript.
you could use window.location.assign('your URL here!'); in the success.
success : function(data) {
window.location.assign('your URL here!');
}
I have the following code (jQuery) to create a json file:
$( ".save" ).on("click", function(){
var items=[];
$("tr.data").each(function() {
var item = {
item.Code : $(this).find('td:nth-child(1) span').html(),
itemQuantity : $(this).find('td:nth-child(4) span').html()
};
items.push(item);
});
});
Now this is my AJAX function:
(function() {
$.ajax({
url : "",
type: "POST",
data:{ //I need my items object, how do I send it to backend server (django)??
calltype:'save'},
dataType: "application/json", // datatype being sent
success : function(jsondata) {
//do something
},
error : function() {
//do something
}
});
}());
Now, my doubt is how do I send the 'item[]' object that I created to the backend? I do need to send both the item[] object and the variable 'calltype' which signals what made the AJAX call, as I have the same Django View (its the Controller equivalent for Django) in the backend being called by different AJAX functions.
How will my AJAX function look like?
Hey guys just got my answer right.
I used the following ajax function to get it right:
(function() {
$.ajax({
url : "",
type: "POST",
data:{ bill_details: items,
calltype: 'save',
'csrfmiddlewaretoken': csrf_token},
dataType: 'json',
// handle a successful response
success : function(jsondata) {
console.log(jsondata); // log the returned json to the console
alert(jsondata['name']);
},
// handle a non-successful response
error : function() {
console.log("Error"); // provide a bit more info about the error to the console
}
});
}());
So, this is sort of a self answer!!! :) Thanks a lot SO!!
I am trying to send an Ajax POST request using Jquery but I am having 400 bad request error.
Here is my code:
$.ajax({
type: 'POST',
url: "http://localhost:8080/project/server/rest/subjects",
data: {
"subject:title":"Test Name",
"subject:description":"Creating test subject to check POST method API",
"sub:tags": ["facebook:work", "facebook:likes"],
"sampleSize" : 10,
"values": ["science", "machine-learning"]
},
error: function(e) {
console.log(e);
}
});
It Says: Can not build resource from request.
What am I missing ?
Finally, I got the mistake and the reason was I need to stringify the JSON data I was sending. I have to set the content type and datatype in XHR object.
So the correct version is here:
$.ajax({
type: 'POST',
url: "http://localhost:8080/project/server/rest/subjects",
data: JSON.stringify({
"subject:title":"Test Name",
"subject:description":"Creating test subject to check POST method API",
"sub:tags": ["facebook:work", "facebook:likes"],
"sampleSize" : 10,
"values": ["science", "machine-learning"]
}),
error: function(e) {
console.log(e);
},
dataType: "json",
contentType: "application/json"
});
May be it will help someone else.
In case anyone else runs into this. I have a web site that was working fine on the desktop browser but I was getting 400 errors with Android devices.
It turned out to be the anti forgery token.
$.ajax({
url: "/Cart/AddProduct/",
data: {
__RequestVerificationToken: $("[name='__RequestVerificationToken']").val(),
productId: $(this).data("productcode")
},
The problem was that the .Net controller wasn't set up correctly.
I needed to add the attributes to the controller:
[AllowAnonymous]
[IgnoreAntiforgeryToken]
[DisableCors]
[HttpPost]
public async Task<JsonResult> AddProduct(int productId)
{
The code needs review but for now at least I know what was causing it. 400 error not helpful at all.
Yes. You need to stringify the JSON data orlse 400 bad request error occurs as it cannot identify the data.
400 Bad Request
Bad Request. Your browser sent a request that this server could not
understand.
Plus you need to add content type and datatype as well. If not you will encounter 415 error which says Unsupported Media Type.
415 Unsupported Media Type
Try this.
var newData = {
"subject:title":"Test Name",
"subject:description":"Creating test subject to check POST method API",
"sub:tags": ["facebook:work", "facebook:likes"],
"sampleSize" : 10,
"values": ["science", "machine-learning"]
};
var dataJson = JSON.stringify(newData);
$.ajax({
type: 'POST',
url: "http://localhost:8080/project/server/rest/subjects",
data: dataJson,
error: function(e) {
console.log(e);
},
dataType: "json",
contentType: "application/json"
});
With this way you can modify the data you need with ease. It wont confuse you as it is defined outside the ajax block.
The question is a bit old... but just in case somebody faces the error 400, it may also come from the need to post csrfToken as a parameter to the post request.
You have to get name and value from craft in your template :
<script type="text/javascript">
window.csrfTokenName = "{{ craft.config.csrfTokenName|e('js') }}";
window.csrfTokenValue = "{{ craft.request.csrfToken|e('js') }}";
</script>
and pass them in your request
data: window.csrfTokenName+"="+window.csrfTokenValue
You need to build query from "data" object using the following function
function buildQuery(obj) {
var Result= '';
if(typeof(obj)== 'object') {
jQuery.each(obj, function(key, value) {
Result+= (Result) ? '&' : '';
if(typeof(value)== 'object' && value.length) {
for(var i=0; i<value.length; i++) {
Result+= [key+'[]', encodeURIComponent(value[i])].join('=');
}
} else {
Result+= [key, encodeURIComponent(value)].join('=');
}
});
}
return Result;
}
and then proceed with
var data= {
"subject:title":"Test Name",
"subject:description":"Creating test subject to check POST method API",
"sub:tags": ["facebook:work, facebook:likes"],
"sampleSize" : 10,
"values": ["science", "machine-learning"]
}
$.ajax({
type: 'POST',
url: "http://localhost:8080/project/server/rest/subjects",
data: buildQuery(data),
error: function(e) {
console.log(e);
}
});
I'm hoping this may be of use to those encountering 400 errors while using AJAX in Wordpress going forward. Even though this question is many years old, the solutions provided have all been programmatic, and I'm sure many have stepped through their code to repeatedly find it's correct, yet continue to find it is not working.
I found dozens of results asking how to resolve "WP AJAX request returning 400 Bad Request" or "WP AJAX request returning 0" and nothing today worked.
Googling "How do I fix 400 bad request on Wordpress?" finally resulted in the answer appearing from https://wp-umbrella.com/troubleshooting/400-bad-request-error-on-wordpress/
Clear your Web Browser Cache and Cookies
You may be surprised, but most 400 errors in WordPress can be fixed by clearing your browser's cache and cookies. Browser caches temporarily store images, scripts, and other parts of websites you visit to speed up your browsing experience.
Clearing both my cache and cookies saw the 400 Bad Request code disappear and results return AJAX results as expected.
I want to to call a method GetAccount from my controller AccountController.cs, in my JavaScript factory LoginFactory.js. Something like this:
AccountController.cs:
public Account GetAccount(string userName)
{ ... }
LoginFactory.js:
if(x>y) {
var account = <%AccountController.GetAccount(someParam);%>
}
I've tried using [WebMethod] and Ajax, but I can't get it to work: I get a 404 response.
Assuming your GetAccount method can be reached at /Account/GetAccount when your application runs, you could use the following:
$.ajax({
type: 'GET',
url: '/Account/GetAccount',
data: { 'username' : 'a-username' },
dataType: 'json',
success: function(jsonData) {
alert(jsonData);
},
error: function() {
alert('error');
}
});
Note - this is dependant on jQuery.
This causes the browser to make a request to /Account/GetAccount as if you had done so by entering the URL in the URL bar, but of course, captures the returned json for use in your client side (javascript) script.
If this returns a 404, it would be worth checking your routing.
I am trying to implement file upload using ajax with Django but facing some problem.
When the user tries to upload the files after selecting the file and submitting the form, then as per my understanding , an ajax request should be send to the server using POST method ,but in my case a POST request is being made to the server, but the server is not able to identify it as an ajax request and browser is redirected to http://<server>:<port>/upload/ and the contents on this page are as follows.
{"status": "error", "result": "Something went wrong.Try Again !!"}
Django Version: 1.6.2
Python Version: 2.7.5
Also, testing on Django Development Server.
views.py
def upload(request):
logging.info('Inside upload view')
response_data = {}
if request.is_ajax():
logging.info('Is_AJAX() returned True')
form = UploaderForm(request.POST, request.FILES)
if form.is_valid():
logging.info('Uploaded Data Validated')
upload = Upload( upload=request.FILES['upload'] )
upload.name = request.FILES['upload'].name
upload.save()
logging.info('Uploaded Data Saved in Database and link is %s' % upload.upload)
response_data['status'] = "success"
response_data['result'] = "Your file has been uploaded !!"
response_data['fileLink'] = "/%s" % upload.upload
return HttpResponse(json.dumps(response_data), content_type="application/json")
response_data['status'] = "error"
response_data['result'] = "Something went wrong.Try Again !!"
return HttpResponse(json.dumps(response_data), content_type='application/json')
Template
<form id="uploadForm" action="/upload/" method="post" enctype="multipart/form-data">
{% csrf_token %}
<input id="fileInput" class="input-file" name="upload" type="file">
<input type="submit" value="Post Images/Files" />
</form>
Javascript 1:
$('#uploadForm').submit(function(){
var formData = new FormData($(this)[0]);
$.ajax({
url: '/upload/',
type: 'POST',
data: formData,
async: false,
success: function (data) {
alert(data)
},
cache: false,
contentType: false,
processData: false
});
return false;
});
Javascript 2
var options = {
url: '/upload/',
type: "POST",
error: function(response) {
alert('Something went Wrong. Try Again');
},
success: function(response) {
if ( response.status == 'success' ) {
alert('success');
}
}
};
$('#uploadForm').ajaxSubmit(options);
Question:
1) Why is Django not able to recognize the ajax request and value of request.is_ajax() is always False.
2) Even if the server doesn't recognize ajax request why is my browser getting redirected to another page ?
There is another similar question here but with no result.
This works for me. You need a jquery.form.js
$("#uploadForm").submit(function(event) {
$(this).ajaxSubmit({
url:'{% url upload_file %}',
type: 'post',
success: function(data) {
console.log(data)
},
error: function(jqXHR, exception) {
console.log("An error occurred while uploading your file!");
}
});
return false;
});
Here's the similar question here with answers.
Make sure that javascript code block
$('#uploadForm').submit(function(){
var formData = new FormData($(this)[0]);
$.ajax({
url: '/upload/',
type: 'POST',
data: formData,
async: false,
success: function (data) {
alert(data)
},
cache: false,
contentType: false,
processData: false
});
return false;
});
loaded after your uploadForm html form in DOM on page. In your case seems you trying to bind submit handler with form element which not yet loaded so when you click, it send simple POST request.
1) why is_ajax() not working?
Have you included the JQuery form plugin (jquery.form.js) ? ajaxSubmit() needs that plugin.
Take a look at http://jquery.malsup.com/form/
If it's already done, you might take a look at the HTTPRequest object
Django Documentation says HttpRequest.is_ajax()
Returns True if the request was made via an XMLHttpRequest. And if you are using some javascript libraries to make the ajax request, you dont have to bother about this matter. Still you can verify "HTTP_X_REQUESTED_WITH" header to see if Django received an XMLHttpRequest or not.
2) Why page redirects?
As I said above, JQuery form plugin is needed for handling the ajax request and its call back. Also, for ajaxSubmit() you need to override the $(#uploadForm).submit()
$('#uploadForm').submit( function (){
$(this).ajaxSubmit(options);
return false;
});
Hope this was helpful :)