Develop Reference

How can I make this javascript function not use a global variable?

This function toggles the active state of a hamburger icon when clicking on it. Also clicking anywhere on the document does the same but only if the dropdown is open.
var dropdownOpen = false;
$(".hamburger").click(function () {
$(this).toggleClass('is-active');
dropdownOpen = !dropdownOpen;
});
$(document).ready(function(){
$(document).click(function(e){
if ($(e.target).is('.hamburger')) {
return;
}
else if (dropdownOpen === true)
{
$(".hamburger").toggleClass('is-active');
dropdownOpen = false;
}
});
});
How would I go about combining two click events so I don't have to use a global variable?
I've tried this:
$(document).ready(function(){
var dropdownOpen = false;
$(document).click(function(e){
if ($(e.target).is('.hamburger')) {
$('.hamburger').toggleClass('is-active');
dropdownOpen = !dropdownOpen;
}
else if (dropdownOpen === true)
{
$(".hamburger").toggleClass('is-active');
dropdownOpen = false;
}
});
});
..but it didn't work, any ideas?

You can wrap all your JS in an Immediately Invoked Function Expression. All the JS variables are not scoped to this function expression instead of being available globally.
(function() {
var dropdownOpen = false;
$(".hamburger").click(function() {
$(this).toggleClass('is-active');
dropdownOpen = !dropdownOpen;
});
$(document).ready(function() {
$(document).click(function(e) {
if ($(e.target).is('.hamburger')) {
return;
} else if (dropdownOpen === true) {
$(".hamburger").toggleClass('is-active');
dropdownOpen = false;
}
});
});
})();

There's no need for the global varable at all.
$(document).click(function(e) {
if ($(e.target).is(".hamburger")) {
$(e.target).toggleClass("is-active");
} else {
$(".hambuger").removeClass("is-active");
}
}
There's no harm in calling removeClass() if the class isn't there.

show div when all input fields have content

I have a form with a few input fields, I only want to show a div when all the input fields got content, when one of the input fields has no content the div should disappear again.
I made it work with one input field, but how do I get it to work when all the input fields are filled in (don't know if its a good clean way?):
$(function () {
$('input').change(function() {
$('.next').toggle($(this).val().length !== 0);
}); });
Fiddle:
http://jsfiddle.net/uQyH9/19/

Try this : http://jsfiddle.net/uQyH9/21/
$(function () {
var _cached=$('input');
_cached.change(function() {
if (_cached.filter(function (){return $(this).val().length }).length==_cached.length)
$('.next').show();
else
$('.next').hide();
});
});

You can use a filter function to check that all the input are filled.
Code:
$(function () {
$('input').change(function () {
$('.next').toggle($("input").filter(function () {
return this.value === "";
}).length === 0)
});
});
Demo: http://jsfiddle.net/IrvinDominin/DwF2P/
UPDATE
You can check the value of the elements by type by cheking type attribute.
Code:
$(function () {
$('input').change(function () {
$('.next').toggle($("input").filter(function () {
var myType=$(this).attr("type");
if (myType === "checkbox") return !$(this).is(":checked");
if (myType==="radio"){
var myName = $(this).attr("name");
if (myName==="") return !$(this).is(":checked");
return $('input[name='+ myName +']:checked').length===0
}
return this.value === "";
}).length === 0)
});
});
Demo: http://jsfiddle.net/IrvinDominin/pqJhg/

Loop over the inputs. If you find one that isn't filled in, then hide the DIV. If you don't, show the DIV.
$('input').change(function() {
var allFilled = true;
$('input').each(function() {
if (this.value === '') {
allFilled = false;
return false; // Terminate the loop
}
}
$('.next').toggle(allFilled);
});

Hide and show particular form items on checked and unchecked selectbox?

I am using the below given code to hide and show particular form items, but this doesn't work kindly let me know what I am missing in my code?
HTML:
<input id="id_code_col" type="checkbox" name="code_col"></input>
SCRIPT:
$(document).ready(function(){
var selectBox = jQuery('#id_code_col');
selectBox.change(function () {
if ($(this).val() == '1') {
$('#id_FullColumn').show();
$('#id_FirstColumn').hide();
$('#id_SecondColumn').hide();
}
else {
$('#id_FullColumn').hide();
$('#id_FirstColumn').show();
$('#id_SecondColumn').show();
}
});
});
N.B: I can not add or remove anything from html. What ever I have to do is to do it with script. Kindly help!

do like this:
if(this.checked)
{
// checked
}
else
{
// unchecked
}
for your case:
$(document).ready(function(){
var selectBox = jQuery('#id_code_col');
selectBox.change(function () {
if (this.checked) {
$('#id_FullColumn').show();
$('#id_FirstColumn').hide();
$('#id_SecondColumn').hide();
}
else {
$('#id_FullColumn').hide();
$('#id_FirstColumn').show();
$('#id_SecondColumn').show();
}
});
});

selectBox.change(function () {
if ($(this).is(':checked')) {
$('#id_FullColumn').show();
$('#id_FirstColumn').hide();
$('#id_SecondColumn').hide();
}
else {
$('#id_FullColumn').hide();
$('#id_FirstColumn').show();
$('#id_SecondColumn').show();
}
});

You can use .is() along with :checked selector to check whether your checkbox is checked or not, so try to use:
if ($(this).is(':checked')) {
or pure javascript using:
if(this.checked)
instead of:
if ($(this).val() == '1') {

Change this
if ($(this).val() == '1') {
to this
if (this.checked) {
Because you don't have to check for the value to 1, as your checkbox doesn't have any value set to 1.
So you have to check for the state of that checkbox with checked method.

$(document).ready(function () {
var selectBox = jQuery('#id_code_col');
selectBox.change(function () {
if (this.checked) {
alert("checked");
}
else {
alert("unchecked");
}
});
});

$(function(){
$('#id_code_col').change(function(){
if($(this.checked)){
alert('checked');
}else{
alert('unchecked');
}
});
});

jQuery: Check if button is clicked

I have two buttons in a form and want to check which one was clicked.
Everything works fine with radioButtons:
if($("input[#name='class']:checked").val() == 'A')
On simple submit button everything crash.
Thanks!

$('#submit1, #submit2').click(function () {
if (this.id == 'submit1') {
alert('Submit 1 clicked');
}
else if (this.id == 'submit2') {
alert('Submit 2 clicked');
}
});

You can use this:
$("#id").click(function()
{
$(this).data('clicked', true);
});
Now check it via an if statement:
if($("#id").data('clicked'))
{
// code here
}
For more information you can visit the jQuery website on the .data() function.

jQuery(':button').click(function () {
if (this.id == 'button1') {
alert('Button 1 was clicked');
}
else if (this.id == 'button2') {
alert('Button 2 was clicked');
}
});
EDIT:- This will work for all buttons.

$('input[type="button"]').click(function (e) {
if (e.target) {
alert(e.target.id + ' clicked');
}
});
you should tweak this a little (eg. use a name in stead of an id to alert), but this way you have more generic function.

$('#btn1, #btn2').click(function() {
let clickedButton = $(this).attr('id');
console.log(clickedButton);
});

try something like :
var focusout = false;
$("#Button1").click(function () {
if (focusout == true) {
focusout = false;
return;
}
else {
GetInfo();
}
});
$("#Text1").focusout(function () {
focusout = true;
GetInfo();
});

How can I change the class of an element with jQuery>

I have a JavaScript function that looks like this:
function UpdateFilterView() {
if (_extraFilterExists) {
if ($('#F_ShowF').val() == 1) {
$('#extraFilterDropDownButton').attr('class', "showhideExtra_up");
$('#extraFilterDropDownButton').css("display", "block");
if ($('#divCategoryFilter').css("display") == 'none') {
$('#divCategoryFilter').show('slow');
}
return;
} else {
if ($('#divCategoryFilter').css("display") == 'block') {
$('#divCategoryFilter').hide('slow');
}
$('#extraFilterDropDownButton').css("display", "block");
$('#extraFilterDropDownButton').attr('class', "showhideExtra_down");
return;
}
} else {
if ($('#divCategoryFilter').css("display") != 'none') {
$('#divCategoryFilter').hide('fast');
}
$('#extraFilterDropDownButton').css("display", "none");
}
}
This will be triggered by the following code (from within the $(document).ready(function () {}):
$('#extraFilterDropDownButton').click(function() {
if ($('#F_ShowF').val() == 1) {
$('#F_ShowF').val(0);
} else {
$('#F_ShowF').val(1);
}
UpdateFilterView();
});
The HTML for this is easy:
<div id="divCategoryFilter">...</div>
<div style="clear:both;"></div>
<div id="extraFilterDropDownButton" class="showhideExtra_down"> </div>
I have two problems with this:
When the panel is hidden and we press the div button (extraFilterDropDownButton) the upper left part of the page will flicker and then the panel will be animated down.
When the panel is shown and we press the div button the panel will hide('slow'), but the button will not change to the correct class even when we set it in the UpdateFilterView script?
The correct class will be set on the button when hovering it, this is set with the following code:
$("#extraFilterDropDownButton").hover(function() {
if ($('#divCategoryFilter').css("display") == 'block') {
$(this).attr('class', 'showhideExtra_up_hover');
} else {
$(this).attr('class', 'showhideExtra_down_hover');
}
},
function() {
if ($('#divCategoryFilter').css("display") == 'block') {
$(this).attr('class', 'showhideExtra_up');
} else {
$(this).attr('class', 'showhideExtra_down');
}
});

To set a class completely, instead of adding one or removing one, use this:
$(this).attr("class","newclass");
Advantage of this is that you'll remove any class that might be set in there and reset it to how you like. At least this worked for me in one situation.

Use jQuery's
$(this).addClass('showhideExtra_up_hover');
and
$(this).addClass('showhideExtra_down_hover');

<script>
$(document).ready(function(){
$('button').attr('class','btn btn-primary');
}); </script>

I like to write a small plugin to make things cleaner:
$.fn.setClass = function(classes) {
this.attr('class', classes);
return this;
};
That way you can simply do
$('button').setClass('btn btn-primary');