It seems I'm stuck again with a simple regex.
What I'd like:
A number between 1 and 999
Optional: a comma , sign
If the comma sign is entered, minimum 1 decimal and maximum 3
decimals should be presebt.
Allowed:
100
999,0
999,999
999,99
Disallowed:
-1
0
999,
999,9999
This is what I have so far:
^[0-9]{1,3}(?:\,[0-9]{1,3})?$
Any tips?
You can use this regex:
/^[1-9]\d{0,2}(?:\,\d{1,3})?$/
RegEx Demo
Main difference from OP's regex is use of [1-9] which matches digits 1 to 9 before rest of the regex.
This regex should work :
^[1-9]\d{0,2}(?:,\d{1,3})?$
Here is the explanation :
^[1-9]: It should begin with a number between 1 and 9
\d{0,2}: Followed by minimum 0, maximum 2 digits (0-9)
(?:,: Followed by a comma
\d{1,3})?: IF there is a comma it should be followed by one to three digits
$: End of line
EXAMPLE
Thanks #dev-null for this link: Explanation
Related
how to make a regular expression into one number (only numbers) and that it does not exceed 10 from 0 to 10
/^[1-9][1]*$/.test(message)
It doesn't work that way for me.
To specify the amount of a specific character use {} instead of [], in this case, as it is only one digit, you do not need to specify a count as 1 is default:
/^[0-9]$/.test(message)
I assume you mean you want to match a single digit between 0 and 10. If not please comment to clarify.
Hope this helps.
Assuming you only want integers or whole numbers, then use:
/^(?:[0-9]|10)$/
If you want to allow for decimals, then use:
/^(?:[0-9](?:\.\d+)?|10(?:\.0+)?)$/
The second regex says to match:
^ from the start of the number
(?:
[0-9] 0 to 9
(?:\.\d+)? any optional decimal component
| OR
10 match integer 10
(?:\.0+)? optional zero decimal only
)
$ end of the number
This question already has answers here:
Regex decimal values between 0 and 1 up to 4 decimal places
(2 answers)
Closed 2 years ago.
I basically want a regex for alpha in RGBA which is always a positive number between 0 & 1. However, I want it to only be upto 2 digits like 0.53 & not more than that like 0.536.
Allowed
Anything between 0 to 1 but only upto 2 decimal places
0
0.0
0.00
0.1
0.12
0.34
1
1.0
1.00
Not Allowed
Anything outside of 0 to 1 & if its between 0 to 1 then it should be less than or equal to 2 decimal places only & even signs not allowed
0.123
90
3
-1
+1
I noticed other similar questions but they allow signs or they allow more than 2 decimal places.
Currently, I have a regex like /^(0+\.?|0*\.\d+|0*1(\.0*)?)$/ which allows for more than 2 decimal places. How do I solve it?
You may use:
^(?:0(?:\.[0-9]{1,2})?|1(?:\.00?)?)$
RegEx Demo
RegEx Details:
^: Start
(?:: Start a non-capture group
0: Match 0
(?:\.[0-9]{1,2})?: Match optional dot followed by 1 or 2 digits
|: OR
1: Match 1
(?:\.00?)?: Match optional 1 or 2 zeroes after dot
): End non-capture group
$: End
Alternatively, try:
^(?!1..?[1-9])[01](?:\.\d\d?)?$
See the online demo
^ - Start string anchor.
(?! - Open negative lookahead:
1..? - A literal "1" followed by any character other than newline and an optional one.
[1-9]- Match a digit ranging from 1-9.
) - Close negative lookahead.
[01] - Match a zero or one.
(?: - Open non-capture group:
\.\d\d? - Match a literal dot, a single digit and an optional one.
)? - Close non-capturing group and make it optional.
$ - End string anchor.
What is regex for age with 2 decimal points value with max value 99.11
Valid examples:
1
12.01
16.06
20.11
Invalid examples:
.0
1.12 (decimal value should be <12)
1.13 (decimal value should be <12)
12.111
100.00 (2 digit before decimal point, max 99.11)
I have tried ^[0-9]\d{0,1}(\.\d[0-1]\d{0,1})*(,\d+)?$ regex but it is not following all criteria.
can anyone help me?
You can try with this pattern:
/^\d{1,2}(\.(0[0-9]|1[01]))?$/
var pattern = /^\d{1,2}(\.(0[0-9]|1[01]))?$/;
console.log(pattern.test('1'));
console.log(pattern.test('12.01'));
console.log(pattern.test('16.06'));
console.log(pattern.test('20.11'));
console.log(pattern.test('.0'));
console.log(pattern.test('1.12'));
console.log(pattern.test('1.13'));
console.log(pattern.test('12.111'));
console.log(pattern.test('100.00'));
Try this.
/^\d\d?(\.(0\d|1[01]))?$/
Description:
^\d\d? - from the start of the string, match 1 or 2 numbers
After that/those numbers, optionally match . plus 2 numbers
The two numbers must be 0 and any number, else 1 and 0 or 1
Anchor to the end of the string
You are missing the two different patterns of floating part, which must be handled with a |.
A character-optimal solution is ^\d{1,2}(\.[0]\d|\.1[01])?$.
i want a regular expression for length limit 10 digit with 2 decimal place numbers with only numbers allowed.10 digit before decimal
allowed
1
1111111111
111
1111111111.22
.2
1.2
1.22
Not allowed
4.
.
-1
abc
Null
Emptystring
""
1.222
-1.22
111111111111
tried but not working
^[0-9]*(\.[0-9]{0,2})?$
You're almost there - all you have to do is include a check that the string is not empty (which can be accomplished with a positive lookahead for .{1,10} right after the ^), and check that its first digit string has at most 10 characters (just use a {0,10} quantifier for the digits). Also note that [0-9] simplifies to \d.
In order to also exclude trailing dots, repeat the digit after the dot with {1,2} instead of {0,2}:
^(?!$)\d{0,10}(?:\.\d{1,2})?$
https://regex101.com/r/Ah8dNu/5
I have also prepared below RegEx.
Seems this will also work.
^[0-9]{1,10}((\.)[0-9]{0,2}){0,1}$
I'm trying to build a regex expression for numbers, only separated with dot, comma is forbidden.
I've tried this code
^(\d+|\d+\.\d{1,4})[1-5]$
but it doesn't help for this rules:
minimum: one number 1 to 9
maxmimum: five numbers 0.0001 or 12345
range: 0.0001 to 99999
allowed examples:
12345
1234.1
123.12
12.345
1.2345 1
0.1
0.01
0.001
0.0001
thanks
You could try the below regex. Negative lookahead at the start asserts that there isn't 99999.<any-num> or only 0.one or more zeros present.
^(?!99999\.\d|0+(?:\.0+)?$)\d{1,5}(?:\.\d{1,4})?$
DEMO