How to postback to a different form using javascript - javascript

I have a form with a textbox in it, I want to submit the value of the textbox to another page after an ajax call is successfully made, how can I achieve this?
This is my ajax method:
$.ajax({
type: "POST",
contentType: "application/json; charset=utf-8",
dataType: "json",
url: "http://test.net/getData",
data: "{some:data}",
success: function (response) {
document.forms.form1.txtData.value = "value1";
document.forms.form1.submit();
},
error: function (response) {
alert("error");
}
});
and then I have my form in page Page1 as:
<form id="form1" runat="server">
<input type="hidden" id="txtData" value="" runat="server" />
</form>
But this will send my data back to the original page (Page1) not to Page2 form.

You can specify action url in action attribute of form.
Take look on documentation
<form id="form1" runat="server" action="Page2.aspx">
<input type="hidden" id="txtData" value="" runat="server" />
</form>

You can use query string, this will redirect to another page with your textvalue
success: function (response) {
var value=response.d
// document.forms.form1.txtData.value = "value1";
// document.forms.form1.submit();
window.location = "http://YourPageName.aspx?id="+value;
}
Code Behind:
On page load you can retrieve the value by using Request.QueryString
if (Request.QueryString["id"] != null)
{
string getTxtValue = Request.QueryString["id"].ToString();
}

You can set the 'action' attribute of the form to action name you need and then submit the form, e.g. like this.
success: function (response) {
var $form = $("#form1");
$form.attr("action", "your-action-name");
$form.submit();
},
About HTML action Attribute

Related

Submit form array fields using Ajax [duplicate]

I have a form with name orderproductForm and an undefined number of inputs.
I want to do some kind of jQuery.get or ajax or anything like that that would call a page through Ajax, and send along all the inputs of the form orderproductForm.
I suppose one way would be to do something like
jQuery.get("myurl",
{action : document.orderproductForm.action.value,
cartproductid : document.orderproductForm.cartproductid.value,
productid : document.orderproductForm.productid.value,
...
However I do not know exactly all the form inputs. Is there a feature, function or something that would just send ALL the form inputs?
This is a simple reference:
// this is the id of the form
$("#idForm").submit(function(e) {
e.preventDefault(); // avoid to execute the actual submit of the form.
var form = $(this);
var actionUrl = form.attr('action');
$.ajax({
type: "POST",
url: actionUrl,
data: form.serialize(), // serializes the form's elements.
success: function(data)
{
alert(data); // show response from the php script.
}
});
});
You can use the ajaxForm/ajaxSubmit functions from Ajax Form Plugin or the jQuery serialize function.
AjaxForm:
$("#theForm").ajaxForm({url: 'server.php', type: 'post'})
or
$("#theForm").ajaxSubmit({url: 'server.php', type: 'post'})
ajaxForm will send when the submit button is pressed. ajaxSubmit sends immediately.
Serialize:
$.get('server.php?' + $('#theForm').serialize())
$.post('server.php', $('#theForm').serialize())
AJAX serialization documentation is here.
Another similar solution using attributes defined on the form element:
<form id="contactForm1" action="/your_url" method="post">
<!-- Form input fields here (do not forget your name attributes). -->
</form>
<script type="text/javascript">
var frm = $('#contactForm1');
frm.submit(function (e) {
e.preventDefault();
$.ajax({
type: frm.attr('method'),
url: frm.attr('action'),
data: frm.serialize(),
success: function (data) {
console.log('Submission was successful.');
console.log(data);
},
error: function (data) {
console.log('An error occurred.');
console.log(data);
},
});
});
</script>
There are a few things you need to bear in mind.
1. There are several ways to submit a form
using the submit button
by pressing enter
by triggering a submit event in JavaScript
possibly more depending on the device or future device.
We should therefore bind to the form submit event, not the button click event. This will ensure our code works on all devices and assistive technologies now and in the future.
2. Hijax
The user may not have JavaScript enabled. A hijax pattern is good here, where we gently take control of the form using JavaScript, but leave it submittable if JavaScript fails.
We should pull the URL and method from the form, so if the HTML changes, we don't need to update the JavaScript.
3. Unobtrusive JavaScript
Using event.preventDefault() instead of return false is good practice as it allows the event to bubble up. This lets other scripts tie into the event, for example analytics scripts which may be monitoring user interactions.
Speed
We should ideally use an external script, rather than inserting our script inline. We can link to this in the head section of the page using a script tag, or link to it at the bottom of the page for speed. The script should quietly enhance the user experience, not get in the way.
Code
Assuming you agree with all the above, and you want to catch the submit event, and handle it via AJAX (a hijax pattern), you could do something like this:
$(function() {
$('form.my_form').submit(function(event) {
event.preventDefault(); // Prevent the form from submitting via the browser
var form = $(this);
$.ajax({
type: form.attr('method'),
url: form.attr('action'),
data: form.serialize()
}).done(function(data) {
// Optionally alert the user of success here...
}).fail(function(data) {
// Optionally alert the user of an error here...
});
});
});
You can manually trigger a form submission whenever you like via JavaScript using something like:
$(function() {
$('form.my_form').trigger('submit');
});
Edit:
I recently had to do this and ended up writing a plugin.
(function($) {
$.fn.autosubmit = function() {
this.submit(function(event) {
event.preventDefault();
var form = $(this);
$.ajax({
type: form.attr('method'),
url: form.attr('action'),
data: form.serialize()
}).done(function(data) {
// Optionally alert the user of success here...
}).fail(function(data) {
// Optionally alert the user of an error here...
});
});
return this;
}
})(jQuery)
Add a data-autosubmit attribute to your form tag and you can then do this:
HTML
<form action="/blah" method="post" data-autosubmit>
<!-- Form goes here -->
</form>
JS
$(function() {
$('form[data-autosubmit]').autosubmit();
});
You can also use FormData (But not available in IE):
var formData = new FormData(document.getElementsByName('yourForm')[0]);// yourForm: form selector
$.ajax({
type: "POST",
url: "yourURL",// where you wanna post
data: formData,
processData: false,
contentType: false,
error: function(jqXHR, textStatus, errorMessage) {
console.log(errorMessage); // Optional
},
success: function(data) {console.log(data)}
});
This is how you use FormData.
Simple version (does not send images)
<form action="/my/ajax/url" class="my-form">
...
</form>
<script>
(function($){
$("body").on("submit", ".my-form", function(e){
e.preventDefault();
var form = $(e.target);
$.post( form.attr("action"), form.serialize(), function(res){
console.log(res);
});
});
)(jQuery);
</script>
Copy and paste ajaxification of a form or all forms on a page
It is a modified version of Alfrekjv's answer
It will work with jQuery >= 1.3.2
You can run this before the document is ready
You can remove and re-add the form and it will still work
It will post to the same location as the normal form, specified in
the form's "action" attribute
JavaScript
jQuery(document).submit(function(e){
var form = jQuery(e.target);
if(form.is("#form-id")){ // check if this is the form that you want (delete this check to apply this to all forms)
e.preventDefault();
jQuery.ajax({
type: "POST",
url: form.attr("action"),
data: form.serialize(), // serializes the form's elements.
success: function(data) {
console.log(data); // show response from the php script. (use the developer toolbar console, firefox firebug or chrome inspector console)
}
});
}
});
I wanted to edit Alfrekjv's answer but deviated too much from it so decided to post this as a separate answer.
Does not send files, does not support buttons, for example clicking a button (including a submit button) sends its value as form data, but because this is an ajax request the button click will not be sent.
To support buttons you can capture the actual button click instead of the submit.
jQuery(document).click(function(e){
var self = jQuery(e.target);
if(self.is("#form-id input[type=submit], #form-id input[type=button], #form-id button")){
e.preventDefault();
var form = self.closest('form'), formdata = form.serialize();
//add the clicked button to the form data
if(self.attr('name')){
formdata += (formdata!=='')? '&':'';
formdata += self.attr('name') + '=' + ((self.is('button'))? self.html(): self.val());
}
jQuery.ajax({
type: "POST",
url: form.attr("action"),
data: formdata,
success: function(data) {
console.log(data);
}
});
}
});
On the server side you can detect an ajax request with this header that jquery sets HTTP_X_REQUESTED_WITH
for php
PHP
if(!empty($_SERVER['HTTP_X_REQUESTED_WITH']) && strtolower($_SERVER['HTTP_X_REQUESTED_WITH']) == 'xmlhttprequest') {
//is ajax
}
This code works even with file input
$(document).on("submit", "form", function(event)
{
event.preventDefault();
$.ajax({
url: $(this).attr("action"),
type: $(this).attr("method"),
dataType: "JSON",
data: new FormData(this),
processData: false,
contentType: false,
success: function (data, status)
{
},
error: function (xhr, desc, err)
{
}
});
});
I really liked this answer by superluminary and especially the way he wrapped is solution in a jQuery plugin. So thanks to superluminary for a very useful answer. In my case, though, I wanted a plugin that would allow me to define the success and error event handlers by means of options when the plugin is initialized.
So here is what I came up with:
;(function(defaults, $, undefined) {
var getSubmitHandler = function(onsubmit, success, error) {
return function(event) {
if (typeof onsubmit === 'function') {
onsubmit.call(this, event);
}
var form = $(this);
$.ajax({
type: form.attr('method'),
url: form.attr('action'),
data: form.serialize()
}).done(function() {
if (typeof success === 'function') {
success.apply(this, arguments);
}
}).fail(function() {
if (typeof error === 'function') {
error.apply(this, arguments);
}
});
event.preventDefault();
};
};
$.fn.extend({
// Usage:
// jQuery(selector).ajaxForm({
// onsubmit:function() {},
// success:function() {},
// error: function() {}
// });
ajaxForm : function(options) {
options = $.extend({}, defaults, options);
return $(this).each(function() {
$(this).submit(getSubmitHandler(options['onsubmit'], options['success'], options['error']));
});
}
});
})({}, jQuery);
This plugin allows me to very easily "ajaxify" html forms on the page and provide onsubmit, success and error event handlers for implementing feedback to the user of the status of the form submit. This allowed the plugin to be used as follows:
$('form').ajaxForm({
onsubmit: function(event) {
// User submitted the form
},
success: function(data, textStatus, jqXHR) {
// The form was successfully submitted
},
error: function(jqXHR, textStatus, errorThrown) {
// The submit action failed
}
});
Note that the success and error event handlers receive the same arguments that you would receive from the corresponding events of the jQuery ajax method.
I got the following for me:
formSubmit('#login-form', '/api/user/login', '/members/');
where
function formSubmit(form, url, target) {
$(form).submit(function(event) {
$.post(url, $(form).serialize())
.done(function(res) {
if (res.success) {
window.location = target;
}
else {
alert(res.error);
}
})
.fail(function(res) {
alert("Server Error: " + res.status + " " + res.statusText);
})
event.preventDefault();
});
}
This assumes the post to 'url' returns an ajax in the form of {success: false, error:'my Error to display'}
You can vary this as you like. Feel free to use that snippet.
jQuery AJAX submit form, is nothing but submit a form using form ID when you click on a button
Please follow steps
Step 1 - Form tag must have an ID field
<form method="post" class="form-horizontal" action="test/user/add" id="submitForm">
.....
</form>
Button which you are going to click
<button>Save</button>
Step 2 - submit event is in jQuery which helps to submit a form. in below code we are preparing JSON request from HTML element name.
$("#submitForm").submit(function(e) {
e.preventDefault();
var frm = $("#submitForm");
var data = {};
$.each(this, function(i, v){
var input = $(v);
data[input.attr("name")] = input.val();
delete data["undefined"];
});
$.ajax({
contentType:"application/json; charset=utf-8",
type:frm.attr("method"),
url:frm.attr("action"),
dataType:'json',
data:JSON.stringify(data),
success:function(data) {
alert(data.message);
}
});
});
for live demo click on below link
How to submit a Form using jQuery AJAX?
I know this is a jQuery related question, but now days with JS ES6 things are much easier. Since there is no pure javascript answer, I thought I could add a simple pure javascript solution to this, which in my opinion is much cleaner, by using the fetch() API. This a modern way to implements network requests. In your case, since you already have a form element we can simply use it to build our request.
const form = document.forms["orderproductForm"];
const formInputs = form.getElementsByTagName("input");
let formData = new FormData();
for (let input of formInputs) {
formData.append(input.name, input.value);
}
fetch(form.action,
{
method: form.method,
body: formData
})
.then(response => response.json())
.then(data => console.log(data))
.catch(error => console.log(error.message))
.finally(() => console.log("Done"));
Try
fetch(form.action,{method:'post', body: new FormData(form)});
function send(e,form) {
fetch(form.action,{method:'post', body: new FormData(form)});
console.log('We submit form asynchronously (AJAX)');
e.preventDefault();
}
<form method="POST" action="myapi/send" onsubmit="send(event,this)" name="orderproductForm">
<input hidden name="csrfToken" value="$0meh#$h">
<input name="email" value="aa#bb.com">
<input name="phone" value="123-456-666">
<input type="submit">
</form>
Look on Chrome Console > Network after/before 'submit'
consider using closest
$('table+table form').closest('tr').filter(':not(:last-child)').submit(function (ev, frm) {
frm = $(ev.target).closest('form');
$.ajax({
type: frm.attr('method'),
url: frm.attr('action'),
data: frm.serialize(),
success: function (data) {
alert(data);
}
})
ev.preventDefault();
});
You may use this on submit function like below.
HTML Form
<form class="form" action="" method="post">
<input type="text" name="name" id="name" >
<textarea name="text" id="message" placeholder="Write something to us"> </textarea>
<input type="button" onclick="return formSubmit();" value="Send">
</form>
jQuery function:
<script>
function formSubmit(){
var name = document.getElementById("name").value;
var message = document.getElementById("message").value;
var dataString = 'name='+ name + '&message=' + message;
jQuery.ajax({
url: "submit.php",
data: dataString,
type: "POST",
success: function(data){
$("#myForm").html(data);
},
error: function (){}
});
return true;
}
</script>
For more details and sample Visit:
http://www.spiderscode.com/simple-ajax-contact-form/
To avoid multiple formdata sends:
Don't forget to unbind submit event, before the form submited again,
User can call sumbit function more than one time, maybe he forgot something, or was a validation error.
$("#idForm").unbind().submit( function(e) {
....
If you're using form.serialize() - you need to give each form element a name like this:
<input id="firstName" name="firstName" ...
And the form gets serialized like this:
firstName=Chris&lastName=Halcrow ...
I find it surprising that no one mentions data as an object. For me it's the cleanest and easiest way to pass data:
$('form#foo').submit(function () {
$.ajax({
url: 'http://foo.bar/some-ajax-script',
type: 'POST',
dataType: 'json',
data: {
'foo': 'some-foo-value',
'bar': $('#bar').val()
}
}).always(function (response) {
console.log(response);
});
return false;
});
Then, in the backend:
// Example in PHP
$_POST['foo'] // some-foo-value
$_POST['bar'] // value in #bar
This is not the answer to OP's question,
but in case if you can't use static form DOM, you can also try like this.
var $form = $('<form/>').append(
$('<input/>', {name: 'username'}).val('John Doe'),
$('<input/>', {name: 'user_id'}).val('john.1234')
);
$.ajax({
url: 'api/user/search',
type: 'POST',
contentType: 'application/x-www-form-urlencoded',
data: $form.serialize(),
success: function(data, textStatus, jqXHR) {
console.info(data);
},
error: function(jqXHR, textStatus, errorThrown) {
var errorMessage = jqXHR.responseText;
if (errorMessage.length > 0) {
alert(errorMessage);
}
}
});
JavaScript
(function ($) {
var form= $('#add-form'),
input = $('#exampleFormControlTextarea1');
form.submit(function(event) {
event.preventDefault();
var req = $.ajax({
url: form.attr('action'),
type: 'POST',
data: form.serialize()
});
req.done(function(data) {
if (data === 'success') {
var li = $('<li class="list-group-item">'+ input.val() +'</li>');
li.hide()
.appendTo('.list-group')
.fadeIn();
$('input[type="text"],textarea').val('');
}
});
});
}(jQuery));
HTML
<ul class="list-group col-sm-6 float-left">
<?php
foreach ($data as $item) {
echo '<li class="list-group-item">'.$item.'</li>';
}
?>
</ul>
<form id="add-form" class="col-sm-6 float-right" action="_inc/add-new.php" method="post">
<p class="form-group">
<textarea class="form-control" name="message" id="exampleFormControlTextarea1" rows="3" placeholder="Is there something new?"></textarea>
</p>
<button type="submit" class="btn btn-danger">Add new item</button>
</form>
There's also the submit event, which can be triggered like this $("#form_id").submit(). You'd use this method if the form is well represented in HTML already. You'd just read in the page, populate the form inputs with stuff, then call .submit(). It'll use the method and action defined in the form's declaration, so you don't need to copy it into your javascript.
examples

On button click send Ajax call and get value from aspx.cs(code behind) to aspx page and display it in input field in the same page

I am new to AJAX and have stuck in a problem, I want to send AJAX CALL on button click, while button clicking the value of input field is sent to aspx.cs (code behind) page and response should be get and I try to show that response to that same input field but it's not working.
ASPX CODE:
<input type="text" class="wpcf7-text" id="d_id" name="d_id" runat="server"> // this id is sent to the Read_Driver_Account funtion and on response it is sending the driver cell number which i want to display in the driver cell number imput field
<input class="wpcf7-text" id="driver_cell" name="driver_cell" runat="server">
<asp:Button ID="btnn1" OnClick="Read_Driver_Account" runat="server" Text="Get"/>
<script>
$("btnn1").click(function (e) {
e.preventDefault();
$.ajax({
type: "POST",
url: "/Udate_Driver_Account/", //Udate_Driver_Account.aspx file is placed in VisualStudio/Websites/Fp/Udate_Driver_Account.aspx, where Fp is name of my website.
data: {
id: $(this).val(),
driver_cell: $("#drivercel").val()
},
success: function (result) {
alert('ok');
},
error: function (result) {
alert('error');
}
});
});
</script>
ASPX.CS CODE:
public string drivercel;
protected void Read_Driver_Account(object sender, EventArgs e)
{
var alldata = d_id.Value;
string driveradres = tokens[7];
string drivercel = tokens[8]; // i want to set this value to the input field id="driver_cell"
}
Note: tokens[8] is a value coming from a live database it's not a static value;
Also i want to set more than one values to more than one input fields.
The JQuery selector you used should be $("#btnn1") instead of $("btnn1"). Then the ajax url should be /pageName/webMethod like /Udate_Driver_Account.aspx/Read_Driver_Account.
And use JSON.stringify to send the data as data: JSON.stringify({ id: $(this).val(), driver_cell: $("#drivercel").val() }).
Add contentType: "application/json; charset=utf-8" to send the data as json and dataType: "json" to get the response data as json.
<input class="wpcf7-text" id="driver_cell" name="driver_cell" runat="server">
<asp:Button ID="btnn1" OnClick="Read_Driver_Account" runat="server" Text="Get"/>
<script>
$("#btnn1").click(function (e) {
e.preventDefault();
$.ajax({
type: "POST",
url: "/Udate_Driver_Account.aspx/Read_Driver_Account", //Udate_Driver_Account.aspx file is placed in VisualStudio/Websites/Fp/Udate_Driver_Account.aspx, where Fp is name of my website.
data: JSON.stringify({
id: $(this).val(),
driver_cell: $("#drivercel").val()
}),
contentType: "application/json; charset=utf-8",
dataType: "json",
success: function (result) {
alert(result);
// $("#drivercel").val(result.d);
},
error: function (result) {
alert('error');
}
});
});
</script>
Then mark your method with WebMethod attribute and make it as public static with parameter name same as the data json above.
public string drivercel;
[System.Web.Services.WebMethod]
public static string Read_Driver_Account(string id, string driver_cell)
{
string drivercel = tokens[8]; // i want to set this value to the input field id="driver_cell"
return drivercel;
}
Note: As you used the asp:Button id directly in JQuery selector, you should add ClientIDMode="Static" property to the button as below to use the same id in client side (OR add the same in Page directive). Otherwise, the button will have different dynamic id in client side and the JQuery click event won't get fired.
<asp:Button ID="btnn1" ClientIDMode="Static" OnClick="Read_Driver_Account" runat="server" Text="Get"/>

Response from Servlet page is shown in new page

I am using Ajax and jQuery to submit a dynamic form.
It works fine, but the response from Servlet is shown in a new page.
function call(formid) {
alert(formid);
var form = $(formid); // id of form tag
form.submit(function () {
$.ajax({
type: form.attr('method'), //post method
url: form.attr('action'), //ajaxformexample url
data: form.serialize(), // serialize input data values
success: function (data) {
var result=data;
$('#content').html(result); //showing result
}
});
return false; // not refreshing page
});
}
How I can show response from Servlet in same page?
(out.println("<br/>Massage = "+message+"<br/>"););
You are experiencing this because you are not stopping what a form submit does:
So, according to .submit( handler ) change your line:
form.submit(function () {
to:
form.submit(function (e) {
e.preventDefault(); // stop form submit and do your ajax call
UPDATE
According to your comment I suggest you to try the following code:
function submitFrm(obj, e) {
e.preventDefault();
var form = $(obj).closest('form'); // id of form tag related to the current button
var formid = form.attr('id');
alert(formid);
$.ajax({
type: form.attr('method'), //post method
url: form.attr('action'), //ajaxformexample url
data: form.serialize(), // serialize input data values
success: function (data) {
var result=data;
$('#content').html(result); //showing result
}
});
}
<script src="https://code.jquery.com/jquery-1.12.4.min.js"></script>
<form id="formid">
First name:<br>
<input type="text" name="firstname"><br>
Last name:<br>
<input type="text" name="lastname">
<input type="submit" value="Submit" onclick="submitFrm(this, event);">
</form>

How can I loop over form data using serialized (jQuery / Ajax)

I'm trying to get post id and insert it into database after user click on add to favorite button.
The problem that all the post are return id 30 which is the last id in the database.
My php/html code
while($row = mysqli_fetch_array($get_posts)) {
<i style="float:right;" class="fa fa-pinterest-square">
<form id="pin_post" method="post"> ';
if (isset($_SESSION['user_id'])){
<input type="hidden" value="'. $_SESSION['user_id'].'" name="user_id" />
}
<input type="hidden" value="'.$row['post_id'].'" name="post_id[]" />
</form>
</i>
The jQuery / Ajax code
<script>
$(document).on("click",".fa-pinterest-square",function(e) {
$.ajax({
url: "includes/test.php",
type: "POST",
data: $('#pin_post').serialize(),
success: function(data) {
alert(data);
}
});
});
</script>
I'm getting last id in the database when I click any post.
Please help me to get the id of each post when I click on the
Since you are using #pin_post when serializing it you will get the last hit when jQuery is looking for #pin_post. Either you should use a unique id or something like this
$(document).on("click",".fa-pinterest-square",function(e) {
var form = $(this).find('form'); //Since the form is child to <i>
$.ajax({
url: "includes/test.php",
type: "POST",
data: form.serialize(),
success: function(data) {
alert(data);
}
});
});

jQuery AJAX submit form

I have a form with name orderproductForm and an undefined number of inputs.
I want to do some kind of jQuery.get or ajax or anything like that that would call a page through Ajax, and send along all the inputs of the form orderproductForm.
I suppose one way would be to do something like
jQuery.get("myurl",
{action : document.orderproductForm.action.value,
cartproductid : document.orderproductForm.cartproductid.value,
productid : document.orderproductForm.productid.value,
...
However I do not know exactly all the form inputs. Is there a feature, function or something that would just send ALL the form inputs?
This is a simple reference:
// this is the id of the form
$("#idForm").submit(function(e) {
e.preventDefault(); // avoid to execute the actual submit of the form.
var form = $(this);
var actionUrl = form.attr('action');
$.ajax({
type: "POST",
url: actionUrl,
data: form.serialize(), // serializes the form's elements.
success: function(data)
{
alert(data); // show response from the php script.
}
});
});
You can use the ajaxForm/ajaxSubmit functions from Ajax Form Plugin or the jQuery serialize function.
AjaxForm:
$("#theForm").ajaxForm({url: 'server.php', type: 'post'})
or
$("#theForm").ajaxSubmit({url: 'server.php', type: 'post'})
ajaxForm will send when the submit button is pressed. ajaxSubmit sends immediately.
Serialize:
$.get('server.php?' + $('#theForm').serialize())
$.post('server.php', $('#theForm').serialize())
AJAX serialization documentation is here.
Another similar solution using attributes defined on the form element:
<form id="contactForm1" action="/your_url" method="post">
<!-- Form input fields here (do not forget your name attributes). -->
</form>
<script type="text/javascript">
var frm = $('#contactForm1');
frm.submit(function (e) {
e.preventDefault();
$.ajax({
type: frm.attr('method'),
url: frm.attr('action'),
data: frm.serialize(),
success: function (data) {
console.log('Submission was successful.');
console.log(data);
},
error: function (data) {
console.log('An error occurred.');
console.log(data);
},
});
});
</script>
There are a few things you need to bear in mind.
1. There are several ways to submit a form
using the submit button
by pressing enter
by triggering a submit event in JavaScript
possibly more depending on the device or future device.
We should therefore bind to the form submit event, not the button click event. This will ensure our code works on all devices and assistive technologies now and in the future.
2. Hijax
The user may not have JavaScript enabled. A hijax pattern is good here, where we gently take control of the form using JavaScript, but leave it submittable if JavaScript fails.
We should pull the URL and method from the form, so if the HTML changes, we don't need to update the JavaScript.
3. Unobtrusive JavaScript
Using event.preventDefault() instead of return false is good practice as it allows the event to bubble up. This lets other scripts tie into the event, for example analytics scripts which may be monitoring user interactions.
Speed
We should ideally use an external script, rather than inserting our script inline. We can link to this in the head section of the page using a script tag, or link to it at the bottom of the page for speed. The script should quietly enhance the user experience, not get in the way.
Code
Assuming you agree with all the above, and you want to catch the submit event, and handle it via AJAX (a hijax pattern), you could do something like this:
$(function() {
$('form.my_form').submit(function(event) {
event.preventDefault(); // Prevent the form from submitting via the browser
var form = $(this);
$.ajax({
type: form.attr('method'),
url: form.attr('action'),
data: form.serialize()
}).done(function(data) {
// Optionally alert the user of success here...
}).fail(function(data) {
// Optionally alert the user of an error here...
});
});
});
You can manually trigger a form submission whenever you like via JavaScript using something like:
$(function() {
$('form.my_form').trigger('submit');
});
Edit:
I recently had to do this and ended up writing a plugin.
(function($) {
$.fn.autosubmit = function() {
this.submit(function(event) {
event.preventDefault();
var form = $(this);
$.ajax({
type: form.attr('method'),
url: form.attr('action'),
data: form.serialize()
}).done(function(data) {
// Optionally alert the user of success here...
}).fail(function(data) {
// Optionally alert the user of an error here...
});
});
return this;
}
})(jQuery)
Add a data-autosubmit attribute to your form tag and you can then do this:
HTML
<form action="/blah" method="post" data-autosubmit>
<!-- Form goes here -->
</form>
JS
$(function() {
$('form[data-autosubmit]').autosubmit();
});
You can also use FormData (But not available in IE):
var formData = new FormData(document.getElementsByName('yourForm')[0]);// yourForm: form selector
$.ajax({
type: "POST",
url: "yourURL",// where you wanna post
data: formData,
processData: false,
contentType: false,
error: function(jqXHR, textStatus, errorMessage) {
console.log(errorMessage); // Optional
},
success: function(data) {console.log(data)}
});
This is how you use FormData.
Simple version (does not send images)
<form action="/my/ajax/url" class="my-form">
...
</form>
<script>
(function($){
$("body").on("submit", ".my-form", function(e){
e.preventDefault();
var form = $(e.target);
$.post( form.attr("action"), form.serialize(), function(res){
console.log(res);
});
});
)(jQuery);
</script>
Copy and paste ajaxification of a form or all forms on a page
It is a modified version of Alfrekjv's answer
It will work with jQuery >= 1.3.2
You can run this before the document is ready
You can remove and re-add the form and it will still work
It will post to the same location as the normal form, specified in
the form's "action" attribute
JavaScript
jQuery(document).submit(function(e){
var form = jQuery(e.target);
if(form.is("#form-id")){ // check if this is the form that you want (delete this check to apply this to all forms)
e.preventDefault();
jQuery.ajax({
type: "POST",
url: form.attr("action"),
data: form.serialize(), // serializes the form's elements.
success: function(data) {
console.log(data); // show response from the php script. (use the developer toolbar console, firefox firebug or chrome inspector console)
}
});
}
});
I wanted to edit Alfrekjv's answer but deviated too much from it so decided to post this as a separate answer.
Does not send files, does not support buttons, for example clicking a button (including a submit button) sends its value as form data, but because this is an ajax request the button click will not be sent.
To support buttons you can capture the actual button click instead of the submit.
jQuery(document).click(function(e){
var self = jQuery(e.target);
if(self.is("#form-id input[type=submit], #form-id input[type=button], #form-id button")){
e.preventDefault();
var form = self.closest('form'), formdata = form.serialize();
//add the clicked button to the form data
if(self.attr('name')){
formdata += (formdata!=='')? '&':'';
formdata += self.attr('name') + '=' + ((self.is('button'))? self.html(): self.val());
}
jQuery.ajax({
type: "POST",
url: form.attr("action"),
data: formdata,
success: function(data) {
console.log(data);
}
});
}
});
On the server side you can detect an ajax request with this header that jquery sets HTTP_X_REQUESTED_WITH
for php
PHP
if(!empty($_SERVER['HTTP_X_REQUESTED_WITH']) && strtolower($_SERVER['HTTP_X_REQUESTED_WITH']) == 'xmlhttprequest') {
//is ajax
}
This code works even with file input
$(document).on("submit", "form", function(event)
{
event.preventDefault();
$.ajax({
url: $(this).attr("action"),
type: $(this).attr("method"),
dataType: "JSON",
data: new FormData(this),
processData: false,
contentType: false,
success: function (data, status)
{
},
error: function (xhr, desc, err)
{
}
});
});
I really liked this answer by superluminary and especially the way he wrapped is solution in a jQuery plugin. So thanks to superluminary for a very useful answer. In my case, though, I wanted a plugin that would allow me to define the success and error event handlers by means of options when the plugin is initialized.
So here is what I came up with:
;(function(defaults, $, undefined) {
var getSubmitHandler = function(onsubmit, success, error) {
return function(event) {
if (typeof onsubmit === 'function') {
onsubmit.call(this, event);
}
var form = $(this);
$.ajax({
type: form.attr('method'),
url: form.attr('action'),
data: form.serialize()
}).done(function() {
if (typeof success === 'function') {
success.apply(this, arguments);
}
}).fail(function() {
if (typeof error === 'function') {
error.apply(this, arguments);
}
});
event.preventDefault();
};
};
$.fn.extend({
// Usage:
// jQuery(selector).ajaxForm({
// onsubmit:function() {},
// success:function() {},
// error: function() {}
// });
ajaxForm : function(options) {
options = $.extend({}, defaults, options);
return $(this).each(function() {
$(this).submit(getSubmitHandler(options['onsubmit'], options['success'], options['error']));
});
}
});
})({}, jQuery);
This plugin allows me to very easily "ajaxify" html forms on the page and provide onsubmit, success and error event handlers for implementing feedback to the user of the status of the form submit. This allowed the plugin to be used as follows:
$('form').ajaxForm({
onsubmit: function(event) {
// User submitted the form
},
success: function(data, textStatus, jqXHR) {
// The form was successfully submitted
},
error: function(jqXHR, textStatus, errorThrown) {
// The submit action failed
}
});
Note that the success and error event handlers receive the same arguments that you would receive from the corresponding events of the jQuery ajax method.
I got the following for me:
formSubmit('#login-form', '/api/user/login', '/members/');
where
function formSubmit(form, url, target) {
$(form).submit(function(event) {
$.post(url, $(form).serialize())
.done(function(res) {
if (res.success) {
window.location = target;
}
else {
alert(res.error);
}
})
.fail(function(res) {
alert("Server Error: " + res.status + " " + res.statusText);
})
event.preventDefault();
});
}
This assumes the post to 'url' returns an ajax in the form of {success: false, error:'my Error to display'}
You can vary this as you like. Feel free to use that snippet.
jQuery AJAX submit form, is nothing but submit a form using form ID when you click on a button
Please follow steps
Step 1 - Form tag must have an ID field
<form method="post" class="form-horizontal" action="test/user/add" id="submitForm">
.....
</form>
Button which you are going to click
<button>Save</button>
Step 2 - submit event is in jQuery which helps to submit a form. in below code we are preparing JSON request from HTML element name.
$("#submitForm").submit(function(e) {
e.preventDefault();
var frm = $("#submitForm");
var data = {};
$.each(this, function(i, v){
var input = $(v);
data[input.attr("name")] = input.val();
delete data["undefined"];
});
$.ajax({
contentType:"application/json; charset=utf-8",
type:frm.attr("method"),
url:frm.attr("action"),
dataType:'json',
data:JSON.stringify(data),
success:function(data) {
alert(data.message);
}
});
});
for live demo click on below link
How to submit a Form using jQuery AJAX?
Try
fetch(form.action,{method:'post', body: new FormData(form)});
function send(e,form) {
fetch(form.action,{method:'post', body: new FormData(form)});
console.log('We submit form asynchronously (AJAX)');
e.preventDefault();
}
<form method="POST" action="myapi/send" onsubmit="send(event,this)" name="orderproductForm">
<input hidden name="csrfToken" value="$0meh#$h">
<input name="email" value="aa#bb.com">
<input name="phone" value="123-456-666">
<input type="submit">
</form>
Look on Chrome Console > Network after/before 'submit'
I know this is a jQuery related question, but now days with JS ES6 things are much easier. Since there is no pure javascript answer, I thought I could add a simple pure javascript solution to this, which in my opinion is much cleaner, by using the fetch() API. This a modern way to implements network requests. In your case, since you already have a form element we can simply use it to build our request.
const form = document.forms["orderproductForm"];
const formInputs = form.getElementsByTagName("input");
let formData = new FormData();
for (let input of formInputs) {
formData.append(input.name, input.value);
}
fetch(form.action,
{
method: form.method,
body: formData
})
.then(response => response.json())
.then(data => console.log(data))
.catch(error => console.log(error.message))
.finally(() => console.log("Done"));
consider using closest
$('table+table form').closest('tr').filter(':not(:last-child)').submit(function (ev, frm) {
frm = $(ev.target).closest('form');
$.ajax({
type: frm.attr('method'),
url: frm.attr('action'),
data: frm.serialize(),
success: function (data) {
alert(data);
}
})
ev.preventDefault();
});
You may use this on submit function like below.
HTML Form
<form class="form" action="" method="post">
<input type="text" name="name" id="name" >
<textarea name="text" id="message" placeholder="Write something to us"> </textarea>
<input type="button" onclick="return formSubmit();" value="Send">
</form>
jQuery function:
<script>
function formSubmit(){
var name = document.getElementById("name").value;
var message = document.getElementById("message").value;
var dataString = 'name='+ name + '&message=' + message;
jQuery.ajax({
url: "submit.php",
data: dataString,
type: "POST",
success: function(data){
$("#myForm").html(data);
},
error: function (){}
});
return true;
}
</script>
For more details and sample Visit:
http://www.spiderscode.com/simple-ajax-contact-form/
To avoid multiple formdata sends:
Don't forget to unbind submit event, before the form submited again,
User can call sumbit function more than one time, maybe he forgot something, or was a validation error.
$("#idForm").unbind().submit( function(e) {
....
If you're using form.serialize() - you need to give each form element a name like this:
<input id="firstName" name="firstName" ...
And the form gets serialized like this:
firstName=Chris&lastName=Halcrow ...
I find it surprising that no one mentions data as an object. For me it's the cleanest and easiest way to pass data:
$('form#foo').submit(function () {
$.ajax({
url: 'http://foo.bar/some-ajax-script',
type: 'POST',
dataType: 'json',
data: {
'foo': 'some-foo-value',
'bar': $('#bar').val()
}
}).always(function (response) {
console.log(response);
});
return false;
});
Then, in the backend:
// Example in PHP
$_POST['foo'] // some-foo-value
$_POST['bar'] // value in #bar
This is not the answer to OP's question,
but in case if you can't use static form DOM, you can also try like this.
var $form = $('<form/>').append(
$('<input/>', {name: 'username'}).val('John Doe'),
$('<input/>', {name: 'user_id'}).val('john.1234')
);
$.ajax({
url: 'api/user/search',
type: 'POST',
contentType: 'application/x-www-form-urlencoded',
data: $form.serialize(),
success: function(data, textStatus, jqXHR) {
console.info(data);
},
error: function(jqXHR, textStatus, errorThrown) {
var errorMessage = jqXHR.responseText;
if (errorMessage.length > 0) {
alert(errorMessage);
}
}
});
JavaScript
(function ($) {
var form= $('#add-form'),
input = $('#exampleFormControlTextarea1');
form.submit(function(event) {
event.preventDefault();
var req = $.ajax({
url: form.attr('action'),
type: 'POST',
data: form.serialize()
});
req.done(function(data) {
if (data === 'success') {
var li = $('<li class="list-group-item">'+ input.val() +'</li>');
li.hide()
.appendTo('.list-group')
.fadeIn();
$('input[type="text"],textarea').val('');
}
});
});
}(jQuery));
HTML
<ul class="list-group col-sm-6 float-left">
<?php
foreach ($data as $item) {
echo '<li class="list-group-item">'.$item.'</li>';
}
?>
</ul>
<form id="add-form" class="col-sm-6 float-right" action="_inc/add-new.php" method="post">
<p class="form-group">
<textarea class="form-control" name="message" id="exampleFormControlTextarea1" rows="3" placeholder="Is there something new?"></textarea>
</p>
<button type="submit" class="btn btn-danger">Add new item</button>
</form>
There's also the submit event, which can be triggered like this $("#form_id").submit(). You'd use this method if the form is well represented in HTML already. You'd just read in the page, populate the form inputs with stuff, then call .submit(). It'll use the method and action defined in the form's declaration, so you don't need to copy it into your javascript.
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