Develop Reference

How to include a random PHP file from one folder together with a fitting JS and CSS file to one document? [duplicate]

I'm trying to make a site where users can submit photos, and then randomly view others photos one by one on another page. I have a directory called "uploads" where the pictures are submitted. I'm having trouble reading the pictures from the file. I just want to randomly select a picture from the directory uploads and have it displayed on the page. Any suggestions appreciated.

You can use glob to get all files in a directory, and then take a random element from that array. A function like this would do it for you:
function random_pic($dir = 'uploads')
{
$files = glob($dir . '/*.*');
$file = array_rand($files);
return $files[$file];
}

I've turned it a little to get more than one random file from a directory using array.
<?php
function random_pic($dir)
{
$files = glob($dir . '/*.jpg');
$rand_keys = array_rand($files, 3);
return array($files[$rand_keys[0]], $files[$rand_keys[1]], $files[$rand_keys[2]]);
}
// Calling function
list($file_1,$file_2,$file_3)= random_pic("images");
?>
You can also use loop to get values.

This single line of code displays one random image from the target directory.
<img src="/images/image_<?php $random = rand(1,127); echo $random; ?>.png" />
Target directory: /images/
Image prefix: image_
Number of images in directory: 127
https://perishablepress.com/drop-dead-easy-random-images-via-php/
Drawbacks
images must be named sequentially (eg image_1.png, image_2.png, image_3.png, etc).
you need to know how many images are in the directory in advance.
Alternatives
Perhaps there's a simple way to make this work with arbitrary image-names and file-count, so you don't have to rename or count your files.
Untested ideas:
<img src=<?php $dir='/images/'; echo $dir . array_rand(glob($dir . '*.jpg')); ?> />
shuffle()
scanDir() with rand(1,scanDir.length)

Or you can use opendir() instead of glob() because it's faster

Download file: direct access to application google chrome or another way to do it

hello friend i am making an aplication based on web plataform html5 css3 ...
and i have a web site with this, but i thought creat a direct link to shout(pop) this aplication to end user from the desktop.
example:
Descarga Aplicativo
but it not work on chrome or other browser. i get error file or uncomplete download. file named: IcarosNetWeb.downkload ....
Can someone help me with this?

Solved by this way
Direct Access
As not able to find the way to do it directly. I created a free mechanism:
1. Create a .bat file (Batch command line) Hiden.(This is the task: create the shortcut to the application with its parameters.)
Compressing the .bat file within a file self-extracting WinRAR and run the .bat file at the end of the extraction, automatically.
Create Hidden Log File on C:/ if have problem executing.
AutoInstall.bat file
#echo off
SETLOCAL ENABLEDELAYEDEXPANSION
SET LinkName=MyAplication
SET Esc_LinkDest=%%HOMEDRIVE%%%%HOMEPATH%%\Desktop\!LinkName!.lnk
SET Esc_LinkTarget=%%ProgramFiles(x86)%%\Google\Chrome\Application\chrome.exe
SET Esc_WorkDir=%%ProgramFiles(x86)%%\Google\Chrome\Application
SET Esc_Icon=%%ProgramFiles(x86)%%\Google\Chrome\Application\chrome.exe,6
SET Esc_URL=www.google.com
SET Esc_ARG=--app=http://!Esc_URL!/
SET cSctVBS=CreateShortcut.vbs
SET LOG=".\%~N0_runtime.log"
((
echo Set oWS = WScript.CreateObject^("WScript.Shell"^)
echo sLinkFile = oWS.ExpandEnvironmentStrings^("!Esc_LinkDest!"^)
echo Set oLink = oWS.CreateShortcut^(sLinkFile^)
echo oLink.TargetPath = oWS.ExpandEnvironmentStrings^("!Esc_LinkTarget!"^)
echo oLink.WindowStyle = 1
echo oLink.IconLocation = oWS.ExpandEnvironmentStrings^("!Esc_Icon!"^)
echo oLink.Arguments = !Esc_URL!
echo oLink.WorkingDirectory = oWS.ExpandEnvironmentStrings^("!Esc_WorkDir!"^)
echo oLink.Description = "Internet Access"
echo oLink.Save
)1>!cSctVBS!
cscript //nologo .\!cSctVBS!
DEL !cSctVBS! /f /q
)1>> !LOG! 2>>&1
attrib +h !LOG!
in Winrar:
put SFX File option, go Advance Tab and Click SFX FIle, on tab General add folder Extraction C:/ and on Instaltion tab in Instaltion after Extraction field add the full name (no path) .bat aplication.

write a file on local disk from web app [duplicate]

I am trying to create and save a file to the root directory of my site, but I don't know where its creating the file as I cannot see any. And, I need the file to be overwritten every time, if possible.
Here is my code:
$content = "some text here";
$fp = fopen("myText.txt","wb");
fwrite($fp,$content);
fclose($fp);
How can I set it to save on the root?

It's creating the file in the same directory as your script. Try this instead.
$content = "some text here";
$fp = fopen($_SERVER['DOCUMENT_ROOT'] . "/myText.txt","wb");
fwrite($fp,$content);
fclose($fp);

If you are running PHP on Apache then you can use the enviroment variable called DOCUMENT_ROOT. This means that the path is dynamic, and can be moved between servers without messing about with the code.
<?php
$fileLocation = getenv("DOCUMENT_ROOT") . "/myfile.txt";
$file = fopen($fileLocation,"w");
$content = "Your text here";
fwrite($file,$content);
fclose($file);
?>

This question has been asked years ago but here is a modern approach using PHP5 or newer versions.
$filename = 'myfile.txt'
if(!file_put_contents($filename, 'Some text here')){
// overwriting the file failed (permission problem maybe), debug or log here
}
If the file doesn't exist in that directory it will be created, otherwise it will be overwritten unless FILE_APPEND flag is set.
file_put_contents is a built in function that has been available since PHP5.
Documentation for file_put_contents

fopen() will open a resource in the same directory as the file executing the command. In other words, if you're just running the file ~/test.php, your script will create ~/myText.txt.
This can get a little confusing if you're using any URL rewriting (such as in an MVC framework) as it will likely create the new file in whatever the directory contains the root index.php file.
Also, you must have correct permissions set and may want to test before writing to the file. The following would help you debug:
$fp = fopen("myText.txt","wb");
if( $fp == false ){
//do debugging or logging here
}else{
fwrite($fp,$content);
fclose($fp);
}

List files, read files as links, php?

This is a strange request I suppose, but I have a directory full of txt files. For example:
- david_smith_interview.txt -
- beth_martin_interview.txt -
- sally_smithart_interview.txt
The contents of these text files are a link to their interview in an mp3 format, for example, if you open the file david_smith_interview.txt, it is simply this:
http://www.interviews/employees/david_smith.mp3
All of the other text files follow the same format. They are simply links to their mp3 interview.
I am trying to use something like below to list the text files:
<?php
$directory = "/employees/";
$phpfiles = glob($directory . "*.txt");
foreach($phpfiles as $phpfile)
{
echo $phpfile; // This will list the files by name
// How can I output something to reflect this:
// david_smith_interview
}
?>
So I am asking is it possible that the text file can be "read" and used as the actual link?
Any thoughts?

Replace _interview.txt with .mp3
echo "" . str_replace(".txt", "", $phpfile). "\";

Since those are .txt files you can just read them one by one to a variable and then echo the result in a for-loop.
In pseudo:
$paths fetch_paths()
$urls = array();
foreach($paths as $path)
{
$url=fopen($path);
array_push($urls,fgets(url)); // Assuming there's only one link per file and it is on one line.
}
foreach($urls as $url)
{
echo <Your formatted link here>
}

Running PHP in text/javascript environment

I'm looking to run this bit of PHP within a text/javascript environment. The point is to display a description for certain media files within the Jplayer Playlister. So how can I run this within a text/javascript environment? If you need an example of the Playerlister working fine, and then breaking upon implementation of the PHP, I can provide that.
Here's the PHP:
// CONFIGURE THESE VARIABLES:
// actual place where your mp3s live on your server's filesystem. TRAILING SLASH REQ'D.
$musicDirectory="myServerPathHere";
// corresponding web URL for accessing the music directory. TRAILING SLASH REQ'D.
$musicURL="myURLhere";
// step through each item...
$fileDir = opendir($musicDirectory) or die ($php_errormsg);
while (false !== ($thisFile = readdir($fileDir))) // step through music directory
{
$thisFilePath = $musicDirectory . $thisFile;
if (is_file($thisFilePath) && strrchr ($thisFilePath, '.') == ".mp3") // not . or .., ends in .mp3
{
// only include files that have a corresponding .txt file
$thisTextPath = substr_replace($thisFilePath, ".txt", (strlen($thisFilePath) - 4));
if (is_file($thisTextPath))
{
$myFullURL=$musicURL . $thisFile;
$myFileSize=filesize($thisFilePath);
$textContents = file($thisTextPath);
foreach ($textContents as $thisLine) echo htmlspecialchars($thisLine) . "\n";
}
}
}
closedir($fileDir);

It's possible I don't fully understand what you're asking, so forgive me if that is the case, but what you seem to be asking is how to run PHP client side.
The simple answer is you can't.
PHP is a server-side language. To accomplish what you're trying to do you need to pass some data from PHP to your javascript.
This has always been a bit of a tricky thing to do for me. I usually resort to setting my variables via an on-page <script> tag like this:
<script>
var myJSVar = <?= $myPHPVar ?>
</script>
I've also used a simple JS object to configure a later script using this same method. There are also some neat tools that enable you to create JSON objects from your PHP objects and pass that to the client side. This makes things pretty smooth, and I recommend you check it out on your own.