Submit jQuery ajax Form with multi buttons and PHP - javascript

here is my problem:
<html>
<head>
<script type="text/javascript" src="http://code.jquery.com/jquery-latest.min.js"></script>
</head>
<body>
<form id="roomform" action="room.php" method="POST">
<button name="room" value="Room01">IMG01</button>
<button name="room" value="Room02">IMG02</button>
<button name="room" value="Room03">IMG03</button>
<button name="room" value="Room04">IMG04</button>
<button name="room" value="Room05">IMG05</button>
<button name="room" value="Room06">IMG06</button>
<button name="room" value="Room07">IMG07</button>
<button name="room" value="Room08">IMG08</button>
<button name="room" value="Room09">IMG09</button>
<button name="room" value="Room10">IMG10</button>
</form>
<script type="text/javascript">
var frm = $('#roomform');
frm.submit(function (ev) {
$.ajax({
type: frm.attr('method'),
url: frm.attr('action'),
data: frm.serialize(),
success: function (data) {
alert('ok');
}
});
ev.preventDefault();
});
</script>
</body>
</html>
PHP using $_POST['room'] to get the room name Room01-Room10(Room100 maybe?) and doing something special.
It works good.
Now I need to do this using Ajax. Above code seems ok, but I cannot get any data(Room01-Room10) from it.
then I found this:
<form action="/vote/" method="post" class="vote_form">
<input type="hidden" name="question_id" value="10" />
<input type="image" src="vote_down.png" class="vote_down" name="submit" value="down" />
<input type="image" src="vote_up.png" class="vote_up" name="submit" value="up" />
</form>
$(".vote_form").submit(function() { return false; });
$(".vote_up, .vote_down").click(function(event) {
$form = $(this).parent("form");
$.post($form.attr("action"), $form.serialize() + "&submit="+ $(this).attr("value"), function(data) {
// do something with response (data)
});
});
but it seems not suitable to my case, my all buttons with same name="room" for $_POST['room'] and no class.
and this not works:
$(function() {
$('input[name=room]').click(function(){
var _data= $('#roomform').serialize() + '&room=' + $(this).val();
$.ajax({
type: 'POST',
url: "room.php?",
data:_data,
success: function(html){
$('div#1').html(html);
}
});
return false;
});
});
anyone know how to solve this problem?

Your (last) code is not sending AJAX requests because you attached the handler to the wrong input selector. Your buttons are button elements, not input elements. This should work:
$('button[name=room]').click(function() { ...
Edit:
Your first code isn't working because your buttons are just buttons. You have to add the type attribute to let your form know you're pressing a submit button: <button type="submit"...>

The serialize() method does not collect the data from a button element. Take a look to the documentation on this link: https://api.jquery.com/serialize/. In your code I would assume that your data object is empty.
Also if you post several form controls (serialized) , they should have different name attributes.

Related

Form submit only one value with AJAX passing form data to PHP in the same page

I need to pass a single value from my form to my php in the same page. It´s probably not an option to create another .php file and take the code there since there´s a lot going on.
This is the part of the code I need to fix, currently it only works when the code is on another file, since the $_POST is not messing around with other parts of the code. Specifically I need to manage to pass the 'client' or the 'empre' from the form alone to the php.
HTML
<html>
<head>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/
libs/jquery/1.3.0/jquery.min.js">
</script>
<script type="text/javascript" >
$(function() {
if($(".cliente").click(function() {
var name = $("#client").val();
var dataString = 'client='+ name;
}))else if($(".empresa").click(function() {
var name = $("#empre").val();
var dataString = 'empre='+ name;
}));
$.ajax({
type: "POST",
data: dataString});
});
</script>
</head>
<body>
<form>
<input name="client" type="text"><br>
<input class="cliente" type="submit" value="Buscar cliente"/><br>
<input name="empre" type="text"><br>
<input class="empresa" type="submit" value="Buscar empresa"/><br>
</form>
//PHP HERE
//HTML AGAIN
</body>
</html>
PHP (same page, just separating for readability)
if(isset($_POST['empre'])){
//DB QUERY
}
elseif(isset($_POST['client'])){
//DB QUERY
}
You can combine and send it in same AJAX call as below, and in PHP you can do:
$parameters = json_decode($_POST['params']);
$parameters would have all the variables sent in that AJAX call.
I would recommend, not to use same page for your AJAX. You should keep it in separate file. That would make code much cleaner, lighter, readable and easy-to-tweak.
$(function() {
$(".cliente, .empresa").click(function(e) {
e.preventDefault();
var paramsToSend = {};
if ($(this).hasClass('client'))
paramsToSend['client'] = $('form[name="client"]').serialize();
else
paramsToSend['empre'] = $('form[name="client"]').serialize()
$.ajax({
url: 'index.php' //assuming this is index.php (same page)
type: "POST",
data: {
params: JSON.stringify(paramsToSend)
},
success: function(data) {},
failure: function(error) {}
});
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form name="client">
<input name="client" type="text" value="some value"><br>
<input class="cliente" type="submit" value="Buscar cliente" />
</form>
<form name="empre">
<input name="empre" type="text" value="some value"><br>
<input class="empresa" type="submit" value="Buscar empresa" />
</form>
//PHP HERE //HTML AGAIN
Why not use separate forms to process the data? (Your PHP logic mentioned will work with this proposed solution)
$(function() {
$(".cliente").click(function(e) {
e.preventDefault();
alert('Going to post data for client, check the console log now');
$.ajax({
url: $('form[name="client"]').attr('action'),
type: "POST",
data: $('form[name="client"]').serialize(),
success: function(data){
console.log(data);
},
failure: function(error){}
});
});
$(".empresa").click(function(e) {
e.preventDefault();
alert('Going to post data for empre, check the console log now');
$.ajax({
url: $('form[name="empre"]').attr('action'),
type: "POST",
data: $('form[name="empre"]').serialize(),
success: function(data){
console.log(data);
},
failure: function(error){}
});
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<form name="client" action="https://someurl.com/fileto.php">
<input name="client" type="text" value="some value"><br>
<input class="cliente" type="submit" value="Buscar cliente"/>
</form>
<form name="empre" action="https://someurl.com/fileto.php">
<input name="empre" type="text" value="some value"><br>
<input class="empresa" type="submit" value="Buscar empresa"/>
</form>

How to: PHP Ajax page update

I have a input field and 2 buttons to add/remove words from a database.
I'm using 3 php files. The main file which is outputting the html code, the addtag.php, which can add a word and the removetag.php file which can remove a word.
I want to call addtag.php when the plus is clicked and send the content of the input field. removetag.php should be called when clicking on the minus symbol.
addtag.php and removetag.php should run in the background and the page should only update <tagboxtxt>.
The elements below are listed multiple times on the same page. There are different links and values but the elements are the same.
<!-- language-all: lang-html -->
<bdiv>
<div>
<img src="001.jpg" />
</div>
<tagbox>
<form>
<input type="text" id="tag" name="tag">
<input type="hidden" id="hash" name="hash" value="23547">
<button class="button" type="submit" formaction="addtag.php" method="GET">+</button>
<button class="button" type="submit" formaction="removetag.php">-</button>
</form>
<tagboxtxt>foo bar</tagboxtxt>
</tagbox>
</bdiv>
<bdiv>
<div>
<img src="002.jpg" />
</div>
<tagbox>
<form>
<input type="text" id="tag" name="tag">
<input type="hidden" id="hash" name="hash" value="67889">
<button class="button" type="submit" formaction="addtag.php" method="GET">+</button>
<button class="button" type="submit" formaction="removetag.php">-</button>
</form>
<tagboxtxt>bla huh</tagboxtxt>
</tagbox>
</bdiv>
I know that Ajax is the way to go, but I cant get it working.
I've tried to use function below. How should I use that in my example?
function addtag () {
$.ajax({
url:"addtag.php",
type: "POST",
success:function(result){
alert(result);
}
});
}
You're missing the javascript that captures the click on the 'plus' button, and calls your ajax function. Try pasting this javascriptsnippet below your function:
//Execute on page ready
$(function() {
$('body').on('click', '.plusSign', function() {
addTag();
});
});
i would call a js file and have it reference the two add and remove php files--i have mocked this up for you first in the main file that outputs the html put this
<head>
<script type='text/javascript'></script>
<script type="text/javascript" src="https://code.jquery.com/jquery-1.10.0.min.js"></script>
<script type="text/javascript" src="tag.js"></script>
</head>
<tagbox>
<input type="text" name="tag">
<div class="cssCircle plusSign" id="plus">+ </div>
<div class="cssCircle minusSign" id="minus" style="position:absolute; top:20px; left:25px;">–</div>
</tagbox>
This will allow you to call the js file to run ajax. the js file named tag.js should look like this
$(document).ready(function() {
$("#plus").click(function() {
$.ajax({
type: "POST",
url: "addtag.php",
dataType: "json",
data: ({word: $("#tag").val(),}),
success:function(result){
alert(result);
}
});
});
$("#minus").click(function() {
$.ajax({
type: "POST",
url: "removetag.php",
dataType: "json",
data: ({word: $("#tag").val(),}),
success:function(result){
alert(result);
}
});
});
});
this should accomplish what you need

JavaScript ActiveElement is form not button with Safari

I have a list of forms on my site with JS/AJAX that submits the forms on click. The JavaScript determines the submit type based on the active element. This has been working find across multiple browser.
Problem: Basically Safari (Version 10.0.2) on MAC considers the activeElement the form instead of the button so the getAttribute returns null. Is there a way to get the clicked element? I need to know which button the user clicked.
HTML Stuff:
<div id="#Records">
<form action="update.php" method="post">
...
<input name="submit" type="submit" data-action="send" value="send stuff" />
<input name="submit" type="submit" data-action="update" value="update" />
<input name="submit" type="submit" data-action="delete" value="delete" />
</form>
</div>
JavaScript stuff
$("#Records form").submit(function (e) {
e.preventDefault();
var url = this.action;
var data = $(this).serializeArray();
var action = document.activeElement.getAttribute('data-action');
data.push({ name: 'submit', value: action });
$.ajax({
type: "POST",
data: data,
cache: false,
url: url
}).done(function (data) {
$("#Records").html(data);
}).fail(function (result) {
ShowMessage("Error updating record!");
});
return false;
});
Can't you get the element using e.currentTarget instead of the active element? Something like
var action = $(e.currentTarget).attr('data-action');
(I'm assuming button click leads to the submit)
Ok, based on Tiny Giant and other comments I have changed the code to this. Not sure it is the best method but seems to work everywhere I have tested.
note simplified, comments welcome
HTML
<div id="#Records">
<form action="update.php" method="post">
...
<input type="button" onclick="return $(this).processRequest(this, 'send');" data-action="send" value="send stuff" />
<input type="button" onclick="return $(this).processRequest(this, 'update');" data-action="update" value="update" />
<input type="button" onclick="return $(this).processRequest(this, 'delete');" data-action="delete" value="delete" />
</form>
</div>
JavaScript
jQuery.fn.processRequest =
function(button, action)
{
var form = $(button).parents('form');
var url = form[0].action;
var data = $(form).serializeArray()
data.push({ name: 'submit', value: action });
$.ajax({
type: "POST",
data: data,
cache: false,
url: url
}).done(function (data) {
$("#Records").html(data);
}).fail(function (result) {
ShowMessage("Error updating record!");
});
return false;
}

PHP Form with Button

I have some experience in JAVA GUI programming and I want to achieve the same in a PHP form.
Situation: I want to have a php form with a submit button. When the button is pressed an ActionEvent should be called to update another part of the form.
How to implement such a feature with HTML,PHP,JAVASCRIPT ?
Load latest version of jQuery:
<script type="text/javascript" src="http://code.jquery.com/jquery-latest.min.js"></script>
HTML code:
<form>
<button type="button" class="formLoader">Click button</button>
<div id="formContentToLoad"></div>
</form>
jQuery code:
<script type="text/javascript">
$(function(){
$(".formLoader").click(function(){
$("#formContentToLoad").load("scriptToRun.php");
});
});
</script>
Whatever markup you need to update in the form, can be put into scriptToRun.php
Use jQuery
Javascript
$(document).ready(function() {
$(".myForm").submit(function() {
$.ajax({
type: "POST",
url: "myForm.php",
data: $(this).serialize(),
success: function(response) {
// todo...
alert(response);
}
})
})
});
Html
<form method="POST" class="myForm">
<input type="text" id="a_field" name="a_field" placeholder="a field" />
<input type="submit" value="Submit" />
</form>
PHP
<?php
if(isset($_POST)) {
$a_field = $_POST["a_field"];
// todo..
}
If you want to use PHP and HTML to submit a form try this:
HTML Form
<form action="" method="post">
<input type="text" placeholder="Enter Name" name="name" />
<input type="submit" name="sendFormBtn" />
</form>
PHP
<?php
if(isset($_POST["sendFormBtn"]{
$name = isset($_POST["name"]) ? $_POST["name"] : "Error Response Here";
//More Validation Here
}

multiple submit buttons different actions with passing variables

I have a form like the code below (called index.php) with multiple submit buttons. I'd like to have different php actions on submit buttons. The 1st button without refreshing the browser's page and of course with passing the variables. The other with normal action which can redirect to a new page (here form_submit.php). I managed to make the 1st button working with the help of this topic but I can't distinguish the 2nd button from the 1st one. Is there any way to switch between functionality of these buttons ?
<? php>
if($_POST['formSubmit'] == "Next") {
$var1 = $_POST['name1'];
$var2 = $_POST['name2'];.
session_start();
$_SESSION['variable1'] = $var1;
$_SESSION['variable2']= $var2;
header("Location: form_submit.php");
exit;
}
?>
<html>
<body>
<form action="index.php" method="post">
<input type="text" name="name1" id="name1" maxlength="50" value="<?=$var1;?>" />
<input type="text" name="name2" id="name2" maxlength="50" value="<?=$var2;?>" />
<input type="submit" name="dataSubmit" value="Insert Data" />
<input type="submit" name="formSubmit" value="Next" />
<script>
$(function () {
$('form').on('submit', function (e) {
e.preventDefault();
$.ajax({
type: 'post',
url: 'data_submit.php',
data: $('form').serialize(),
});
});
});
</script>
</form>
</body>
</html>
As soon as 1st button doesn't actually need to make submit you can set 'onClick' event handler on it and make it just 'button'. In this case only JS will be triggered when you press the button and browser will not submit the form. Here is what I mean:
<input type="button" id="justButton" name="dataSubmit" value="Insert Data" />
<input type="submit" name="formSubmit" value="Next" />
<script>
$(function () {
$('#justButton').on('click', function (e) {
$.ajax({
type: 'post',
url: 'data_submit.php',
data: $('form').serialize(),
});
});
});
</script>
First, add clicked class to button:
$('.submitButton').click(function(){
$('.submitButton').removeClass('clicked');
$(this).addClass('clicked');
});
Than in submit event check button:
$('form').submit(function(){
var button = $('.submitButton.clicked');
if (button.attr('id') == 'name1') {
...
} else {
...
}
return false;
});

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