Sound Track List Image URL:
https://www.dropbox.com/s/2gtd4hrhfhxl4sm/song2.png?dl=0
I have list of sound track. If i click on the first song Play button will appear as well as click second one the play button should be moved to second song and first should be as usual. But output is not an expected result. Can anyone please guide me.??
My script is here
function loadSong(song_url, play_img, sequence_id){
var x = document.createElement("IMG");
x.setAttribute("src", "images/play.jpg");
document.getElementById(sequence_id).appendChild(x);
}
Since you didn't post the HTML structure, I'll assume it's something like:
<div id="container">
<div class="song">
<div class="songImgDiv"></div>
<div class="songTitle">Song 1</div>
</div>
<!-- other songs -->
</div>
And the img has class .activePlay.
$('.song').on('click', function () {
var imgSrc = "images/play.jpg";
$('.song img.activePlay').remove();
var img = $('<img/>').prop('src', imgSrc).addClass('activePlay');
$(this).find('.songImgDiv').append(img);
});
jsfiddle DEMO
Related
i want my popup (when a button is clicked) to show a random image out of my folder each time i click the button. I used html, css and javascript for my website.
The problem: it is the same random image each time. Only if i restart the page a different random image is showed.
What works right now: when i click the start-button a popup with a random image from that folder shows up (just how i want it) but if i click the close-button on my random picture and press the start-button again the same picture pops up again. Only if i restart my page then a new random picture will show when i press the start-button. But that picture stays the same, when i close the popup and want to start it again.
I want a random image everytime when i press the start-button without having to restart the page.
Do i use a boolean in javascript? Can i restart the function on its own? I have seen similar questions all the time but none of the solutions have worked for me kinda.
(the start-button is also a picture but it is a button) Sorry if the code is weirdly formatted, i am new to code <3
Thank you!!
My code:
HTML:
<div class="popup" id="popup-1">
<div class="overlay"> </div>
<div class="content">
<img class="imagelook"/> <!-- image is start-button -->
<div
class="close-btn"
onclick="togglePopup()"
onclick="generateRandomPicture(array)">× <!-- random image from folder -->
</div>
</div>
</div>
<body>
<button type="button" onclick="togglePopup()" class="imglook"></button> <!-- the start-button -->
</body>
Javascript:
function togglePopup(){
document.getElementById("popup-1").classList.toggle("active");
}
const imageArray =[
"zettel/9.png",
"zettel/8.png",
"zettel/10.png",
"zettel/11.png",
"zettel/12.png",
"zettel/13.png"
];
const image = document.querySelector("img");
window.onload = () => generateRandomPicture(imageArray);
function generateRandomPicture(array){
let randomNum = Math.floor(Math.random() * imageArray.length);
image.setAttribute("src", imageArray[randomNum]);
}
Perhaps the following might help - coded to allow for multiple popup elements in conjunction with multiple button elements to trigger the display of different images in the respective popup div
const images = [
"zettel/9.png",
"zettel/8.png",
"zettel/10.png",
"zettel/11.png",
"zettel/12.png",
"zettel/13.png"
];
const _CN='active';
const bttnclickhandler=function(e){
// generate random image based upon array
let imgsrc=images[mt_rand(0,images.length-1)];
// assign image the new src
this.previousElementSibling.querySelector('img').src=imgsrc;
this.previousElementSibling.classList.add(_CN);
console.info(imgsrc)
};
const closeclickhandler=function(e){
e.target.closest('.popup').classList.remove(_CN);
this.previousElementSibling.src='';
console.clear();
};
// generate a random number between a & b
const mt_rand=(a,b)=>Math.floor( Math.random() * ( b - a + 1 ) + a );
// assign listeners to all pertinent elements
document.querySelectorAll('button.imglook').forEach(n=>n.addEventListener('click',bttnclickhandler));
document.querySelectorAll('div.close-btn').forEach(n=>n.addEventListener('click',closeclickhandler));
document.querySelectorAll('div.popup').forEach(n=>{
n.querySelector('img').src=images[mt_rand(0,images.length-1)]
})
.active{background:pink}
.popup{margin:1rem;}
.imglook{padding:1rem}
<div class="popup">
<div class="overlay"></div>
<div class="content">
<img class="imagelook" />
<div class="close-btn">×</div>
</div>
</div>
<button type="button" class="imglook"></button>
<div class="popup">
<div class="overlay"></div>
<div class="content">
<img class="imagelook" />
<div class="close-btn">×</div>
</div>
</div>
<button type="button" class="imglook"></button>
I want to create a basic page in html that displays a single image.
I also added two buttons Previous and Next. These buttons should allow the user to move forward or backward. Have 6 images in total. When the user reaches the end (or beginning when clicking on the back button) of the slide show, the slide show should not wrap around to the beginning (or end).
button onclick function for both the cases is not working. Its only getting displayed the first image as what mentioned in the img src attribute.
This is what I have done so far. I put all the images into an array and try to travel the array forward and backward side based on the button click.
<body>
<img src="img1.jpg" id="demo" style="width:400px;height:600px"/img>
<br/>
<input type="button" onclick="preImage()" value="Previous
">
<input type="button" onclick = "nextImage()" value="Next
">
<script>
var slider_content = document.getElementById("demo");
var image = ['img1','img2','img3','img4','img5','img6'];
var i = image.length;
function nextImage(){
if(i<image.length){
i=i+1;
}else{
i=1;
}
slider_content.innerHTML="<img src="+image[i-1]+".jpg>";
}
function preImage(){
if(i<image.length+1 && i>1){
i=i-1;
}else{
i=image.length;
}
slide_content.innerHTML = "<img src="+image[i-1]+".jpg">
}
</script>
</body>
Create a wrapper div to your image and change the innerHTML of the div.
<div id="demo" style="width:400px;height:600px">
<img src="img1.jpg">
</div>
An error needs to be corrected in the preImage function:
slide_content.innerHTML = "<img src="+image[i-1]+".jpg">
to
slider_content.innerHTML = "<img src="+image[i-1]+".jpg>";
and also what Daniel said.
Online example of my goal:
I'm trying to display bike products on a category page. On each product there's a frame variant color, I'm displaying that using round divs.
When I click a color, the image should change as you can see on Specialized website: (underneath the product image) Specialized Example.
My own website
You can see my own example here: My own website example (scroll down till you see the product with multiple products).
My target functionality:
When I click the GREEN div I'd like to show picture 2 and when I click the RED div I'd like to see image 3, but as Default it will always be the firs
The first color = the first image
The second color = the second image
And so forth
My HTML:
<div class="frameColors">
<div class="frameColor" data-color="#95BD40" style="background-color:#95BD40"></div>
<div class="frameColor" data-color="#000000" style="background-color:#000000"></div>
<div class="frameColor" data-color="#C6352D" style="background-color:#C6352D"></div>
</div>
<a href="/produkter/cykler/mountain-bikes/specialized/epic-hardtails/epic-hardtail/">
<div class="categoryImage" data-frame-color="95BD40">
<img src="/media/1072/165519.jpg?anchor=center&mode=crop&width=500&height=350&rnd=131200748910000000" class="productImage">
</div>
<div class="categoryImage" data-frame-color="000000">
<img src="/media/1071/165518.jpg?anchor=center&mode=crop&width=500&height=350&rnd=131200746750000000" class="productImage">
</div>
<div class="categoryImage" data-frame-color="C6352D">
<img src="/media/1073/166762.jpg?anchor=center&mode=crop&width=500&height=350&rnd=131200749050000000" class="productImage">
</div>
</a>
My Foreach(s):
var imageIds = item.GetPropertyValue<string>("productImages").Split(new string[] { "," }, StringSplitOptions.RemoveEmptyEntries);
var images = Umbraco.Media(imageIds);
<div class="frameColors">
#foreach (var bikeColor in images)
{
var color = bikeColor.GetPropertyValue("frameColor");
<div class="frameColor" data-color="##color" style="background-color:##color"></div>
}
</div>
<a href="#item.Url">
#foreach (var img in images)
{
<div class="categoryImage" data-frame-color="#img.GetPropertyValue("frameColor")">
<img src="#img.GetCropUrl("product image")" class="productImage" />
</div>
}
</a>
Based on Adeneo reply I managed to modify the code a little so it worked out as I wanted.
First, I added a css line: .categoryImage { display:none; } to hide ALL the product images.
I then added the script based on Adeneo's reply. I start off with targeting EACH of the .frameColor divs and inside that, I added this the following line to show the first image: categoryImage.first().show();
If the CSS line is not included, all of the product images will be displayed by default, so it was necessary to HIDE all the images and inside the script, show the first image.
$(function () {
$(".frameColor").each(function () {
var categoryImage = $(this).parent("div").next("a").find(".categoryImage");
categoryImage.first().show();
if ($(categoryImage).length > 1) {
$(this).on('click', function () {
var color = $(this).data('color').replace('#', '');
$(categoryImage).hide().filter(function () {
return $(this).data('frame-color') === color;
}).show();
});
}
else {
$(this).hide();
}
});
});
Credits goes to Adeneo for providing the original script.
I have a page that is a series of N img elements. I need each image to, when clicked, change to the next image in their own series of three. I have listed my html below to explain.
<body>
<div class="images">
<div class="image_group">
<img id="first" src="group1_image1"></img>
<img id="second" src="group1_image2"></img> //this isn't displayed until clicked
<img id="third" src="group1_image3"></img> //when this is displayed, it cycles back to group1image1
</div>
...
<div class="image_group">
<img id="first" src="groupN_image1"></img>
<img id="second" src="groupN_image2"></img>
<img id="third" src="groupN_image3"></img>
</div>
</div>
</body>
Each image_group div displays only one image until clicked, when it displays the second, then the third when clicked, then cycles back to the first when clicked a third time.
My problem is writing a JQuery method that can do this cycling by making "second" images replace "first" images when clicked and so on. The below method rewrites the image source which seems silly but I can't think of a better way to do it. I'm also not sure if the "first" class image will be isolated in the "image_group" div (as it should) or if it will change all images on the page to their "second" class image.
$("#first").attr("src","group1_image2.jpg");
Can anyone think of a way to do this?
I would do something like this
$("image_group img").on("click", function() {
var index = $(this).index();
$(this).attr("src", index === $("img").length - 1 ? $(this).next().src : $("img")[0].src);
});
refine your html:
<body>
<div class="images">
<div class="image_group">
<img id="1,1" data_num="1,1" src="group1_image1"></img>
</div>
...
<div class="image_group">
<img id="n,1" data_num="n,1" src="groupN_image1"></img>
</div>
</div>
</body>
and then you might do something like:
$("image_group img").on("click", function() {
var max = 3;
var indexes = $(this).data('num').split(',');
if ( indexes[1] == max
indexes[1] = 1;
else
indexes[1]++;
$(this).attr("src", "group" + indexes[0] + "_image" + indexes[1]);
$(this).data('num', indexes.join(','))
});
The home page of my site has a container that holds square boxed with an image and a title. I changed some of those tiles to .gif images so once you hover over the image changes to another. There is not title anymore. The issue is when I load the page, the pictures that are gif do not load unless I hover over them. Once I hover over all, and do a page resize they all look fine.
Could it be because of the page resize function?
http://geranbaha.com/indextest.html
Can someone point out what I am doing wrong.
<script language="JavaScript">
<!-- Hide the script from old browsers -->
img0_on = new Image(311,235);
img0_on.src="upload/ketabmoghadas.gif";
img0_off = new Image(311,235);
img0_off.src="upload/ketabmogadasWeb.gif";
img1_on = new Image(311,235);
img1_on.src="upload/divine.gif";
img1_off = new Image(311,235);
img1_off.src="upload/divineculture.gif";
img2_on = new Image(311,235);
img2_on.src="upload/tv.gif";
img2_off = new Image(311,235);
img2_off.src="upload/rozaneh.gif";
img3_on = new Image(311,235);
img3_on.src="upload/radio.gif";
img3_off = new Image(311,235);
img3_off.src="upload/radio1.gif";
function over_image(parm_name)
{
document[parm_name].src = eval(parm_name + "_on.src");
}
function off_image(parm_name)
{
document[parm_name].src = eval(parm_name + "_off.src");
}
//<! --End Hiding Here -->
html section
the commented part in this section is what it used to be and I replaced it with one line html code to show the gif images.
<div class="project-post web-design illustration">
<img src="ketabmogadasWeb.gif" border="0" name="img0">
<!-- <img alt="" src="upload/divineculture.jpg">
<div class="hover-box">
<div class="project-title">
<h2>فرهنگ الهی</h2>
<span>www.divine-culture.com</span>
<div><i class="fa fa-arrow-right"></i></div>
</div>
</div> -->
</div>
Put all of your javascript in
$( document ).ready(function() {
// Put all your image stuff here
});
And remove onmouseover="over_image('img0');" onmouseout="off_image('img0')"
Those onmouseover functions is what makes it change on a hover.