Develop Reference

save and read the checkbox value in the db, change the status of the label

I have to use a checkbox as a preference choice, so I save it in a mysql db to have it always available. When I select the chekbox the label changes to Enabled and vice versa. When you save (submit) the page sends an allert message indicating the status of the checkbox, and save the new value in the db 0 = disabled 1 = enabled and "reload" the same page and read the new values. Now I have the problem that the scripts intervene before I can read the value from the db. Only when I reload the page the second time do I get the correct values. I inserted a page refresh but I did not solve the problem.
-js-
<script>
function checked() {
if (document.getElementById("check1").checked){
$(check1).siblings('label').html('Abled');
alert("Abled Notify");
$.get("birthdaysend.php");
} else {
$(check1).siblings('label').html('Disabled');
alert("Disabled Notify");
}
}
// function change label checked
$('#check1').click(function() {
if ($(this).is(':checked')) {
$(this).siblings('label').html('Abled');
} else {
$(this).siblings('label').html('Disabled');
}
});
function urlCheck() {
if(window.location.href=="preference.php"){
//load page = read satus
checked();
}
}
urlCheck()
</script>
-Insert in to db-
$dbox = "SELECT value FROM box WHERE id = '1'";
$dbox= $db->ExecuteScalar($dbox);
print_r($dbox);//temp
if (isset($_POST['check1']) && $_POST['check1'] == '1') {
Execute("UPDATE box SET value='1' WHERE id = '1'");
header("Refresh:0");
}else{
Execute("UPDATE box SET value='0' WHERE id = '1'");
//header("Refresh:0");
}
-Html-
<form name="preference" action="preference.php" method="POST">
<div class="col-sm-4"><label class="container" for="check1">Tag 1</label><input type="checkbox" class="checkmark" name="check1" id="check1" value="1" <?php echo ($dbox == 1 ? 'checked' : '');?>></div>
<button style="float:left; margin-left: 0px;" type="submit" class="btn btn-primary"><i class="fa fa-floppy-o"></i> Save </button>
</form>

First of all change this, make update code first and then select
if (isset($_POST['check1']) && $_POST['check1'] == '1') {
Execute("UPDATE box SET value='1' WHERE id = '1'");
}else{
Execute("UPDATE box SET value='0' WHERE id = '1'");
}
$dbox = "SELECT value FROM box WHERE id = '1'";
$dbox= $db->ExecuteScalar($dbox);
print_r($dbox);//temp
Remove Urlcheck and checked functions from javascript
In label add this code instead of tag 1
echo ($dbox == 1 ? 'Abled' : 'Disabled');

A better way to do that would be with Ajax where the code to insert the value into a database is a different page from the one with a check box. Ajax is a JavaScript Library that has a synchronous ability.W3Schools tutorial for Ajax

How to implement “select all” check box

i have invoice page and customer select the invoice and pay. invoice page if invoices are multiple then customer need to select check box each then click on Generate Invoice for payment. i want if invoice are multiple customer should check All then its work customer dont have choice select single. he should select All the check boxes then its work.
i think on page javascript code is below:
<script language="JavaScript">
function checkAll(theForm, cName) {
for (i=0,n=theForm.elements.length;i<n;i++)
if (theForm.elements[i].className.indexOf(cName) !=-1)
if (theForm.elements[i].checked == true) {
theForm.elements[i].checked = false;
} else {
theForm.elements[i].checked = true;
}
}
</script>
on invoice page i have also option select All check box
code is below:
<input type="checkbox" name="kk" id="kk" onClick="checkAll(document.getElementById('form4'), 'chk1');" >
when invoice are more multiple from database check code is:
<input name="orderNo[]" <?php if ($SQLRow["priceStatus"]=="Received") { ?> disabled="disabled"<?php } ?> type="checkbox" id="orderNo[]" value="<?php echo $SQLRow["orderNo"];?>" class="chk1" />
i just want one help if all the check boxes are selected then its work.

Try this
$('#kk').on('click', function() {
if($(this).prop("checked")){
$('input:checkbox').each(function() {
$(this).attr("checked", "checked");
$(this).prop("checked", true);
});
}
else{
$('input:checkbox').each(function() {
$(this).removeAttr("checked", "checked");
$(this).prop("checked", false);
});
}
});
Jsfiddle is here

Validate checkbox using JavaScript.

I would like some help with checkbox validation.
If you look in below picture, when user click the image, the checkbox becomes selected.
What I would want is if all checkbox are selected alert an simple message.
This is a code to select checkbox by clicking on an image.
$( document ).ready(function() {
$("#roll-<?php echo $row['id_vnr']; ?><?php echo $cut_counter; ?>").click (function(){
var $$ = $(this)
if( !$$.is('.checked')){
$$.addClass('checked');
$('#imgCheck-<?php echo $row['id_vnr']; ?><?php echo $cut_counter; ?>').prop('checked', true);
}
});
});
So I can select check box by clicking on an image. How I can alert message if all check box are selected. Soon user click last picture, the picture will disappear, the red tick box will appear and user should see alert message.
Thank you in advance.

You can achieve this by getting the number of elements with the class 'checked'. If the number is 6, then you can show the alert.

Try this way:
var checkboxes = $('[type="checkbox"]');
checkboxes.on('change', function() {
var checked = $('[type="checkbox"]:checked');
console.log('all:', checkboxes.length, ' / ', 'checked:', checked.length);
if (checkboxes.length === checked.length) {
console.log('ALL CHECKED!');
}
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="checkbox">1
<input type="checkbox">2
<input type="checkbox">3

You can use the following javascript code:
$(function(){
$('input[type="checkbox"]').click(function() {
totalCheckboxCount = $('input[type="checkbox"]').length;
selectedBoxesCount = $('input[type="checkbox"]:checked').length;
if(totalCheckboxCount == selectedBoxesCount) {
alert("All checkboxes selected!");
}
});
});

get radio button value (PhP MySQL and ajax)

Newbie here..
I have this code for my displaying the database records in a table,
I want to know how do i get the value of radio button (the radio button contains the id of selected row). I tried doing it in javascript but no luck.
table.php
<table border="1">
<th></th>
<th>Particulars</th>
<th>Amount</th>
<?php
include('includes/config.php');
$qry = $con->prepare('SELECT * FROM fees');
$qry->execute();
$row = $qry->rowCount();
while ($row = $qry->fetch(PDO::FETCH_ASSOC)) {
$id = $row['fee_id'];
$fee = $row['fee_name'];
$amt = $row['amount'];
?>
<?php echo "
<tr title='Click to edit or delete record'>
<td><input type = 'radio' name = 'radio' class ='radio' value = $row[fee_id]></td>
<td>$fee</td>
<td>$amt</td>
</tr>
"; ?>
<?php } ?>
</table>
<input type="button" value="Delete Selected Fee" style="width:250px; height:40px;font-weight:bold;" onclick="delete();"><br><br>
javascript code
<script type="text/javascript">
function delete(){
if (document.getElementsByClassName(this.class).checked){
var val = document.getElementsByClassName(this.class).value;
alert (val);
}
}
</script>

Use this
function delete(){
if($('input[name="radio"]').is(':checked')){
var val = $('input[name="radio"]').val();
console.log(val);
}
}

I suggest you to use hidden field instead if you don't want to show. The property of radio buttons is to show only true / false value. It may be on / off or yes / no, according to your uses. Use like
<input type = 'hidden' name = 'whatever' class ='radio' value =<?php echo $row['fee_id']; ?>>

You can try this, this should get your radio button value using your input name.
<script type="text/javascript">
function delete(){
if($('input[name="radio"]').is(':checked')){
var val = $('input[name="radio"]').val();
alert (val);
}
}
</script>

Following code will give you your radio button value
<script type="text/javascript">
function delete(){
if($('input[name="radio"]').is(':checked')){
var val = $('input[name="radio"]').val();
alert (val);
}
}
</script>
you can use console.log(val);

how to deselect a particular selected checkbox when condition fails

I want to deselect a particular selected checkbox when condition fails.i have selected number of checkboxes but when my condition fails, i want to show there is alert message and don't want to select that checkbox. But when i am doing this, there is alert message but checkbox is selected.I want to unselect this selected checkbox when message is displaying
<input type="checkbox" id="ChkIds_<?php echo $row['leader_id']; ?>" value="" name="selected[]" onChange="myFunction(this)" class="<?php echo $row['state_point'];?>">
<td align="center" bgcolor="#FFFFFF"><span id="total" class="0">1000</span></td>
<script type = "text/javascript">
function myFunction(obj) {
if(obj.checked==1) {
var valuenew=obj.value;
var NewVal=$('#total').text();
var calcVal=Number(NewVal)-Number(valuenew);
if(calcVal<=0)
{
alert('hi');
}
else
{
$('#total').text(calcVal);
obj.id.checked=false;
}
}
else {
var valuenew=obj.value;
var NewVal=$('#total').text();
var calcVal=Number(NewVal)+Number(valuenew);
$('#total').text(calcVal); }
}
</script>

You can call a function onchange and uncheck the desired checkbox
$("#chkbox_id:checked").attr("checked", false);

If you want to uncheck the checkbox which was just check, then:
$(obj).attr("checked", false);
If another one:
$("#checkboxid").attr("checked", false);
If all of them:
$("input:checkbox").attr("checked", false);