Develop Reference

Two button submit form issue

Hi successfully made a form where there are two submit buttons.
I needed two buttons because I need each button to take the form to a different place, while get/post the information in the first form.
This is how I did it
Javascript:
function submitForm(action) {
var form = document.getElementById('form1');
form.action = action;
form.submit();
}
<form id="form1" method="post" >
<div class="f-row">
<label for="pick">Pick-Up Address</label>
<input type="text" input name="pick" required value="<?php echo isset($_POST['pick']) ? $_POST['pick'] : ''; ?>"/>
</div>
<input type="button" onclick="submitForm('page2.php')" class="btn small color left" value="ADD ANOTHER STOP" />
<input type="button" onclick="submitForm('page3.php')" class="btn medium color right" value="Continue" />
</form>
It works, both buttons submits to the relevant pages.
But now there is one problem I can't seem to fix, previously if the form was not filled, and i clicked submit, it would ask me to fill up the required fields, now it does not anymore.
If required fields are not filled up, it still submits the form.
I need button 1 to not require required fields to be filled up, and button 2 to require it as button 2 submits the form, while button 1 brings it to a new form to fill up with other details before they submit from there.
Anyone know of a way I can sort this?

You can try this: <input type="text" name="pick" id="pick" required/> and in the javascript
function submitForm(action) {
var form = document.getElementById('form1');
form.action = action;
if (document.getElementById('pick').value) {
form.submit();
}}
else{
alert('Please fill the required field!');}

You just need to use jquery to validate the form when the first button is clicked and you can use formaction attribute on the button to specify where the button should go when it's clicked.
$('document').ready(function(){
$('#btn1').on('click',function(){
var pick = $('input[type="text"][name="pick"]').val();
if(pick == ""){
alert("enter pick");
return false;
}else{
$(this).submit();
}
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form id="form1" method="post" >
<div class="f-row">
<label for="pick">Pick-Up Address</label>
<input type="text" name="pick" value="your value">
</div>
<button type="submit" formaction="page2.php" class="btn small color left" id="btn1">ADD ANOTHER STOP</button>
<button type="submit" formaction="page3.php" class="btn medium color right">Continue</button>
</form>

You could use jQuery for this.
if ($('#something').length)
This will check if there exist an element with the id 'something', but not if it is empty or which value it has.
To check this you can use:
if($('#something').val().length>0)
or
if($('#something').val() != "")
Do with it what ever is needed.
You could even add this check within your submitForm function just above the current code.

Try this:
<script>
function submitForm(action) {
var a = $("input[name=pick]").val();
if(a) {
var form = document.getElementById('form1');
form.action = action;
form.submit();
} else {
alert('please fill the required field');
return false;
}
}
</script>

Using this way(simple way):--
<form id="myForm" name="myForm" onSubmit="encriptar_rc4();return false;">
<input type="submit" name="submitOne" value="submitOne" class="submitButton" />
<input type="submit" name="submitTwo" value="submitTwo" class="submitButton" />
</form>
<script>
$(function(){
$(".submitButton").click(function(e){
alert($(this).attr("name"));
});
encriptar_rc4();{
alert('hola');
}
});
</script>

PHP form submit button but not leave page

I have a button that links to a php file that tracks user's email when clicked, but I don't want the user to leave the page when button is clicked, I just want to change button's value.
This is the html of the form.
<form action="mysql-query.php" method="post">
<input type="text" name="email" style="display:none;">
<input type="submit" value="Press here" id="test" onclick="Press()">
</form>
And this is the script that handles the form:
<script>
function Press() {
var test= document.getElementById("test");
test.value="Thank you";
localStorage.value=("ok");
}
</script>
I put the display:none; because I don't want to display anything but the button and have a way to connect with my php file.
Any ideas?

You need to use ajax:
html:
<form action="mysql-query.php" method="post" onsubmit="return Press(this)">
<input type="text" name="email" style="display:none;">
<input type="submit" value="Press here" id="test">
</form>
js:
function Press(form) {
$.post($(form).attr('action'), function() {
var test= document.getElementById("test");
test.value="Thank you";
localStorage.value=("ok");
});
return false; // prevent submitting the form
}
or better bind submit event using jQuery:
$('form').submit(function() {
$.post($(this).attr('action'), function() {
var test= document.getElementById("test");
test.value="Thank you";
localStorage.value=("ok");
});
return false; // prevent submitting the form
});

Use:
<form action="javascript:void()">
Ok, this thing prevents the form from sending the data anywhere, unless you use "onclick" event on the submit button.

What you can do is remove the type="submit" on the button and replace it with type="button". Next you can do an ajax call to your php and do your magic.

Javascript setting value of textbox by function, without getting reset

My goal is to have a text box and a button. If I enter "Hello" in the text box and press the submit button I would like to have see the text box filled with "World.
For the moment the value of the text box will be changed betweeen the
<html>
<body>
<script>
function validateForm() {
var x = document.forms["myForm"]["Input"].value;
if (x == "Hello") {
alert("test");
document.getElementById("Input").value = "World";
alert("test2");
}
}
</script>
<form name="myForm" action="test.html" onsubmit="return validateForm()" method="post">
Input: <input type="text" id="Input"><br>
<input type="submit" value="Submit">
</form>
</body>
</html>

The problem is that the form gets submitted right after the validation. So you are redirected to test.html again.
If you don't want that to happen, add event.preventDefault(); to your Event Handler (check out the fiddle to see it working):
<html>
<body>
<script>
function validateForm(event) {
event.preventDefault();
var x = document.forms["myForm"]["Input"].value;
if (x == "Hello") {
alert("test");
document.getElementById("Input").value = "World";
alert("test2");
}
}
</script>
<form name="myForm" action="test.html" onsubmit="return validateForm(event)" method="post">
Input: <input type="text" id="Input"><br>
<input type="submit" value="Submit">
</form>
</body>
</html>
You can learn more about event.preventDefault() at MDN.
Just as a sidenote: It is generally better to use addEventListener instead of the onsubmit attribute (Better separation of concerns, you can add multiple event listeners, etc.).

When you submit your page, then the content in the action page will be loaded.
In your case test.html will be loaded.
If you want the value "World" to be shown in the text box on hitting the submit, then return false on your validateForm() method.

Use return false; to stay on the same page and stop form submission.
function validateForm() {
var x = document.forms["myForm"]["Input"].value;
if (x == "Hello") {
document.getElementById("Input").value = "World";
return false;
}
}

Perform a clean submit by removing hidden divs

I am trying to perform a 'clean' submit, i.e. a submit that is invoked after removing all hidden divs from the form field.
Since this is a feature I am going to use more often, I shifted my code into the extend-part:
$.fn.extend({
bindCleanSubmit: function() {
$(this).submit( function(event) {
event.preventDefault();
$(this).find("div:hidden").remove();
console.log("trying to commit...");
return true;
});
}
});
Now, all divs are removed, the console event is triggered but at the end the submit has not performed.
Do you now the problem here?

I'm not sure what you are trying to do with preventDefault(), but if you remove it from bindCleanSubmit(), hidden divs will be removed from the form and it will be submitted normally. So given the following html:
<form id="myform" method="POST" action="/">
<input type="text" name="displayedInput" value="1"/>
<div style="display: none">
<input type="text" name="hiddenInput" value="1"/>
</div>
<button type="submit">Submit</button>
</form>
...and the updated plugin:
$.fn.extend({
bindCleanSubmit: function() {
$(this).submit( function(event) {
$(this).find("div:hidden").remove();
console.log("trying to commit...");
return true;
});
}
});
$('#myform').bindCleanSubmit();
...only the displayedInput value will be submitted to the server when myform is submitted.

my jquery form validation is not working as i hope it should

I have some javascipt code here that validates a user form. When the user inputs the correct answer it tells them and gives them the link to the next question. At least, that's what it is supposed to do. When i click the form it reloads the page but it should not because i added return false.
the div tra holds 35
and the div usermsg is the user inputted value.
<script>
$("#submit").click(function(){
var clientmsg6 = $("#usermsg").val();
var rightanswer = $("#tra").val();
if (clientmsg6<>rightanswer)
{
$("#confirm").html("<h2>Sorry, wrong answer.</h2>");
}
else
{
$("#confirm").html("<a href='#' onclick='play();' style='font-size:20px;' id='new1'>Click here for Question 2</a>");
}
return false;
});
</script>
Any ideas why this is not working?

It should be
if (clientmsg6 != rightanswer)
not
if (clientmsg6<>rightanswer)

To prevent a form submission, you need to return false on the form itself instead of on the submit button. Your code should become:
HTML
<form action="page.php" method="post">
<input id="usermsg" type="text" name="answer" />
<input id="submit" type="submit" value="Submit" />
</form>
JS (please note the line where you have clientmsg6, you have a syntax error)
$("#myform").on('submit', function(){
var clientmsg6 = $("#usermsg").val();
var rightanswer = $("#tra").val();
if (clientmsg6 != rightanswer) { //This line was also wrong, should be != instead of <>
$("#confirm").html("<h2>Sorry, wrong answer.</h2>");
}
else {
$("#confirm").html("<a href='#' onclick='play();' style='font-size:20px;' id='new1'>Click here for Question 2</a>");
}
return false;
});
Alternatively, you can keep your existing code by changing your submit button to be just a plain old button, but you will lose the extra functionality of the user being able to hit the enter key and performing the same action.
<form action="page.php" method="post">
<input id="usermsg" type="text" name="answer" />
<input id="submit" type="button" value="Submit" />
</form>

Instead of using .html(), try using .text()

if #submit is a link tag otherwise use the form ID and the submit event
$("#submit").click(function(e){
e.preventDefault()
...
...
...
});

You need to attach handlers once the document has finished loading.
Wrap your script in the following
<script>
$(function() {
// script
});
</script>