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ajax isnt sending post request to php

Javascript doesn't send any post data to php file
$(document).ready(function(){
function showComment(){
$.ajax({
type:"post",
url:"process.php",
data:"action=showcomment",
success:function(data){
$("#comment").html(data);
}
});
}
showComment();
$("#button").click(function(){
var name = $("#name").val();
var message = $("#message").val();
var dataString = "name="+name+"&message="+message+"&action=addcomment";
$.ajax({
type:"post",
url:"process.php",
data:dataString,
success:function(data){
showComment();
}
});
});
});
form:
<form action="" method="POST" enctype="multipart/form-data">
name : <input type="text" name="name" id="name"/>
</br>
message : <input type="text" name="message" id="message" />
</br>
<input type="submit" value="Post" name="submit" id="button">
<div id="info" />
<ul id="comment"></ul>
</form>
php
$action=$_POST["action"];
if($action=="addcomment"){
echo "Add comment WORKS!";
}
if($action=="showcomment"){
echo "default";
}
Tried to add such lines as if post addcomment than show some words, just for a test since sql request didn't but php doesn't show any response at all, like there was no post action at all.
ps. I'm really new ajax so if possible show me a solution to solve it.

You're using a submit button so it will be making the form submit and reload which will bypass your ajax, you can change your jQuery to listen for the form submit event instead like this:
$("form").on('submit', function(e){
// Stop form from submitting
e.preventDefault();
var name = $("#name").val();
var message = $("#message").val();
var dataString = "name="+name+"&message="+message+"&action=addcomment";
$.ajax({
type:"post",
url:"process.php",
data:dataString,
success:function(data){
showComment();
}
});
});
Or simply change the button from type="submit" to type="button" or replace it with a element.

You are using submit button as Dontfeedthecode mentioned. Your form does not have any action so it is self posting. I have added action and id to the html form and a hidden field to pass the action. Now javascript serialize the form and send it to the process.php.
$(function () {
$("#my-form").on("submit", function (e) {
$("#action").val("addcomment");
$.ajax(
{
url: this.action,
type: this.method,
data: $(this).serialize(),
success: function (data) {
showComment();
}
});
return false;
});
});
<form action="process.php" method="POST" id="my-form" enctype="multipart/form-data">
<input type="hidden" id="action" name="action" value="" />
name : <input type="text" name="name" id="name" />
</br>
message : <input type="text" name="message" id="message" />
</br>
<input type="submit" value="Post" name="submit" id="button">
<div id="info" />
<ul id="comment"></ul>
</form>

PHP Form with Button

I have some experience in JAVA GUI programming and I want to achieve the same in a PHP form.
Situation: I want to have a php form with a submit button. When the button is pressed an ActionEvent should be called to update another part of the form.
How to implement such a feature with HTML,PHP,JAVASCRIPT ?

Load latest version of jQuery:
<script type="text/javascript" src="http://code.jquery.com/jquery-latest.min.js"></script>
HTML code:
<form>
<button type="button" class="formLoader">Click button</button>
<div id="formContentToLoad"></div>
</form>
jQuery code:
<script type="text/javascript">
$(function(){
$(".formLoader").click(function(){
$("#formContentToLoad").load("scriptToRun.php");
});
});
</script>
Whatever markup you need to update in the form, can be put into scriptToRun.php

Use jQuery
Javascript
$(document).ready(function() {
$(".myForm").submit(function() {
$.ajax({
type: "POST",
url: "myForm.php",
data: $(this).serialize(),
success: function(response) {
// todo...
alert(response);
}
})
})
});
Html
<form method="POST" class="myForm">
<input type="text" id="a_field" name="a_field" placeholder="a field" />
<input type="submit" value="Submit" />
</form>
PHP
<?php
if(isset($_POST)) {
$a_field = $_POST["a_field"];
// todo..
}

If you want to use PHP and HTML to submit a form try this:
HTML Form
<form action="" method="post">
<input type="text" placeholder="Enter Name" name="name" />
<input type="submit" name="sendFormBtn" />
</form>
PHP
<?php
if(isset($_POST["sendFormBtn"]{
$name = isset($_POST["name"]) ? $_POST["name"] : "Error Response Here";
//More Validation Here
}

One Javascript Control Multiple Form Submission

I am trying to build a page with multiple forms submitting different values to another php script "another-script.php" using Javascript as shown below:
<html>
<head>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
</head>
<body>
<div id="simple-msg"></div>
<form name="ajaxform" id="ajaxform" action="another-script.php" method="POST">
<input type=hidden name=a value='value1'>
<input type="button" id="simple-post" value="Run Code" />
</form>
<form name="ajaxform" id="ajaxform" action="another-script.php" method="POST">
<input type=hidden name=a value='value2'>
<input type="button" id="simple-post" value="Run Code" />
</form>
<form name="ajaxform" id="ajaxform" action="another-script.php" method="POST">
<input type=hidden name=a value='value3'>
<input type="button" id="simple-post" value="Run Code" />
</form>
<script>
$(document).ready(function()
{
$("#simple-post").click(function()
{
$("#ajaxform").submit(function(e)
{
$("#simple-msg").html("<img src='/logo/progress_bar.gif'/>");
var postData = $(this).serializeArray();
var formURL = $(this).attr("action");
$.ajax(
{
url : formURL,
type: "POST",
data : postData,
success:function(data, textStatus, jqXHR)
{
$("#simple-msg").html('<pre>'+data+'</pre>');
},
});
e.preventDefault(); //STOP default action
e.unbind();
});
$("#ajaxform").submit(); //SUBMIT FORM
});
});
</script>
</body>
</html>
The forms should be able to submit different values by themselves but when using Javascript to submit to a different script "another-script.php", only the first form works. Would you please kindly advise what I should do to make each form submitting their own values.
Thank you very much!

multiple submit buttons different actions with passing variables

I have a form like the code below (called index.php) with multiple submit buttons. I'd like to have different php actions on submit buttons. The 1st button without refreshing the browser's page and of course with passing the variables. The other with normal action which can redirect to a new page (here form_submit.php). I managed to make the 1st button working with the help of this topic but I can't distinguish the 2nd button from the 1st one. Is there any way to switch between functionality of these buttons ?
<? php>
if($_POST['formSubmit'] == "Next") {
$var1 = $_POST['name1'];
$var2 = $_POST['name2'];.
session_start();
$_SESSION['variable1'] = $var1;
$_SESSION['variable2']= $var2;
header("Location: form_submit.php");
exit;
}
?>
<html>
<body>
<form action="index.php" method="post">
<input type="text" name="name1" id="name1" maxlength="50" value="<?=$var1;?>" />
<input type="text" name="name2" id="name2" maxlength="50" value="<?=$var2;?>" />
<input type="submit" name="dataSubmit" value="Insert Data" />
<input type="submit" name="formSubmit" value="Next" />
<script>
$(function () {
$('form').on('submit', function (e) {
e.preventDefault();
$.ajax({
type: 'post',
url: 'data_submit.php',
data: $('form').serialize(),
});
});
});
</script>
</form>
</body>
</html>

As soon as 1st button doesn't actually need to make submit you can set 'onClick' event handler on it and make it just 'button'. In this case only JS will be triggered when you press the button and browser will not submit the form. Here is what I mean:
<input type="button" id="justButton" name="dataSubmit" value="Insert Data" />
<input type="submit" name="formSubmit" value="Next" />
<script>
$(function () {
$('#justButton').on('click', function (e) {
$.ajax({
type: 'post',
url: 'data_submit.php',
data: $('form').serialize(),
});
});
});
</script>

First, add clicked class to button:
$('.submitButton').click(function(){
$('.submitButton').removeClass('clicked');
$(this).addClass('clicked');
});
Than in submit event check button:
$('form').submit(function(){
var button = $('.submitButton.clicked');
if (button.attr('id') == 'name1') {
...
} else {
...
}
return false;
});

Submit form to other page

I need help with submiting data form #send_form to #f_from in another page.
<script type="text/javascript">
function post_form() {
$('#send_form').action = "form01.html";
$('#send_form').submit();
return false;
}
</script>
<form id='send_form' action='form01.html' method='POST' onsubmit="post_form();">
<input type="text" name="f_in01" value="User" />
<input type="text" name="f_in02" value="12345" />
<input type="submit" />
</form>
The form01.html
<script type="text/javascript">
function f_res()
{
var res01=document.f_form.f_in01.value;
var res02=document.f_form.f_in02.value;
var result = res01 + " " + res02;
document.f_form.f_out01.value=result;
}
</script>
<form id="f_form" onSubmit="f_res();return false;">
<input type="text" name="f_in01" /><br>
<input type="text" name="f_in02" /><br>
<br>
<input type="submit" onClick="f_res();" value="Enter w/Sub" /><br>
<input type="text" name="f_out01" />
</form>
Now it doesn't work. The data doesn't post in page01.html

Have you tried
$('#send_form').attr('action', "form01.html");
instead of
$('#send_form').action = "form01.html";
check out this fiddle

Amin is right, but in jQuery, when an event handler returns false, it amounts to the same as e.preventDefault(); e.stopPropagation(). Essentially, you cancel the event. Try returning true, instead of false.
If you don't want the page to change, you'll have to look at AJAX to post the form data.

You want AJAX for this something like:
$('#button').click(function(){
$.ajax({
type:"POST", //php method
url:'process.php',//where to send data...
cache:'false',//IE FIX
data: data, //what will data contain (no SHIT Sherloc...)
//check is data sent successfuly to process.php
//success:function(response){
//alert(response)
//}
success: function(){ //on success do something...
$('.success').delay(2000).fadeIn(1000);
//alert('THX for your mail!');
} //end sucess
}).error(function(){ //if sucess FAILS!!
alert('An error occured!!');
$('.thx').hide();
});
});