This question already has answers here:
How do I return the response from an asynchronous call?
(41 answers)
Closed 7 years ago.
I have json data in file that I want to read. It prints to the console.log the correct file data.
How do I get that data into variable x? When I run the code, x is undefined.
function getData() {
$.get('data/APPFeaturesMetaData.json', function (data) {
console.log(data);
return data;
});
};
var x = getData();
It's an asynchronous call, So the var x = getData(); runs before the AJAX request is complete.
The answer is, use deferred it looks something like this:
var request = $.ajax(
{
url: url,
});
// When the request is done, do something with data.
request.done(function (data) {
console.log(data);
});
In your case, it's different if you want to return data, you will have some scoping problems. the fix is really easy, Here's what your final code will look like, I will explain stuff in the comments:
function getData() {
// This is where we store the data.
var myData;
// This will refference current object.
// You need to keep the refference of this object.
var self = this;
$.get( 'data/APPFeaturesMetaData.json' ).done(function(data) {
// the keyword `this` will not work here, because you're inside an AJAX callback.
// When you say `this`, you're actually refferencing the AJAX object
// And not the getData object.
self.myData = data;
});
return myData;
};
Related
This question already has answers here:
How do I return the response from an asynchronous call?
(41 answers)
Closed 2 years ago.
I have one oDataModel and I am reading a particular property, with read function. When data read is success I am assigning it to a variable. But it is always saying undefined
readData : function(){
var oModel = this.getView().getModel();
var locationID;
oModel.read('/Locations',{
success: function(oData,oResponse){
console.log(oData.results[0].id); //This is printing the data in console, properly
locationID = oData.results[0].id;
}
});
console.log(locationID); //This is printing as undefined
}
read is asynchronous. When you do oModel.read, it essentially fires the request but doesn't block the executing thread. If you do a debug of the above code, you'll observe that execution goes to console.log(locationID); immediately after oModel.read. At this point, locationID is undefined (Since assignment hasn't happened yet). The assignment only happens after the callback function success is executed.
To solve this, you can wrap your oModel.read within a Promise. You need to resolve your promise inside success.
readData: function() {
var oModel = this.getView().getModel();
var locationID;
new Promise((resolve, reject) => {
oModel.read('/Locations', {
success: function (oData, oResponse) {
console.log(oData.results[0].id);
locationID = oData.results[0].id;
resolve(locationID)
},
failure: function (oError) {
reject(oError)
}
});
}).then(data => console.log(data))
}
I'm not 100% sure of the syntax, but this should help put you on the right path.
This question already has answers here:
Javascript infamous Loop issue? [duplicate]
(5 answers)
Closed 8 years ago.
Hello there I have the following problem - within a loop I have a certain number of jQuery ajax calls - in the return of the ajax call I want to use a local variable as well as the data returned by the ajax call:
In the JavaScript class DOCache.class.js (note that I use the global variable doCache here, which also does not "feel clean" but I do not know how to pass "this"):
function DOCache() {
this.cache = new Array();
this.capi = new JsonAPI();
// loads all the properties saved in the cache object
this.loadUpdateCache = function(allLoaded) {
for(var prop in this.cache) {
// a delay will be here for each object!
this.capi.get(this.cache[prop]['url'],(function(data) {
doCache.cache[prop]['data'] = data;
doCache.cache[prop]['ready'] = true;
if(doCache.cache[prop]['loaded'] instanceof Function) {
var propLoaded = doCache.cache[prop]['loaded'];
propLoaded(data);
}
// check all initialized
if(doCache.checkAllReady()===true && allLoaded instanceof Function) {
allLoaded(doCache.cache);
}
}) (prop) // KEY: If we have this, we get the correct prop - if removed, we get the correct data - but never both
);
}
};
}
In JsonAPI.class.js:
function JsonAPI(){
this.ajax = function(request_method,api_url,data,done,fail,always) {
var jqxhr = $.ajax(
{
type:request_method,
dataType: "json",
url: JSON_BASE+api_url,
data: data
},JSON_BASE+api_url,data)
.done(function(data) {
if(done instanceof Function) {
done(data);
}
})
.fail(function(data) {
if(fail instanceof Function) {
fail(data);
}
})
.always(function(data) {
if(always instanceof Function) {
always(data);
}
});
return jqxhr;
};
this.get = function(api_url,done,fail,always) {
return this.ajax('GET',api_url,"",done,fail,always);
};
}
The problem is that I do not know how to pass the local variable from the loop (which is a different string on each loop iteration) to the actual callback function without passing it explicitly using (prop) . But if I do this I do not get the data from the callback passed in.
So the actual question is: How can I use a local variable from an iteration (which obviously end before any ajax response is returned) in an Ajax callback function?
Try to aggregate your Ajax calls within an array. Then use $.when to set the callback:
var ajaxRequests = [];
var req1 = $.ajax();
ajaxRequests.push(req1);
$.when(ajaxRequests).done(function () {});
Note, this code is untested.
This question already has answers here:
How do I return the response from an asynchronous call?
(41 answers)
Variables set during $.getJSON function only accessible within function
(6 answers)
Closed 8 years ago.
I have a small piece of js that pull some data from via ajax.
solarSystem = "test";
$.getJSON( "ajax/getLocation.php", function( data ) {
var items = [];
$.each( data, function( key, val ) {
solarSystem = val;
});
});
alert(solarSystem);
val is being set but its not outputting to the alert if i put the alert in that function it works. I assume its something to do with scope but im new to js if anyone can point me in the right direction it would be much apreciated.
While JavaScript is single-threaded, it can perform tasks asynchronously, i.e. function calls do not necessarily complete before the next line of code. AJAX (asynchronous JavaScript and XML) calls do just that. For example,
console.log("starting")
$.getJSON("path/to/resource", function (data) {
console.log("data retrieved")
})
console.log("finished")
The above code will most likely print starting and finished before it prints data retrieved. This is because $.getJSON is asynchronous. It requests a resource on a server somewhere, waits for a response, then calls the anonymous function provided as a callback, i.e. the function (data) { /* etc */ } part.
In your case, the callback function is running after alert, even though it is written above it in your code. If you want to alert(solarSystem), you'll need to place that inside of your $.getJSON call to ensure it is processed correctly:
solarSystem = "test"
$.getJSON("ajax/getLocation.php", function (data) {
var items = []
$.each(data, function (key, val) {
solarSystem = val
})
alert(solarSystem)
})
Anything inside the $.getJSON cannot access anything outside without some changes to your code. You need what is a called a callback function, and the problem is due to variable scoping.
solarSystem = "test";
function setSolarSystem(newSystem){
solarSystem = newSystem;
alert(solarSystem);
}
$.getJSON( "ajax/getLocation.php", function( data ) {
var items = [];
$.each( data, function( key, val ) {
setSolarSystem(val);
});
});
This question already has answers here:
How do I return the response from an asynchronous call?
(41 answers)
Closed 8 years ago.
I have a function that returns JSON information. I want to be able to store that into a variable and then use alert and the variable name to display the content returned from that function. Here is my code:
var getStuff2 (function (num) {
$.getJSON('http://whateverorigin.org/get?url=' + encodeURIComponent('http://catholic.com/api-radio/' + num) + '&callback=?', function(data) {
//console.log(data.contents);
//$('#response').text(data.contents);
obj = data.contents;
//alert(obj);
}];
return data.contents;
});
});
function getData(){
getStuff2(6387);
}
getData();
alert(getStuff2);
You have to put the alert inside of the callback handler for the AJAX function. AJAX calls are asynchronous which means that if you do something like this, the return won't work in the order you expect:
function getData() {
doAjax(function(data) {
obj = data.contents;
});
alert(obj);
}
You see, the AJAX call will return when it returns, and all of the code after it will just keep executing while the AJAX call is still waiting on a response.
So what you have to do is this:
function getData() {
doAjax(function(data) {
obj = data.content;
alert(obj);
});
}
I assume, that data.contents is a object, so your alert output will look something like [object object], so you just can't alert the content.
To make it globally available just store the content in a gloabl variable.
var result;
var getStuff2 (function(num) {
$.getJson(url, function(data)
result = data.contents;
});
}),
asynchronous functions cannot return values. Instead you need to explicitly do something with the value from inside the AJAX callback.
function getStuff(num, onContents){
$.getJSON(..., function(data){
//call the oncontents callback instead of returning
onContents(data.contents);
});
}
//when calling getstuff, pass a function that tells what to do with the contents
getStuff(6387, function(contents){
console.log(contents);
});
This question already has answers here:
Closed 11 years ago.
Possible Duplicate:
return from a function ajax
JavaScript asynchronous return value / assignment with jQuery
How do you output the data variable to the second alert statement.
$.post("index.ajax.php", { lookup:value },
function(data) {
alert(data)
test = data;
})
alert(test)
Or would it be possible to do something like this?
function confirm_search(input) {
$.post("index.ajax.php", { lookup:input },
function(data) {
$("#temp").val(data);
})
}
var test = confirm_search(value);
alert(test);
You can't.
AJAX is asynchronous. The response is not available until some time later.
The jQuery.post call will begin the AJAX request, and return the jqXHR object which is handling the request. The script will continue to be executed (alert(test) will fire next), and then some time later when the AJAX request has completed (i.e. the HTTP response is received), the callback:
function(data) {
alert(data)
test = data;
}
will be executed.
If you are strict with scenerio, define test variable in global scope, in that way you can use it anywhere in your code.
Try this way :
var test;
$.post("index.ajax.php", { lookup:value },
function(data) {
alert(data)
test = data;
})
function alertTest(){
if(test != undefined) {
alert(test);
clearInterval(t);
}
}
var t = setInterval(alertTest, 1000);
You will get test value when ajax request is completed and test is assigned