I have a very specific issue on custom javascript code in gtm.
I have a regex match that defines the output variable.
It works for 99% of the tests, but bugs on a few ones, and I have no idea why.
The goal is to format output value to use as a content grouping in GA.
Here are 2 of the strings that don't trigger the regex:
Checkout-Login
__SYSTEM__Page-Render
And here is the code :
if({{page_template}}.test(/(__SYSTEM__Page-Render|Blog)/g)){grouping = "Content pages";}
else if({{page_template}}.test(/(Checkout|Shipping|Payment|Order)/g)){grouping = "Checkout";}
Would you have any idea why it doesn't work ?
Thanks
I need to highlight the keyword used for search in the blog. So far i managed to used the following script http://www.jquery.info/scripts/SearchHighlight/demo_en.html
problem is when i try to use the same for Arabic it fails due to Unicode issue. Fiddle example: http://jsfiddle.net/gq4hkvgd/6/
var val2 = "Per id";
// var val2 = "النظر";
var options = {
exact: "exact",
style_name_suffix:false,
keys:val2
}
$('.wrapper').SearchHighlight(options);
I looked for such example which can work for both english & arabic but could not find.
Possible solution might be in this link http://tiku.io/questions/1079426/using-regex-and-jquery-to-select-patterns-in-arabic-text
but i am not able to resolve way this script to be modified to work with arabic version also.
SearchHighlight has hard-coded assumptions about Latin-based text (such as regexAccent) and might even assume left-to-right (I didn't analyze the code carefully enough to tell). You might want to look for a search plugin that specifically supports non-Latin codepages.
Nevertheless, SearchHighlight appears to work with Arabic after making one small change:
exact: "partial",
To match the arabic letters with regex in JavaScript use:
[\u0600-\u06FF]
I'm using the following to exclude emojis/emoticons from a string in php. How do I do the same with javascript or jQuery?
preg_replace('/([0-9|#][\x{20E3}])|[\x{00ae}|\x{00a9}|\x{203C}|\x{2047}|\x{2048}|\x{2049}|\x{3030}|\x{303D}|\x{2139}|\x{2122}|\x{3297}|\x{3299}][\x{FE00}-\x{FEFF}]?|[\x{2190}-\x{21FF}][\x{FE00}-\x{FEFF}]?|[\x{2300}-\x{23FF}][\x{FE00}-\x{FEFF}]?|[\x{2460}-\x{24FF}][\x{FE00}-\x{FEFF}]?|[\x{25A0}-\x{25FF}][\x{FE00}-\x{FEFF}]?|[\x{2600}-\x{27BF}][\x{FE00}-\x{FEFF}]?|[\x{2900}-\x{297F}][\x{FE00}-\x{FEFF}]?|[\x{2B00}-\x{2BF0}][\x{FE00}-\x{FEFF}]?|[\x{1F000}-\x{1F6FF}][\x{FE00}-\x{FEFF}]?/u', '', $text);
This is what I try to do
$('#edit.popup .btn.save').live('click',function(e) {
var item_id = $(this).attr('id');
var edited_text = $('#edit.popup textarea').val().replace(/([0-9|#][\x{20E3}])|[\x{00ae}|\x{00a9}|\x{203C}|\x{2047}|\x{2048}|\x{2049}|\x{3030}|\x{303D}|\x{2139}|\x{2122}|\x{3297}|\x{3299}][\x{FE00}-\x{FEFF}]?|[\x{2190}-\x{21FF}][\x{FE00}-\x{FEFF}]?|[\x{2300}-\x{23FF}][\x{FE00}-\x{FEFF}]?|[\x{2460}-\x{24FF}][\x{FE00}-\x{FEFF}]?|[\x{25A0}-\x{25FF}][\x{FE00}-\x{FEFF}]?|[\x{2600}-\x{27BF}][\x{FE00}-\x{FEFF}]?|[\x{2900}-\x{297F}][\x{FE00}-\x{FEFF}]?|[\x{2B00}-\x{2BF0}][\x{FE00}-\x{FEFF}]?|[\x{1F000}-\x{1F6FF}][\x{FE00}-\x{FEFF}]?/u, '');
$('#grid li.image#' + item_id + ' img').attr('data-text', edited_text);
});
I found this suggestion in another post on Stack Overflow, but it's not working. It's still allowing emojis from ex ios.
.replace(/([\uE000-\uF8FF]|\uD83C[\uDF00-\uDFFF]|\uD83D[\uDC00-\uDDFF])/g, '')
What I try to achieve is to not allow emojis in textfield, and if an emoji is inserted (from ex ios keyboard) it will be replaced by nothing. It works with php. Someone here who can help me out with this?
Based on the answer from mb21, this regex did the job. No loop required!
/[\uD800-\uDBFF][\uDC00-\uDFFF]/g
As pointed out in this answer, JavaScript doesn't support Unicode code points outside the Basic Multilingual Plane (where iOS emojis lie).
I highly recommend reading The Absolute Minimum Every Software Developer Absolutely, Positively Must Know About Unicode and Character Sets (No Excuses!). Then you'll understand what was meant with:
So some indirect approach is needed. Cf. to JavaScript strings outside of the BMP.
For example, you could look for code points in the range [\uD800-\uDBFF] (high surrogates), and when you find one, check that the next code point in the string is in the range [\uDC00-\uDFFF] (if not, there is a serious data error), interpret the two as a Unicode character, and replace them by whatever you wish to put there. This looks like a job for a simple loop through the string, rather than a regular expression.
Trying to replace certain words in HTML pages with the same word but as a URL linking to that resource.
For example, replace the word 'MySQL' with MySQL
Using the JS replace function with regex, and it's doing the replacing just fine.
BUT it's also replacing words that are already part of URLs... which is the problem.
For the MySQL example, it's replacing BOTH the "MySQL" text that's already linked, AND the URL leading to mysql.com, so breaking the already existing link.
Is there a way to update the inline regex (in the .replace call) to NOT do replacing in existing links, i.e. elements?
Here's the replace code:
var NewHTML = OriginalHTML
.replace(/\bJavaScript\b/gi, "$&")
.replace(/\bMySQL\b/gi, "$&")
;
Here's the full sample code (tried to paste it inline but wasn't looking right with the backticks):
http://pastie.org/private/v4l2s2c42aqduqlopurpw
Went through the JS regexp reference (here), and tried various other permutations in the regex matching, like the following, but all that does it make it not match ANY words on the page...
.replace(/\b(\<a\>*!\>)JavaScript\b/i,xxxxx
The following regex DOES prevent the match from happening wherever the word is literally touching a slash or a dash... but that's not the solution (and it does not fix the mysql example above):
.replace(/\b(?!\>)(?!\-)(?!\/)MySQL\b(?!\-)(?!\/)/gi, "$&")`
I've read through the related threads on stackoverflow and elsewhere, but can't seem to find this particular scenario, not in JavaScript anyway.
Any help would be greatly appreciated. :-)
Thanks!
You could change your regex to exclude keywords that precede the end anchor tag, </a>:
.replace(/\bMySQL\b(?![^<]*?<\/a>)/gi, "$&")
See jsfiddle for example.
A negative lookahead should be sufficient:
.replace(/\bMySQL(?!\.com)\b/gi, "$&")
I have to find the first url in the text with a regular expression:
for example:
I love this website:http://www.youtube.com/music it's fantastic
or
[ es. http://www.youtube.com/music] text
I looked into this issue last year and developed a solution that you may want to look at - See: URL Linkification (HTTP/FTP) This link is a test page for the Javascript solution with many examples of difficult-to-linkify URLs.
My regex solution, written for both PHP and Javascript - is not simple (but neither is the problem as it turns out.) For more information I would recommend also reading:
The Problem With URLs by Jeff Atwood, and
An Improved Liberal, Accurate Regex Pattern for Matching URLs by John Gruber
The comments following Jeff's blog post are a must read if you want to do this right...
Note that this question gets asked a lot. Maybe do a search next time :)
You can't do this perfectly with a regular expression. You may be interested in this blog post. There is a bit more information on Regex Guru, but even those look very fragile. You will need to have additional checks outside of your regular expression to catch the edge cases.
Identifying URLs is tricky because they are often surrounded by punctuation marks and because users frequently do not use the full form of the URL. Many JavaScript functions exist for replacing URLs with hyperlinks, but I was unable to find one that works as well as the urlize filter in the Python-based web framework Django. I therefore ported Django's urlize function to JavaScript: https://github.com/ljosa/urlize.js
It actually would not pick up the URL in your example because there is a colon right before the URL. But if we modify the example a little:
urlize("I love this website: http://www.youtube.com/music it's fantastic", true, true)
=> 'I love this website: http://www.youtube.com/music it's fantastic"'
Note the second argument which, if true, inserts rel="nofollow" and the third argument which, if true, quotes characters that have special meaning in HTML.
This might work->
\b(([\w-]+://?|www[.])[^\s()<>]+(?:\([\w\d]+\)|([^[:punct:]\s]|/)))
Found it somewhere
Will find links ->
http://foo.com/blah_blah/
(Something like http://foo.com/blah_blah)
http://foo.com/blah_blah_(wikipedia)
Hope this works....
i am using this regex : :) ( its translated ABNF )
[a-zA-Z]([a-zA-Z]|[0-9]|\+|\-|\.)*:\/\/((([a-zA-Z]|[0-9]|-|\.|_|~)|%[0-9A-Fa-f][0-9A-Fa-f]|[!$&'\(\)\*\+,;=]|:)*#)?(\[((([0-9A-Fa-f]{1,4}:){6}([0-9A-Fa-f]{1,4}:[0-9A-Fa-f]{1,4}|(25[0-5]|2[0-4][0-9]|1[0-9]{2}|[1-9][0-9]|[0-9])\.(25[0-5]|2[0-4][0-9]|1[0-9]{2}|[1-9][0-9]|[0-9])\.(25[0-5]|2[0-4][0-9]|1[0-9]{2}|[1-9][0-9]|[0-9])\.(25[0-5]|2[0-4][0-9]|1[0-9]{2}|[1-9][0-9]|[0-9]))|::([0-9A-Fa-f]{1,4}:){5}([0-9A-Fa-f]{1,4}:[0-9A-Fa-f]{1,4}|(25[0-5]|2[0-4][0-9]|1[0-9]{2}|[1-9][0-9]|[0-9])\.(25[0-5]|2[0-4][0-9]|1[0-9]{2}|[1-9][0-9]|[0-9])\.(25[0-5]|2[0-4][0-9]|1[0-9]{2}|[1-9][0-9]|[0-9])\.(25[0-5]|2[0-4][0-9]|1[0-9]{2}|[1-9][0-9]|[0-9]))|([0-9A-Fa-f]{1,4})?::([0-9A-Fa-f]{1,4}:){4}([0-9A-Fa-f]{1,4}:[0-9A-Fa-f]{1,4}|(25[0-5]|2[0-4][0-9]|1[0-9]{2}|[1-9][0-9]|[0-9])\.(25[0-5]|2[0-4][0-9]|1[0-9]{2}|[1-9][0-9]|[0-9])\.(25[0-5]|2[0-4][0-9]|1[0-9]{2}|[1-9][0-9]|[0-9])\.(25[0-5]|2[0-4][0-9]|1[0-9]{2}|[1-9][0-9]|[0-9]))|(([0-9A-Fa-f]{1,4}:){0,1}[0-9A-Fa-f]{1,4})?::([0-9A-Fa-f]{1,4}:){3}([0-9A-Fa-f]{1,4}:[0-9A-Fa-f]{1,4}|(25[0-5]|2[0-4][0-9]|1[0-9]{2}|[1-9][0-9]|[0-9])\.(25[0-5]|2[0-4][0-9]|1[0-9]{2}|[1-9][0-9]|[0-9])\.(25[0-5]|2[0-4][0-9]|1[0-9]{2}|[1-9][0-9]|[0-9])\.(25[0-5]|2[0-4][0-9]|1[0-9]{2}|[1-9][0-9]|[0-9]))|(([0-9A-Fa-f]{1,4}:){0,2}[0-9A-Fa-f]{1,4})?::([0-9A-Fa-f]{1,4}:){2}([0-9A-Fa-f]{1,4}:[0-9A-Fa-f]{1,4}|(25[0-5]|2[0-4][0-9]|1[0-9]{2}|[1-9][0-9]|[0-9])\.(25[0-5]|2[0-4][0-9]|1[0-9]{2}|[1-9][0-9]|[0-9])\.(25[0-5]|2[0-4][0-9]|1[0-9]{2}|[1-9][0-9]|[0-9])\.(25[0-5]|2[0-4][0-9]|1[0-9]{2}|[1-9][0-9]|[0-9]))|(([0-9A-Fa-f]{1,4}:){0,3}[0-9A-Fa-f]{1,4})?::[0-9A-Fa-f]{1,4}:([0-9A-Fa-f]{1,4}:[0-9A-Fa-f]{1,4}|(25[0-5]|2[0-4][0-9]|1[0-9]{2}|[1-9][0-9]|[0-9])\.(25[0-5]|2[0-4][0-9]|1[0-9]{2}|[1-9][0-9]|[0-9])\.(25[0-5]|2[0-4][0-9]|1[0-9]{2}|[1-9][0-9]|[0-9])\.(25[0-5]|2[0-4][0-9]|1[0-9]{2}|[1-9][0-9]|[0-9]))|(([0-9A-Fa-f]{1,4}:){0,4}[0-9A-Fa-f]{1,4})?::([0-9A-Fa-f]{1,4}:[0-9A-Fa-f]{1,4}|(25[0-5]|2[0-4][0-9]|1[0-9]{2}|[1-9][0-9]|[0-9])\.(25[0-5]|2[0-4][0-9]|1[0-9]{2}|[1-9][0-9]|[0-9])\.(25[0-5]|2[0-4][0-9]|1[0-9]{2}|[1-9][0-9]|[0-9])\.(25[0-5]|2[0-4][0-9]|1[0-9]{2}|[1-9][0-9]|[0-9]))|(([0-9A-Fa-f]{1,4}:){0,5}[0-9A-Fa-f]{1,4})?::[0-9A-Fa-f]{1,4}|(([0-9A-Fa-f]{1,4}:){0,6}[0-9A-Fa-f]{1,4})?::)|v[0-9A-Fa-f]\.(([a-zA-Z]|[0-9]|-|\.|_|~)|[!$&'\(\)\*\+,;=]|:))\]|(25[0-5]|2[0-4][0-9]|1[0-9]{2}|[1-9][0-9]|[0-9])\.(25[0-5]|2[0-4][0-9]|1[0-9]{2}|[1-9][0-9]|[0-9])\.(25[0-5]|2[0-4][0-9]|1[0-9]{2}|[1-9][0-9]|[0-9])\.(25[0-5]|2[0-4][0-9]|1[0-9]{2}|[1-9][0-9]|[0-9])|(([a-zA-Z]|[0-9]|-|\.|_|~)|%[0-9A-Fa-f][0-9A-Fa-f]|[!$&'\(\)\*\+,;=])*)(:[0-9]*)?(((\/(([a-zA-Z]|[0-9]|-|\.|_|~)|%[0-9A-Fa-f][0-9A-Fa-f]|[!$&'\(\)\*\+,;=]|:|#)*)*|\/((([a-zA-Z]|[0-9]|-|\.|_|~)|%[0-9A-Fa-f][0-9A-Fa-f]|[!$&'\(\)\*\+,;=]|:|#){1}(\/(([a-zA-Z]|[0-9]|-|\.|_|~)|%[0-9A-Fa-f][0-9A-Fa-f]|[!$&'\(\)\*\+,;=]|:|#)*)*)?|(([a-zA-Z]|[0-9]|-|\.|_|~)|%[0-9A-Fa-f][0-9A-Fa-f]|[!$&'\(\)\*\+,;=]|:|#){1}(\/(([a-zA-Z]|[0-9]|-|\.|_|~)|%[0-9A-Fa-f][0-9A-Fa-f]|[!$&'\(\)\*\+,;=]|:|#)*)*|(([a-zA-Z]|[0-9]|-|\.|_|~)|%[0-9A-Fa-f][0-9A-Fa-f]|[!$&'\(\)\*\+,;=]|#){1}(\/(([a-zA-Z]|[0-9]|-|\.|_|~)|%[0-9A-Fa-f][0-9A-Fa-f]|[!$&'\(\)\*\+,;=]|:|#)*)*))?\/?(\?((([a-zA-Z]|[0-9]|-|\.|_|~)|%[0-9A-Fa-f][0-9A-Fa-f]|[!$&'\(\)\*\+,;=]|:|#)|\/|\?)*)?(\#((([a-zA-Z]|[0-9]|-|\.|_|~)|%[0-9A-Fa-f][0-9A-Fa-f]|[!$&'\(\)\*\+,;=]|:|#)|\/|\?)*)?
You can use the following regex expression for extracting any type of url coming in message.
String regex = "(http(s)?:\/\/.)?(www\.)?[-a-zA-Z0-9#:%._\+~#=]{2,256}\.[a-z]{2,6}\b([-a-zA-Z0-9#:%_\+.~#?&/=]*)";
Typescript/Angular
This works for me:
const regExpressionUrl = new RegExp(/(https?:\/\/[^\s]+)/g); //detect URL
Ref: https://www.regextester.com/96249%7CRegular