Pass a value to multiple PHP pages at once with JQuery - javascript

My inexperience has me here asking this question.
Can I pass a value to multiple PHP pages in JQuery?
Here is an example of what I am trying to do.
$(function() {
$("#account").change(function() {
$("#facilities").load("displayfacilities.php?q=" + $("#account").val());
$("#facilities").load("updatefacilities.php?f=" + $("#account").val());
});
});
When the user changes a selection within a drop down list, a unique ID will be sent over to displayfacilities.php. I also need that ID in updatefacilities.php which is called from displayfacilities.php.
Is this a bad idea, or is there a better way?

Try to make use of $_SESSION and example of the usage.
This object allows you to store and retrieve data and a usual use case is to share this data across multiple pages within a session.
ex.
$(function() {
$("#account").change(function() {
// store value in superglobal variable and retrieved
// by session_start() in php script, see usage examples above
<?php $_SESSION['some_key'] = *some_value* ?>
// the following value however needs to be sent to server
// either via AJAX or some request.
$("#account").val();
});
});
Hope this helps.

Check this out,
First call ajax, when the response is received, make the second ajax call.
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.2/jquery.min.js"></script>
<script type="text/javascript">
$(function() {
$("#account").change(function() {
var dataString1 = "q="+$("#account").val();
$.ajax
({
url: "displayfacilities.php",
type : "POST",
cache : false,
data : dataString1,
success: function(result1)
{
alert("Response from PHP file 1");
var dataString2 = "f=" + $("#account").val();
$.ajax
({
url: "updatefacilities.php",
type : "POST",
cache : false,
data : dataString2,
success: function(result2)
{
alert("Response from PHP file 2");
}
}
});
});
});
});
</script>

Related

Passing data with POST with AJAX

I'm trying to POST some data to another page with AJAX but no info is going, i'm trying to pass the values of two SELECT (Dropdown menus).
My AJAX code is the following:
$('#CreateHTMLReport').click(function()
{
var DeLista = document.getElementById('ClienteDeLista').value;
var AteLista = document.getElementById('ClienteParaLista').value;
$.ajax(
{
url: "main.php",
type: "POST",
data:{ DeLista : DeLista , AteLista : AteLista },
success: function(data)
{
window.location = 'phppage.php';
}
});
});
Once I click the button with ID CreateHTMLReport it runs the code above, but it's not sending the variables to my phppage.php
I'm getting the variables like this:
$t1 = $_POST['DeLista'];
$t2 = $_POST['ParaLista'];
echo $t1;
echo $t2;
And got this error: Notice: Undefined index: DeLista in...
Can someone help me passing the values, I really need to be made like this because I have two buttons, they are not inside one form, and when I click one of them it should redirect to one page and the other one to another page, that's why I can't use the same form to both, I think. I would be great if someone can help me with this, on how to POST those two values DeLista and ParaLista.
EDIT
This is my main.php
$('#CreateHTMLReport').on('click',function() {
$.ajax({
// MAKE SURE YOU HAVE THIS PAGE CREATED!!
url: "main.php",
type: "POST",
data:{
// You may as well use jQuery method for fetching values
DeLista : $('#ClienteDeLista').val(),
AteLista : $('#ClienteParaLista').val()
},
success: function(data) {
// Use this to redirect on success, this won't get your post
// because you are sending the post to "main.php"
window.location = 'phppage.php';
// This should write whatever you have sent to "main.php"
//alert(data);
}
});
});
And my phppage.php
if(!empty($_POST['DeLista'])) {
$t1 = $_POST['DeLista'];
# You should be retrieving "AteLista" not "ParaLista"
$t2 = $_POST['AteLista'];
echo $t1.$t2;
# Stop so you don't write the default text.
exit;
}
echo "Nothing sent!";
And I'm still getting "Nothing Sent".
I think you have a destination confusion and you are not retrieving what you are sending in terms of keys. You have two different destinations in your script. You have main.php which is where the Ajax is sending the post/data to, then you have phppage.php where your success is redirecting to but this is where you are seemingly trying to get the post values from.
/main.php
// I would use the .on() instead of .click()
$('#CreateHTMLReport').on('click',function() {
$.ajax({
// MAKE SURE YOU HAVE THIS PAGE CREATED!!
url: "phppage.php",
type: "POST",
data:{
// You may as well use jQuery method for fetching values
DeLista : $('#ClienteDeLista').val(),
AteLista : $('#ClienteParaLista').val()
},
success: function(data) {
// This should write whatever you have sent to "main.php"
alert(data);
}
});
});
/phppage.php
<?php
# It is prudent to at least check here
if(!empty($_POST['DeLista'])) {
$t1 = $_POST['DeLista'];
# You should be retrieving "AteLista" not "ParaLista"
$t2 = $_POST['AteLista'];
echo $t1.$t2;
# Stop so you don't write the default text.
exit;
}
# Write a default message for testing
echo "Nothing sent!";
You have to urlencode the data and send it as application/x-www-form-urlencoded.

How to pass variable inside dom using ajax?

Sorry it was a mistake to post a question about making a condition to checkbox earlier without further investigation. It seems i need to pass my variables here
function setsession(sessionid,action, data){
$("#totalselection").show();
$.ajax({
type:'POST',
url:'test.php',
data:'sBorrow='+sessionid+'&action='+action,
cache:false,
success:function(data){
var out = "<p align='center' style='text-decoration:none;color:white;'>Total Selection: "+data+"<br/>Click here to submit your request <a href='borrowform.php?subid=borrow' id='submitborrow' name='submitborrow' style='text-align:center;'><input type='button' value='REQUEST' id='submitborrow' name='submitborrow'></a> || Click here to clear the selection <a href='#' style='text-align:center;'><input type='button' value='CLEAR'></a></p>";
datachecked(data, this.indexValue);
$("#totalselection").html(out)
}
});
}
to the DOM of other php page. NOT TO THIS URL. It was different page. Im still not clear to this ajax and i know that ajax can only send to 1 url only. However i want the data value that this ajax hold to put it inside my php echo and make if else statement using that data. Should i create one more ajax? or else? How to send data from success to my php page and received it?
I think you are asking how to send your variable in ajax call. Try this simple syntax of jquery ajax call by which you can send any number of variables.
$.ajax({
url : 'process.php',
method: 'post',
data : {
var1 : val1,
var2 : val2
// by this way you can send multiple variable
},
success : function(response){
alert(response)
}
});
process.php:
$val1 = $_REQUEST['var1'];
$val2 = $_REQUEST['var2'];
// use it in your own way
$("document").ready(function () {
data = {
'name':'ys',
'surname':'ysss',
'pass':'123456',
'number':5
};
$.post('content.php',data,function(response,status){
if(status == 'success'){
$("#information").html(response);
}
});
you can send data as long as possible by writing to the 'data'

Extract data from current URL and use it in ajax call as a paramenter

I am developing a website in which only 1 html page is there in which I first fethch the url & gets the id from url and send it to api using ajax call. On success, I displays data of the given id from url.My code is as-
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js"></script>
<script type="text/javascript">
$(document).ready(function () {
$('#main').hide();
var url = window.location.href;
var formno = url.substr(url.lastIndexOf('/') + 1);
if (formno != 'Login.html') {
var apiUrl = 'http://localhost:801/api/api/Patient/Get';
$.ajax({
url: apiUrl,
crossDomain: true,
contentType: "application/json",
type: 'GET',
data: { formNo: formno },
success: function (result) {
$('#main').show();
alert("Success" + result)
},
error: function (result) {
alert("error :: " + JSON.stringify(result))
}
});
}
});
</script>
when I use the url as abc.in#1 it displays the success alert but I want to give the url in format abc.in/1 at that time it gives
HTTP Error 404.0 - Not Found
The resource you are looking for has been removed, had its name changed, or is temporarily unavailable.
Why it can not find the page? Is there any solution for this?
I want to give plain url as abc.in/1 where 1 is id and which is dynamic.
Is there any solution?
Your browser is probably trying to access document on location abc.in/1, which doesn't exist. You will need some server side logic for this, e.g. php router which will always serve your document, and additonal parameters will be processed by it. abc.in#1 anchor is different type of url parameter, which purpose is to be processed by document or javascript on client side.

Javascript get current page html (after editing)

I have a page that I have edited after load and what I want to do is get the pages current HTML and pass that off to a PHP script.
I first passed document.documentElement.innerHTML but that ended up including a bunch of computed style garbage at the top which I did not want. After googling around I found I could use ajax to get a copy of the current file on the server and then replace the edited part afterwards.
I can get the copy of the file using this:
var url = window.location.pathname;
var filename = url.substring(url.lastIndexOf('/')+1);
$.ajax({
url: filename,
async: false, // asynchronous request? (synchronous requests are discouraged...)
cache: false, // with this, you can force the browser to not make cache of the retrieved data
dataType: "text", // jQuery will infer this, but you can set explicitly
success: function( data, textStatus, jqXHR ) {
origPage = data; // can be a global variable too...
// process the content...
}
});
Which works fine and gets me the html I expected and see when viewing the page in notepad.
The next step is what I cannot figure out. All I want to do is swap out the innerHTML of a div with an id of 'editor' with what the current value is, so I have tried this:
origPage.getElementById('editor').innerHTML = e.html;
But I get the error "TypeError: undefined is not a function". I must be doing something simple wrong I feel but I don't know the proper formatting to do this. I have tried the following variations:
alert($(origPage).getElementById('editor').innerHTML);
//Different attempt
var newHtml = $.parseHTML( origPage );
alert($(newHtml).getElementById('editor').innerHTML);
//Different attempt
alert($(origPage).html().getElementById('editor').innerHTML);
But I always get "TypeError: undefined is not a function" or "TypeError: Cannot read property 'getElementById' of undefined". How can I do this properly?
EDIT:
Complete page html below:
<!DOCTYPE html>
<html>
<body>
<div id="editor">
<h1>This is editable.</h1>
<p>Click me to start editing.</p>
</div>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.2/jquery.min.js"></script>
<script type="text/javascript" src="snapeditor.js"></script>
<script type="text/javascript">
var editor = new SnapEditor.InPlace("editor", {onSave: function (e) {
var isSuccess = true;
//var origPage = e.html;
var origPage;
var url = window.location.pathname;
var filename = url.substring(url.lastIndexOf('/')+1);
// Actually perform the save and update isSuccess.
// Javascript:
$.ajax({
url: filename,
async: false, // asynchronous request? (synchronous requests are discouraged...)
cache: false, // with this, you can force the browser to not make cache of the retrieved data
dataType: "text", // jQuery will infer this, but you can set explicitly
success: function( data, textStatus, jqXHR ) {
origPage = data; // can be a global variable too...
// process the content...
}
});
//origPage shows expected html as this point
//alert($(origPage).getElementById('editor').innerHTML);
//alert($(origPage).html().getElementById('editor').innerHTML);
$(origPage).getElementById('editor').innerHTML = e.html;//fails here
alert(origPage);
//alert(newHtml.getElementById('editor').innerHTML);
$.ajax({
data: {html: origPage, docName: 'example1.html'},
url: 'savePage.php',
method: 'POST', // or GET
success: function(msg) {
alert(msg);
isSuccess = true;
}
});
return isSuccess || "Error";
},
onUnsavedChanges: function (e) {
if(confirm("Save changes?")) {
if(e.api.execAction("save")){
//location.reload();
}
} else {
e.api.execAction("discard");
}
}});
</script>
</body>
</html>
It seems that you get the user's changes in a variable - you called the var e.html. That is not a good variable name, BTW. If you can, change it to something like htmlEdited
Question: If you add the command alert(e.html); what do you get? Do you see the HTML after user edits?
If yes, then what you need to do is send that variable to a PHP file, which will receive the data and stick it into the database.
Code to send the data:
javascript/jQuery:
alert(e.html); //you should see the user-edited HTML
$.ajax({
type: 'post',
url: 'another_php_file.php',
data: 'userStuff=' + e.html, //var_name = var_contents
success: function(d){
window.location.href = ''; //redisplay this page
}
});
another_php_file.php:
<?php
$user_edits = $_POST['userStuff']; //note exact same name as data statement above
mysql_query("UPDATE `your_table_name` SET `your_col_name` = '$user_edits' ") or die(mysql_error());
echo 'All donarino';
The AJAX javascript code will send the var contents to a PHP file called another_php_file.php.
The data is received as $user_edits, and then inserted into your MySQL db
Finally, I presume that if you redisplay that page it will once again grab the contents of the #editor div from the database?
This is where you haven't provided enough information, and why I wanted to see all your code.
ARE you populating that div from the database? If not, then how do you expect the page to be updated after refreshing the page?
You would benefit from doing some tutorials at phpacademy.org or a thenewboston.com. Do these two (free) courses and you'll be an expert:
https://phpacademy.org/videos/php-and-mysql-with-mysqli
https://phpacademy.org/videos/oop-loginregister-system
If all you need to do is insert the contents of e.html to replace the #editor div, then try this:
$('#editor').html(e.html);
HOWEVER, you need an event to trigger that code. Are you able to do this?
alert(e.html);
If so, then put the first bit of code at that same spot. If not, we need more information about when your code receives that variable -- that is where you put the $('#editor').html(e.html); statement.

javascript or ajax to update database with asp.net mvc?

I have a function here from a change event on a dropdownlist. When the selection gets changed I want to update a row in my database. Should I use javascript or ajax. I don't want the page to be refreshed. I think it should be ajax, but not sure? If ajax, can anyone point me to a tutorial/video/etc?
Here is where I want to update my db row.
var statusdropdown = document.getElementById("enumstatus");
statusdropdown.addEventListener("change", function(event) {
// call db and update row
}, false);
Looks like you using asp.net mvc.
You can write your ajax calls with pure javascript Ajax docs or the easiest way, using JQuery.
You need to add one action on your controller to receive the ajax data, and then insert/update your db.
See this, this and this.
Most common scenario would be making an ajax call using HTTP POST/PUT to a controller method, which would then handle the data and update the database directly or pass through to your service/data layer code.
Probably the easiest way to make the call would be using the jQuery.ajax method. Documentation can be found here: http://api.jquery.com/jquery.ajax/
You can try something like this
<script type="text/javascript">
$(function () {
$('#btnSubmit').click(function () {
var name = $('#TextBox1').val();
var email = $('#TextBox2').val();
if (name != '' && email != '') {
$.ajax
({
type: 'POST',
url: 'Home/UpdateDB', //if it is plain asp.net then UpdateDB is declared as WebMethod
async: false,
data: "{'name':'" + name + "','email':'" + email + "'}",
contentType: 'application/json; charset =utf-8',
success: function (data) {
var obj = data.d;
if (obj == 'true') {
$('#TextBox1').val('');
$('#TextBox2').val('');
alert("Data Saved Successfully");
}
},
error: function (result) {
alert("Error Occured, Try Again");
}
});
}
})
});
</script>
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