How do I reverse the words in this string including the punctuation?
String.prototype.reverse = function () {
return this.split('').reverse().join('');
}
var str = "This is fun, hopefully.";
str.reverse();
Currently I am getting this:
".yllufepoh ,nuf si sihT"
When I want to return this:
"sihT si nuf, yllufepoh."
You could reverse each word instead of the whole string, but you have to keep spaces, periods etc seperate, so a word boundary is needed
String.prototype.reverse = function () {
return this.split(/\b/g).map(function(word) {
return word.split('').reverse().join('');
}).join('');
}
var str = "This is fun, hopefully.";
document.body.innerHTML = str.reverse();
Note that this moves the comma one space as it gets the comma and the space in one boundary and swaps them. If the comma needs to stay in the same spot, split on spaces as well, and change the regex to /(\b|\s)/g
Simply reversing the string wont give the solution.
Get each word.
Reverse It
Again rejoin
var str = "This is fun, hopefully.";
alert(str.split("").reverse().join("").split(" ").reverse().join(" "));
You can imagine that you receive a stream of letters and you have to construct words based on some separators (like: spaces, commas, dashes .etc).
While reading each character you keep constructing the word in reverse.
When you hit any separator you finished the word.
Now you just add it to the result and append the separator (this way the separators will not be put at the beginning of the word, but at the end).
Here is an example:
const inputString = "HELLO, Welcome to Google's meeting. My name is Jean-Piere... Bye";
console.log('Normal words: ', inputString);
const result = reverseWords(inputString);
console.log('Words reversed: ', result);
function reverseWords(str='', separators=' ,.-') {
let result = '';
let word = '';
for (const char of str) {
if (separators.includes(char)) {
result += word + char;
word = '';
} else {
word = char + word;
}
}
// Adds last remaining word, if there is no separator at the end.
result += word;
return result;
}
const str = "This is fun, hopefully.";
function reverseWords(str){
const tempArr= str.split(" ")
let reversedTempArr=''
for(let i=0; i<tempArr.length;i++){
let tempStr=''
for(let j=tempArr[i].length-1;j>=0;j--){
tempStr += tempArr[i][j]
}
reversedTempArr += tempStr+ " "
}
return reversedTempArr
}
console.log(reverseWords(str))
You can reverse each word in a string in squence by splitting that word in to an array of words and then reversing each word and storing it in a new array and then joining that array as shown below.
//1) Reverse words
function reverseWords(str) {
// Go for it
let reversed;
let newArray=[];
reversed = str.split(" ");
for(var i = 0;i<reversed.length; i++)
{
newArray.push(reversed[i].split("").reverse().join(""));
}
return newArray.join(" ");
}
let reversedString = reverseWords("This is fun, hopefully.");
console.log("This is the reversed string : ",reversedString);
Related
I am working on a code to transform a string of text into a Sentence case which would also retain Acronyms. I did explore similar posts in StackOverflow, however, I couldn't find the one which suits my requirement.
I have already achieved the transformation of Acronyms and the first letter in the sentence. however, I ran into other issues like some letters in the sentence are still in Uppercase, especially texts in and after Double Quotes (" ") and camelcase texts.
Below is the code I am currently working on, I would need someone to help me Optimize the code and to fix the issues.
String.prototype.toSentenceCase = function() {
var i, j, str, lowers, uppers;
str = this.replace(/(^\w{1}|\.\s*\w{1})/gi, function(txt) {
return txt.charAt(0).toUpperCase() + txt.substr(1).toLowerCase();
});
// Certain words such as initialisms or acronyms should be left uppercase
uppers = ['Id', 'Tv', 'Nasa', 'Acronyms'];
for (i = 0, j = uppers.length; i < j; i++)
str = str.replace(new RegExp('\\b' + uppers[i] + '\\b', 'g'),
uppers[i].toUpperCase());
// To remove Special caharacters like ':' and '?'
str = str.replace(/[""]/g,'');
str = str.replace(/[?]/g,'');
str = str.replace(/[:]/g,' - ');
return str;
}
Input: play around: This is a "String" Of text, which needs to be cONVERTED to Sentence Case at the same time keeping the Acronyms as it is like Nasa.
Current Output: Play around - This is a String Of text, which needs to be cONVERTED to Sentence Case at the same time keeping the ACRONYMS as it is like NASA.
Expected Output: Play around - this is a string of text, which needs to be converted to sentence case at the same time keeping the ACRONYMS as it is like NASA.
Here's a runnable version of the initial code (I have slightly modified the input string):
String.prototype.toSentenceCase = function() {
var i, j, str, lowers, uppers;
str = this.replace(/(^\w{1}|\.\s*\w{1})/gi, function(txt) {
return txt.charAt(0).toUpperCase() + txt.substr(1).toLowerCase();
});
// Certain words such as initialisms or acronyms should be left uppercase
uppers = ['Id', 'Tv', 'Nasa', 'Acronyms'];
for (i = 0, j = uppers.length; i < j; i++)
str = str.replace(new RegExp('\\b' + uppers[i] + '\\b', 'g'),
uppers[i].toUpperCase());
// To remove Special caharacters like ':' and '?'
str = str.replace(/[""]/g,'');
str = str.replace(/[?]/g,'');
str = str.replace(/[:]/g,' - ');
return str;
}
const input = `play around: This is a "String" Of text, which needs to be cONVERTED to Sentence Case at the same time keeping the Acronyms as it is like Nasa. another sentence. "third" sentence starting with a quote.`
const result = input.toSentenceCase()
console.log(result)
I ran into other issues like some letters in the sentence are still in Uppercase, especially texts in and after Double Quotes (" ") and camelcase texts.
Some letters remain uppercased because you are not calling .toLowerCase() anywhere in your code. Expect in the beginning, but that regex is targetingonly the initial letters of sentences, not other letters.
It can be helpful to first lowercase all letters, and then uppercase some letters (acronyms and initial letters of sentences). So, let's call .toLowerCase() in the beginning:
String.prototype.toSentenceCase = function() {
var i, j, str, lowers, uppers;
str = this.toLowerCase();
// ...
return str;
}
Next, let's take a look at this regex:
/(^\w{1}|\.\s*\w{1})/gi
The parentheses are unnecessary, because the capturing group is not used in the replacer function. The {1} quantifiers are also unnecessary, because by default \w matches only one character. So we can simplify the regex like so:
/^\w|\.\s*\w/gi
This regex finds two matches from the input string:
p
. a
Both matches contain only one letter (\w), so in the replacer function, we can safely call txt.toUpperCase() instead of the current, more complex expression (txt.charAt(0).toUpperCase() + txt.substr(1).toLowerCase()). We can also use an arrow function:
String.prototype.toSentenceCase = function() {
var i, j, str, lowers, uppers;
str = this.toLowerCase();
str = str.replace(/^\w|\.\s*\w/gi, (txt) => txt.toUpperCase());
// ...
return str;
}
However, the initial letter of the third sentence is not uppercased because the sentence starts with a quote. Because we are anyway going to remove quotes and question marks, let's do it at the beginning.
Let's also simplify and combine the regexes:
// Before
str = str.replace(/[""]/g,'');
str = str.replace(/[?]/g,'');
str = str.replace(/[:]/g,' - ');
// After
str = str.replace(/["?]/g,'');
str = str.replace(/:/g,' - ');
So:
String.prototype.toSentenceCase = function() {
var i, j, str, lowers, uppers;
str = this;
str = str.toLowerCase();
str = str.replace(/["?]/g,'');
str = str.replace(/:/g,' - ');
str = str.replace(/^\w|\.\s*\w/gi, (txt) => txt.toUpperCase());
// ...
return str;
}
Now the initial letter of the third sentence is correctly uppercased. That's because when we are uppercasing the initial letters, the third sentence doesn't start with a quote anymore (because we have removed the quote).
What's left is to uppercase acronyms. In your regex, you probably want to use the i flag as well for case-insensitive matches.
Instead of using a for loop, it's possible to use a single regex to look for all matches and uppercase them. This allows us to get rid of most of the variables as well. Like so:
String.prototype.toSentenceCase = function() {
var str;
str = this;
str = str.toLowerCase();
str = str.replace(/["?]/g,'');
str = str.replace(/:/g,' - ');
str = str.replace(/^\w|\.\s*\w/gi, (txt) => txt.toUpperCase());
str = str.replace(/\b(id|tv|nasa|acronyms)\b/gi, (txt) => txt.toUpperCase());
return str;
}
And looks like we are now getting correct results!
Three more things, though:
Instead of creating and mutating the str variable, we can modify this and chain the method calls.
It might make sense to rename the txt variables to match variables, since they are regex matches.
Modifying a built-in object's prototype is a bad idea. Creating a new function is a better idea.
Here's the final code:
function convertToSentenceCase(str) {
return str
.toLowerCase()
.replace(/["?]/g, '')
.replace(/:/g, ' - ')
.replace(/^\w|\.\s*\w/gi, (match) => match.toUpperCase())
.replace(/\b(id|tv|nasa|acronyms)\b/gi, (match) => match.toUpperCase())
}
const input = `play around: This is a "String" Of text, which needs to be cONVERTED to Sentence Case at the same time keeping the Acronyms as it is like Nasa. another sentence. "third" sentence starting with a quote.`
const result = convertToSentenceCase(input)
console.log(result)
I'm trying to do a challenge which is converting all strings into camelCase but without using regex, only using the methods like(split, slice, replace, includes.. etc). Some words have spaces and should remove them. Here's the CODE and I'm really STUCK. NOTE: the user enters the STRING and when user clicks the button should return to the camelCase.
INPUT =>
//underscore_case
//first_name
//Some_Variable
// calculate_AGE
//delayed_departure
OUTPUT =>
//underscoreCase
//firstName
//someVariable
//calculateAge
//delayedDeparture
document.body.append(document.createElement('textarea'));
document.body.append(document.createElement('button'));
document.querySelector('button').addEventListener('click', function() {
const text = document.querySelector('textarea').value;
const row = text.split('\n');
let [...n] = '';
for (const theText of row) {
const lowerText = theText.toLowerCase().trim();
if (lowerText.includes('_')) {
n = lowerText.replace('_', ' ');
console.log([...n]);
}
}
});
Explanation of this simple algorithm:
Your input must have words that split by a certain character, as you need something to identify which part of the string is a word. Let's assume your string has words separated by '//' instead of spaces as you mentioned in the comments, and each of those words is split by '_'.
First you need to split all words in the string into an array, you can use the split() method in order to do that.
Then when iterating through each word, split it again with split() but this time with whatever identifies the different words, in our case it's _.
Iterate through each split words, if it's the first word lowercase it using toLowerCase() and add it to the new word variable, if not, lowercase it and capitalize the first letter.
And that's it. Here's the implementation:
const inputWithoutCamelCase = 'hello_world // HOW_ARE_YOU // foo_BAR'
function stringToCamelCase(string) {
const allNames = string.split('//')
let camelCasedString = '';
for (const name of allNames) {
camelCasedString += nameToCamelCaseHelper(name);
}
return camelCasedString;
}
function nameToCamelCaseHelper(word) {
const splittedName = word.split('_');
let camelCasedName = '';
for (let i = 0; i < splittedName.length; i++) {
if (i === 0) {
camelCasedName += splittedName[i].toLowerCase();
} else {
camelCasedName += capitalizeFirstLetter(splittedName[i].toLowerCase())
}
}
return camelCasedName;
}
function capitalizeFirstLetter(string) {
return string.charAt(0).toUpperCase() + string.slice(1);
}
stringToCamelCase(inputWithoutCamelCase) // helloWorld howAreYou fooBar
Beginner Coder and I'm confused if my include method is wrong. Maybe I should create an array and push the characters in? Am I on the right track?
Aba is a German children's game where secret messages are exchanged. In Aba, after every vowel we add "b" and add that same vowel. Write a method that takes in a sentence string and returns a new sentence representing its Aba translation. Capitalized words of the original sentence should be properly capitalized in the new sentence.
function abaTranslate(sentence) {
var words = sentence.split(" ");
const vowels = 'AEIOUaeiou';
var newStr = "";
var char = words[i];
for (var i = 0; i < sentence.length; i++) {
if (words.includes(vowels)) {
newStr += (words + "b")
}
}
return newStr;
}
console.log(abaTranslate("Cats and dogs")); // returns "Cabats aband dobogs"
You don't need to split your sentence into individual words, as you're not interested in looking at the words, but rather the individual characters in the sentence. With this in mind, you can use the current loop that you have, and for each i grab the current character from the input sentence at index i.
If the current character is a vowel (ie: if it is included in the vowels string), then you know the current character is a vowel, and so, you can add the current character separated by a "b" to your output string. Otherwise, it if its not a vowel, you can just add the current character to the output string.
See example below:
function abaTranslate(sentence) {
const vowels = 'AEIOUaeiou';
var newStr = "";
for (var i = 0; i < sentence.length; i++) {
var currentCharacter = sentence[i];
if (vowels.includes(currentCharacter)) { // the current character is a vowel
newStr += currentCharacter + "b" + currentCharacter;
} else {
newStr += currentCharacter; // just add the character if it is not a vowel
}
}
return newStr;
}
console.log(abaTranslate("Cats and dogs")); // returns "Cabats aband dobogs"
If you want to use JS methods to help you achieve this, you could use .replace() with a regular expression. Although, it's probably better to try and understand the above code before diving into regular expressions:
const abaTranslate = sentence => sentence.replace(/[aeiou]/ig, "$&b$&");
console.log(abaTranslate("Cats and dogs")); // returns "Cabats aband dobogs"
I trying to split text by two rules:
Split by whitespace
Split words greater than 5 symbols into two separate words like (aaaaawww into aaaaa- and www)
I create regex that can detect this rules (https://regex101.com/r/fyskB3/2) but can't understand how to make both rules work in (text.split(/REGEX/)
Currently regex - (([\s]+)|(\w{5})(?=\w))
For example initial text is hello i am markopollo and result should look like ['hello', 'i', 'am', 'marko-', 'pollo']
It would probably be easier to use .match: match up to 5 characters that aren't whitespace:
const str = 'wqerweirj ioqwejr qiwejrio jqoiwejr qwer qwer';
console.log(
str.match(/[^ ]{1,5}/g)
)
My approach would be to process the string before splitting (I'm a big fan of RegEx):
1- Search and replace all the 5 consecutive non-last characters with \1-.
The pattern (\w{5}\B) will do the trick, \w{5} will match 5 exact characters and \B will match only if the last character is not the ending character of the word.
2- Split the string by spaces.
var text = "hello123467891234 i am markopollo";
var regex = /(\w{5}\B)/g;
var processedText = text.replace(regex, "$1- ");
var result = processedText.split(" ");
console.log(result)
Hope it helps!
Something like this should work:
const str = "hello i am markopollo";
const words = str.split(/\s+/);
const CHUNK_SIZE=5;
const out = [];
for(const word of words) {
if(word.length > CHUNK_SIZE) {
let chunks = chunkSubstr(word,CHUNK_SIZE);
let last = chunks.pop();
out.push(...chunks.map(c => c + '-'),last);
} else {
out.push(word);
}
}
console.log(out);
// credit: https://stackoverflow.com/a/29202760/65387
function chunkSubstr(str, size) {
const numChunks = Math.ceil(str.length / size)
const chunks = new Array(numChunks)
for (let i = 0, o = 0; i < numChunks; ++i, o += size) {
chunks[i] = str.substr(o, size)
}
return chunks
}
i.e., first split the string into words on spaces, and then find words longer than 5 chars and 'chunk' them. I popped off the last chunk to avoid adding a - to it, but there might be a more efficient way if you patch chunkSubstr instead.
regex.split doesn't work so well because it will basically remove those items from the output. In your case, it appears you want to strip the whitespace but keep the words, so splitting on both won't work.
Uses the regex expression of #CertainPerformance = [^\s]{1,5}, then apply regex.exec, finally loop all matches to reach the goal.
Like below demo:
const str = 'wqerweirj ioqwejr qiwejrio jqoiwejr qwer qwer'
let regex1 = RegExp('[^ ]{1,5}', 'g')
function customSplit(targetString, regexExpress) {
let result = []
let matchItem = null
while ((matchItem = regexExpress.exec(targetString)) !== null) {
result.push(
matchItem[0] + (
matchItem[0].length === 5 && targetString[regexExpress.lastIndex] && targetString[regexExpress.lastIndex] !== ' '
? '-' : '')
)
}
return result
}
console.log(customSplit(str, regex1))
console.log(customSplit('hello i am markopollo', regex1))
I'm facing some problem while trying to send text to some spelling API.
The API return the corrections based on the words index, for example:
sentence:
"hello hoow are youu"
So the API index the words by numbers like that and return the correction based on that index:
0 1 2 3
hello hoow are youu
API Response that tell me which words to correct:
1: how
3: you
On the code I using split command to break the sentence into words array so I will be able to replace the misspelled words by their index.
string.split(" ");
My problem is that the API trim multiple spaces between words into one space, and by doing that the API words index not match my index. (I would like to preserve the spaces on the final output)
Example of the problem, sentence with 4 spaces between words:
Hello howw are youu?
0 1 2 3 4 5 6 7
hello hoow are youu
I thought about looping the words array and determine if the element is word or space and then create something new array like that:
indexed_words[0] = hello
indexed_words[0_1] = space
indexed_words[0_2] = space
indexed_words[0_3] = space
indexed_words[0_4] = space
indexed_words[0_5] = space
indexed_words[0_6] = space
indexed_words[0_7] = space
indexed_words[1] = how
indexed_words[2] = are
indexed_words[3] = you?
That way I could replace the misspelled words easily and than rebuild the sentence back with join command but the problem but the problem that I cannot use non-numeric indexes (its mixed up the order of the array)
Any idea how I can keep the formatting (spaces) but still correct the words?
Thanks
in that case you have very simple solution:L
$(document).ready(function(){
var OriginalSentence="howw are you?"
var ModifiedSentence="";
var splitstring=OriginalSentence.split(' ')
$.each(splitstring,function(i,v){
if(v!="")
{
//pass this word to your api and appedn it to sentance
ModifiedSentence+=APIRETURNVALUE//api return corrected value;
}
else{
ModifiedSentence+=v;
}
});
alert(ModifiedSentence);
});
Please review this one:
For string manipulation like this, I would highly recommend you to use Regex
Use online regex editor for faster try and error like here https://regex101.com/.
here I use /\w+/g to match every words if you want to ignore 1 or two words we can use /\w{2,}/g or something like that.
var str = "Hello howw are youu?";
var re = /\w+/g
var words = str.match(re);
console.log("Returning valus")
words.forEach(function(word, index) {
console.log(index + " -> " + word);
})
Correction
Just realize that you need to keep spacing as it is, please try this one:
I used your approach to change all to space. create array for its modified version then send to your API (I dunno that part). Then get returned data from API, reconvert it back to its original formating string.
var ori = `asdkhaskd asdkjaskdjaksjd askdjaksdjalsd a ksjdhaksjdhasd asdjkhaskdas`;
function replaceMeArr(str, match, replace) {
var s = str,
reg = match || /\s/g,
rep = replace || ` space `;
return s.replace(reg, rep).split(/\s/g);
}
function replaceMeStr(arr, match, replace) {
var a = arr.join(" "),
reg = match || /\sspace\s/g,
rep = replace || " ";
return a.replace(reg, rep);
}
console.log(`ori1: ${ori}`);
//can use it like this
var modified = replaceMeArr(ori);
console.log(`modi: ${modified.join(' ')}`);
//put it back
var original = replaceMeStr(modified);
console.log(`ori2: ${original}`);
Updated
var str = "Hello howw are youu?";
var words = str.split(" ");
// Getting an array without spaces/empty values
// send it to your API call
var requestArray = words.filter(function(word){
if (word) {
return word;
}
});
console.log("\nAPI Response that tell me which words to correct:");
console.log("6: how\n8: you");
var response = {
"1": "how",
"3": "you"
}
//As you have corrected words index, Replace those words in your "requestArray"
for (var key in response) {
requestArray[key] = response[key];
}
//now we have array of non-empty & correct spelled words. we need to put back empty (space's) value back in between this array
var count = 0;
words.forEach(function(word, index){
if (word) {
words[index] = requestArray[count];
count++;
}
})
console.log(words);
Correct me, if i was wrong.
Hope this helps :)
Try this JSFiddle
, Happy coding :)
//
// ReplaceMisspelledWords
//
// Created by Hilal Baig on 21/11/16.
// Copyright © 2016 Baigapps. All rights reserved.
//
var preservedArray = new Array();
var splitArray = new Array();
/*Word Object to preserve my misspeled words indexes*/
function preservedObject(pIndex, nIndex, title) {
this.originalIndex = pIndex;
this.apiIndex = nIndex;
this.title = title;
}
/*Preserving misspeled words indexes in preservedArray*/
function savePreserveIndexes(str) {
splitArray = str.split(" ");
//console.log(splitArray);
var x = 0;
for (var i = 0; i < splitArray.length; i++) {
if (splitArray[i].length > 0) {
var word = new preservedObject(i, x, splitArray[i]);
preservedArray.push(word);
x++;
}
}
};
function replaceMisspelled(resp) {
for (var key in resp) {
for (var i = 0; i < preservedArray.length; i++) {
wObj = preservedArray[i];
if (wObj.apiIndex == key) {
wObj.title = resp[key];
splitArray[wObj.originalIndex] = resp[key];
}
}
}
//console.log(preservedArray);
return correctedSentence = splitArray.join(" ");
}
/*Your input string to be corrected*/
str = "Hello howw are youu";
console.log(str);
savePreserveIndexes(str);
/*API Response in json of corrected words*/
var apiResponse = '{"1":"how","3":"you" }';
resp = JSON.parse(apiResponse);
//console.log(resp);
/*Replace misspelled words by corrected*/
console.log(replaceMisspelled(resp)); //Your solution