I am trying to create a canvas object which I can use to create an image from (using canvas.toDataURL()).
One of the key elements of this canvas, has to be the background gradient set using the following css:
background: -webkit-linear-gradient(-45deg, #1e5799 0%,#2989d8 36%,#207cca 71%,#7db9e8 100%);.
As you can see this is set using a certain angle (-45deg).
Is there any way for me to create this using canvas and also being able to create an image from this which includes this background?
This doesn't work when manually setting the css-background property, as toDataURL does not take into account any css. I have also looked at drawing it into the canvas myself, but ctx.createLinearGradient does not support drawing of angles.
How can I achieve a canvas which allows toDataURL which includes my desired background?
Grabbing the background of the canvas element will not work as it is not part of the canvas bitmap (2D context in this case).
You have to use the createLinearGradient for that. As you say, it does not support an angle directly, but creates a gradient using a line (x1,y1)-(x2,y2).
This means we can use a little trigonometry to produce the angle we want.
If you want to create a line at an angle just do:
var x2 = length * Math.cos(angle); // angle in radians
var y2 = length * Math.sin(angle); // angle in radians
Now you can use this with createLinearGradient:
var gr = ctx.createLinearGradient(0, 0, x2, y2);
Example
var ctx = document.querySelector("canvas").getContext("2d"),
angle = 45 * Math.PI / 180,
x2 = 300 * Math.cos(angle),
y2 = 300 * Math.sin(angle),
gr = ctx.createLinearGradient(0, 0, x2, y2);
gr.addColorStop(0, "black");
gr.addColorStop(1, "blue");
ctx.fillStyle = gr;
ctx.fillRect(0, 0, ctx.canvas.width, ctx.canvas.height);
var uri = ctx.canvas.toDataURL();
console.log(uri);
<canvas></canvas>
Related
I was trying to get the green triangle to rotate about its center and orient itself towards the mouse position. I was able to accomplish this, and you can view the full code and result here:
https://codepen.io/Carpetfizz/project/editor/DQbEVe
Consider the following lines of code:
r = Math.atan2(mouseY - centerY, mouseX - centerX)
ctx.rotate(r + Math.PI/2)
I arbitrarily added Math.PI/2 to my angle calculation because without it, the rotations seemed to be 90 degrees off (by inspection). I want a better understanding of the coordinate system which atan2 is being calculated with respect to so I can justify the reason for offsetting the angle by 90 degrees (and hopefully simplify the code).
EDIT:
To my understanding, Math.atan2 is measuring the angle illustrated in blue. Shouldn't rotating both triangles that blue angle orient it towards the mouse mouse pointer (orange dot) ? Well - obviously not since it's the same angle and they are two different orientations, but I cannot seem to prove this to myself.
This is because of how the Math.atan2 works.
From MDN:
This is the counterclockwise angle, measured in radians, between the positive X axis, and the point (x, y).
In above figure, the positive X axis is the horizontal segment going from the junction to the right-most position.
To make it clearer, here is an interactive version of this diagram, where x, y values are converted to [-1 ~ 1] values.
const ctx = canvas.getContext('2d'),
w = canvas.width,
h = canvas.height,
radius = 0.3;
ctx.textAlign = 'center';
canvas.onmousemove = canvas.onclick = e => {
// offset mouse values so they are relative to the center of our canvas
draw(as(e.offsetX), as(e.offsetY));
}
draw(0, 0);
function draw(x, y) {
clear();
drawCross();
drawLineToPoint(x, y);
drawPoint(x, y);
const angle = Math.atan2(y, x);
drawAngle(angle);
writeAngle(angle);
}
function clear() {
ctx.clearRect(0, 0, w, h);
}
function drawCross() {
ctx.lineWidth = 1;
ctx.beginPath();
ctx.moveTo(s(0), s(-1));
ctx.lineTo(s(0), s(1));
ctx.moveTo(s(-1), s(0));
ctx.lineTo(s(0), s(0));
ctx.strokeStyle = ctx.fillStyle = '#2e404f';
ctx.stroke();
// positive X axis
ctx.lineWidth = 3;
ctx.beginPath();
ctx.moveTo(s(0), s(0));
ctx.lineTo(s(1), s(0));
ctx.stroke();
ctx.lineWidth = 1;
ctx.font = '20px/1 sans-serif';
ctx.fillText('+X', s(1) - 20, s(0) - 10);
}
function drawPoint(x, y) {
ctx.beginPath();
ctx.arc(s(x), s(y), 10, 0, Math.PI * 2);
ctx.fillStyle = 'red';
ctx.fill();
ctx.font = '12px/1 sans-serif';
ctx.fillText(`x: ${x.toFixed(2)} y: ${y.toFixed(2)}`, s(x), s(y) - 15);
}
function drawLineToPoint(x, y) {
ctx.beginPath();
ctx.moveTo(s(0), s(0));
ctx.lineTo(s(x), s(y));
ctx.strokeStyle = 'red';
ctx.setLineDash([5, 5]);
ctx.stroke();
ctx.setLineDash([0]);
}
function drawAngle(angle) {
ctx.beginPath();
ctx.moveTo(s(radius), s(0));
ctx.arc(s(0), s(0), radius * w / 2,
0, // 'arc' method also starts from positive X axis (3 o'clock)
angle,
true // Math.atan2 returns the anti-clockwise angle
);
ctx.strokeStyle = ctx.fillStyle = 'blue';
ctx.stroke();
ctx.font = '20px/1 sans-serif';
ctx.fillText('∂: ' + angle.toFixed(2), s(0), s(0));
}
// below methods will add the w / 2 offset
// because canvas coords set 0, 0 at top-left corner
// converts from [-1 ~ 1] to px
function s(value) {
return value * w / 2 + (w / 2);
}
// converts from px to [-1 ~ 1]
function as(value) {
return (value - w / 2) / (w / 2);
}
<canvas id="canvas" width="500" height="500"></canvas>
So now, if we go back to your image, it currently points to the top (positive Y axis), while the angle you just measured is realtive to the x axis, so it doesn't point where you intended.
Now we know the problem, the solution is quite easy:
either apply the + Math.PI / 2 offset to your angle like you did,
either modify your original image so that it points to the positive X axis directly.
The coordinate system on canvas works with 0° pointing right. This means anything you want to point "up" must be initially drawn right.
All you need to do in this case is to change this drawing:
to
pointing "up" 0°
and you can strip the math back to what you'd expect it to be.
var ctx = c.getContext("2d"), img = new Image;
img.onload = go; img.src = "https://i.stack.imgur.com/Yj9DU.jpg";
function draw(pos) {
var cx = c.width>>1,
cy = c.height>>1,
angle = Math.atan2(pos.y - cy, pos.x - cx);
ctx.setTransform(1,0,0,1,cx, cy);
ctx.rotate(angle);
ctx.drawImage(img, -img.width>>1, -img.height>>1);
}
function go() {
ctx.globalCompositeOperation = "copy";
window.onmousemove = function(e) {draw({x: e.clientX, y: e.clientY})}
}
html, body {margin:0;background:#ccc}
#c {background:#fff}
<canvas id=c width=600 height=600></canvas>
When you do arctangents in math class, you're generally dealing with an y-axis that increases going upwards. In most computer graphics systems, however, including canvas graphics, y increases going downward. [erroneous statement deleted]
Edit: I have to admit what I wrote before was wrong for two reasons:
A change in the direction of the axis would be compensated for by adding π, not π/2.
The canvas context rotate function rotates clockwise for positive angles, and that alone should compensate for the flip of the y-axis.
I played around with a copy of your code in Plunker, and now I realize the 90° rotation simply compensates for the starting orientation of the graphic image you're drawing. If the arrowhead pointed right to start with, instead of straight up, you wouldn't need to add π/2.
I encountered the same problem and was able to achieve the desired result with a following axis 'trick':
// Default usage (works fine if your image / shape points to the RIGHT)
let angle = Math.atan2(delta_y, delta_x);
// 'Tricky' usage (works fine if your image / shape points to the LEFT)
let angle = Math.atan2(delta_y, -delta_x);
// 'Tricky' usage (works fine if your image / shape points to the BOTTOM)
let angle = Math.atan2(delta_x, delta_y);
// 'Tricky' usage (works fine if your image / shape points to the TOP)
let angle = Math.atan2(delta_x, -delta_y);
I'm trying to rotate an image and move it around the canvas using the arrow keys. The plan is to have the left and right keys control the rotation of the image, and the up-down key control the movement - a bit like a tank!
I can successfully rotate an image around a centre point and place it back where it should be in the canvas, but once I rotate it by, say 45 deg, I would like the up key to move it right, rotate 180 and the up-key moves it down the canvas etc. At the moment, I can rotate the image using left/right keys, but up/down keys are always up/down the canvas.
Do I somehow need to rotate the canvas coordinates by the same amount as the image?
This is what I have so far and is in my draw function…
ctx.save();
ctx.clearRect(0, 0, canvas.width, canvas.height);
ctx.translate(T1.x + base_image.width/2, T1.y + base_image.height/2);
ctx.rotate(rotation * Math.PI/180);
ctx.translate(-(T1.x + base_image.width/2), -(T1.y + base_image.height/2));
ctx.drawImage(base_image, T1.x, T1.y);
ctx.stroke();
ctx.restore()
T1.x and T1.y are the x and y coordinates of the image.
Thanks!
Finally got it! The solution was to separate the rotation and the movement rather than trying to do it all using ctx.translate.
In my draw function called every 100 Hz:
ctx.save();
ctx.translate(T1.x + base_image.width/2, T1.y + base_image.height/2);
ctx.rotate(rotation*Math.PI/180);
ctx.drawImage(base_image, -base_image.width/2, -base_image.height/2);
ctx.restore();
ctx.stroke();
The left key is, for example, like:
rotation = rotation - 5;
Draw();
The up key is, for example, like:
var radians = (rotation*Math.PI/180)
T1.x += 4*Math.cos(radians);
T1.y += 4*Math.sin(radians);
Draw();
Note: For this to work, I had to change the default orientation of the image in paint by 45 deg.
The quickest way to draw a rotated, uniformly-scaled image on Edge, Chrome, and Firefox is
// When the image has loaded add the center offsets
image.onload = function(){
// … your code
this.centerX = -this.width/2;
this.centerY = -this.height/2;
}
// When rendering
// x,y position of image center
// scale the uniform scale
// rotate angle in radians starting at 0 and + clockwise
var xdx = Math.cos(rotate) * scale;
var xdy = Math.sin(rotate) * scale;
ctx.setTransform(xdx, xdy, -xdy, xdx, x, y);
ctx.drawImage(image,image.centerX,image.centerY)
The above method with the extra sin and cos and the two multiplications is significantly quicker on Chrome, slightly quicker on Firefox, and I forget the margin on Edge, but it was quicker than the next quickest method:
ctx.setTransform(scale, 0, 0, scale, x, y);
ctx.rotate(rotate);
ctx.drawImage(image, image.centerX, image.centerY);
Though I am leaving the canvas transform state as it is, you can continue using both methods without having to reset the canvas state. When you are done with all the rendering, to restore the current transform, use
ctx.setTransform(1, 0, 0, 1, 0, 0);
To save a tiny bit of time, each time you convert from degrees to radians, create a const DEG2RAD = Math.PI/180;. Then, you can convert with var radians = degrees*DEG2RAD; or save by typing const D2R = Math.PI/180; or call const oneDeg = Math.PI/180;.
I want to achive the following:
Draw a bg-image to the canvas (once or if needed repeatedly)
The image should not be visible at the beginning
While i "paint" shapes to the canvas the bg-image should get visible where the shapes were drawn
The parts of the image that will be revealed shall be "painted" (like with a brush) so i want to use strokes.
What i tried:
- Do not clear the canvas
- Paint rects to the canvas with globalCompositeOperation = 'destination-in'
This works, the rectangles reveal the image but i need strokes
If i use strokes they are ignored with 'destination-in' while i see them with normal globalCompositeOperation.
Is this intended that the strokes are ignored? Is there a workaround like somehow converting the stroke/shape to a bitmap? Or do i have have to use two canvas elements?
In OpenGL i would first draw the image with its rgb values and with a = 0 and then only "paint" the alpha in.
You can solve it by these steps:
Set the image as a pattern
Set the pattern as fillStyle or strokeStyle
When you now fill/stroke your shapes the image will be revealed. Just make sure the initial image fits the area you want to reveal.
Example showing the principle, you should be able to adopt this to your needs:
var ctx = canvas.getContext("2d"),
img = new Image,
radius = 40;
img.onload = setup;
img.src = "http://i.imgur.com/bnAEEXq.jpg";
function setup() {
// set image as pattern for fillStyle
ctx.fillStyle = ctx.createPattern(this, "no-repeat");
// for demo only, reveals image while mousing over canvas
canvas.onmousemove = function(e) {
var r = this.getBoundingClientRect(),
x = e.clientX - r.left,
y = e.clientY - r.top;
ctx.beginPath();
ctx.moveTo(x + radius, y);
ctx.arc(x, y, radius, 0, 2*Math.PI);
ctx.fill();
};
}
<canvas id=canvas width=900 height=600></canvas>
Hope this helps!
Alternative solution:
Put the image as a normal image on your website
add a canvas and use CSS positioning to place it right above the image
Fill the canvas with the color you use as the page background
have your paint tools erase the canvas when you draw. By the way, you can set context.globalCompositionOperation = 'destination-out' to turn all drawing operations into an eraser.
Here is an example. As you can see, the alpha properties of your tools are respected.
var canvas = document.getElementById('canvas');
var ctx = canvas.getContext('2d');
//prepare canvas
ctx.fillStyle = '#ffffff'
ctx.fillRect(0, 0, 120, 120);
//prepare a 30% opacity eraser
ctx.globalCompositeOperation = 'destination-out';
ctx.lineWidth = 5;
ctx.strokeStyle = 'rgba(0, 0, 0, 0.3)';
// make random strokes around cursor while mouse moves
canvas.onmousemove = function(e) {
var rect = this.getBoundingClientRect();
var x = e.clientX - rect.left;
var y = e.clientY - rect.top;
ctx.beginPath();
ctx.moveTo(x + Math.random() * 33 - 16, y + Math.random() * 33 - 16);
ctx.lineTo(x + Math.random() * 33 - 16, y + Math.random() * 33 - 16);
ctx.stroke();
}
<span>Move your mouse:</span>
<div>
<img src='https://upload.wikimedia.org/wikipedia/commons/thumb/6/61/HTML5_logo_and_wordmark.svg/120px-HTML5_logo_and_wordmark.svg.png' style='position:absolute'>
<canvas id='canvas' width=120 height=120 style='position:absolute'></canvas>
</div>
I want to place a number of light sources on a background for a game I'm making, which works great with one light source as shown below:
This is achieved by placing a .png image above everything else that becomes more transperant towards the center, like this:
Works great for one light source, but I need another approach where I can add more and move the light sources around.
I have considered drawing a similar "shadow layer" pixel by pixel for each frame, and calculate the transparency depending of the distance to each light source. However, that would probably be very slow and I'm sure there are way better solutions to this problem.
The images are just examples and each frame will have considerably more content to move around and update using requestAnimationFrame.
Is there a light weight and simple way to achieve this? Thanks in advance!
Edit
With the help of ViliusL, I came up with this masking solution:
http://jsfiddle.net/CuC5w/1/
// Create canvas
var canvas = document.createElement('canvas');
var ctx = canvas.getContext('2d');
canvas.width = 300;
canvas.height = 300;
document.body.appendChild(canvas);
// Draw background
var img=document.getElementById("cat");
ctx.drawImage(img,0,0);
// Create shadow canvas
var shadowCanvas = document.createElement('canvas');
var shadowCtx = shadowCanvas.getContext('2d');
shadowCanvas.width = canvas.width;
shadowCanvas.height = canvas.height;
document.body.appendChild(shadowCanvas);
// Make it black
shadowCtx.fillStyle= '#000';
shadowCtx.fillRect(0,0,canvas.width,canvas.height);
// Turn canvas into mask
shadowCtx.globalCompositeOperation = "destination-out";
// RadialGradient as light source #1
gradient = shadowCtx.createRadialGradient(80, 150, 0, 80, 150, 50);
gradient.addColorStop(0, "rgba(255, 255, 255, 1.0)");
gradient.addColorStop(1, "rgba(255, 255, 255, .1)");
shadowCtx.fillStyle = gradient;
shadowCtx.fillRect(0, 0, canvas.width, canvas.height);
// RadialGradient as light source #2
gradient = shadowCtx.createRadialGradient(220, 150, 0, 220, 150, 50);
gradient.addColorStop(0, "rgba(255, 255, 255, 1.0)");
gradient.addColorStop(1, "rgba(255, 255, 255, .1)");
shadowCtx.fillStyle = gradient;
shadowCtx.fillRect(0, 0, canvas.width, canvas.height);
Another way to play with light is to use the globalCompositeOperation mode 'ligther' to ligthen things, and just use globalAlpha to darken things.
First here's an image, with a cartoon lightening on the left, and a more realistic lightening on the right, but you'd rather watch the fiddle, since it's animated :
http://jsfiddle.net/gamealchemist/ABfVj/
So how i did things :
To darken :
- Choose a darkening color( most likely black, but you can choose a red or another color to teint the result).
- choose an opacity ( 0.3 seems a good start value ).
- fillRect the area you want to darken.
function darken(x, y, w, h, darkenColor, amount) {
ctx.fillStyle = darkenColor;
ctx.globalAlpha = amount;
ctx.fillRect(x, y, w, h);
ctx.globalAlpha = 1;
}
To lighten :
- Choose a lightening color. Beware that this color's r,g,b will be added to the previous point's r,g,b : if you use a high value your color will get burnt.
- change the globalCompositeOperation to 'lighter'
- you might change opacity also, to have more control over the lightening.
- fillRect or arc the area you want to lighten.
If you draw several circles while in lighter mode, the results will add up, so you can choose a quite low value and draw several circles.
function ligthen(x, y, radius, color) {
ctx.save();
var rnd = 0.03 * Math.sin(1.1 * Date.now() / 1000);
radius = radius * (1 + rnd);
ctx.globalCompositeOperation = 'lighter';
ctx.fillStyle = '#0B0B00';
ctx.beginPath();
ctx.arc(x, y, radius, 0, 2 * π);
ctx.fill();
ctx.fillStyle = color;
ctx.beginPath();
ctx.arc(x, y, radius * 0.90+rnd, 0, 2 * π);
ctx.fill();
ctx.beginPath();
ctx.arc(x, y, radius * 0.4+rnd, 0, 2 * π);
ctx.fill();
ctx.restore();
}
Notice that i added a sinusoidal variation to make the light more living.
Ligthen : another way :
You can also, while still using the 'ligther' mode, use a gradient to have a smoother effect (first one is more cartoon like, unless you draw a lot of circles.).
function ligthenGradient(x, y, radius) {
ctx.save();
ctx.globalCompositeOperation = 'lighter';
var rnd = 0.05 * Math.sin(1.1 * Date.now() / 1000);
radius = radius * (1 + rnd);
var radialGradient = ctx.createRadialGradient(x, y, 0, x, y, radius);
radialGradient.addColorStop(0.0, '#BB9');
radialGradient.addColorStop(0.2 + rnd, '#AA8');
radialGradient.addColorStop(0.7 + rnd, '#330');
radialGradient.addColorStop(0.90, '#110');
radialGradient.addColorStop(1, '#000');
ctx.fillStyle = radialGradient;
ctx.beginPath();
ctx.arc(x, y, radius, 0, 2 * π);
ctx.fill();
ctx.restore();
}
i also added here a sin variation.
Rq : creating a gradient on each draw will create garbage : store the gradient if you use a single gradient, and store them in an array if you want to animate the gradients.
If you are using the same light in several places, have a single gradient built, centered on (0,0), and translate the canvas before drawing always with this single gradient.
Rq 2 : you can use clipping to prevent some parts of the screen to be lightened (if there's an obstacle).
I added the blue circle on my example to show this.
So you might want to ligthen directly your scene with those effects, or create separately a light layer that you darken/lighten as you want before drawImage it on the screen.
There are too many scenari to discuss them here (light animated or not, clipping or not, pre-compute a light layer or not, ...) but as far as speed is concerned, for Safari and iOS safari, the solution using rect/arc draws -either with gradient or a solid fill- will be rocket faster than drawing an image/canvas.
On Chrome it will be quite the opposite : it's faster to draw an image than to draw each geometry when the geometry count raises.
Firefox is rather similar to Chrome for this.
your png should have full transparent corners and not transparent white in middle.
or you can draw this, but not pixel by pixel like here jsfiddle.net/pr9r7/2/
More examples: jsfiddle.net/pr9r7/3/ http://codepen.io/cwolves/pen/prvnb
Here is my Take on it:
A. Don't worry about performance until you have tried it out. The Canvas is pretty darn fast at drawing.
B. Rather than having a image with dark Corners and a Transparent middle. Why don't you try and make it more "IRL" and have the overall world be more Dark and let the light-source illuminate the Area? Highlight a small area, instead of darken everything EXCEPT a small Area.
I am working on a HTML5 Project.There is a drawing graphics API to draw Rectangle (fillRectStrokeRect).But how can i draw a SQUARE. I have tried the following way to draw it
CODE
getMouse(e);
x2=mx; y2=my;
var width=endX-startX;
var height=endY-startY;
annCanvasContext.beginPath();
annCanvasContext.lineWidth=borderWidth;
var centerX=width/2;
var centerY=width/2;
var radius=width/2;
annCanvasContext.arc(centerX+5, centerY+5, radius, 0, 2 * Math.PI, false);
annCanvasContext.stroke();
Use fillRect or strokeRect with the width and height being equal.
var x = 0, y = 0,
side = 10;
ctx.fillRect(x, y, side, side);
Demo
As you say in the comments, if you want to fit the largest square in a circle, it's more Math related than about code. I'll trying explaining it to you, but you'll probably find better, more visual explanations elsewhere on the Internet.
Draw the diameter of the circle in a way that it divides your square into two equal parts. Now one part is a right angled triangle, which has two of its sides equal. We know the diameter. Using the Pythogorean theorem, you get this equation:
side^2 + side^2 = diameter^2.
Let's find the side now.
2(side^2) = diameter^2
side^2 = (diameter^2)/2
side = Math.sqrt( (diameter^2)/2 )
Now, to turn this into code.
var ctx = document.getElementById('canvas').getContext('2d'),
radius = 20;
ctx.canvas.addEventListener('click', function (e){
ctx.fillStyle = 'black';
ctx.arc(e.pageX, e.pageY, radius, 0, Math.PI*2, false);
ctx.fill();
ctx.beginPath();
ctx.fillStyle = 'red';
var diameter = radius * 2;
var side = Math.sqrt( (diameter * diameter)/2 );
ctx.fillRect(e.pageX - side/2, e.pageY - side/2, side, side);
ctx.closePath();
}, false);
This would draw a square inside a circle wherever you click on the canvas.
Demo