Develop Reference

Row of blocks - click on one and the rest slide off the screen

I have a row of blocks. When one is clicked, I want the rest to slide off the screen and have the clicked box in the first position.
for example
I tried to mess with jQueryUI slide but it didn't seem to help. Here is a JS Fiddle showing the original blocks. Maybe I need to position them differently than floating? I thought about trying to move the distance left and off the screen but the animation looked awful.
$('.block').on('click', function() {
$('.block').not($(this)).hide("slide", { direction: "left" }, 500, function() {
});

$(document).ready(function(e) {
$('.block').each(function(item) {
$(this).click(function() {
$('.block').not($(this)).hide('slide', {direction: 'left'}, 500);
})
});
})
You still need to include jQueryUi, bellow jQuery, in order to achieve the slide effect.

Animate image left to right on scroll

What I am trying to do is I have around 6 inline images I want slide them left to right on specific position and stop there for each image. And images have to slide at the time the scrool comes over them.
I tried this javascript for it (totally new to JS)
$(window).scroll(function(){
if($this.scrollTop()>300)
{
$('.onfoot1').slideright();
}
function slideright(){
var a = getElementsByClassName('.onfoot1');
var stoppos = 100;
if (parseInt(a.style.left)< stoppos )
{
a.style.left = parseInt(a.style.left) + 3 + "px";
setTimeout(slideright , 1);
}
}
});
Markup
<div class="onfoot1"></div>
CSS
div.onfoot1{
content:url(../img/onfoot1.jpg);
left:0;
}

I've put together a working examle for your code: https://jsfiddle.net/hmzw9y65/
I've made a few assumptions there... You are using $(...) syntax so I guessed you are using JQuery. JQuery has a .animate() function which should do the trick (http://api.jquery.com/animate/). Also I guessed that you may want to make the css-position of the div fixed so it stays on screen when you scroll.
EDIT: I noticed that you don't want you image on the bottom of the screen but animating when screen reaches it. Updated my fiddle to do that: https://jsfiddle.net/hmzw9y65/1/

Slide in menu - off canvas

I have a menu that is hidden from view (for mobile) using CSS:
#filter-column {
position:absolute;
left:-400px;
}
When the user clicks a link I want to hide everything else except that menu which will slide in from the left. I want the reverse to happen when the layer is closed.
I have the following jQuery:
// Show/hide filters on mobile //
$("#openMobileFilters").click(function(){
$("#filter-column").animate({left:'0'},600).css('position', 'relative');
$('#results-container, #footer').addClass('hidden-xs');
});
$(".closeFilters").click(function(){
$("#filter-column").animate({left:'-400px'},600).css('position', 'absolute');
$('#results-container, #footer').removeClass('hidden-xs');
});
The problem is when I click to hide the menu the content shows before it is actually hidden. Is there a better way of doing this?

Without seeing this in action in a fiddle, I can only suggest you move the removal of the hidden class to the complete function of animate
$(".closeFilters").click(function(){
$("#filter-column").animate({left:'-400px'}, 600, function() {
$('#results-container, #footer').removeClass('hidden-xs');
}).css('position', 'absolute');
});
Currently, you are showing the content while the animation is going on which is why you see the content right away.

you have to put the code you want to be executed after the animation in the complete callback .. for example:
$("#filter-column").animate({
left:'-400px',
complete: function() {$('#results-container, #footer').removeClass('hidden-xs');}
}, 600)

Change scrollTop offset

I am using bootstrap 3 and have a fullscreen hero unit at the top of my page, below that is my navigation. I have some js which allows my navbar to stick to be fixed at the top after you scroll past the full screen hero. Also some js for my smooth scrolling links.
The problem is the offset is different before you scroll past the full screen hero and after. But it works fine when you are past the jumbotron. I have tried a bunch of different things but I can seem to get this to work exactly.
Check out the fiddle here.
Here is my js for the smooth scrolling links:
$(document).ready(function() {
// navigation click actions
$('.scroll-link').on('click', function(event){
event.preventDefault();
var sectionID = $(this).attr("data-id");
scrollToID('#' + sectionID, 750);
});
// scroll to top action
$('.scroll-top').on('click', function(event) {
event.preventDefault();
$('html, body').animate({scrollTop:0}, 1200);
});
// mobile nav toggle
$('#nav-toggle').on('click', function (event) {
event.preventDefault();
$('#main-nav').toggleClass("open");
});
});
// scroll function
function scrollToID(id, speed){
var offSet = 95;
var targetOffset = $(id).offset().top - offSet;
var mainNav = $('#main-nav');
$('html,body').animate({scrollTop:targetOffset}, speed);
if (mainNav.hasClass("open")) {
mainNav.css("height", "1px").removeClass("in").addClass("collapse");
mainNav.removeClass("open");
}
}
if (typeof console === "undefined") {
console = {
log: function() { }
};
}
By changing var offSet = 95; I am able to adjust the offset but what would be the best way to use 180 before the navbar sticks to the top but 95 when it does?
Also here is the js I am using for my navbar:
$(function () {
/* $(".navbar-fixed-top").css({"top":$(".jumbotron").height()});
$(window).resize(function (e) {
$(".navbar-fixed-top").css({"top":$(".jumbotron").height()});
});*/
$(document).on( 'scroll', function(){
console.log('scroll top : ' + $(window).scrollTop());
if($(window).scrollTop()>=$(".jumbotron").height())
{
$(".navbar").addClass("navbar-fixed-top");
}
if($(window).scrollTop()<$(".jumbotron").height())
{
$(".navbar").removeClass("navbar-fixed-top");
}
});
});

Are you open to angular.js? I have a directive i use for this. As seen here.
I'll grab the plunker link for you. you might find the code helpful.
Essentially you need to create a ghost dom element to take the place of the menu when you pull it to an new layout position.
EDIT: Here it is
I won't suggest grabbing angular just for this. But you can use the basis of the events and logic to build your own solution.
This here is creating an element and placing in its place
$scope.spacer = $element.after(
'<div class="spacer" style="height:' + $element[0].clientHeight + 'px"> </div>').next();
then this element is removed when the menu is back to its static position.
Inspect the dom and watch how it changes, this will probably help you see the events and changes that need to take place.
EDIT 2 SOLUTION:
HERE is the concepts applied to your JSFiddle

It's not the best solution but by adding margin: 0 0 -100px 0; to your .navbaryou lose the spacing issue.
Also you're getting 22 console errors because of missing images. I'm not saying that this is causing any major problems but you would be better off losing them.

The problem is that when you have not scrolled past the hero, navigation is still part of the layout and pushes content bellow it a little lower. When you scroll past (either manually or via a script) the hero, navigation is removed and fix positioned. That makes everything which was bellow to "jump up" exactly of the navigation height.
That means if portfolio was 1000px from the top, on click you say: go 1000px from top; but then porfolio moves 100px up (as explained above) meaning it is now 900px from the top while the window scrolled 1000px as you asked.
When you have scrolled past the hero, nothing changes its position.

How to resolve mouse hover on overlapping images in jQuery?

This question seems somewhat related to
How do I check if the mouse is over an element in jQuery?
jQuery check hover status before start trigger
but still not quite. Here's the thing: I'm writing a small gallery and at some point the user clicks on a thumbnail. The large version of the image shows as an inside of a full-screen . So far, so good. When the mouse hovers over that I show three images: close, left, right, intended to navigate through an album; when the mouse leaves the image or the navigation images, the three navigation images fade.
These three navigation images partially overlap with the main image, e.g. the close image is a circle in the upper left corner. And that's the tricky part.
The mouseleave triggers whenever the mouse moves from the main image off the side, or from the main image onto one of the three small overlapping images. The mouseenter triggers for each of the small overlapping images as expected.
However, this creates a funky blinking effect because on mouseleave of the main image I hide() the three small images, which immediately triggers a mouseenter for the main image because of the overlap and the mouse still being on top of the main image.
To avoid that, I tried to determine if, upon mouseleave of the main image, the mouse has moved onto one of the small overlapping images. For that, I used this code:
main_img.mouseleave(function() {
if (!hoverButtons()) {
doHideButtons();
}
});
function hoverButtons() {
return (close_img.is(":hover")) || (left_img.is(":hover")) || (right_img.is(":hover"));
}
This works great on Safari and Chrome, but not on FF and IE where the images still blink. Further noodling around posts, it seems that ":hover" is the problem here as it is not a proper selector expression but rather a CSS pseudo class?
I tried to work with switches that I flip on/off as I mouseenter/mouseleave the various images, but that doesn't work either because the events seem to trigger in different orders.
How do I go about this? Thanks!
EDIT: I might have to clarify: before the navigation buttons are shown, I set their respective left and top attributes in order to place them in dependence of the main image's position. That means I need to do some work before I can call .show() on a jQuery selector. I tried to add a new function .placeShow() but that didn't quite work with respect to selectors like $(".nav-button:hidden").placeShow().

You can try with this:
$("#main, #small").mouseenter(function() {
$("#small:hidden").show();
}).mouseleave(function(e) {
if(e.target.id != 'main' || e.target.id != 'small') {
$('#small').hide();
}
});
DEMO

Here is what I ended up doing. There are four images I use in my slide show: the main image, and then left, right, close button images.
main_img = $("<img ... class='main-photo slide-show'/>");
close_img = $("<img ... class='nav-button slide-show'/>");
left_img = $("<img ... class='nav-button slide-show'/>");
right_img = $("<img ... class='nav-button slide-show'/>");
The classes here are essentially empty, but help me to select based on above answers. The main image then shows without navigation buttons, and I attach these event handler functions:
$(".slide-show").mouseenter(function() {
$(".photo-nav:hidden").placeShow();
});
$(".slide-show").mouseleave(function() {
$(".photo-nav").hide();
});
where the placeShow() moves the navigation buttons into their respective places. This function is defined as follows:
$.fn.placeShow = function() {
var pos = main_img.position();
var left = pos.left;
var top = pos.top;
var width = main_img.width();
var height = main_img.height();
close_img.css({ "left":"" + (left-15) + "px", "top":"" + (top-15) + "px" }).show();
left_img.css({ "left":"" + (left+(width/2)-36) + "px" , "top": "" + (top+height-15) + "px" }).show();
right_img.css({ "left":"" + (left+(width/2)+3) + "px", "top":"" + (top+height-15) + "px" }).show();
}
This worked so far on Safari, IE, FF, Chrome (well, the versions I've got here...)
Let me know what you think, if I can trim this code more, or if there are alternative solutions that would be more elegant/fast. The final result of all this is on my website now.
Jens