Develop Reference

Removing last forwardslash and the text before it

I have an URL looking like this:
https://www.website.com/dk/da/home/category/
I am trying to remove the last forward slash and the text before it, untill it reaches the new forwardslash. Meaning i would like the new URL to look like this:
https://www.website.com/dk/da/home/
I am trying to use substring to achieve this, but i run into problems because I always have a forward slash at the end of the URL.
var to = url.lastIndexOf('/');
to = to == -1 ? url.length : to + 1;
newUrl = url.substring(0, to);

Use regex
let url = "https://www.website.com/dk/da/home/category/"
url = url.replace(/\w+\/$/, "")
console.log(url)
Explanation of the given example: https://regex101.com/r/3Nw7sL/2
UPDATE: as pointed out by #CertainPerformance in the comments of this answer, it is even easier to search for the last part of the url (\w+/) and replace it with an empty string.

string.lastIndexOf can take a second parameters indicating from which index the search must be done (starting from the end)
so you can do this to get the last which is not the last character of the string :
let url = "https://www.website.com/dk/da/home/category/"
var to = url.lastIndexOf('/', url.length - 2);
to = to == -1 ? url.length : to + 1;
newUrl = url.substring(0, to);
console.log(newUrl)

other way:
str='https://www.website.com/dk/da/home/category/';
arr = str.split('/');
arr.pop();
arr.pop();
str = arr.join('/');
str = str + '/';

How about executing same logic twice :
public static void main(String[] args)
{
String url = "https://www.website.com/dk/da/home/category/";
int to = url.lastIndexOf('/');
to = to == -1 ? url.length() : to;
String newUrl = url.substring(0, to);
to = newUrl.lastIndexOf('/');
to = to == -1 ? newUrl.length() : to;
newUrl = url.substring(0, to);
System.out.println(newUrl);
}
PS - Don't write it the logic twice instead use methods.

How to get the last folder name and file name from a path using JavaScript?

how can i get the last folder name and file name from a full path,I need a solution for this.
Example:
d:\folder1\folder2\assets\images\62f9a0f4-98b9-4dd0-8047-ed1a3cc306cf.png
In my case,I just need \images\62f9a0f4-98b9-4dd0-8047-ed1a3cc306cf.png from the path in Javascript.

This should do it:
var str = "d:\\folder1\\folder2\\assets\\images\\62f9a0f4-98b9-4dd0-8047-ed1a3cc306cf.png";
var ret = str.split("\\").reduce((p,c,i,arr) => {if(i >= arr.length - 2){return (p?("\\"+p+"\\"):"")+c}});
console.log(ret);

Not the ideal solution, but gets the work done. I had to escape the \ while creating the string
var arr = "d:\\folder1\\folder2\\assets\\images\\62f9a0f4-98b9-4dd0-8047-ed1a3cc306cf.png".split("\\");
var length = arr.length, path = "\\" + arr[length-2] + "\\" + arr[length-1];
console.log(path);

var url = window.location.pathname;
var filename = url.substring(url.lastIndexOf('/')+1);
var indxend = url.lastIndexOf('/')-1
var folderName =url.substring(0,indxend).substring(url.substring(0,indxend).lastIndexOf('/')+1);

Give this a go:
var path = 'd:\\folder1\\folder2\\assets\\images\\62f9a0f4-98b9-4dd0-8047-ed1a3cc306cf.png';
var parts = path.split('\\');
var file = parts.pop();
var fileAndPar = parts.pop() + '\\' + file;
console.log(fileAndPar);

Replace the last dash value from a data attribut?

var dataUrl = $('#AjaxMoreStatus').attr("data-url");
// http://localhost:8888/app/status/get/31/7
I need to change the last value of the link from the last dash (7) by another value.
7 is a dynamic value.
Ho can i do it ?
For instance if i want to change the dynamic value 7 by 9 :
var new = 9;
$("#AjaxMoreStatus").attr("data-url", url without the 7 + '/' + new);

use lastIndexOf to check the index of last occurrence of "/"
var dataUrl = $('#AjaxMoreStatus').attr("data-url");
var newValue = 9;
dataUrl = dataUrl.substring( 0, dataUrl.lastIndexOf( "/" ) ) + "/" + newValue;

Use split() to separate the pieces of the url and replace the last item:
var url = "http://localhost:8888/app/status/get/31/7";
url = url.replace("http://", "").split("/");
var newValue = "9";
url[(url.length - 1)] = newValue;
var newUrl = "http://"+url.join("/");

You can use replace method just like here
var url = "http://localhost:8888/app/status/get/31/7";
a.replace(/\/(\d*)$/, '/' + newValue);

If you only need to change the last 7 for other thing, try this code:
var dataUrl = 'http://localhost:8888/app/status/get/31/7';
var newValue = 9;
dataUrl = dataUrl.replace(/([0-9])$/i, newValue);
https://jsfiddle.net/8hf6ra8k/1/
Hope it may help you :).

You can use .lastIndexOf() to find the index. Then you can replace value at that index. For reference, refer following post: How do I replace a character at a particular index in JavaScript?.
var url = "htt[://stacloverflow.com/test/param/tobe/replaced/with/newValue";
var newVal = "testNewValue";
var lastIndex = url.lastIndexOf('/');
var result = url.substring(0,lastIndex+1) + newVal;
alert(result)

How to get the ID from this URL?

I need a way to get the ID ( 153752044713801 in this case ) of this page:
https://www.facebook.com/pages/%D8%A7%D9%84%D8%B4%D8%B1%D8%A7%D8%A8%D9%8A%D8%A9/153752044713801
I tried this code but doen't work:
var str = 0, pagefb = 0;
var fburl = 'https://www.facebook.com/pages/%D8%A7%D9%84%D8%B4%D8%B1%D8%A7%D8%A8%D9%8A%D8%A9/153752044713801';
var re1 = /^(.+)facebook\.com\/pages\/([-\w\.]+)\/([-\w\.]+)/;
if(re1.exec(fburl)){
str = re1.exec(fburl)[3];
pagefb = str.substr(str.lastIndexOf("-") + 1);
alert('ok');
}

try:
var fburl = 'https://www.facebook.com/pages/%D8%A7%D9%84%D8%B4%D8%B1%D8%A7%D8%A8%D9%8A%D8%A9/153752044713801';
var parts = fburl.split("/");
var myId = parts[parts.length-1];
alert(myId);

Try this regular expression: ^(.+)facebook\.com\/pages\/.*\/(\d*)
(in JavaScript, you have to add "/" at the beginning and end of the pattern like you did before)

this works for me
fburl.split('/')[fburl.split('/').length-1]

You can split the string using .split("/"). More information is availible on MDN
var fburl = 'https://www.facebook.com/pages/%D8%A7%D9%84%D8%B4%D8%B1%D8%A7%D8%A8%D9%8A%D8%A9/153752044713801';
var parts = fburl.split('/')
var myFacebookId = parts[parts.length - 1]
Basically it returns an array of the string split into multiple parts (at the character/s you put inside the brackets).
The parts[parts.length - 1] will get the last item in the array parts
Demo below (Don't worry about the document..., they just print out data):
var fburl = 'https://www.facebook.com/pages/%D8%A7%D9%84%D8%B4%D8%B1%D8%A7%D8%A8%D9%8A%D8%A9/153752044713‌​801/?ref=sfhsidufh';
var parts = fburl.split('/')
var myFacebookId = parts[parts.length - 1]
// If first digit is ?
if (myFacebookId[0] == '?') {
// Set myFacebookId to the second from last part
myFacebookId = parts[parts.length - 2]
}
document.write('MyFacebookId: ' + myFacebookId)

How to replace second specific character in url using jquery

I have the following url to work with:
...login?returnUrl=%2F%2Fprint?newdata=%test1234
I need to replace the second(last) ' ? ' by an ampersand
Please help..

You could;
url = url.replace(/\?([^\?]*)$/g, '&$1')

var url = 'your url';
//GET INDEX OF FIRST "?" CHARACTER
var index = url.indexOf("?");
//FIRST PART OF URL (BEFORE AND INCLUDING THE FIRST "?" CHARACTER)
var first_part = url.substring(0,(index+1));
//SECOND PART OF STRING (AFTER AND EXCLUDING THE FIRST "?" CHARACTER)
var second_part = url.substring((index+1), url.length);
//SECOND PART REPLACE "?" WITH "&"
var second_part_replace = second_part.replace("?","&");
//YOUR FINAL URL
var new_string = first_part+""+second_part_replace;

var count = 0;
str.replace(/\?/g, function () { return count++ == 0 ? '?' : '&'; });

var parts = url.split('?');
url = parts.slice(0, parts.length - 2).join('?') +'&'+parts[parts.length - 1];
Using slice, split and join you can achieve that. Or using some regular expressions.

Try this (targets the second one) :
var url = 'login?returnUrl=%2F%2Fprint?newdata=%test1234';
var index = url.indexOf('?', url.indexOf('?') + 1);
if (index !== -1) url = url.slice(0, index) + '&' + url.slice(index + 1);
Or this (targets the last one) :
var url = 'login?returnUrl=%2F%2Fprint?newdata=%test1234';
url = url.replace(/\?(?=[^\?]*$)/, '&');