Develop Reference

How to control when a jQuery slideToggle(); which is position:absolute; is higher than viewport?

I have a slideToggle(); menu which is positioned absolutely on the bottom of the page. The slideToggle(); is going to show big content and sometimes this ends up being taller than the viewport.
My question is, how do I prevent the menu to:
1 - Not going on the top of the logo as they are both on the sidebar of my website
2 - When it reaches a height taller than the viewport, this will be scrollable
To explain myself better, I'd like the content of my menu, once is shown by slideToggle(); and whenever is taller than the viewport's height minus logo's height, to stop right below my logo and to continue expanding downwards if that's the case, and that I am able to scroll it down despite its position:absolute.
Does anyone have an idea on how I can achieve that? Please have a look at the snippet.
$( "#click" ).click(function() {
$( ".content" ).slideToggle();
});
.logo {
background: #11a1d6;
margin: 10px;
height: 100px;
width: 300px;
}
.list {
width: 200px;
position: absolute;
bottom: 20px;
}
.content {
background: #082965;
height: 10000px;
display: none;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div class="logo"></div>
<ul class="list">
<li id="click">
Click me
<div class="content"></div>
</li>
</ul>

You would need an additional wrapper for your .content that has overflow-y: hidden and height set to the max height available. To determine this height you need a function that runs after your DOM is loaded and adds this to your .content-wrapper:
function setContentMaxHeight() {
let containerHeight = $('.container').height()
let logoMargin = $('.logo').offset().top;
let logoHeight = $('.logo').height();
let listHeight = $('.list').height();
let listMargin = 20;
let maxHeight = containerHeight - ( 2 * logoMargin ) - logoHeight - ( 2 * listMargin) - listHeight;
$('.content-wrapper').css({
'height': maxHeight + 'px'
});
}
$(document).ready(function(){
setContentMaxHeight();
window.onresize = setContentMaxHeight; // detect the window resize and rerun the function
});
working fiddle

On scroll up use the animate() and show the div

I have two navigation in my website. Both the navigation bars are fixed. Basically when I scroll up, I would like to use the animate() and show both the navigation bar in the page. How do I get the scroll up event and use that to animate the divs, like the Google search widget. I would really appreciate your help. Thank you.
html:
<div id="navbar_header">
some link
</div>
<div id="main_content">
<p>Some content...</p>
</div>
<div id="navbar_footer">
some link
</div>
css:
#navbar_header {
background: #22313F;
position: fixed;
top: 0px;
left: 0px;
width: 100%;
height: 40px;
}
#navbar_footer {
background: #22313F;
position: fixed;
bottom: 0px;
left: 0px;
width: 100%;
height: 40px;
}

Normally using the window for the scroll event should be sufficient, as it's big enough and the one element, that's being scrolled. If jQuery is loaded correctly, you could try something like this:
$(document).ready(function(){
var lastTopPosition = 0;
$(window).scroll(function(){
var topPosition = $(window).scrollTop();
if (topPosition > lastTopPosition ){
$("#navbar_header").stop(true).animate({'top':'-40px'}, 200);
$("#navbar_footer").stop(true).animate({'bottom':'-40px'}, 200);
} else {
$("#navbar_header").stop(true).animate({'top':'0px'}, 200);
$("#navbar_footer").stop(true).animate({'bottom':'0px'}, 200);
}
lastTopPosition = topPosition;
}
});
This piece of code gets the current position from the top everytime you scroll. If the distance gets bigger (scroll down) the two bars fadeout. If it's getting smaller (scroll up) it fades in. You can replace the FadeOut/In methods here with you animate() call too. A check, if the elements are displayed would be good here too, but I guess you can figure that one out ;-)

If I understood this right, something along the lines of:
$("#main_content").scroll(function(){
$('#navbar_header').show(300);
$('#navbar_footer').show(300);
});
Where show(300) will basically do a 300ms showing animation of your divs.

Switch div from fixed to absolute at bottom of browser

Im trying to add a footer at the bottom of this content that doesn't overlay the content but moves it up.
The only way I can see it working would be something like, when browser is at the bottom remove 'fixed' class on the left red '#work'.
js fiddle DEMO
Updated js fiddle DEMO
HTML
<div id="header-block">
Header-block, this sits here in the background
</div>
<div id="content">
<div id="work">
This content should be fixed when at the top
</div>
<div id="description">
This content should scroll -
</div>
</div><!-- end content -->
<div id="footer">
This should appear at the bottom
</div>
CSS
body {
margin: 0px;
padding: 0px;
}
#header-block {
background: green;
width: 100%;
position: fixed;
z-index: 1;
height: 300px;
top: 0;
}
#content {
margin-top: 300px;
width: 100%;
position: relative;
z-index: 2;
}
#work {
background: red;
width: 50%;
height: 100vh;
float: left;
position: absolute;
}
#description {
background: blue;
width: 50%;
height: 1200px;
float: right;
font-size: 30px;
}
#footer {
background: black;
width: 100%;
height: 100px;
position: absolute;
z-index: 3;
bottom: 0;
}

If I understand your question correct, this should do the trick (although it depends very much on JavaScript unfortunately).
// Fix work column on scroll
contentStart = $("#content").offset().top ;
contentSize = $("#content").height() ;
window.onscroll = function(){
if( window.XMLHttpRequest ) {
var position=window.pageYOffset;
// calculate the position of the footer and the actual seen window
var docViewTop = $(window).scrollTop();
var docViewBottom = docViewTop + $(window).height();
var elemTop = $("#footer").offset().top;
if ( position > 300 && !(docViewBottom >= elemTop)) {
$('#work').css({'position':'fixed', 'top':'0', 'height':'100vh'});
} else {
// if the footer is visible on the screen
if(docViewBottom >= elemTop) {
$('#work').css({ 'top': 0 - (docViewBottom - elemTop) }); // scroll the #main div relative to the footer
} else {
$('#work').css({'position':'relative', 'top': 'auto'}) ;
}
}
}
}
For further informations about the calculations, perhaps this question on stackoverflow is useful.
Edit: Andrew Haining posted his answer in between of my answer, perhaps give his link a try and maybe it's a better (more proper) solution. Unfortunately I haven't actualised this page when I was testing your code in JSFiddle and I didn't see his answer.
If you want to use my script, make sure you can test it with different resolutions. It works just fine for my resolution in JSFiddle, I didn't test any other.

I'm not 100% sure what you want, but if you remove the position: absolute and the bottom: 0 from the footer, and put a div with class='clearboth' above the footer, it seems to do what you need.
CSS
.clearboth {
clear: both;
}
This is a drawing of what I see on your fiddle;
Do you want the red and the blue to always be touching the black?
I don't see the red overlying the black

You should use jQuery to add a class containing the position:fixed value when the scroll position of the page is less than the inline position of the #work div. Once it scrolls past the position, remove the class and have the element fall back in line.
You can achieve this using the following jQuery methods.. .scrollTop() .offset().top() and $(window).height().
This tutorial will give you an understanding of what you need to do to achieve the necessary results, you will just have to change the calculation slightly using $(window).height(), $('#footer').height() and a few other changes to get what you desire.

Based on the question you asked i think this is what you mean. The red div should be fixed when it gets to the top but be absolute when it is below the top for scrolling and the black footer should be below the red while scrolling, check this code i have done for you. just add this jquery script and run it.
<script type="text/javascript" src="js/jquery.js"></script>
<script>
$(document).ready(function() {
$(window).scroll(function () {
console.log($(window).scrollTop());
if ($(window).scrollTop() >= 322) {
$('#footer').css("z-index","1");
$('#work').css(
{
"background": "red",
"width": '50%',
'height': '100vh',
'float': 'left',
'position': 'fixed',
'top': '0'
});
}
if ($(window).scrollTop() <= 322)
{
$('#work').css(
{
"background": "red",
"width": "50%",
"height": "100vh",
"float": "left",
"position": "absolute"
});
};
});
});
</script>

If not exactly a parallax, this is somewhat close to how parallax works, containers moving at different speeds, and some containers sitting fixed or scrolling when they attain a particular top/bottom offset in the viewport.
There's plugin that can do it. Skrollr
You can use Skrollr along with skrollrcss, and it'll make sure how the containers take position on screen based on scrolltop of the window and the container specifically.

Slide panel in from right

I'm trying to replicate the effect on this website in the portfolio section where it slides a panel in the full size of the viewport and then slides it out when you click close.
Example here: http://alwayscreative.net/#portfolio
Here's my current markup:
<section class="panel" id="portfolio">
<section class="content">
<h1>What are you <strong>interested</strong> in?</h1>
<a class="btn-portfolio" id="btn-commercial" href="#">Commercial</a>
<a class="btn-portfolio" id="btn-residential" href="#">Residential</a>
</section>
</section>
The .panel section is 100% height and width of the viewport and I'd like 2 different panels to be able to slide in — one for #btn-commercial and one for #btn-residential.
Any ideas how to make this happen?
If it helps any, here's my site so far: http://www.freshbrand.ca/testlink/top40/#portfolio

Here's how you would do it with JQuery but clearly you can do it in normal javascript if you prefer. Set up the panels with position absolute in your css:
.panel {
position: absolute;
top: 0;
height: 100%;
border-width: 0;
margin: 0;
}
.panel inactive{
display: none;
}
.panel active {
display: block;
left: 0;
width: 100%;
height: 100%;
}
in your javascript (after the dom has loaded) get the screen dimensions and set the positions of the inactive elements to just off the right hand edge of the screen:
$('.panel').css('width', screen.innerWidth);
var setup = function() {
$('.portfolio-panel.inactive').css('left', window.innerWidth);
$('.portfolio-panel.active').css('left', 0);
}
setup();
When you wish to slide a panel in from the right, pass its id to the following function:
var slideIn = function(panelId) {
$('#' + panelId).animate({
left: 0
}, 400, function () { // animates the #left property from the screen width down to zero (i.e. slide it in from the right hand edge of the screen)
// tidy up
$('.portfolio-panel.active').removeClass('active').addClass('inactive');
$('#'+panelId).removeClass('inactive').addClass('active');
setup();
});
};
EDIT: The event handler would look something like this:
$('.btn-portfolio').click(function() {
slideIn($(this).attr('id').substr(4)); // extract the panel name from the id and pass it into slideIn
});
The only remaining issue is to eliminate the horizontal scroll bar you will probably see during the animation. Just add overflow-x: hidden; to the element to which the scroll bar belongs (probably body, but it depends on how you've structured and styled the rest of your site)

This is basically a single page website, a lot of jQuery plugins are available for the same.
I personally prefer
http://joelb.me/scrollpath/
Check out it's demo and download the code from github's link
https://github.com/JoelBesada/scrollpath
Hope this helps

floating menu bar in containing div (js)

I have a JavaScript menu bar that is positioned on my webpage, then when the browser bar reaches the top of the menu it locks into a fixed position and moves with the window. However, i need to contain the menu within a div, how can this be done?
This is my menu bar:
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.5.1/jquery.min.js"></script>
<script type='text/javascript'>
$(window).load(function(){
$(window).scroll(function(){
if ($(window).scrollTop() >= 200)
{
$("#floatbar").css({position:'fixed',left:'0',top:'0'});
}
else
{
$("#floatbar").css({position:'absolute',left:'0',top:'200px'});
}
});
});
</script>
and this is my html:
<div id="menu_runner">
<div id="floatbar">
Issue 49<br />
Issue 48<br />
Issue 47<br />
Issue 46<br />
</div>
</div>
and my css:
#menu_runner {
width: 100px;
height: 2000px;
float: right;
position: relative;
}
#floatbar {
width: 70px;
position: absolute;
top: 200px;
}
where the menu runner is the containing div of the menu, and the floatbar obviously contains the menu which runs the JavaScript.
However when I try this code, the menu sticks to the left and 200px from the top, and not within the menu_runner div. How can i make the floatbar be positioned in the menu_runner div and then scroll down with the JavaScript within the div as it should.
Here's a live demo of my code: http://jsfiddle.net/f4dhy/

Here's one method:
Live demo
Javascript:
$(window).scroll(function() {
if ($(window).scrollTop() >= 200) {
screenWidth = $(window).width();
containerWidth = $("#menu_runner").outerWidth(true);
pos = screenWidth - containerWidth;
$("#floatbar").css({
position: 'fixed',
left: pos,
top: '0'
});
}
else {
$("#floatbar").css({
position: 'absolute',
left: '0',
top: '200px'
});
}
});
The idea is get the screen's width, the menu container's width, and from that we get figure out how to position the left edge of the menu so that it lines up with the container.
In your css, add:
body{
padding: 0;
margin: 0;
}
which fixes the slightly off positioned problem you'd see without it due to the default margin set by browsers.
You might see the menu kinda bounce into position when you scroll it to the top, which is unfortunate but hopefully not too much of a problem.
This doesn't work in IE6 because of the position:fixed being used. You'll have to search for a solution to that. I'm not too familiar with what the accepted workaround is (but a quick google search shows a few hacks that might work)
I'm curious though, any reason you want to do it this way? Why have the menu scroll with the screen and then stop at the top? Why not just fix it to one place on the screen from the start, something like this?