I have a program that removes a character from a string and it works fine what I was trying to add was to make the program read a text file with multiple lines of text and remove the specific character if the character exists in the first position of every line. How can I implement this. Any help is appreciated. Thanks in advance.
Example:
22Orange
22Banana
would become:
Orange
Bannana
//something like this but this only works if I have a single line string
var aStr = fs.readFileSync('filePath', 'utf-8')
var bStr = aStr.replace(/^22+/i, '');
console.log(bStr)
Use the global (g) and multiline (m) flags.
let str = `22Orange
22Banana`;
console.log(str.replace(/^22/gm, ''));
So I am trying to figure out how I can remove a select set of characters on the end of a string. I've tried some general 'solutions' like str.replace or creating a rtrim, but I kept seeing some situation in which it wouldn't work.
Possible inputs might be:
\r\n some random text \r\n
\r\n some random text
some random text \r\n
some random text
Only the first and the third line should be affected by this function.
Basicly I'm looking for a rtrim function that takes as a parameter, the value/character set that should be trimmed.
I think it might be something way too obvious that I don't see, but at this point I feel like I could use some help.
You can use the following piece of code to do that for you:
var a = "\r\n some random text \r\n";
a = a.replace(new RegExp('\r\n$'), '');
Here, $ matches end of input.
You can refer to the regular expressions guide here to find out more about regex in JS.
EDIT:
If you really need a function for this:
var rTrimRegex = new RegExp('\r\n$');
var rTrim = function(input){
return input.replace(rTrimRegex, '');
}
And then use it inside your code maybe like:
var str = 'my name is foo\r\n\r\n';
str = rTrim(str);
I am trying to find a regex to achieve the following criteria which I need to use in javascript.
Input file
some string is here and above this line
:62M:C111111EUR1211498,00
:20:0000/11111000000
:25:1111111111
:28C:00001/00002
:60M:C170926EUR1211498,06
:61:1710050926C167,XXNCHKXXXXX 11111//111111/111111
Output has to be
some string is here and above this line
:61:1710050926C167,XXNCHKXXXXX 11111//111111/111111
Briefly, find :62M: and then replace (and delete) the lines starting with :62M: followed by lines starting with :20:, :25:, :28c: and :60M:.
Or, find :62M: and replace (and delete) until the line starting with :61:.
Each line has fixed length of 80 characters followed by newline (CR LF).
Is this really possible with regex?
I know how to find a string and replace the same line where the string is. But here multiple lines to be removed which is quite hard for me.
Please could someone help me out if it is possible with regex.
Here it is. First I'm finding text to delete using regex (note that I'm using [^]* to match all the lines insted of .*, as it also matches newlines). Then I'm replacing it with a newline.
var regex = /:62M:.*([^]*):61:.*/;
var text = `some string is here and above this line
:62M:C111111EUR1211498,00
:20:0000/11111000000
:25:1111111111
:28C:00001/00002
:60M:C170926EUR1211498,06
:61:1710050926C167,XXNCHKXXXXX 11111//111111/111111`;
var textToDelete = regex.exec(text)[1];
var result = text.replace(textToDelete, '\n');
console.log(result);
Hi I have some text in following format,
683101,
682303,
682302,
682315,
683581,
686667,
682008,
683572,
683573,
682313,
686672,
683545 etc....
Each line break'ed into next line with "Enter". I have nearly 2000 lines of text like this. i want o display the above string to a single line like this.
683101,
682303,
682302,
682315,
683581,
686667,
682008,
683572,
683573,
682313,
686672,
683545,
686672,
683545 etc..
I think there is some tweak options in CSS for doing this. Is there a way in JavaScript to do this? Actually it is not a requirement for me, am just curious to know how it is done.
Edit:
In My text editor it looks like this,
When i try to run it, this is what i get.
Thats why i want to remove the enter, multiline.......
You can use Regular expression to remove all the linebreaks and replace them using space.
str = str.replace(/\n/g, ' ');
Here, \n will match all the line-breaks, and replace them by space
I have a simple way for this. You can do this without extra code. Just write like this -
var str = "12345,\
234234,\
234324,\
234324,\
234324,\
234234";
now just add a slash
Ok, If you don't want to use the above method then use another plan is -
take inside an array and after that use the join method
var str = [12345,
234234,
234324,
234324,
234324,
234234];
str.join(",");
If we are using ES6, Then we have an elegant way to do this using Backtick -
var str = `12345,
234234,
234324,
234324,
234324,
234234`;
Since your data is already comma separated, you can try to add "[" to the beginning and append " ].toString().replace(/\n/g," ") " to the end of your data to get a single line string like this:
[683101,
682303,
682302,
682315,
683581,
686667,
682008,
683572,
683573,
682313,
686672,
683545].toString().replace(/\\n/g," ")
then you get:
"683101,682303,682302,682315,683581,686667,682008,683572,683573,682313,686672,683545"
I hope this helps :)
If all you want is to put those values in one line then, you can set those values as the value of a textarea field. This will allow you to read all those values into a javascript string. Afterward you can apply the regular expression that Tushar suggested.
See the code segment below:
<textarea id="content">
683101,
682303,
682302,
682315,
683581,
686667,
682008,
683572,
683573,
682313,
686672,
683545
</textarea>
Here is the javascript:
var content = $('#content').val();
var content = content.replace(/\n/g, ' ');
console.log(content);
I got a string like this one:
var tweet ="#fadil good:))RT #finnyajja: what a nice day RT #fadielfirsta: how are you? #finnyajja yay";
what kind of code should work to extract any words with # character and also removing any special char at the end of the words? so it would an array like this :
(#fadil, #finnyajja, #fadielfirsta, #finnyajja);
i have tried the following code :
var users = $.grep(tweet.split(" "), function(a){return /^#/.test(a)});
it returns this:
(#fadil, #finnyajja:, #fadielfirsta:, #finnyajja)
there's still colon ':' character at the end of some words. What should I do? any solution guys? Thanks
Here is code that is more straightforward than trying to use split:
var tweet_text ="#fadil good:))RT #finnyajja: what a nice day RT #fadielfirsta: how are you? #finnyajja yay";
var result = tweet_text.match(/#\w+/g);
The easiest way without changing your current code too much would be to just remove all colons prior to calling split:
var users = $.grep(tweet_text.replace(":","").split(" "), function(a){return /^#/.test(a)});
You could also write a regex to do all the work for you using match. Something like this:
var regex = /#[a-z0-9]+/gi;
var matches = tweet.match(regex);
This assumes that you only want letters and numbers, if certain other characters are allowed, this regex will need to be modified.
http://jsfiddle.net/YHM87/