Below are my code parts javascript, main.php and getparty.php
1) getparty.php code is as follow called from javascript to take details
from party table on change of dropdown value of party from main.php
<?php
$q = intval($_GET['q']);
include "dbc.php";
$sql= mysql_query("Select a.pcode,a.pname,a.discperc,a.delvterm from PARTY a where a.pcode='$q'") or die(mysql_error());
$row = mysql_fetch_array($sql) or die(mysql_error());
$pcode=$row['pcode'];
$ppname=$row['pname'];
$pdiscperc=$row['discperc'];
?>
main.php ... it is my main form to display main form for user to enter
<tr>
<td><font face="verdana" size="2" color="#000000">Party</font></td>
<td>
<?php
<td align="left" >
<?php
$sql="UPDATE PARTY set repo_flag=0 ";
if (!mysql_query($sql,$conn))
{
die('Error: ' . mysql_error());
}
if ($ppname!="")
{
$sql="UPDATE PARTY set repo_flag=1 where pname='$ppname' ";
}
if (!mysql_query($sql,$conn))
{
die('Error: ' . mysql_error());
}
$dropdown = "<select id='pname' name='pname' style='width:275px' onchange='showparty(this.value)' value='<?php echo $ppname; ?>' >";
$query1 = "select pcode,pname from PARTY order by repo_flag DESC ";
$get=mysql_query($query1);
while($row = mysql_fetch_array($get))
{
$dropdown .= "\r\n<option value='{$row['pcode']}'>{$row['pname']}</option>";
}
$dropdown .= "\r\n</select>";
echo $dropdown;
?>
?>
</td>
</tr>
<tr>
<td><input type="text" maxlength="3" size="3" name="txtdiscperc" value="<?php echo $pdiscperc; ?>"/></td>
</tr>
Javascript .. This is called to take value of party when dropdown
combo changes
<script>
function showparty(str) {
if (str == "") {
document.getElementById("txtpartyname").innerHTML = "";
return;
} else {
if (window.XMLHttpRequest) {
// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp = new XMLHttpRequest();
} else {
// code for IE6, IE5
xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange = function() {
if (xmlhttp.readyState == 4 && xmlhttp.status == 200) {
document.getElementById("txtpartyname").innerHTML = xmlhttp.responseText;
}
}
xmlhttp.open("GET","getparty.php?q="+str,true);
xmlhttp.send();
}
}
</script>
I am not getting value of Discount % in main.php, and some other fields also I want to get from party table which I can write code when above discount % gets properly. How can I
Related
I want the output of "cor_resp_template" where is nome and select that values for in next page do some operations like(sum, multiplication,...). I try the first time use JavaScript, but i don´t know if the code is correct. I try to analysis step by step and seems ok for that operation.
In next picture like you see the empty values. Don´t show the table with the values for after submit that values for next page.
The output of database of the table template where is all the values:
That is the output of that page:
http://localhost/dissertacao/conceptualization13.php?menuId=1
After we have the code where we use the JavaScript for get the values in next page where is the PHP query.
<script>
function showUser(str) {
if (str == "") {
document.getElementById("$option").innerHTML = "";
return;
} else {
if (window.XMLHttpRequest) {
// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp = new XMLHttpRequest();
} else {
// code for IE6, IE5
xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange = function() {
if (this.readyState == 4 && this.status == 200) {
document.getElementById("$option").innerHTML = this.responseText;
}
};
xmlhttp.open("GET","template1.php?option="+str,true);
xmlhttp.send();
}
}
</script>
</head>
<body>
<form>
<?php
echo "<select name='template' class='form-control' onchange='showUser(this.value)'>";
mysql_connect("localhost","root","") or die(mysql_error());
mysql_select_db("teste") or die(mysql_error()); // selecciona a database do server escolhido
echo "<center>";
// Get the county names from database - no duplicates
$query = "SELECT DISTINCT nome FROM template";
{
// execute the query, $result will hold all of the Counties in an array
$resultado = mysql_query($query) or die(mysql_error());
while($row = mysql_fetch_array($resultado))
$option .="<option>" . $row['nome'] . "</option>";
echo $option;
}
echo "</select>";
echo "<br>";
?>
<input type="submit" value="Submit">
</form>
<br>
<div id="valores"><b>Os valores para este template são:</b></div>
template1.php
The following code is the PHP QUERY where is called for give the output of the table with the values where is nome in the SQL table.
<?php
$option = (isset($_POST['nome']) ? $_POST['nome'] : '');
mysql_connect("localhost","root","") or die(mysql_error());
mysql_select_db("teste") or die(mysql_error()); // selecciona a database do server escolhido
$query="SELECT * FROM template WHERE 'nome' = '".$option."'";
$resultado = mysql_query($query) or die(mysql_error());
echo "<table>
<tr>
<th>Valores</th>
</tr>";
while($row = mysql_fetch_array($resultado)) {
var_dump ($resultado);
echo "<tr>";
echo "<td>" . $row['corp_resp_template'] . "</td>";
echo "</tr>";
}
echo "</table>";
?>**
Ive been try to make a page with Pagination on table. Upon button click, the table in main.php got populated by the first 16 rows retrieved from the query in page.php. For example the retrieved rows were 20. So there would be an excess of 4 for the second page. The thing is when I clicked the "Next" button to show the missing 4 records, the page is then diverted to page.php with the missing records. What I want to happen is for the 20 records in main.php be replaced by the 4 records.
MAIN.PHP
<div id="section">
<head3>Asset Assignment</head3><br><br>
<table>
<td>
<tr>Search Asset:</tr>
<tr><input type="text" id="sidt" name="sid"></tr>
<tr><input type="button" name="searchSub" value="Search" onClick="searchItem()"></tr>
</td>
</table><br>
<table>
<tr>
<td>Employee ID</td>
<td>Asset Serial Number</td>
</tr>
<tr>
<td><input type="text" name="empID"></td>
<td><input type="text" name="srlID"></td>
</tr>
<tr>
<td align="right"><input type="button" name="assign" value="Assign" onClick="assignItem()"></td>
</tr>
</table><br>
</div>
<div id="section2"></div>
JAVASCRIPT
function searchItem()
{
var xhr;
if (window.XMLHttpRequest) {
xhr = new XMLHttpRequest();
}
else if (window.ActiveXObject) {
xhr = new ActiveXObject("Microsoft.XMLHTTP");
}
var data = "asid=" + document.getElementById("sidt").value;
xhr.open("POST", "page.php", true);
xhr.setRequestHeader("Content-Type", "application/x-www-form-urlencoded");
xhr.send(data);
xhr.onreadystatechange = display_data;
function display_data()
{
if (xhr.readyState == 4)
{
if (xhr.status == 200)
{
document.getElementById("section2").innerHTML = xhr.responseText;
}
else
{
alert('There was a problem with the request.');
}
}
}
}
function assignItem(){}
PAGE.PHP
<?PHP
session_start();
$dbHost = "localhost";
$dbUser = "root";
$dbPass = "password";
$dbDatabase = "awsims";
$db = new PDO("mysql:dbname=$dbDatabase;host=$dbHost;port=3306", $dbUser, $dbPass);
if (!isset($_GET['startrow']) or !is_numeric($_GET['startrow'])) {
$startrow = 0;
} else {
$startrow = (int)$_GET['startrow'];
}
$sql = $db->prepare("SELECT * FROM assets LIMIT $startrow, 16");
$sql->execute();
$fetch = $sql->rowCount();
$num=$fetch;
if($num>0)
{
echo "<table style='width: 100%' border='1'>";
echo "<tr><td>ID</td><td>Drug</td><td>quantity</td></tr>";
for($i=0;$i<$num;$i++)
{
$row = $sql->fetch(PDO::FETCH_ASSOC);
$a = $row['SerialNumber'];
$b = $row['AssetType'];
$c = $row['AssetSubType'];
echo "<tr>";
echo "<td>$a</td>";
echo "<td>$b</td>";
echo "<td>$c</td>";
echo "</tr>";
}
echo "</table>";
}
echo '<a href='.$_SERVER['PHP_SELF'].'?startrow='.($startrow+16).'>Next</a>';
$prev = $startrow - 16;
//if ($prev >= 0)
echo '<a href='.$_SERVER['PHP_SELF'].'?startrow='.$prev.'>Previous</a>';
?>
Try changing your sql statement to as following query.
$sql = $db->prepare("SELECT * FROM assets LIMIT 16 OFFSET $startrow");
The next and previous link code should be like following.
echo '<a href='.$_SERVER['PHP_SELF'].'?startrow='.($startrow+1).'>Next</a>';
$prev = $startrow - 1;
echo '<a href='.$_SERVER['PHP_SELF'].'?startrow='.$prev.'>Previous</a>';
Here is the easiest and smartest PHP MySQL Pagination example I had ever read! Very well explained and a full code is provided which is tested and working 100%.
I display a table on the website after a select option (I use ajax) and get the datas from the database. What I want to do is to insert a checkbox in my table and when it is checked delete the row in the database. I don't want to use a submit button but only the checkbox to delete it.
I'm not really good with ajax and JavaScript. This is the code:
The select :
<p>
<label for="client">Veuillez choisir le fournisseur :</label><br />
<select name="client" id="client" onchange="showUser(this.value)">
<?php
// echo '<option value=""/></option>';
while ($donnees = $reponse->fetch())
{
echo '<option value='.$donnees['refCustomer'].'>'.$donnees['legalCompanyName'].' </option>';
//$value = $donnees['refCustomer'];
}
$reponse->closeCursor();
?>
</select>
</p>
The script :
<script>
function showUser(str) {
if (str == "") {
document.getElementById("txtHint").innerHTML = "";
return;
} else {
if (window.XMLHttpRequest) {
// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp = new XMLHttpRequest();
} else {
// code for IE6, IE5
xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange = function() {
if (xmlhttp.readyState == 4 && xmlhttp.status == 200) {
document.getElementById("txtHint").innerHTML = xmlhttp.responseText;
}
}
xmlhttp.open("GET","getTableBuffer.php?q="+str,true);
xmlhttp.send();
}
}
</script>
getTableBuffer.php :
<?php
$q = intval($_GET['q']);
try
{
$bdd = new PDO());
}
catch (Exception $e)
{
die('Erreur : ' . $e->getMessage());
}
$reponse = $bdd->query('select * from vendor_'.$q.'_offers_ncli_amendments_buffer');
echo '<table class="imagetable">';
echo '<tr>';
echo '<th>code</th>';
echo '<th>dateAdded</th>';
echo '<th>effectiveDate</th>';
echo '<th>price</th>';
echo '<th>type</th>';
echo '<th>destination</th>';
echo '</tr>';
while ($donnees = $reponse->fetch())
{
echo '<tr>';
echo '<td><input type="checkbox" name="code" id="code" value="'.$donnees['code'].'"/>'.$donnees['code'].'</td>';
echo '<td>'.$donnees['dateAdded'].'</td>';
echo '<td>'.$donnees['effectiveDate'].'</td>';
echo '<td>'.$donnees['price'].'</td>';
echo '<td>'.$donnees['type'].'</td>';
echo '<td>'.$donnees['destination'].'</td>';
echo "</tr>";
}
echo "</table>";
echo "</br>";
echo "</br>";
$reponse->closeCursor();
?>
Add event onclick to your checkbox :
echo '<td><input onclick="remove(this);" type="checkbox" name="code" id="code" ....';
create function remove() in you javascript, that send the $donnees['code'] to a remove.php to delete it from DB :
function remove(e)
{
if (e.target.checked)
{
....
xmlhttp.open("GET","remove.php?code="+e.target.value,true);
xmlhttp.send();
}
}
Create remove.php that get the code and delete from DB :
<?php
if(isset($_GET['code'])){
//Query to remove from DB where code = $_GET['code']
}
?>
Hope this will help.
I would like to display one column of data, [pin], based on the [plan] and [order_id] values. plan=9 and order_id=0. Would like to load data without reloading page, using ajax.
Here is my HTML/Script:
<script>
function showPins(str) {
if (str == "") {
document.getElementById("txtHint").innerHTML = "";
return;
} else {
if (window.XMLHttpRequest) {
// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp = new XMLHttpRequest();
} else {
// code for IE6, IE5
xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange = function() {
if (xmlhttp.readyState == 4 && xmlhttp.status == 200) {
document.getElementById("txtHint").innerHTML = xmlhttp.responseText;
}
}
xmlhttp.open("GET","getPins.php?q="+str,true);
xmlhttp.send();
}
}
</script>
HTML:
<div align="center">
<h3>View PIN's</h3>
<form>
<select name="users" onchange="showPins(this.value)">
<option value="">Select Plan Type:</option>
<option value="1">Plan1</option>
<option value="2">Plan2</option>
<option value="3">Plan3</option>
</select>
</form>
<br/>
<div id="txtHint"></div>
</div>
This is my PHP file (getPins.php):
<?php
$q = intval($_GET['q']);
$con = mysqli_connect('myHost','myUsername','myPw','my_db');
if (!$con) {
die('Could not connect: ' . mysqli_error($con));
}
mysqli_select_db($con,"my_db");
$sql="SELECT * FROM attPins WHERE (order_id=0, plan=9 and id = '".$q."')";
$result = mysqli_query($con,$sql);
echo "<table>
<tr>
<th>PIN's</th>
</tr>";
while($row = mysqli_fetch_array($result)) {
echo "<tr>";
echo "<td>" . $row['pin'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysqli_close($con);
This is based off the tutorial shown here: http://www.w3schools.com/php/php_ajax_database.asp
Trying to make it work for showing the correct pins for plan type chosen.
your query would be wrong read manual where
$sql="SELECT * FROM attPins WHERE (order_id=0, plan=9 and id = '".$q."')";
It would be
WHERE (order_id=0 and plan=9 and id = '".$q."')
Or
WHERE (order_id=0 OR plan=9 and id = '".$q."')
according to your requirment
This is my table subjects in lecturer database
No subject credit_hour
1 (111) AAA 4
2 (222) BBB 3
3 (222) CCC 4
4 (333) DDD 3
This is what I have done using ajax
This is my testing1.php
<?php
$conn = mysql_connect('localhost','root','password');
mysql_select_db('lecturer');
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
?>
<html>
<head>
<script>
function showUser(str)
{
if (str==="")
{
document.getElementById("txtHint").innerHTML="";
return;
}
if (window.XMLHttpRequest)
{// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp=new XMLHttpRequest();
}
else
{// code for IE6, IE5
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange=function()
{
if (xmlhttp.readyState===4 && xmlhttp.status===200)
{
document.getElementById("txtHint").innerHTML=xmlhttp.responseText;
}
}
xmlhttp.open("GET","testing3.php?q="+str,true);
xmlhttp.send();
}
</script>
</head>
<body>
<form>
<select name="subjects" onchange="showUser(this.value)">
<option value="">Select a subject:</option>
<?php $result= mysql_query('SELECT * FROM subjects'); ?>
<?php while($row= mysql_fetch_assoc($result)) {
$list=array($row['subject'],$row['credit_hour']);
?>
<option>
<?php echo htmlspecialchars($row['subject'] ); ?>
<?php echo htmlspecialchars($row['credit_hour'] ); ?>
</option>
<?php } ?>
</select>
</form>
<br>
<div id="txtHint"><b>subject info will be listed here.</b></div>
</body>
</html>
This is my testing3.php
<?php
$q = intval($_GET['q']);
$con = mysqli_connect('localhost','root','password','lecturer');
if (!$con)
{
die('Could not connect: ' . mysqli_error($con));
}
mysqli_select_db($con,"lecturer");
$sql="SELECT * FROM subjects WHERE No = '".$q."'";
$result = mysqli_query($con,$sql);
echo "<table border='1'>
<tr>
<th>Subject</th>
<th>Credit_hour</th>
</tr>";
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['subject'] . "</td>";
echo "<td>" . $row['credit_hour'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysqli_close($con);
?>
The problem is that when I select (111)AAA 4
it should be appearing a table which is located in testing3.php
but it did't fetch any data in the table
Thank you
After your first select query you should put the subject, hour_credit pair in an array, then on onchange event of the first option(your subject list) you should check which index is selected then set the second options selected index.