In my website I use:
- www.example.com/es/index.html
- www.example.com/en/index.html
- www.example.com/ch/index.html
How can I easily get the value language? (es or en or ch)
language = url.split("/")[1];
Where url is the URL you are parsing. Maybe use 'location' to get it.
You can use:
var url = 'www.example.com/es/index.html'
var lang = url.split('/')[1]
can use var lang = location.pathname.split('/')[1]
this assumes that the language directory is always right after .com
While all those
str.split("/")[1]
solutions are good I want to suggest a regex (if only for completeness sake).
Using
str = "www.example.com/es/index.html";
str.match(/www\.example\.com\/(.+)\//)[1]
works aswell and furthermore it also matches correctly for strings like:
"http://www.example.com/es/index.html"
fiddle: http://jsfiddle.net/zpmvrv2a/
As u_mulder suggested, you can use document.location like so:
document.location.href.split("/")[1];
Related
For example I have a url like:
ftp://xxx:xxx#ftp.example.com/BigFile.zip
How can I get example.com from this url using javascript/jquery?
You can get the browser to parse the URL for you like this :
var a = document.createElement('a');
a.href = 'ftp://xxx:xxx#ftp.example.com/BigFile.zip';
var host = a.hostname;
That gets you the hostname, which in this case would be ftp.example.com, if for some reason you have to remove the subdomain, you can do
var domain = host.split('.');
domain.shift();
var domain = domain.join('.');
FIDDLE
Here's the different parts to a URL -> https://developer.mozilla.org/en-US/docs/Web/API/Location#wikiArticle
Here is using javascript RegExp
input = "ftp://xxx:xxx#ftp.example.com/BigFile.zip";
pattern = new RegExp(/ftp:\/\/\S+?#\S+?\.([^\/]+)/);
match = pattern.exec(input);
alert(match[1]);
You can also use i at the end of regex to make it case insensitive.
pattern = new RegExp(/ftp:\/\/\S+?#\S+?\.([^\/]+)/i);
You can use jquery like this:
var url = "ftp://xxx:xxx#ftp.example.com/BigFile.zip";
var ahref = $('<a>', { href:url } )[0]; // create an <a> element
var host = ahref.hostname.split('.').slice(1).join('.'); // example.com
You can have a regex to do this for you.
url = 'ftp://xxx:xxx#ftp.example.com/BigFile.zip'
base_address = url.match(/#.*\//)[0];
base_address = base_address.substring(1, base_address.length-1)
This would contain ftp.example.com though. You can fine tune it as per your need.
I just wanted to try/add something different (can't bet for performance or the general solution, but it works and hey ! without DOM/regexp involved):
var x="ftp://xxx:xxx#ftp.example.com/BigFile.zip"
console.log((x.split(".")[1]+ "." + x.split(".")[2]).split("/")[0]);
For the given case can be shortest since always will be ".com"
console.log(x.split(".")[1]+ ".com");
Another (messy) approach (and will work with .com.something:
console.log(x.substring((x.indexOf("#ftp"))+5,x.indexOf(x.split("/")[3])-1));
And well on this we're dependend about having "#ftp" and the slashes "/" (at least 3 of them or one after the .com.something) for example would not work with: ftp://xxx:xxx#ftp.example.com
Last update This will be my best
without DOM/RegExp, nicer (but also confusing) that the previous ones
solves the problem about having or don't the slashes,
still dependant on having "#ftp." in the string.
works with .com.something.whatever
(function (splittedString){
//this is a bit nicer, no regExp, no DOM, avoid abuse of "split"
//method over and over the same string
//check if we have a "/"
if(splittedString.indexOf("/")>=0){
//split one more time only to get what we want.
return (console.log(splittedString.split("/")[0]));
}
else{
return (console.log(splittedString));//else we have what we want
}
})(x.split("#ftp.")[1]);
As always it depends how maintainable you want your code to be, I just wanted to honor the affirmation about there's more than one way to code something. My answer for sure is not the best, but based on it you could improve your question.
I request the javascript guru masters again!
Okay this is probably simple, blowing my mind atm.
Example: http://example.com/page.php
var path = location.pathname;
Returns: /page.php
I would like it to not include the first / so it would return page.php
Thank you guru masters!
You just need to use one of the several substring functions.
var path = location.pathname.substr(1);
Update:
substr is now a deprecated method, so you should use slice instead.
var path = location.pathname.slice(1);
var path = location.pathname.substring(1);
You can use replace() function also, but it replaces the all found forward slashes in path.
var path = location.pathName.replace("/","");
The question is simple, assume the following string:
var str = 'aaaaab\'s'
How do you extract the value of href. I would think something like
var arr = str.match(/(?:href=")(\w+)/g) ;
--> ["href="aaaa", "href="bb"]
Of course I want
["aaaa", "bb"]
Withoug the /g it get close, but it only matches "aaaa". Any suggestions how to fix this ?
Thanks!
DOM parsing with JS is so easy.
var str = 'aaaaab\'s',
help = document.createElement('div');
helper.innerHTML = str;
Array.prototype.forEach.call(help.querySelectorAll("a[href]"), function (elem) {
console.log(elem.getAttribute('href'));
});
http://jsfiddle.net/ExplosionPIlls/gtdFh/
Because Javascript doesn't have lookbehind, this may be what you want. Naturally there will be more elegant solutions:
input.match(/<[^href|/]*(href[\s]*=[\s]*")([^"]+)(?=">)/g).map(
function(x){return x.split('href')[1].replace(/[^"]+"(.*)/,'$1');
})
Additionally, you may be better off getting a HTML parsing plugin. And extracting the properties you need using that.
Cheers.
I want to remove the string code=hads1328fas& on my URL, so that
BEFORE
http://example.com/main/index.php?code=hads1328fas&store=food#home
AFTER
http://example.com/main/index.php?store=food#home
However, the string code=hads1328fas& may not always the same, so the code below won't works in this case.
var url = window.location.href;
url.replace('code=hads1328fas&')
Is there any way that is possible for the case?
Thanks
Use regular expressions:
url = "http://example.com/main/index.php?code=hads1328fas&store=food#home";
url = url.replace(/code=[^&]+&/,'');
After this, url will contain
http://example.com/main/index.php?store=food#home
I'm using javascript and would like to take a URL string that I have and break it down into its components such as the host, path, and query arguments.
I need to do this in order to get to one of the query arguments, which is itself a URL and is thus encoded in the original URL string.
I feel like there should be an easy way to do this in Javascript. Perhaps something that looks like this:
var what_I_Want = url("http://www.domain.com?queryArg1=somequeryargument").getQueryArgumentValue("queryArg1");
The parseUri function will do everything you need
Edit
Alternatively you can get the DOM to do the hard work for you and access properties on a newly created a object for different parts of the URL.
<script type="text/javascript" language="javascript">
newURL = window.location.protocol + "//" + window.location.host + "/" + window.location.pathname;
</script>
Hope this will help..
In javascript you can do this by using split() for the params and using the location object for the protocol and domain -- like Carl suggested
Also you can use parseUri as Tak suggested
There is also a jQuery plugin which makes parsing easier if you are already using jQuery in your project: https://github.com/allmarkedup/jQuery-URL-Parser#readme
Example:
$.url('http://allmarkedup.com?sky=blue&grass=green').param('sky'); // returns 'blue'
Probably not the greatest way of doing it but a simple method to get the query string in JavaScript would be to just use something along the lines of:
a = "http://www.domain.com?queryArg1=somequeryargument";
query = a.substring(a.indexOf('?')+1);
You could then split the query up based on the &'s and again on the = to get at whatever param you need.
Sorry if this ain't very helpful as its a bit of a low tech method :P
EDIT:
Just wrote a quick little JavaScript object to get URL Query parameters for you (sort of like) in your example. Only tested it in chrome but in theory it should work :)
//Quick and dirty query Getter object.
function urlQueryGetter(url){
//array to store params
var qParam = new Array();
//function to get param
this.getParam = function(x){
return qParam[x];
}
//parse url
query = url.substring(url.indexOf('?')+1);
query_items = query.split('&');
for(i=0; i<query_items.length;i++){
s = query_items[i].split('=');
qParam[s[0]] = s[1];
}
}
//Useage
var bla = new urlQueryGetter("http://www.domain.com?queryArg1=somequeryargument&test=cheese");
alert(bla.getParam('test'));