I need a RegEx pattern to match any/all instances that look like {!(.*)}
I have tried the following:
ie.
var mergefield_array = value.match(patt);
where value = '{!lat},{!lng}'
and patt = /{!(.*)}/
it returns a single result: {!lat},{!lng}
but I want it to return two matches in this case ('{!lat}' and '{!lng}').
How do I do it?
Colin G
Your regex is greedy in nature due to use of .* hence matching first { to last }, grabbing anything on the way.
To fix you can make it non-greedy:
patt = /{!(.*?)}/g
Or use negation:
patt = /{!([^}]*)}/g
Related
In Javascript, from a string like this, I am trying to extract only the number with a hyphen. i.e. 67-64-1 and 35554-44-04. Sometimes there could be more hyphens.
The solvent 67-64-1 is not compatible with 35554-44-04
I tried different regex but not able to get it correctly. For example, this regex gets only the first value.
var msg = 'The solvent 67-64-1 is not compatible with 35554-44-04';
//var regex = /\d+\-?/;
var regex = /(?:\d*-\d*-\d*)/;
var res = msg.match(regex);
console.log(res);
You just need to add the g (global) flag to your regex to match more than once in the string. Note that you should use \d+, not \d*, so that you don't match something like '3--4'. To allow for processing numbers with more hyphens, we use a repeating -\d+ group after the first \d+:
var msg = 'The solvent 67-64-1 is not compatible with 23-35554-44-04 but is compatible with 1-23';
var regex = /\d+(?:-\d+)+/g;
var res = msg.match(regex);
console.log(res);
It gives only first because regex work for first element to test
// g give globel access to find all
var regex = /(?:\d*-\d*-\d*)/g;
I'm trying to use a regex in JS to remove the last part of a string. This substring starts with &&&, is followed by something not &&&, and ends with .pdf.
So, for example, the final regex should take a string like:
parent&&&child&&&grandchild.pdf
and match
parent&&&child
I'm not that great with regex's, so my best effort has been something like:
.*?(?:&&&.*\.pdf)
Which matches the whole string. Can anyone help me out?
You may use this greedy regex either in replace or in match:
var s = 'parent&&&child&&&grandchild.pdf';
// using replace
var r = s.replace(/(.*)&&&.*\.pdf$/, '$1');
console.log(r);
//=> parent&&&child
// using match
var m = s.match(/(.*)&&&.*\.pdf$/)
if (m) {
console.log(m[1]);
//=> parent&&&child
}
By using greedy pattern .* before &&& we make sure to match **last instance of &&& in input.
You want to remove the last portion, so replace it
var str = "parent&&&child&&&grandchild.pdf"
var result = str.replace(/&&&[^&]+\.pdf$/, '')
console.log(result)
I am using JavaScript and would like to match everything in a custom template language like this:
Begin10
Match THIS keyword and ANOTHER
End10
So I would like to find Begin10 using the 10 as variable to find End10 and match THIS and ANOTHER between them.
I've looked at capture groups. I assume this is the way to go, but I can't figure out how to compose the expression.
THIS and ANOTHER need to be targeted for syntax highlighting by my code.
You can use regex with captured group
var str = `Begin10
Match THIS keyword and ANOTHER1
End10
Begin20
Match THIS keyword and ANOTHER2
End20`;
console.log(
str.match(/\bBegin(\d+)[\s\S]*?\bEnd\1\b/g)
);
To get the string between them, do something like this
var str = `Begin10
Match THIS keyword and ANOTHER1
End10
Begin20
Match THIS keyword and ANOTHER2
End20`;
var res = [],
regex = /\bBegin(\d+)\s+([\s\S]*?)\s+\bEnd\1\b/g,
match;
while (match = regex.exec(str)) {
res.push(match[2]);
}
console.log(res);
Regex explanation here
UPDATE :
If there is only THIS or ANOTHER between them then use
var str = `Begin10
THIS
End10
Begin20
ANOTHER
End20`;
var res = [],
regex = /\bBegin(\d+)\s+(THIS|ANOTHER)\s+\bEnd\1\b/g,
match;
while (match = regex.exec(str)) {
res.push(match[2]);
}
console.log(res);
This will work
\bBegin(\d+)\b([\S\s]*)\bEnd\1\b
Regex Demo
\nBegin(\d+)\s*\nMatch \b(\w+)\b keyword and \b(\w+)\b\s*\nEnd\1\n
Explanation:
\n will match a newline, and I am sure you don't want to get anything besides newline.
\1 that's a variable for the first group to make sure it has the same value.
\s* just to ignore some unnecessary whitespaces.
I was able to build a regex to extract a part of a pattern:
var regex = /\w+\[(\w+)_attributes\]\[\d+\]\[own_property\]/g;
var match = regex.exec( "client_profile[foreclosure_defenses_attributes][0][own_property]" );
match[1] // "foreclosure_defenses"
However, I also have a situation where there will be a repetitive pattern like so:
"client_profile[lead_profile_attributes][foreclosure_defenses_attributes][0][own_property]"
In that case, I want to ignore [lead_profile_attributes] and just extract the portion of the last occurence as I did in the first example. In other words, I still want to match "foreclosure_defenses" in this case.
Since all patterns will be like [(\w+)_attributes], I tried to do a lookahead, but it is not working:
var regex = /\w+\[(\w+)_attributes\](?!\[(\w+)_attributes\])\[\d+\]\[own_property\]/g;
var match = regex.exec("client_profile[lead_profile_attributes][foreclosure_defenses_attributes][0][own_property]");
match // null
match returns null meaning that my regex isn't working as expected. I added the following:
\[(\w+)_attributes\](?!\[(\w+)_attributes\])
Because I want to match only the last occurrence of the following pattern:
[lead_profile_attributes][foreclosure_defenses_attributes]
I just want to grab the foreclosure_defenses, not the lead_profile.
What might I be doing wrong?
I think I got it working without positive lookahead:
regex = /(\[(\w+)_attributes\])+/
/(\[(\w+)_attributes\])+/
match = regex.exec(str);
["[a_attributes][b_attributes][c_attributes]", "[c_attributes]", "c"]
I was able to also achieve it through noncapturing groups. Output from chrome console:
var regex = /(?:\w+(\[\w+\]\[\d+\])+)(\[\w+\])/;
undefined
regex
/(?:\w+(\[\w+\]\[\d+\])+)(\[\w+\])/
str = "profile[foreclosure_defenses_attributes][0][properties_attributes][0][other_stuff]";
"profile[foreclosure_defenses_attributes][0][properties_attributes][0][other_stuff]"
match = regex.exec(str);
["profile[foreclosure_defenses_attributes][0][properties_attributes][0][other_stuff]", "[properties_attributes][0]", "[other_stuff]"]
I am trying to get a serial number from a zigbee packet (i.e get from 702442500 *13*32*702442500#9).
So far, I've tried this:
test = "*#*0##*13*32*702442500#9##";
test.match("\*#\*0##\*13\*32\*(.*)#9##");
And this:
test.match("*#*0##*13*32*(.*)#9##");
With no luck. How do I get a valid regular expression that does what I want?
The below regex matches the number which has atleast three digits,
/([0-9][0-9][0-9]+)/
DEMO
If you want to extract the big number, you can use:
/\*#\*0##\*13\*32\*([^#]+)#9##/
Note that I use delimiters / that are needed to write a pattern in Javascript (without the regexp object syntax). When you use this syntax, (double)? quotes are not needed. I use [^#]+ instead of .* because it is more clear and more efficent for the regex engine.
The easiest way to grab that portion of the string would be to use
var regex = /(\*\d{3,}#)/g,
test = "*13*32*702442500#9";
var match = test.match(regex).slice(1,-1);
This captures a * followed by 3 or more \d (numbers) until it reaches an octothorpe. Using the global (/g) modifier will cause it to return an array of matches.
For example, if
var test = "*13*32*702442500#9
*#*0##*13*32*702442500#9##";
then, test.match(regex) will return ["*702442500#", "*702442500#"]. You can then slice the elements of this array:
var results = [],
test = "... above ... ",
regex = /(\*\d{3,}#)/g,
matches = test.match(regex);
matches.forEach(function (d) {
results.push(d.slice(1,-1));
})
// results : `["702442500", "702442500"]`