I'd like to validate a phone number input using JavaScript to allow only number input. I prefer not to use regex, so I wrote a function like this:
function numberTest(){
for(var i=0;i<phone_number.length;i++){
if(phone_number.charCodeAt(i) >= 48 && phone_number.charCodeAt(i) <=57){
return true;
}else{
return false;
}
}
}
However it does not work. Any ideas why?
This doesn't work because it returns true after the first valid character. Neither branch will get past the first character, so you need to only return if you find an invalid character. Otherwise, if you reach the end without finding an invalid characters, you can finally return true.
Something like:
function numberTest(phone_number) {
for (var i = 0; i < phone_number.length; i++) {
if (phone_number.charCodeAt(i) < 48 && phone_number.charCodeAt(i) > 57) {
return false;
}
}
return true;
}
// Test various values
var testData = ["1234", "12ab", "123451234512345", "a1234123", "123123123a"];
var output = document.getElementById("results");
testData.forEach(function(test) {
var next = document.createElement("li");
next.textContent = numberTest(test);
});
<ul id="results"></ul>
The isNaN() (means is not a number) method will give you the reverted result in a simpler way...
var phone_number = "5511112223";
alert(isNaN(phone_number)); //returns false meaning it is a valid number
phone_number = "55aa1g11d12223";
alert(isNaN(phone_number)); //returns true meaning it is not a number
Related
This is from LeetCode - Valid Palindrome.
Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignoring cases.
Note: For the purpose of this problem, we define empty string as valid palindrome.
while (regex.test(s[start])) {
start++;}
--> can't understand how it works, I understood only that s[start] is alphanumeric characters, it will be false
if (!s[start] || !s[end])
--> What does this mean?
Below is the whole code
var isPalindrome = function(s) {
let regex = /[\W]/;
let start = 0;
let end = s.length - 1;
while (start < end) {
// Moves front runner to next alphanumeric
while (regex.test(s[start])) {
start++;
}
// Moves back runner to next alphanumeric
while (regex.test(s[end])) {
end--;
}
// Above would run until null if there are no alphanumeric characters so return true
if (!s[start] || !s[end]) {
return true;
}
// Check if equal and return false if not
if (s[start].toLowerCase() != s[end].toLowerCase()) {
return false;
}
// If index values match continue the while loop
start++;
end--;
}
return true;
};
Please Advise!
Same as previous solution, plus:
+ removing spaces and symbols, except (A-Z,a-z,0-9)
+ lowercasing
const isPalindrome = function(str) {
const expr = /[\W_]/g;
const lowcaseStr = str.toLowerCase().replace(expr, '');
const reverseStr = lowcaseStr.split('').reverse().join('');
return lowcaseStr === reverseStr
};
This is heavily over-engineered. Why not just use one for loop with 2 counters, one starting at 0 and one at the last index and, while they aren't equal, check if the characters at those indices are the same. Or use built in functions like
function palindrome(str){ return str.split('').reverse().join('') == str}
I have a function to validate phone number in a contact form, but i need to be able to put in "xxx xxx xxxx" for example, and not just "xxxxxxxx"
The number format should be:
xxx xxx xxxx
xxx-xxx-xxxx
xxx.xxx.xxxx
function validatePhone() {
var phone = document.getElementById("phone").value;
if (phone.length == 0) {
var w = document.getElementById("phoneError").textContent;
alert(w);
return false;
}
if (phone.length != 10) {
var r = document.getElementById("phoneError").textContent;
alert(r);
return false;
}
// THIS IS NOT WORKING
if (
!phone.match(/^[0-9]{10}$/) ||
!phone.match(/^\d{3}-\d{3}-\d{4}$/) ||
!phone.match(/^\d{3}.\d{3}.\d{4}$/)
) {
var t = document.getElementById("phoneError").textContent;
alert(t);
return false;
}
}
Two things: First, you are mixing up AND and OR:
if (
!phone.match(/^[0-9]{10}$/) ||
!phone.match(/^\d{3}-\d{3}-\d{4}$/) ||
!phone.match(/^\d{3}.\d{3}.\d{4}$/)
) {
As soon as one of the conditions fails, it will return false (which is basically always). You want this if to apply, when none of the expressions matches, e.g. when all of them are false. Therefor, you have to use && instead of ||. Not a AND not b AND not c.
Second: your 3rd regex is a bit off: . means "any character", so this regex would also match "123x123y1234". You need to escape the dot with a backslash: /^\d{3}\.\d{3}\.\d{4}$/
Also, you can improve this code significantly. You have 5 conditions, which could all be handled in one (if you want to allow the input of "123.123 234", otherwise you will have to do it using 3 regex). And for just checking if a regex matches a string, you maybe should use test(), because it is just slightly faster (it won't matter in your case, but just out of principle).
You can reduce your code to:
if (/^\d{3}[\s-.]\d{3}[\s-.]\d{4}$/.test(document.getElementById("phone").value) === false) {
alert (document.getElementById("phoneError").textContent);
return false;
}
I've been doing a lot of searching, chopping and changing, but I'm...slightly lost, especially with regards to many of the regex examples I've been seeing.
This is what I want to do:
I have a text input field, size 32.
I want users to enter their telephone numbers in it, but I want them to enter a minimum of 10 numbers, separated by a single comma. Example:
E.g. 1
0123456789,0123456789 = right (first group is >=10 numbers, second group = >=10 numbers & groups are separated by a single comma, no spaces or other symbols)
E.g. 2
0123456789,,0123456789 = wrong (because there are 2 commas)
E.g. 3
0123456789,0123456789,0123456789 = right (same concept as E.g. 1, but with 3 groups)
I've got the following, but it does not limit the comma to 1 per 10 numbers, and it does not impose a minimum character count on the number group.
$(document).ready(function(){
$("#lastname").keypress(function (e) {
//if the letter is not digit then display error and don't type anything
if (e.which != 8 && e.which != 0 && String.fromCharCode(e.which) != ','
&& (e.which < 48 || e.which > 57)) {
//display error message
$("#errmsg").html("Digits Only").show().fadeOut("slow");
return false;
}
});
});
Preferably, I'd like to warn the user of where they are going wrong as well. For example, if they try to enter two commas, I'd like to specifically point that out in the error, or if they havent inserted enough numbers, i'd like to specifically point that out in the error. I'd also like to point out in the error when neither a number or a comma is inserted. I'd like to ensure that the tab, and F5 keys are not disabled on the keyboard as well. And very importantly, I'd like to specifically detect when the plus or addition key is used, and give a different error there. I think I'm asking for something a little complex and uninviting so sorry :/
The example code I provided above works pretty well across all browsers, but it doesn't have any of the minimum or maximum limits on anything I've alluded to above.
Any help would be appreciated.
As far as a regex that will check that the input is valid (1-3 phone numbers of exactly 10 digits, separated by single commas), you can do this:
^\d{10}(,\d{10}){0,2}$
Try like the below snippet without Regex
var errrorMessage = '';
function validateLength (no) {
if(!no.length == 10) {
return false;
}
return true;
}
function validatePhoneNumbers (currentString, splitBy) {
if(currentString) {
var isValid = true,
currentList = currentString.split(splitBy);
// If there is only one email / some other separated strings, Trim and Return.
if(currentList.length == 1) {
errrorMessage = 'Invalid Length in Item: 1';
if(validateLength( currentString.trim() )) isValid = false;
}
else if(currentList.length > 1) {
// Iterating mainly to trim and validate.
for (var i = 0; i < currentList.length; i++) {
var listItem = currentList[i].trim();
if( validateLength(listItem ) ) {
isValid = false;
errrorMessage = 'Invalid Length in Item:' + i
break;
}
// else if for some other validation.
}
}
}
return isValid;
}
validatePhoneNumbers( $("#lastname").val() );
My code isn't working, can someone please tell me what the problem is?
I'm guessing it's the for loop, but I cannot find the problem.
<html>
<body>
<script>
username = prompt("Please enter a your username:");
for (var i = 0; i < username; i++) {
if(isFinite(username.charAt(i))) {
result = true;
document.write("The username consists of one or more numbers." + BR);
}
else {
result = false;
document.write("The username must consist of one or more numbers." + BR);
}
}
</script>
</body>
</html>
You have two problems in your code:
In the for loop, use the length of the variable to establish the stop condition
for (var i = 0; i < username.length; i++)
BR is not defined
Working code: http://jsfiddle.net/f643fr4w/
From the output I can probably assume you just want to check if username consists of at least one number, actually: a digit.
// iterate over the input
for (var i = 0; i < username.length; i++) {
// check if it is a number (not a digit but that's the same here)
if (isFinite(username.charAt(i))) {
result = true;
// The requirement "one or more numbers" is fulfilled,
// we can break out of the loop
break;
}
else {
result = false;
}
// print something according to "result"
if(result === true){
document.write('The username consists of one or more numbers.');
} else {
document.write('The username must consist of one or more numbers.');
}
}
You have to go over the full length of the string to find out if there's no number but not if you want to find out if there is any number in it.
Now, if you want to test if it consists of only digits you have to reword the requirements, they are a bit too ambiguous now.
Additional hints:
you need to check the input, you always have to check user input!
you need to be aware that JavaScript strings are UTF16. Rarely a problem but gets easily one if you iterate over JavaScript strings.
String.charAt() returns a character, not a number. Don't rely on the automatic conversions in JavaScript, you way too easily shoot yourself in the foot if you rely on it but also if you don't, so be careful.
please don't use document.write, use either the console if available or change the text-node of an HTML element.
With these points in mind you may get something like this:
// make a list of digits
var digits = ['0','1','2','3','4','5','6','7','8','9'];
// ask the user for a username
var username = prompt("Please enter a your username:");
// check input
if (username.length === 0) {
console.log('no username given');
} else {
for (var i = 0; i < username.length; i++) {
// indexOf searches for the same type, that's why the digits above
// are strings with quotes around them
if (digits.indexOf(username.charAt(i)) >= 0) {
result = true;
// The requirement "one or more numbers" is fullfilled,
// we can break out of the loop
break;
}
else {
result = false;
}
}
// print something according to "result"
if (result === true) {
console.log('The username consists of one or more numbers.');
} else {
console.log('The username must consist of one or more numbers.');
}
}
The above is one variation of many and could easily give rise to a heated discussion on some forums (not here! Of course not! ;-) ) but I hope it helps.
Use a regex for such shenanigans:
var username = prompt("username plz kk thx");
var result = /[0-9]/.test(username);
document.write("The username " + (result ? "consists" : "must consist") + " of one or more numbers");
Would someone a little smarter than myself be able to help me with this function? Its purpose is to validate a text input in a form, a phone number field that will only accept 0-9, dash and dot. The HTML calls the function fine.
function validateFeedback() {
var phone = document.getElementById("phone");
var validNumber = "0123456789.-";
for (i = 0; i < phone.length; i++); {
if (validNumber.indexOf(phone.charAt(i)) == -1); {
alert("You have entered an invalid phone number");
return false;
}
}
return true;
}
Thanks so much for any help.
Regular expressions should help ;)
I'm sorry I haven't tried to run this code, but it should be OK.
function validateFeedback(){
var phone = document.getElementById("phone");
var RE = /^[\d\.\-]+$/;
if(!RE.test(phone.value))
{
alert("You have entered an invalid phone number");
return false;
}
return true;
}
try like this:
function validateFeedback()
{
var phone = document.getElementById("phone");
var validNumber = "0123456789.-";
for(i = 0; i < phone.length; i++) {
if(validNumber.indexOf(phone.charAt(i)) == -1) {
alert("You have entered an invalid phone number");
return false;
}
}
return true;
}
there are ; out of place ...
I think you should use a regex to do this. Something link this:
function validateFeedback() {
var phone = document.getElementById("phone").value;
var reg = new RegExp("[0-9 .-]*");
return reg.test(phone);
}
If the text input is in a form, you can reference it more directly using the form id and the element id:
var phone = document.<formId>.phone;
What you want to test is the value of the element, so you need:
var phone = document.<formName>.phone.value;
Since the function is probably called from a submit listener on the form, you can make things more efficient using:
<form onsubmit="return validateFeedback(this);" ...>
It also seems to me that a phone number has only digits, not "-" or "." characters, so you should only test for digits 0-9.
So the function can be like:
function validateFeedback(form) {
var phoneValue = form.phone.value;
// Use a regular expression to validate the value
// is only digits
if (/\D/.test(phoneValue) {
// value contains non-digit characters
// advise user of error then
return false;
}
}
you may want to test that the length is reasonable too, but note that phone numbers in different places are different lengths, depending on the location and use of area or country codes, and whether the number is for a mobile, landline or other.
I would prefer to use regular expressions for something like this.
Please look at my modified version of your function which should work in all major browsers without any framework.
function validateFeedback() {
// Get input
var phone = document.getElementById("phone"),
// Remove whitespaces from input start and end
phone = (phone || '').replace(/^\s+|\s+$/g, ''),
// Defined valid charset as regular expression
validNumber = "/^[0123456789.-]+$/";
// Just in case the input was empty
if (phone.length == 0) {
// This depends on your application - is an empty number also correct?
// If not, just change this to "return false;"
return true;
}
// Test phone string against the regular expression
if (phone.match(validNumber)) {
return true;
}
// Some invalid symbols are used
return false;
}
Try this one
function validateFeedback(value) {
var length = value.length;
chk1="1234567890()-+ ";
for(i=0;i<length;i++) {
ch1=value.charAt(i);
rtn1=chk1.indexOf(ch1);
if(rtn1==-1)
return false;
}
return true;
}
function phonenumber(inputtxt)
{
var phoneno = /^\d{10}$/;
if((inputtxt.value.match(phoneno))
{
return true;
}
else
{
alert("message");
return false;
}
}